Practice Quiz 13_ Attempt review
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School
Thompson Rivers University *
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Course
1901
Subject
Mathematics
Date
Apr 3, 2024
Type
Pages
9
Uploaded by CaptainArt11246
Started on
Tuesday, 1 August 2023, 3:27 PM
State
Finished
Completed on
Tuesday, 1 August 2023, 3:56 PM
Time taken
28 mins 42 secs
Question 1
Correct
Mark 1.00 out of 1.00
A prism with parallelogram bases has
faces (including the base),
edges, and
vertices.
6
12
8
Your answer is correct.
The correct answer is:
A prism with parallelogram bases has [6] faces (including the base), [12] edges, and [8] vertices.
Question 2
Correct
Mark 1.00 out of 1.00
Match the surface area formulas to the objects. Formula notation: l
is length; w
is width; h
is height; B
is base area; p
is perimeter; r
is
radius; s
is slant height.
Rectangular box
Prism
Cylinder
Cone
Pyramid
Your answer is correct.
The correct answer is: → Rectangular box, → Prism, → Cylinder, → Cone, B
+
1
2
ps
→ Pyramid
Question 3
Partially correct
Mark 0.60 out of 1.00
Match the volume formulas to the objects. Formula notation: l
is length; w
is width; h
is height; B
is base area; r
is radius.
\(lwh)\)
\(Bh\)
\(\pi {r^2}h\)
\(\frac{1}{3}\pi {r^2}h\)
\(\frac{1}{3}Bh\)
Prism
Rectangular box
Cylinder
Cone
Pyramid
Your answer is partially correct.
You have correctly selected 3.
The correct answer is: \(lwh)\)
→ Rectangular box, \(Bh\)
→ Prism, \(\pi {r^2}h\)
→ Cylinder, \(\frac{1}{3}\pi {r^2}h\)
→ Cone, \(\frac{1}{3}Bh\)
→ Pyramid
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Question 4
Incorrect
Mark 0.00 out of 1.00
Imagine an Egyptian right pyramid with a square base. Suppose the sides of the square base are 80 metres long and the tallest
point in the centre of the pyramid is 80 metres above ground.
Calculate the total surface area of the pyramid (not including the base) and the volume of the pyramid. Surface area =
25000
m
, volume =
17070
m
. (Round your answers to the nearest ten; do not include any words or calculations.)
2
3
The figure below shows how to find the area of one of the lateral faces of the pyramid. We need the slant height, s
, in order to find the
area of a lateral face.
Using the Pythagorean theorem we get \(s = \sqrt {{{80}^2} + {{40}^2}} = \sqrt {8000} \) m.
So, the area of one face is \(\frac{1}{2} \times 80 \times \sqrt {8000} = 40 \times \sqrt {8000} \) m
.
Thus, the surface area (not including the base) is \(4 \times 40 \times \sqrt {8000} = 160 \times \sqrt {8000} = 14,310\) m
.
Volume \( = \frac{1}{3} \times {80^2} \times 80 = 170,670\) m
.
2
2
3
Question 5
Correct
Mark 1.00 out of 1.00
Fill in the blanks question: Consider the following diagrams.
i. ii.
iii.
Diagram (i) represents
Diagram (ii) represents
Diagram (iii) represents
reflection across the x-axis
translation of 5 units to the right and 2 units down
rotation of 180° around the origin
Your answer is correct.
The correct answer is:
Fill in the blanks question: Consider the following diagrams.
i. ii.
iii.
Diagram (i) represents [reflection across the x‑axis]
Diagram (ii) represents [translation of 5 units to the right and 2 units down]
Diagram (iii) represents [rotation of 180° around the origin]
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Question 6
Correct
Mark 1.00 out of 1.00
Question 7
Partially correct
Mark 0.67 out of 1.00
Which of the following statements is correct?
Select one:
a.
Isosceles triangles have only reflection symmetry, while equilateral triangles have only rotation symmetry.
b.
Isosceles triangles have only rotation symmetry, while equilateral triangles have only reflection symmetry.
c.
Isosceles triangles have only reflection symmetry, while equilateral triangles have both reflection and rotation symmetry.
d.
Isosceles triangles have both reflection and rotation symmetry, while equilateral triangles have only reflection symmetry.
e.
None of the statements a-d are correct.
Your answer is correct.
The correct answer is: Isosceles triangles have only reflection symmetry, while equilateral triangles have both reflection and rotation
symmetry.
Any square has
lines of reflection symmetry and
rotation symmetry.
A non-square rectangle has
lines of reflection symmetry and
rotation symmetry.
A non-rectangular parallelogram has
lines of reflection symmetry and
rotation symmetry.
four
4-fold
four
2-fold
two
2-fold
Your answer is partially correct.
You have correctly selected 4.
The correct answer is:
Any square has [four] lines of reflection symmetry and [4‑fold] rotation symmetry.
A non-square rectangle has [two] lines of reflection symmetry and [2‑fold] rotation symmetry.
A non-rectangular parallelogram has [no] lines of reflection symmetry and [2‑fold] rotation symmetry.
Question 8
Correct
Mark 1.00 out of 1.00
Ms. Winstead’s class went outside on a sunny day and measured the lengths of some of their classmates’ shadows. The class also
measured the length of a shadow of a tree. Inside, the students made the following table:
Tyler
Jessica
Sunjae
Lameisha
Tree
Shadow
length
83 cm
86 cm
80 cm
86 cm
6.7
m
Height
138
cm
143 cm
133
cm
143 cm
?
Calculate the approximate height of the tree. The tree is approximately
11
metres tall. (Write a whole number; do not include words or calculations.)
Two similar triangles are formed: one side is the tree or child, a second side is the shadow, and the third side is the first ray of light
that is not blocked by the tree or child.
The angle of the light is the same for both the tree and the children, and the tree and children are all perpendicular to the ground (i.e.,
they are parallel), so the triangles formed are similar. The height of the tree is unknown, but the lengths of the shadows and the
heights of the children are known. The ratios of each child’s height to their shadow length are each 1.66. So, the tree should be
about 1.66 times as tall as its shadow is long, about 1.66 × 6.7 = 11 metres tall.
Question 9
Correct
Mark 1.00 out of 1.00
Question 10
Partially correct
Mark 0.50 out of 1.00
Sue has a rectangular garden with an area of 6 m
. If Sue makes her garden twice as wide and twice as long as it is now, what will
the area of her new garden be?
Select one:
a.
3 m
b.
12 m
c.
24 m
d.
36 m
e.
We can’t calculate the area of her new garden without knowing the width and length of the old garden.
2
2
2
2
2
Your answer is correct.
Since each length measurement is multiplied by 2, the area is multiplied by 2
= 4
The correct answer is: 24 m
2
2
A scale model is constructed for a domed hockey arena with a scale of 1 to 100. The model’s dome is made of 4 square metres of
cardboard. The model contains 2 cubic metres of air. The actual arena’s dome will be made of
40000
square metres of material and will contain
4000000
cubic metres of air. (Write whole numbers; no words or calculations.)
The actual surface area of the dome is 4 × 100
= 40,000 m
and the actual volume of the arena is 2 × 100
= 2,000,000 m
.
2
2
3
3
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