Worksheet1-1
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Feb 20, 2024
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MATH 201 Statistics for Environmental Professionals ● Worksheet 1
Name Section 1.
Suppose that you are a wildlife biologist working in a National Park. One of your tasks is to conduct demographic surveys of American alligators in the park. You have conducted a nightlight survey and measured encountered alligators. The survey data are shown in the below table. Answer the following
questions using this dataset.
Animal
ID
Habitat
type
Water
temperature
(°C)
Head
Length
(cm)
Total
Length
(cm)
Weight
(kg)
Sex
Number of
deformities
1
Marsh
20
21.2
144.5
9
Female
0
2
Marsh
19
25.6
185.2
16
Male
0
3
Marsh
20
20.4
139.9
8
Female
0
4
Marsh
19
26.8
203.3
19
Female
1
5
Marsh
20
30.0
211.5
17
Male
0
6
Marsh
22
30.0
224.5
28
Female
1
7
Marsh
20
29.5
212.8
17
Male
0
8
Marsh
20
26.9
195.8
19
Male
0
9
River
23
25.7
186.9
19
Male
0
10
River
23
32.9
247.7
39
Male
0
11
River
23
29.6
210
27
Female
0
12
River
25
24.3
178.5
15
Male
2
Question 1. How many variables are in the data set? Refer to the textbook 1.1. (5 pts.)
8
Question 2. List all numerical (quantitative) variables and classify them into continuous or discrete. Refer to your textbook 1.1 & 1.2. (5 pts.)
Discrete- number of deformities, animal ID
Continuous - Temperature, head length, total length, weight, Question 3. Find the median weight of the female alligators. Show your work.
Refer to the textbook 2.3. (10 pts.)
8 9 19 27 28 = 19
Question 4. Calculate the mean weight of the female alligators.. Show your work.
Refer to the textbook 2.5. (10 pts.)
9+8+19+28+27= 91/5= 18.2
Question 5. Find the standard deviation of weight of the female alligators.. Show your work.
Refer to the textbook 2.7. (10 pts.)
1.
Find the mean: Mean=9+8+19+28+275=915=18.2
2.
Subtract the mean from each data point and square the result: (9−18.2)2=82.44(9−18.2)2=82.44 (8−18.2)2=105.64(8−18.2)2=105.64 (19−18.2)2=0.64(19−18.2)2=0.64 (28−18.2)2=96.04(28−18.2)2=96.04 (27−18.2)2=76.84(27−18.2)2=76.84
3.
Find the mean of these squared differences: Mean of squared differences=82.44+105.64+0.64+96.04+76.845=361.65=72.32
4.
Take the square root of that mean: Standard Deviation=72.32≈8.50
Question 6. Using the descriptive statistics Excel worksheet provided, calculate the descriptive statistics for one of the following variables: head length, total length, or weight. (10 pts.)
Chosen Variable
weight
Sample size (n)
Mean
Standard deviation
Minimum
1st Quartile
Median (2nd Quartile)
3rd Quartile
Maximum (4th Quartile)
12 (?)
21.08
8.45
8
15
18
23
23
Section 2.
Suppose that you are an employee of the United Nations Environment Programme for forest conservation. You are assigned to summarize the recent deforestation rate by country using a graph and interpreting the graph. The accompanying file contains a part of the data of nationwide deforestation rate (percentage) in 2020. Answer the following questions using the dataset.
Question 1. Using Excel, create a histogram of percentage of deforestation with bin width (width of each bar) 5. Attach the histogram to this report. (20 pts.)
Question 2. What is the most typical class (
range for tallest bar on the histogram
) of deforestation? (10 pts.)
0-4.7%
Question 3. Is there any outlier in the data? If so, which country(s)? Refer to your textbook 2.1. (10 pts.)
There wasn’t a solo outlier but there is no connection between 9.4-14.1 to 18.8-23.5. You could count 18.8-23.5, 23.5-28.2, and 28.2-32.9 as the outliers.
Question 4. Describe the skewness of the data. Refer to your textbook 2.6 (10 pts.)
Most data are distributed towards the left side of the histogram.
Source: UNEP (2020): The UNEP Environmental Data Explorer, as compiled from Food and Agriculture Organization of the United Nations (FAO) - FAOStat. United Nations Environment Programme. http://ede.grid.unep.ch
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