StewartCalcch1s11e2

Stewart Calculus 8e: Section 1.1 - Exercise 2 Page 1 of 1 Exercise 2 If f ( x ) = x 2 - x x - 1 and g ( x ) = x is it true that f = g ? Solution The two functions are not equal because the domain of f is { x | x 6 = 1 } , whereas the domain of g is { x | x ∈ R } . In other words, even though f ( x ) = x 2 - x x - 1 = x ( x - 1) x - 1 = x and g ( x ) = x, there is a hole (or point of discontinuity) at x = 1 in the graph of f versus x but no hole in the graph of g versus x . www.stemjock.com