Assignment 4
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School
Straighterline *
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Course
250
Subject
Mathematics
Date
Nov 24, 2024
Type
Pages
5
Uploaded by supabrown
Belascc
Name
lianna
GoureB MAC2312
Progessor
De.
Cseoca
Kapkoul's
3T0
6361629
lQote
áblo La023
Asianmen
Assianmnent 4 lntegnals af Monotoníc funchons
Ppblemn 4.1
im
-o
= lim
= lim
=
n
n
n>teO
n2 (n+ 1)*
-n-too
n
lim
4
=lim
n
n
4
t
+ I
(2)
+ i) dx
n340
h
-i
(G
.
n3to
lim
on
+
n2to
+
lim
nto
-2=im
2
n
n
linni-2)
n
O
n(nt)
Created with Scanner Pro
im
()
+ x +x
=im
+
+ *i
+
)
n5t0
=lim
n(nt
+
n(n)
ntoo
=
19
+t
+
4
ProblamH.g
Dex) =A
po
=o +i
n
In
+hene
ane
ineinitely
manu
€
(Qensiy
a
Reals)
D ) =max(A ,B)
Riemenn
ppen
Sum
n-1
max(A,s)
(
i-Xi)= max
(A8)
b
-)L:)
ia
(
maw A,G)
h
=ma (A,8)
()
Riemann
m
Loser
L(o, e)
-\min(A,es)
(xi -4)
Ci
- x;)
=min (A8)
=min
(A,8) (+I
-)
=min (A,8)(0
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Pooolem 4.8
im
o(k*)
n-to
Kal
k
n
D(k
=
A
-im
Kal
lin
nA
(t o ) A
n2o
A
Ž
O
4hen
+oo
en
Roblem
Lim
(2
3i
n
n7
n
=in
ulx
- m
2
+
nto
n7too
n
+
n5to0
2n
n (nt)
+
+
=
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lim
=
lim
n>t
3
)
n
iel
n+0
3
im
Ror
Rim
u (,ela,sT
lin
4i2
n2
+
n-+o
=in
4
+
+
+(
)
12,n (n+)
= im
n
n
n
= lim
27n
n
tos
2n
2
+
39
=
3)im
2+
= im
3
4
3i
Por
2
36i
Lin
u(z
pla,s]
+ a7
n-o
n
-lim
++
36
+
(
)
.n(n+)
.
n
16n
23
108 (nin))
162n3
3n
24n
1bn
lhln+)
n-2teo
24
+ 54
+
54
+
4
4
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loblem
4.4
n-l
l4)
= im
ntoo
n
lim
n-5t
im
n
n
o
=im
L(X
pco,i
lim
nto
n-to
n
lim
n>to
n+)
n
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