MATH 1281-01 - AY2024-T2
If a sample of size 900 has a mean of 452 and a standard deviation of 96, what is the margin of error for a 95% confidence interval for the population mean?
Group of answer choices
6.4
7.1
5.2
6.1
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Answer
1 month ago
To calculate the margin of error for a 95% confidence interval for the population mean, you can use the formula:
Margin of Error = Z * (Standard Deviation / √Sample Size)
Where Z is the z-score corresponding to the desired confidence level. For a 95% confidence level, the z-score is approximately 1.96.
Given that the sample size is 900, the mean is 452, and the standard deviation is 96, we can calculate the margin of error as follows:
Margin of Error = 1.96 * (96 / √900)
Simplifying the equation:
Margin of Error = 1.96 * (96 / 30)
Calculating the result:
Margin of Error ≈ 6.27
Therefore, the margin of error for a 95% confidence interval for the population mean is approximately 6.27.
Among the given answer choices, the closest option is 6.1.
