What is the hypothesis in this scenario?
Did the new fuel process take less or more time? How do you know?
In the scenario, did you conduct a one or two-tailed test?
What is the p
-value? (Remember to interpret what the E-06 means and round to 3 decimal places)
Do you think (as Freddy does) that the result is not statistically significant?
Do the results “prove” anything?
The hypothesis in this scenario is that the new fueling process will take less time with the new equipment than the current process. If that is the case, Freddy will purchase expensive new fueling equipment for his operations at multiple airports. To understand this with the experiments, we will be looking for the mean of the fueling time with the new equipment to be lower than the mean fueling time with the current equipment. The desired answers from the question require this to be a one-tailed test.
The p-value of 3.82255E-06 is seen as the formula 3.82255*E^-6=.0000038226. The provided p-value is in scientific notation and the fact that it has four 0's after the decimal place suggests that the p-value is less than 0.0001. Therefore, E^-06 is equal to 10^-6, which is .000001. Comparing the mean amount of time taken for the fueling processes it is observed that the new way is indeed fasting with the new equipment. Observing the mean being 48.15 with the new equipment and the mean being 63.15 with the old equipment, it took less time on average than the current process. We easily observe the mean of the times of each. The p-value
for the difference is 3.82255E-06, which is <.001.
The p-value is less than the significance level and we can reject the null hypothesis. Counter to what Fredy thinks, the results are statistically significant, and they can prove that there is sufficient evidence to support that the new process is more efficient than the current fueling process, on average.
Wells
