Chap 8 - assignment
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Ashworth College *
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OMM615
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Industrial Engineering
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Dec 6, 2023
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Minimax Location- Class Exercise
The Provincial Government is considering a site for a police station, which should serve 3
rural communities: Red Sox, Blue Sky and Newmont.
There are 3 possible sites available for the police station, with the following information:
The distances from Site 1
are: 20km to Red Sox, 14 to Blue Sky and 27 to Newmont.
The distances from Site 2
are: 10km to Red Sox, 24 to Blue Sky and 17 to Newmont.
The distances from Site 3
are: 15km to Red Sox, 18 to Blue Sky and 21 to Newmont.
You have to recommend the best site for the police station, according to the Minimax
Rule.
Answer:
The minimax rule is a decision rule used for minimizing loss for a worst-case scenario. In
other words, it is used to determine the best course of action in any given situation.
For
the purpose of this exercise, we need to minimize the distance between each community
vis a vie the police station.
Name
Red Sox
Blue Sky
Newmont
Maximum
Site 1
20
14
27
27
Site 2
10
24
17
24
Site 3
15
18
21
21
Based on the above we need to minimize the maximum therefore site 3 would be the
smallest maximum distance of all three sites.
Centre of Gravity- Class Exercise
The following table gives the map co-ordinates and shipping loads for some local
cities. We wish to build a new warehouse in a central location in order to minimize
transportation costs. At what co-ordinates should this warehouse be located?
City
Map Co-ordinates (x, y)
Number of truckloads
______________________________________________________________
Brampton
(6.0, 3.0)
9
Barrie
(9.0, 10.0)
10
Mississauga
(6.0, 1.8)
15
Oakville
(2.0, 0.8)
6
Hamilton
(0.9, 0.5)
18
Guelph
(1.2, 4.0)
12
Milton
(1.8, 2.8)
8
Answer:
For the above we would use the Center of Gravity Method to calculate geographic
coordinates for the new facility which will minimize costs.
We use this equation to
calculate:
x= ∑ dix Vi/ ∑ Vi
y= ∑ diy Vi/ ∑ Vi
We plot as follows :
X = (6*9) + (9*10) + (6*15) + (2*6) + (0.9*18) + (1.2*12) + (1.8*8) / 78 = 3.73
Y = (3*9) + (10*10) + (1.8*15) + (0.8*6) + (0.5*18) + (4*12) + (2.8*8) / 78 = 3.05
Therefore the co-ordinates are 3.73, 3.05
0
1
2
3
4
5
6
7
8
9
10
0
2
4
6
8
10
12
3
10
1.8
0.8
0.5
4
2.8
3.05
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