Final Exam Review Guide Sp 21

docx

School

Louisiana State University *

*We aren’t endorsed by this school

Course

3302

Subject

Industrial Engineering

Date

Dec 6, 2023

Type

docx

Pages

13

Uploaded by miniflassy

Report
IE3302 Final Exam – Review Guide Exam Coverage The Final Exam is comprehensive (any materials covered in the course) but emphasis will be on the latest chapters, particularly chapters 8 & 10. Proportionately, exam coverage will be approximately: Chapters: 4 1-3 5-6 8,10 In this guide, I have only included review problems related to Chapters 8 & 10; you should also do a quick review of the review guides and test solutions from Midterms #1 & #2. Following is a summary of the topics which you should be familiar with from chapters 8 and 10 specifically: Chapter 8 (Sampling Distributions): Standard error vs. standard deviation X-bar & difference in means: Z, T statistics & distributions S 2 : Chi-Square statistic & distribution Ratio of variances: F statistic & distribution For each distribution: o Conditions for when to use, key words to identify o How to calculate critical values or find probabilities o Meaning of o Two-tailed vs. one tailed test o How to use tables and Excel functions Chapter 10 (Hypothesis tests): Hypothesis Tests: o Formulating/stating o Selecting right test statistic One sample mean One sample variance Two sample means – 4 cases: Known variance, unknown but equal variance, unknown unequal variance, paired observations Two sample variance o Understanding & calculating , , power, p-value, critical values o Interpreting results & drawing conclusions Confidence Intervals – calculating, interpreting Operation of the Exam Please review the following carefully: The final exam is scheduled for 3-5pm Monday April 26 th , 2021 . o If you have requested an extended time accommodation (& provided an ODS form to document), extended time exam will instead run 3-6pm. The exam itself will be on Moodle during the scheduled exam time . Note the exam will automatically open at 1:30pm and automatically close at the end of the exam period. You must be on Zoom with video turned on throughout the exam for proctoring purposes . The exam Zoom URL will be the same as the "Scheduled Class Time" zoom link on Moodle. Once you are admitted to Zoom, you will be assigned to a breakout room with a proctor.
o During the exam, your audio should be muted unless a proctor or I need to talk to you. Use Chat to communicate questions to your proctor. The proctor will either relay the question to me or ask you to return to the main session to talk to me if they are not able to answer it directly. o If you need to leave the video frame of view for any reason, notify the proctor first by chat and indicate why. Any break is expected to be short. If you will need to leave for more than a couple of minutes, you must end and submit your exam before leaving or be assigned a zero. If you have not submitted your exam and leave the video frame of view without notifying the proctor first, you will be assigned a zero for the exam. o If your video turns off during the exam, you will be asked once to turn it back on. If that does not occur quickly, you will be assigned a zero for the exam. o For anyone arriving late to Zoom, or leaving early from Zoom, the Zoom attendance logs will be matched against the Moodle exam logs. If the logs do not match (i.e., you were working on the exam while not on Zoom), you will be assigned a zero for the exam. See rules below as to what you may use during the exam. Rules of the Exam You may use the following during the exam: Calculator (graphing calculators ok) and/or Excel. Excel may also be used for generating graphs. Pen / pencil and blank paper for calculations Formula sheets: Up to four sheets (8.5’ x 11’) double-sided (8 pages total) or eight single-sided pages (same size restriction). You may print and/or hand-write. Discrete (Binomial & Poisson) and Continuous (Standard Normal) Probability Tables from Appendix A. These may be accessed on your computer, you can but do not have to print. As you will have access to Excel, I strongly advise you use Excel functions instead to avoid the need for interpolation . Computer, to be used ONLY for zoom proctoring, calculations (calculator app or Excel), probability tables, and entering exam solutions in Moodle. o Any other form of messaging, file sharing, web browsing/search, etc. is not allowed o Use of any materials / files / apps on your computer other than listed here is not allowed NO cell phones may be out during the exam, except to scan handwritten work for essay style questions. For all calculation problems, maintain calculations to at least 4 decimal positions through final answer. Multiple choice, matching, true/false , or Moodle numeric answer problems (the last is a type of auto-graded Moodle problem for which you provide a single numeric answer): No or limited partial credit will be given for incorrect answers on these problems. You do NOT show work for these problems. Work must be shown for essay type questions. For these problems, if using Excel or statistical / integration functions on your calculator, formulation must be shown to earn credit. If using Excel, include the Excel formula(s) used. To show integrations, use the Moodle equation editor or a MATLAB-like notation; e.g.,, x = 1 10 3 x 2 dx can be written as int(3x^2, x=1 to 10) 1
CHEATING IN ANY FORM WILL NOT BE TOLERATED AND IS PARTICULARLY PROBLEMATIC FOR STUDENTS STUDYING TO BE PROFESSIONAL ENGINEERS OR COMPUTER SCIENTISTS. ANY SUSPECTED CHEATING WILL BE REFERRED DIRECTLY TO THE DEAN OF STUDENTS JUDICIAL OFFICE FOR FURTHER ACTION. Review Materials Only questions from Chapters 8 & 10 materials are included here. Do a quick scan of the midterm review guides to refresh your memory on Chapters 1-6 materials. The questions here come from old IE3302 exams. A recent final exam I have given is included at the end of this document. Most problems have solutions; for those without you are welcome to check your results with me, after making a good effort at solving the problem. The final exam will be 100pts. Use the points noted in the guide to get an idea of the number of questions covered on any one exam. The problems here are primarily from in-person paper exams. With the exam on Moodle, there will be significantly more multiple-choice, matching, numeric questions on your exam then shown in the review questions (but note that any of the problems in the guide can be turned into multiple choice problems; this does not mean fewer calculation problems). 1. [15pts] A new fracturing method is suggested to increase natural gas flow rates in existing wells. Flow rates are measured both before and after applying the treatment on 8 different wells. Perform an appropriate hypothesis test at a significance level of 0.05, stating your null and alternative hypothesis, test statistic, either critical value(s) or p-value, and the conclusion of your test. Well 1 2 3 4 5 6 7 8 Flow rate before (Mcf/day) 3.2 2.4 2.9 3.1 3.4 4.5 5.2 1.8 Flow rate after (Mcf/day) 3.7 2.9 3.3 3.3 3.5 4.5 6.4 2 -0.5 -0.5 -0.4 -0.2 -0.1 0 -1.2 -0.2 Let current method be method 1 and new one method 2 H0: 1 - 2 = 0 H1: 1 - 2 < 0 =0.05 Since both methods applied on same well, use paired observations. Test statistic: t =( -bar – 0) / ( S / sqrt(n) ) =(-0.3875 – 0) / (0.3758 / sqrt(8)) = -2.916 Lower tail test -t 0.05, 7 = -1.895 Since -2.916 < -1.895, reject H0. Evidence supports new method is better -OR- p -2.916 between 0.01 and 0.015 (approx. 0.011). Since p < , reject H0. Evidence supports new method is better 2
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
NOTE: Some students may have reversed methods 1 and 2 in calculations, so that delta-bar is positive. Still correct so long as correctly state H1 and do upper tail test instead of lower tail. 3
2. [20pts total] A medical equipment company supplies rechargeable batteries for use in AEDs (automatic external defibrillators). The batteries have historically provided N(200, 5) milliamps (mA) of current. 12 AEDs are selected at random from the most recently produced batteries, and the mean amperage and standard deviation are calculated to be 196 mA and 4 mA, respectively. a. [10pts] Does this sample appear to come from the historical distribution? State the appropriate hypothesis test and assuming a 0.05 significance level, calculate the critical value(s) for the test. Also state your test conclusion. H0: = 200 H1: 1 <> 200 =0.05 n=12 Comparing sample mean against known mean with known variance. Because of small sample size, use t-distribution. t= (196 – 200) / (4/sqrt(12)) = -3.4641 Two sided test, 0.025 in each tail Critical values +/- t 0.025; 11 +/- 2.201 Since test statistic is outside critical values, reject H0. The batteries do not appear to come from the same distribution. b. [10pts] Find the 90% confidence interval on the sampled mean for the average amperage. = 196 ± t 0.05 , 11 ( 4 12 ) ¿ 196 ±( 1.796 ) ( 4 12 ) ¿ 196 ± 2.0738 ¿ 193.9262 < μ < 198.0738 3. [15pts] A drug manufacturer will face serious sanctions if its variability exceeds =.001mg per pill in the key ingredient of one of its medicines. A sample of 30 pills is taken at random by an FDA inspector and S is found to be 0.0013mg. At a 5% significance level, what conclusion should the inspector draw? Full state the specifics of your hypothesis test in answering this question. H0: = 0.001 H1: > 0.001 =0.05 n=30 Comparing sample variability against assumed variance. Test Statistic: 2 = (30-1)*0.0013 2 / 0.001 2 = 49.01 Upper tail test, Critical value: 2 .05;29 = 42.557 Since 49.01 > 42.557, reject H0 – pills exceed maximum variability allowed in key ingredient. 4
4. [10pts] People arrive individually and randomly at a small club at an average arrival rate of 9 people per hour between the hours of 10pm to 2am. Assume the club opens at 10pm, and that no one arrives before opening time (i.e., the club opens empty). The club can only hold 25 people. The average time between arrivals of the last 30 arrivals was 10 minutes. Does this seem an unusually large sample average inter-arrival time? Perform an appropriate hypothesis test. State your hypothesis and significance level, calculate your test statistic and critical value(s), and state both your statistical and practical conclusion for the test. Need to get time units all the same; here will convert to minutes: = 9 people per hour / 60 minutes per hour = 0.15 people per minute For exponential, = =1/ =1/0.15=6.667 minutes; and = =6.667 minutes Test on mean, single population, known variance and n >= 30 H 0 : =6.667 H 1 : >6.667 =0.05 Test Statistic: Z = (10-6.667)/(6.667/sqrt(30)) = 2.7382 Critical value: Z .95 = 1.645 (will accept 1.64 or 1.65 as well) Since 2.7382 > 1.645, Reject H 0 . It appears the inter-arrival times during this period had a higher population mean than historical. 5. [12pts] At Disneyland, a popular roller coaster ride has had high variability in loading times. High variability causes blocking and idle time for the ride that reduces overall ride capacity and increases waiting times for customers. You have come up with an idea to make loading times less variable. You take a sample of 20 observations of loading times before implementing your idea and determine S before =35 seconds. After implementing, you collect another 20 observations and determine S after =18 seconds. Perform an appropriate hypothesis test to test whether your improvement was effective. State your hypothesis and significance level, calculate your test statistic and critical value(s), and state both your statistical and practical conclusion for the test. Comparison of variances (2 populations) – F distribution. H 0 : b = a H 1 : b > a =0.05 Test Statistic: F = 35 2 /18 2 = 3.7809 Critical value: F .05,19,19 = 2.16 Since 3.7809 > 2.12, Reject H 0 . Your idea was effective in reducing loading time variance. 6. [13pts] A new equipment maintenance process is being put in place at your companies 5 manufacturing facilities in the gulf coast region. The number of hours of production downtime during 5
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
the two months preceding putting the process in place is collected for each facility, and then again for two months after implementing the new process. Perform an appropriate hypothesis test to test whether your improvement was effective. State your hypothesis and significance level, calculate your test statistic and critical value(s), and state both your statistical and practical conclusion for the test. Facility Before After Houston 230 231 -1 Mobile 180 140 40 Lafayette 250 194 56 New Orleans 130 67 63 Vicksburg 145 148 -3 Sample Mean: 187 156 31 Sample S: 52.153 6 61.866 8 31.265 Difference in means - Paired observation (delta column added for solution) H 0 : =0 H 1 : >0 (since before – after, positive means after is smaller) =0.05 Test Statistic: t = (31 - 0)/(31.265/sqrt(5)) = 2.2171 Critical value: t .05,4 = 2.132 Since 2.2171 > 2.132, Reject H 0 . The new maintenance process is effective in reducing production downtime. 6
IE3302 Sample Final Exam For problems 1-5, you are given X~NORM( =40, =20). n=36, =0.05 (significance level). 1. [5pts] An ´ X = 42.4 is drawn. For a one-sided test (H 1 : >40), what is the p-value? a. 0.7200 b. 0.7751 c. 0.2358 d. 0.3156 e. 72.8971 f. 0.4522 2. [5pts] Pr( 27 ≤ X ≤ 40) (to 2 decimal places): a. 0.50 b. 1.00 c. 0.24 d. 0.76 3. [5pts] For a one-sided test on the mean (H 1 : >40), the critical value for ´ X is: a. 45.4828 b. 34.5172 c. 0.95 d. 7.1029 e. 0.05 f. None of the above 4. [4pts] X 0.25 ? Choose closest from following: a. 4.04 b. 37.75 c. 0.25 d. 26.51 e. 24.30 5. [5pts] Pr( ´ X > 40 | ´ X > 39 )? a. 0.9617 b. 0.5000 c. 1.3086 d. 0.8092 e. None of the above 7 known, n>= 30, use Z = Pr( ´ X 42.4) = 1 - ( (42.4-40)/(20/sqrt(36)) ) = 1 - (0.72) = 1 – 0.7642 = 0 .2358 = F(40) – F(27) = 0.5 - ( (27-40)/20=-0.65) = 0.5 – 0.2578 = 0.24 = ´ X 1 0.05 = 0.95 = Z 0.95 *(20/sqrt(36))+40 = 1.645*(20/sqrt(36))+40 = 45.48 Closest Z in table is -1.67 = -0.67*20+40 = 26.6 Interpolating or using norm.inv yields 26.51 = Pr( ´ X >40) / Pr( ´ X >39) = 0.5 / (1 - ( (39-40)/(20/sqrt(36))=-0.3) = 0.5 / (1 – 0.3821) = 0.8092
6. [5pts] Suppose a distribution's has changed to 2 . For a hypothesis test on the mean, circle ALL the statements which are true (note: points taken off for both missed and wrong answers) a. Increasing confidence increases b. Increasing sample size n decreases c. Increasing decreases d. Increasing power increases Type I error 7. [4pts] X ~ b * (x; k=3,p=0.3). Pr(X=2)? (to 2 decimal places) a. 0.08 b. 0.00 c. 0.16 d. 0.97 e. 0.19 8. [4pts] An observation is made of X which is one standard deviation below the mean. Given X is normally distributed, what Z value does this correspond to? a. -2.5 b. -1.0 c. 0.5 d. 0.16 e. None of the above 9. [4pts] For a sample, skew sk = -1.8. Which of the following box and whisker charts is most likely for this sample? (select one only) a) b) c) 8 X, the number of trials, must be at least >= k, the number of successes in those trials. 3 successes in two trials is impossible, so Pr(X=2) = 0 Z is the number of standard deviations above/below the mean, so one standard deviation below the mean is Z = -1
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
10. [4pts] B(3; 9, 0.4)? a. 0.7334 b. 0.2706 c. Pr(X<3) d. 0.4128 e. None of the above 11. [5pts] You are studying a maintenance operation. You have made significant changes in how the process is performed (new tools and methods) in an effort to reduce repair time. You have taken a sample of 40 service times both before and again after the improvement and calculated ´ X and S for each. Which hypothesis test would be most appropriate? a. T test on mean of a single population b. Comparison of means, unknown but equal variances (t test) c. F-test d. Chi-Square test e. Paired observations (Paired-t) f. Comparison of means, unknown and possibly unequal variances (t test) g. Z test on mean of a single population h. Comparison of means, known variance (t test) 12. [5pts] Same problem as Q#11. Write the H 0 and H 1 hypothesis for this problem H 0 : b = a , or b - a = 0 , or d 0 = 0 H 1 : b > a , or b - a > 0 , or d 0 > 0 13. [5pts] Given degrees of freedom v=21, write the Excel formula for finding Pr( T ≤ - 0.12 ). = t.dist(-0.12,21,true) 14. [5pts] 10 th percentile for t for a sample size of n=30? t 0.9,29 = -t 0.1,29 = -1.311 (from student-t table, or t.inv(0.1,29)) 9 =Pr(X<=3; n=9,p=0.4) From binomial table or using Binom.Dist(3,9,0.4,true), = 0.4826 You've changed the process, so two populations. Variance unknown, and since how the process is performed changed, you can't assume variances equal. Comparison of means, unknown and possibly unequal variances. Also accepted if you reversed before and after, as long as sign changed direction for H1
10
15. [5pts] Pr( 2 < 23.828) for n=21? Pr( 2 < 23.828) = 1 - Pr( 2 < 23.828) = 1 - For v=n-1=20, =0.25 (from Chi-Square table) = 1 – 0.25 = 0.75 You could also have used chisq.dist(23.828,20,true) 16. [10pts] A key dimension of a part has historically been produced with =1.24cm and =0.01cm (approximately normally distributed). A sample of 22 parts was taken this morning, with a S=0.018cm. It seems to you that something may have caused variability to increase. Perform the appropriate hypothesis test using a significance level of 0.05. State H 0 , H 1 , , your test statistic, the test p-value, and conclusion (both statistically and in practical terms). Variance, single population: chi-square statistic H 0 : = 0.01 H 1 : > 0.01 [one-sided] =0.05 Test statistic: 2 = (n-1)S 2 / 2 = 21*0.018^2 / 0.01^2 = 68.04 p-value: p=Pr( 2 >= 68.04) From table, goes right off the table for v=21, so less than 0.001 If use Excel chisq.dist.rt(68.04,21), = 9.2192E-07 (effectively 0) Since p < , reject H 0 The variability has increased 17. [10pts] For a sample of 15, ´ X = 221.8 and S=14.6. The underlying X's are normally distributed. Calculate and state the 90% CI on ´ X and indicate whether the mean has changed from the historical assumed mean of 214.0 or not. not given, use student-t distribution. ½ alpha in each tail (0.05) ´ X +/- t 0.05,14 *S/sqrt(n) 221.8 +/- 1.761*14.6/sqrt(15) 221.8 +/- 6.6384 or [215.1616, 228.4384] Since H 0 of =214.0 does not fall within this interval, reject H 0 The mean has changed 11
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
18. [10pts] You have two coordinate measurement machines (CMM), which are used to take quality control measurements of part dimensions. Due to measurement variability, you will get differences between the two machines, but you suspect there is an average difference between the two. You use the two machines to measure the same small dimension (in mm) on seven different parts; i.e., each part is measured by both machines (CMM1 and CMM2). Results for each of the parts is shown in the table below. Perform the appropriate hypothesis test using a significance level of 0.05. State H 0 , H 1 , , your test statistic, the test critical value, and conclusion (both statistically and in practical terms). Part CMM1 CMM2 1 7.30 7.01 0.29 2 6.29 6.19 0.1 3 7.19 6.82 0.37 4 6.94 6.79 0.15 5 7.72 8.17 -0.45 6 6.60 6.43 0.17 7 7.15 7.13 0.02 ´ X d : 0.0929 S d : 0.2661 Comparison of means: paired observation test. Calculate deltas, then sample mean and standard deviation of the deltas (see above) H 0 : 1 = 2 (d 0 = 0) H 1 : 1 <> 2 (d 0 <> 0)[two-sided] =0.05 Test statistic: t = ( 0.0929 - 0) / ( 0.2661 / sqrt(7)) = 0.9237 Critical values: t 0.025,7-1=6 = 2.447 (upper critical value) t 0.975,6 = -2.447 (lower critical value Since the test statistic falls between these two critical values, fail to reject H 0 There is insufficient evidence that CMM1 and CMM2 have different measurement means. 12