Finance Homework

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School

Laikipia University *

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J789

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Finance

Date

Nov 24, 2024

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docx

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3

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Chapter 9: Finance Homework NAME: Tra McNair Show all work for full credit. 1. You want to have $100,000 in your account when you retire in 30 years. Your retirement account earns 3% interest. How much do you need to deposit each month to meet your retirement goal? Round to the next highest dollar. From the given data we have Annuity=100,000 n=30 years n=30×12months n=360 moths Interest rate (i) is r=3%+ r=3100 r=0.03per Annam r=0.0312 Annuity =(p(1+r)n−11+r) Here p=periodic payment each month 100,000=(p(1+0.0312)/30−11+0.0312) 100,000=p(2.097−1)1.0025 100,000=p1.0971.0025100,000×1.0025=p1.097 100,250=p1.097 p=100,2501.097 =91,385.59 2. Find the simple interest when the principal is $1,500, the interest rate is 6.0%, and the
time is 5 years. Solution : Given that P=Rs.1,500 R=6.0%p.a Time=T=5years Find Simple interest ( S.I) SI=P×T×R/100 =1,500×5×6/100 =450 =RS.450 3. Jose wants to take out a $250,000 mortgage. The interest rate on the loan is 3% and the loan is for 15 years. How much will his monthly payments be? Given mortgage amount P= $250,000 interest rate i = 3% Number of monthly payments n= 15×12= 180 Now we have to find out the monthly payment=? Formula for amortization- Monthly payment A = {P* i * (1+i)^ n} / {(1+i)^n – 1)} So by using this formula , Monthly payment A= $1726.45 4. Joanne wants to take out a $350,000 mortgage. The interest rate on the loan is 6% and the loan is for 30 years. How much will her monthly payments be? To calculate Joanne's monthly mortgage payments, we can use the formula for an amortizing loan. The formula is: \[ M = P \times \frac{r(1 + r)^n}{(1 + r)^n - 1} \] Where: M = monthly payment P = principal amount (loan amount)
r = monthly interest rate (annual interest rate divided by 12) n = number of payments (loan term in months) First, we need to convert the annual interest rate to a monthly interest rate: \[ r = \frac{6\%}{100 \times 12} = 0.005 \] Next, we convert the loan term to months: \[ n = 30 \times 12 = 360 \] Now we can calculate the monthly payment: \[ M = 350,000 \times \frac{0.005(1 + 0.005)^{360}}{(1 + 0.005)^{360} - 1} \] By plugging these values into the formula, we find that Joanne's monthly mortgage payment will be approximately $2,098.69.
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