5.5 Lab Assignment_EET113_U5_Lab 11_ Series & Parallel Resonance

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Electric Circuits LAB EET113 Unit-5 Lab#11 Analyses of Series & Parallel Resonant Filters By: Trevor Davis Date: 01/20/2023 Online EET Department ECPI University I pledge to support the Honor System of ECPI. I will refrain from any form of academic dishonesty or deception, such as cheating or plagiarism. I am aware that as a member of the academic community it is my responsibility to turn in all suspected violators of the honor code. I understand that any failure on my part to support the Honor System will be turned over to a Judicial Review Board for determination. I will report to a Judicial Review Board hearing if summoned. Name ...................... Date xx/xx/20xx 1

Mandatory Lab Conduct Figures All of your lab reports will require a “screenshot” figure containing the MultiSim circuit, the computers system tray, and the file information window. Your instructor needs to see the “Time Stamp” on this screenshot to make sure your work is original. An example of the screenshot is illustrated below with the required items circled in red. This figure with the required components is captured by: 1) Displaying the file information window=>Select “File”, then “File Information.” 2) For Windows based computers, press the Print Screen key on your keyboard and then paste the figure into your Word document 3) For Mac computers using XenDesktop, press at the same time “Command”, “Shift”, and “3” in order to take a screenshot or press “Command”, “Shift”, and “4” in order to generate cross-hairs with your pointer that can be used to select the area that you want to copy. In either case, the screenshot/desired image will be automatically saved to your computer desktop (Not the XenDesktop). You will need to insert the screenshot/desired image into your Word document You are required to place your first MultiSim screenshot figure in the section labeled, “ Place your screenshot with “Time Stamp” Here”. 2

Series Resonant Band-Pass Filter Parallel Resonant Band-Stop Filter Abstract: By using a bode plotter on the resonance wave I was able to find the voltage out by measuring the bandwidth and the high cutoff and low cutoff frequencies. From there I could measure and calculate to verify if they were correct. Introduction : By using the provided multi SIM series circuit I could determine the center frequency and what the lower and upper cut offs were. Part-1 Series Resonant Band-Pass Filter Method and Procedure :  Review the solution on Page 700-701, Example 15-8 in your textbook.  Open the MultiSim software (On XenDesktop or on your laptop) and run the downloaded files E18-08.ms8.  Do the Related Problem. a) Calculate the BW (Bandwidth) for H = 1mH and Rw = 18 Ω b) Use Bode plotter to measure the center frequency (fo) and BW for Rw=10 Ω c) Use Bode plotter to measure the center frequency (fo) and BW for Rw=18 Ω Results and Figures : (Include your calculations, measurements, formulas & screenshots from Multisim if appropriate. Your instructor needs to see all your work.) Place your screenshot with “Time Stamp” Here. 3

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a) Calculate the BW (Bandwidth) for H = 1mH and Rw = 18 Ω. Follow the Example 15-8. Gain 1.441 UCF = 117.073kHz LCF = 98.344kHz Observed BW = 18.73 kHz Calculated BW = 18.78 kHz BW = 𝑅 𝑡𝑜𝑡𝑎𝑙 2 𝜋 𝐿 = 𝑅 𝑤 + 𝑅 2 𝜋 𝐿 = 100 + 18 2 𝜋 ⋅ 1 𝑚 = 18.78 𝑘𝐻𝑧 b) Use Bode plotter to measure the center frequency (fo) and BW for Rw=10 Ω. Place your screenshot here. Your instructor has completed this part for you. Please read all the steps very carefully. Connected the Bode plotter as shown. Move the marker until you get “0 dB” 4

for the gain. Since this a simulation and done at small steps, you may not get the exact “0 dB”, in this case, we have “ -0.897 dB” which is the closest to “0 dB”. This is shown in the right box under the plot. Now, in the left box, you see “106.7 KHz”, that is the center frequency. To find the BW of this plot, you need to go 3 dB above and 3 dB below the center frequency and obtain each frequency. Those are called lower cut-off and upper cut-off frequencies. BW = 115.022kHz - 100kHz Where fuc = Upper cut-off frequency (at -3dB below the center gain to the right) flc = Lower cut-off frequency (at -3dB below the center gain to the left) Figure below shows how to get the lower cut-off frequency. Since the center frequency was not exactly at 0 dB (It was at “ -0.897 dB”), -3dB from this value will be about - 3.897 dB. Try to get a very close value to this on the Bode plotter, by shifting the marker to the LEFT of the center frequency. Figure below, shows the closest value is “- 4.194 dB”. At this gain, the lower cut-off frequency is “98.247” 5

Figure below shows how to get the upper cut-off frequency. Since the center frequency was not exactly at 0 dB (It was at “ -0.897 dB”), -3dB from this value will be about - 3.897 dB. Try to get a very close value to this on the Bode plotter, by shifting the marker to the RIGHT of the center frequency. Figure below, shows the closest value is “-3.596 dB”. At this gain, the upper cut-off frequency is “115.88” Therefore, the BW = 115.88 - 98.24 = 17.6 kHz 6

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c) Use Bode plotter to measure the center frequency (fo) and BW for Rw=18 Ω Place your screenshot here. Fill in the following table: fo and BW Calculated Measured Rw = 10 Ω fo = 107 kHz BW = 17.5 kHz fo = 107.248 kHz BW =115.022 kHz Rw = 18 Ω fo = 107 kHz BW = 12 kHz fo = 107.248 kHz BW = 12.873 kHz Part-2 Parallel Resonant Band-Stop Filter. Method and Procedure  Review the solution on Page 705-706, Example 15-12 in your textbook. Verify the calculations. 7

 Open the MultiSim software (On XenDesktop or on your laptop) and run the downloaded file E18-12.ms8.  Do the Related Problem. a) Calculate the minimum Vout for R=1 KΩ b) Use Bode plotter to measure the minimum Vout for R=560 Ω c) Use Bode plotter to measure the minimum Vout for R=1 KΩ Results and Figures : (Include your calculations, measurements, formulas & screenshots from Multisim if appropriate. Your instructor needs to see all your work) a) Calculate the minimum Vout for R=1 KΩ Follow the Example 15-12 Minimum Vout = 𝑉𝑖𝑛⋅ 𝑅 𝑅 + 𝑍 𝑝 = 10 ⋅ 1000 1000 + 4170.66 < − 2.509 = 1.934 < 2.02 𝑉 b) Use Bode plotter to measure the minimum Vout for R=560 Ω Place your screenshot here. 8

Note : The Bode plotter will show Gain (Vout/Vin) versus frequency. When Vout is at minimum, the gain is at lowest (From Bode plotter is at -17.89 dB). But you can calculate the absolute minimum Vout: Voltage gain = 20 log (Vout / Vin) The minimum gain is observed -18.024 dB at 5.773 MHz. 𝑘 = 10 − 18.024 20 = 0.1255 Solution: Vout min= k*Vin= 0.1255*10= 1.255V c) Use Bode plotter to measure the minimum Vout for R=1 KΩ Place your screenshot here. 9

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Voltage gain = 20 log (Vout / Vin) The minimum gain is observed -13.779 dB at 5.773 MHz. 𝑘 = 10 − 11.773 20 = 0.2578 Solution: Vout min= k*Vin= 0.2578*10= 2.578V Fill in the following table: Min Vout Calculated Measured R = 560 Ω Min Vout = 1.18 V Min Vout = 1.255V R = 1 KΩ Min Vout = 2.02V Min Vout = 2.578V Conclusions: 10

(Student needs to write this). In your own words, write a short paragraph for conclusions. It should not exceed three or four sentences References: (You may use this list or any other list if appropriate) 1. Text book: Electric Circuits, Edited by Ron Smith, 2nd Edition, Pearson Custom Publishing 2. Multisim Software Version 14.0 3. Citations from the web (If you have used any). 4. Instructor’s note 2017. 11