wwallaceLab3
pdf
keyboard_arrow_up
School
University of Guelph *
*We aren’t endorsed by this school
Course
1010
Subject
Electrical Engineering
Date
Apr 3, 2024
Type
Pages
3
Uploaded by DeanMorningDeer50
Lab 3 –
Kirchhoff’s
Rule Experiment 1 Methods: The pictures to the left show the setup of the first experiment. The first image showing how the breadboard was setup in order to mimic the circuit given in the lab, with two 3.3V sources on direct opposite sides of the breadboard. There were two 2k
Ω
resistors to the left of the sources, and two 1k
Ω
resistors to the right of the sources. There was also a 4.7k
Ω
resistor in parallel between the two sources. The second image shows the two blue alligator clips plugged into the 3.3V ports as the sources, the two white clips plugged into the ground ports, and the red clip plugged into the A7 port to record readings. Results: The image to the left is the data collected while finding the voltage across all the resistors. It can be seen that the voltage decreases from around 2.7V to 0.26V. The image to the left is the calculations used to determine the theoretical and experimental values of the currents in the circuits loops. One can see that the theoretical value of the current through the 1000
Ω
resistors is 0.000266A, the theoretical value of the current through the 2000
Ω
resistors is 0.000266A, and finally the theoretical value of the current through the 4700
Ω
is 0.000532A. Below is the diagram of the circuit that the calculations were based off.
The below chart shows the potential difference values, current calculations for each resistor and the percent difference from the theoretical values of current. Potential difference Current Current Percent Difference (%) Resistor 1 0.264V 0.000264A 0.75 Resistor 2 2.508V 0.000534A 0.38 Resistor 3 0.528V 0.000264A 0.75 Resistor 4 0.264V 0.000264A 0.75 Resistor 5 0.528V 0.000264A 0.75 Conclusion: As seen in the results section of the lab the theoretical and experiment values of the current in the resistors are almost identical, with all of the percent differences being below 1%. These findings show just how accurate kichoffs rule can be when calculating these types of values. Experiment 2
Meathods: The images to the left show the experimental setup of the second experiment. In the first image one can see how the breadboard was setup to match the diagram. In the second image one can see how the blue alligator clip is plugged into the 3.3V port and the far right white alligator clip is plugged into the DAC port which has been set to deliver 2.2V. The red alligator clip is plugged into the A7 port and used to take readings in the circuit. The last white alligator clip is plugged into the ground port. Results:
The image to the left shows the different voltages through each resistor. This data was collected with the red alligator clip plugged into the A7 port. The difference in potential is around 3.3V to 0.718V.
The images to the left show the theoretical calculations for the current through the resistors in the second experiment. Using the theoretical calculations a system of linear equations was made. This SLE was made into a matrix using matlab and solved for the I values using matlab. The image below shows the RREF of the SLE matrix and the values of the currents in the system, with the top value being R1 then R2 then R3 and so on. Resistor Potetial Difference (V) Current (mA) Percent Difference (%) 1 2.547 0.5410 0.166 2 0.346 0.2161 22.3 3 0.935 0.8107 14.2 4 0.718 0.7571 5.30 5 1.065 0.5946 11.0 1.
The fundemental quantity that is being conserved in the loop rule is the Voltage, as the rule itself states that the voltage in a circuit sums to zero. The quantity being conserved in the junction rule is current, as the rule itself states that the current that enters the junction is the same as the current that leaves the junction. Conclusion: The experimental and theoretical values of the current through the resistors in this circiut were almost the same. Most of the percent differences within the lab are below or within 10% of 1%. This shows the accuracy of Kirchhoffs rule when calculating the values for current, voltage and resistance.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Related Questions
How would you find total Resistance. I found Ra of R7,Rload, and R8 to be 12kOhms. Rb of R6 and Ra as 4kOhms. Rc of R4,Rb, and R5 as 12k Ohms. Rd of R3 and Rc as 4kOhms
arrow_forward
I need to fill in a VIR chart for the combination circuit in the image below. The resistors amounts on in the mini chart next to it. I need to also reduce the original circuit to a single equivalent resistor. I've been working on it for a couple days and struggling.
arrow_forward
12
Which of the circuits in the figure will give you Vab = 7 V?
O b
none from the choices
O a
Oc
3 V
3V
SV
IV
SV
IV
(c)
a
3V
3 V
5V
IV
(b)
SV
IV
(d)
a
arrow_forward
Problem 5: A V = 86-V source is connected in series with an R = 1.8-kΩ resistor and an L = 28-H inductor and the current is allowed to reach maximum. At time t = 0 a switch is thrown that disconnects the voltage source, but leaves the resistor and the inductor connected in their own circuit. After the current decreases to 53 % of its maximum value, the battery is reconnected into the circuit by reversing the switch.
B) How much energy, in millijoules, is supplied in total by the battery, both in initially bringing the current to maximum and in bringing the current back to the 77 % level from 53 %? Ignore energy dissipated in the resistor during those processes.
arrow_forward
Employing the characteristic curve in Figure 1 and obtain the design for a voltage divider configuration that has a Q point of ICQ = 5 mA and VCEQ = 8 V. Using VCC = 24 V and RC = 3RE. Find the following:
a) Draw the configuration indicating each of the elements
b) Determine RC and RE
c) Find VE
d) Determine VB
e) Calculate ? for point Q f) Find R2 if R1 = 24 kΩ
arrow_forward
Question 1
For the circuit given below, find CT.
4.5 uF 4,5 uF 4,5 uF
3HF
1 HF 1HF
500 Vo
OA CT=1.2 uF
O B. C7= 1.5 F
O C. None of the given answers
O D. CT=0.2 uF
O E CT=0.5 µF
O F. C7=5 µF
arrow_forward
For given value of the circuit, Vsupply = 120 V, and with R₁= 202, R₂=30.0N, R3=75N, R4=30, R5=
2002, R6-400 and R7=12002?
• What is the total current?
0.23 A
2 A
1 A
1.2 A
V1
120 V
R1
2002
R3
75Q
R7
21200
R6
400
R2
2300
R4
2302
R5
$2002
arrow_forward
A RL series has two resistors and two inductors. The Z of the circuit is 1000 ohms. The XL of the inductors is 220 ohms and 470 ohms. one of the resistors has a resistance of 300 ohms. What is the resistance of the other resistor?
arrow_forward
8. Find the following:
a. the voltage across R5 (Vo)
b. the current through R5
11
1A
ES
10k
R1
27k
R4
18k
10k
Vo
R5
27k
R7
12k
R6
6.8k
arrow_forward
For the circuit shown in the figure select the best value forces voltage V
arrow_forward
Please answer both subpart I will like only for both subpart...
arrow_forward
For the following circuit, Vsrc=1.5 V and Rload=225 Q. What is Is?
Is
Vsrc
VR
Rload
arrow_forward
The images are attached with the question and circuit. Please include a drawing with the solution. Thank you
arrow_forward
Hello, I keep getting lost in the middle of this problem. I appreciate any help and advice. Thank you for your time.
The circuit has a 30mA current source in parallel with a 1kΩ and then is connected througha switch with a circuit that is made of a 9kΩ in series with a 10Ω in parallelwith an unspecified inductance L. The switch is closed for a long time for thecurrent source to supply power to charge up the inductor. You understand thata steady current is now through the inductor, since there is a maximum amountof energy to be stored in the inductor in this circuit.
Now the switch is opened. Let us call that time t = 0. After that time theinductor circuit is no longer connected to the current source. Its energy, asdetermined by its current, will be dissipated.
A). Find the value of inductance L such that the inductor current decays witha time constant of 1 ms. Recall that we define the time constant associatedwith a time function on an exponential decay associated with e^− t/τ whereτ…
arrow_forward
5- Find the unknown quantities for the
circuits of Figure below. *
|2 A
E
U6
P = 12 W
arrow_forward
B-5-8.Referring to the system shown in Figure 5-75, determine the values of K and K such that
the system has a damping ratio of 0.7 and an undamped natural frequency of 4 rad/sec.
Figure 5-75 Closed-loop system.
R(s)
K
S +2
k
S
C(s)
arrow_forward
SEE MORE QUESTIONS
Recommended textbooks for you
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning
Related Questions
- How would you find total Resistance. I found Ra of R7,Rload, and R8 to be 12kOhms. Rb of R6 and Ra as 4kOhms. Rc of R4,Rb, and R5 as 12k Ohms. Rd of R3 and Rc as 4kOhmsarrow_forwardI need to fill in a VIR chart for the combination circuit in the image below. The resistors amounts on in the mini chart next to it. I need to also reduce the original circuit to a single equivalent resistor. I've been working on it for a couple days and struggling.arrow_forward12 Which of the circuits in the figure will give you Vab = 7 V? O b none from the choices O a Oc 3 V 3V SV IV SV IV (c) a 3V 3 V 5V IV (b) SV IV (d) aarrow_forward
- Problem 5: A V = 86-V source is connected in series with an R = 1.8-kΩ resistor and an L = 28-H inductor and the current is allowed to reach maximum. At time t = 0 a switch is thrown that disconnects the voltage source, but leaves the resistor and the inductor connected in their own circuit. After the current decreases to 53 % of its maximum value, the battery is reconnected into the circuit by reversing the switch. B) How much energy, in millijoules, is supplied in total by the battery, both in initially bringing the current to maximum and in bringing the current back to the 77 % level from 53 %? Ignore energy dissipated in the resistor during those processes.arrow_forwardEmploying the characteristic curve in Figure 1 and obtain the design for a voltage divider configuration that has a Q point of ICQ = 5 mA and VCEQ = 8 V. Using VCC = 24 V and RC = 3RE. Find the following: a) Draw the configuration indicating each of the elements b) Determine RC and RE c) Find VE d) Determine VB e) Calculate ? for point Q f) Find R2 if R1 = 24 kΩarrow_forwardQuestion 1 For the circuit given below, find CT. 4.5 uF 4,5 uF 4,5 uF 3HF 1 HF 1HF 500 Vo OA CT=1.2 uF O B. C7= 1.5 F O C. None of the given answers O D. CT=0.2 uF O E CT=0.5 µF O F. C7=5 µFarrow_forward
- For given value of the circuit, Vsupply = 120 V, and with R₁= 202, R₂=30.0N, R3=75N, R4=30, R5= 2002, R6-400 and R7=12002? • What is the total current? 0.23 A 2 A 1 A 1.2 A V1 120 V R1 2002 R3 75Q R7 21200 R6 400 R2 2300 R4 2302 R5 $2002arrow_forwardA RL series has two resistors and two inductors. The Z of the circuit is 1000 ohms. The XL of the inductors is 220 ohms and 470 ohms. one of the resistors has a resistance of 300 ohms. What is the resistance of the other resistor?arrow_forward8. Find the following: a. the voltage across R5 (Vo) b. the current through R5 11 1A ES 10k R1 27k R4 18k 10k Vo R5 27k R7 12k R6 6.8karrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Delmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage Learning
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning