Semiconductors HW 5

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Feb 20, 2024

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Daniel Barbotko Semiconductors homework 5 Chapter 9 Part 1) Answer all Review Questions 1. What is the purpose of the n+ sinker in Figure IV.1? a. N+ sinker is used as a way to create a low resistance path from the upper surface to the buried layer in a device. 2. Equation (9.1) describes the prototype BJT under forward active bias. Why is it reasonable to neglect the recombination current in the emitter-base junction? a. Recombination current in the emitter-base junction can be neglected because it is extremely small in comparison to the current in the collector. 3. Explain why it is advantageous to make the base thin in a bipolar junction transistor. a. The fraction of carries that recombine in the base before the collector is reduced. Because of this, current gain increases and so does the efficiency of the transistor. 4. Explain the reasons for doping the emitter heavily compared with the base, and for doping the collector lightly. a. It enhances the injection of majority charge carriers (electrons or holes) into the base, improving transistor efficiency and speed. Doping the collector lightly reduces the intrinsic carrier concentration, widening the depletion region and allowing for a larger electric field, facilitating the efficient collection of charge carriers and increasing the transistor's gain. 5. Why should we reduce back-injection (from the base back into the emitter)? What can be done to control it? a. Reduce back-injection to prevent undesired leakage currents and maintain the integrity of the transistor's operation. To control back-injection, careful design of the doping profile, particularly in the base region, and optimizing the dimensions of the transistor help minimize the likelihood of minority carriers diffusing back into the emitter, ensuring proper transistor functionality. 6. Explain how band-gap narrowing in the degenerate emitter affects the current gain β. What is the physics behind this? a. Band-gap narrowing occurs due to a high concentration of carriers, reducing the effective energy gap. This narrowing lowers the effective bandgap in the emitter region, increasing the carrier concentration and, consequently, the current gain (β) in a bipolar junction transistor
Daniel Barbotko Semiconductors homework 5 7. From the SIMS plot of Figure 9.8, it is clear that the doping is graded in all three regions —the emitter, base, and collector. Why, then, is this device referred to as a graded-base transistor? a. Since it has a doping-engineered electric field in the base, it reduces the charge carrier base transit time. This is what makes it a graded-base transistor, which is a high speed BJT. 8. Explain in words how grading the base doping can increase the common-emitter current gain of a transistor. a. Grading the base doping of a transistor increases the injection efficiency of electrons from the emitter into the base, which in turn increases the common- emitter current gain of the transistor. This is because the rate of emitter electron current injection into the base is determined by the base-emitter voltage and the doping of the base, which is swept into the collector due to the potential drop from base to collector and the narrowness of the base region. 9. Explain why, in Figure 9.9, EC bends downward and EV bends upward toward the surface of the semiconductor. a. EC bends downward and EV bends upward due to the band-bending phenomenon. This occurs when there is a change in the electron affinity or the energy gap of the material used in the semiconductor. 10. Explain why an increasing V CE causes the collector current to increase, even in the active region. a. In the active region of a transistor, an increase in the collector-emitter voltage (V CE ) causes the depletion region between the base and collector to widen, which reduces the effective base width. This leads to an increase in the collector current. 11. Explain why in an HBT having the emitter band gap greater than that of the base increases β. a. In an HBT, the injection efficiency is optimized by using a material with a larger energy band gap for the emitter than that used for the base material. The large energy band-gap emitter blocks injection of holes from the base, which increases the common-emitter current gain (β) of the transistor. 12. Why is the base of a BJT doped more lightly than the emitter but in an HBT the base is more heavily doped?
Daniel Barbotko Semiconductors homework 5 a. In BJT’s, the base is doped more lightly than the emitter to ensure that the base region is narrow enough to allow for the majority of the injected electrons from the emitter to reach the collector. However, in an HBT, the base is more heavily doped than the emitter to reduce the base resistance and increase the current gain of the transistor. The high base doping makes the device less susceptible to punch through and the base can be made thinner resulting in a faster transistor. 13. What is the purpose of having the collector band gap of a DHBT greater than that of the base? a. This enhances carrier confinement, and reduces the base-collector depletion region width and increases the collector current density. It also reduces the recombination as well as improving the transistors efficiency and speed. By using this design it optimizes the performance by minimizing the loss of charge carriers in the device. Part 2) Solve problems 9.1, 9.5, 9.8
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Daniel Barbotko Semiconductors homework 5
Daniel Barbotko Semiconductors homework 5
Daniel Barbotko Semiconductors homework 5
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Daniel Barbotko Semiconductors homework 5