CPAN112_MidtermTest_Tyler_Escobar

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Humber College *

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112

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Feb 20, 2024

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Fundamentals of Numeric Computing CPAN 112 Midterm Test Please read the following instruction very carefully before answering any questions: Please read all the questions very carefully. Please provide your answers in the boxes below each question, and do not change the text colour. Your answer MUST show the solution procedure. There is no credit if you only state the final answer. Please highlight your final answer to each question. Please keep the naming conventions requested in this lab and each question. Once you complete your lab, rename your word document file to the ( CPAN112_MidtermTest_FirstName_LastName ). Replace FirstName and LastName with your first name and last name, respectively. It will be a 10% mark deduction if you do not follow the guidelines mentioned above.
1) Evaluate and round to one decimal place [5 points]: 9210(5 – 1.38 * 169/420) BEDMAS: Step 1: First DM, that being Multiplication 9210(5 – 233.22/420) Step 2: Second DM, that being Division = 9210(5 – 0.555285714) Step 3: AS, that being Subtracted = 9210(4.444714286) Step 4: Multiply Number outside bracket into bracket = 40935.81857 Step 5: Round to 1 Decimal Place = 40935.8 2) Ana, Aamir and Charlotte worked 11 3 4 , 14 13 20 , and 22 4 5 hours respectively. What was the total cost of labour if they were paid $18.00 per hour? [10 points] LCD = 20 (47/4) x 20, (293/20) x 20, (114/5) x 20 = 235 hours , 293 hours , 456 hours = Ana worked 235 hours, = Aamir worked 293 hours = Charlotee worked 456 hours = 18 per hour = 18x = 18(235) = 4,230 $ Ana made = 18(293) = 5,274 $ Aamir made = 18(456) = 8,208 $ Charlotte made 3) A smartphone was being sold for $660 while on sale. If the price dropped by 20% for the sale, what was the original price of the smartphone? [15 points] 660 = discounted price 20%/0.2 = rate of discount Net Price = List Price – Amount of Discount = N = L – A or N = L (1 – d)
= 660 = L (1 – 0.20) = 660 = L (0.80) = 660 / 0.80 = 825 Amount of Discount = 825 * (0.2) = 165 = 660 = 825 – 165 or 660 = 825 (1 – 0.20) The Original Price of the Smartphone was $825, and when it went on a 20% discount, it dropped to $660, having $165 less than the original 4) What is the price of gasoline per litre in Canadian dollars if a U.S. gallon of gasoline costs $2.90 U.S.? One U.S. dollar is worth $1.0372 Canadian, and one U.S. gallon is equivalent to 3.8 litres. [20 points] 1 U.S Gallon = 3.8 Litres U.S Gallon = 2.90 USD 3.8 Litres = 2.90 USD 1 USD = 1.0372 CAD 2.90 x 1.0372 = 3.00788 = 3.01 CAD A Gallon of Gasoline is 3.01 Canadian Dollars 3.8 Litres = 3.01 CAD 3.8/3.8 = 3.01/3.8 1 = 0.792105263 1 litre = 0.79 The price of Gasoline per litre would be 0.79 Canadian Cents per Litre 5) A theatre holds 400 seats. Two types of seats are available: orchestra and balcony. The cost of an orchestra seat is $60.00 and the cost of a balcony seat is $45.00. If all 400 seats are sold the theatre would collect $22 500.00. How many of each type of seat is available? [20 points] Two Types of Seats 60 dollars seats = 60x 45 dollars seats = 45y Amount of both seats sold = x + y =400 Amount earned from both seats = 60x + 45y = 22,500.00 Method: Elimination;
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(x + y = 400) x –45 = -45x – 45y = -18,000 = 60x + 45y = 22,500 = 15x = 4,500 = 15x/15 = 4,500/15 = x = 300 Substitute x into an equation = (300) + y =400 = y = 400 – 300 = y = 100 60(300) + 45(100) = 22,500 18,000 + 4,500 = 22,500 Orchestra Seats sold 300 seats and Balcony Seats sold 100 seats 6) Caroline needs to put some money in her pocket this winter, so she plans on removing snow from driveways. She will need to pay $560 for a snow-blower to make her job easier. A variable cost of $3 per job for supplies would also be required. She estimates that she could clean 40 driveways a month. What price should she charge the customers for the service in order to break even? [30 points] Fixed Cost = Snow Blower = $560 Variable Cost = Cost of Supplies = $3 Plans to do 40 driveways this season = X Selling Price is undecided = SP Break Even = TR = TC TR = FC + (VC*x) TR = 560 + 3x TR = SP * x TR = SPx SPx = 560 + 3x SP(40) = 560 + 3(40) SP(40) = 560 + 120 SP(40) = 680 SP = 680/40 SP = 17
For Caroline to Break Even this Winter, she would need to charge about 17 dollars per Driveway if see plan to shovel 40 driveways a month to break even on the revenue and costs TR = SPx = 17(40) = 680 TC = 560 + 3(40) = 680 TR = TC Deliverables : The word document file ( CPAN112_MidtermTest_FirstName_LastName ) contains your solution.