Lab 6 REPORT FORM_F22

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Lab 6: How Does Molecular Shape Affect Polarity? REPORT FORM Answer the following discussion questions. Support your claim using evidence, i.e., experimental data and/or observations that support the claim. Cite specific observations and/or results. Connect your evidence (data and/or observations) to your claim using reasoning that explains why your evidence supports your claim. Reasoning should be based on a scientific rule, law, principle or definition. Part 1B. Electron Groups and Molecular Geometries Question #1. VSEPR stands for “valence -shell electron- pair repulsion”. How does electron pair repulsion determine the molecular shape/molecule geometry? Use two specific examples (molecular shapes) from Data Table 2 (in the data form) to explain your answer. (Hint: In the simulation, is it possible to force the electron domains to be close together?) Electron pairs arrange themselves to minimize the repulsion between them meaning the more electron pairs there are then the smaller the bond angle is and the less electron pairs or bonds then the bigger the bond angle is. The electron pairs do this because they want to be as far apart as possible.
Question #2. Identify the molecular geometry and electron group rearrangement for each shape and record the number of lone pairs on each central atom. Explain your answer using the total number of electron groups around the central atom in a particular molecular geometry. Part 1C. Bond Angles Question #3. Which one of these assumptions about the space occupied by nonbonding (lone pair) electron pairs is most consistent with the experimental bond angles that you observed in the simulation? Do nonbonding pairs occupy more , less , or the same amount of space as bonding pairs? Explain using the structures of two examples from Data Table 3 (in the data form). Nonbonding pairs occupy more space than a bonding pair because its not shared by 2 nuclei and it takes up more space near the central atom. For example, NH 3 is trigonal pyramidal so the expected bond angle would be 109.5° but its actual angle is 107.8° which proves that the lone pair is taking up more space than the bonded pairs. Another example is H 2 O which is bent and the predicted angle is 109.5° but its actual angle is 104.5°. 1.) This molecule has 2 lone pairs and 4 bonded pairs totaling to 6 electron pairs which would make its molecular geometry octahedral, and the 2 lone pairs would make its electron geometry square planar. 2.) This molecule has no lone pairs and 4 bonded pairs totaling to 4 electron pairs which would make its molecular and electron geometry the same, being tetrahedral. 3.) This molecule has 1 lone pair and 4 bonded pairs totaling to 5 electron pairs which would make its molecular geometry trigonal bipyramidal and the 1 lone pair would make its electron geometry seesaw
Part 2A. Investigating Bond Polarity with the molecule AB Question #4. What is the relationship between the orientation of the dipole arrow and the partial charge on atoms A and B? Explain using words and/or diagrams/structures, or examples. Question #5. What is the relationship between magnitude of the dipole arrow and the difference in electronegativity between atoms A and B? Explain using words and/or diagrams/structures, or examples. The orientation of the dipole arrow point towards the more electronegative atom so the partial charge will be negative on that atom and vice versa. the bigger the electronegativity difference is the bigger the magnitude is.
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Question #6. How does changing the electronegativity of the atoms affect the bond polarity ? Explain using words and/or diagrams/structures, or examples. Question #7. How does changing the electronegativity of the atoms affect the bond character (more ionic or more covalent)? Explain using words and/or diagrams/structures, or examples. The bigger the electronegativity difference then the more polar the atom is. The bigger the electronegativity of the atoms is then the more ionic the atom is.
Part 2B. Molecules in Electric Fields Question #8. What happens to the molecule AB when it has a bond dipole and the electric field is turned on? What happens to the molecule if the bond dipole is zero? Is there a relationship between the bond dipole and how the molecule is affected by the electric field? If there is a relationship, explain it using your observations from the simulation. Part 2D. Putting it all together… Question #9. What is the difference between Molecular Shape/Molecule Geometry and Electron Group Arrangement/Electron Geometry? In other words, what information does each classification provide you about the structure of the molecule? Use examples if that helps with your explanation. It flipped the molecule, so the opposite charge is with the opposite charge of the electric field. If the bond dipole is zero, then it doesn t flip. Yes, the bigger the bond dipole then the faster the molecule flips and vice versa The amount of electron pairs determines the molecular shape while the number of bonded and lone pairs determines the molecular geometry. For example, a molecule can have a total of 3 electron pairs with all of them bonded and the electron geometry and molecular geometry would be trigonal planar. If that molecule only had 2 bonded electron pairs with one being a lone pair its electron geometry would still be trigonal planar because the total number of electron pairs stayed the same. The molecular geometry would be bent since there is one lone pair.
Question #10. List at least five characteristics of a molecule that can be determined from a Lewis Structure. You may wish to use an example Lewis Structure and list what information you can observe and deduce about the molecule from the Lewis Structure. Electron geometry, molecular geometry, number of electron in the molecule, formal charge, and bond angles.
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