7_KHPReport2023

101 Bb UTF-8"Lab%205-%20PI x Bb UTF-8"Lab%202-%20st Bb UTF-8"Lab%201-%20SCX I https://mssu.yellowdig x Question 4 of 34 If you have 155 mL solution of a 0.762M FeCl solution, how many moles of FeCl, are contained in this sample? mlsetuton ADD FACTOR DELETE ANSWER RESET *( ) 1 1000 162.2 10 35.45 6.60 55.85 0.01 12.6 0.203 100 0.118 0.1 0.001 155 4.92 0.762 19.2 11.8 118

Calculate final concentration

Pre-lab question 1: Standard solutions are made using the volumes and concentrations listed in the table below. Calculate the final concentration of SCN and FeSCN2+ in the solution. Report all calculations involving the NaSCN data to 3 significant figures. A B C D E F Volume 0.00200 M 0.25 mL 0.50 mL 0.75 mL 1.00 mL 1.25 mL 6.00 mL NaSCN added mL [Fe3+] 0.200M added Approximate [Fe3+] in solution Mol NaSCN added Mol SCN added [SCN] ion in standard solution [FeSCN²+] in standard solution Absorbance 0.043 0.087 0.125 0.173 0.211 1.050

1) Listen Calculate the new concentration of a NaOH solution when 75 mL of a 1.6 M NaOH is diluted to a final volume of 315 mL. 0.38 M 6.7 M 150 M 0.98 M Type here to search 1205 PM 3//2021 hp rt se delete ome 5. backspace Q home enter pause B M * shift end alt alt ctri ins

Quantity Your Data 1.   Grams of vinegar sample used for your titration 25.000 g 2. Initial Buret Reading of Sodium Hydroxide solution 10.00 mL 3. Final Buret Reading of Sodium Hydroxide solution 28.00 mL 4. Amount of Sodium Hydroxide Solution used to neutralize the vinegar sample   5. Concentration of NaOH in the NaOH solution 0.050 g/mL 6. Grams of NaOH used to neutralize the vinegar   7. Grams of acetic neutralized by the amount of NaOH   8. Percent acetic acid in the vinegar   Hints:     For #4, The amount of NaOH used is the difference between the starting buret value and the ending buret value.   For #6, Once you calculate the amount of sodium hydroxide used, multiple that value by the concentration of NaOH in the NaOH solution.   For #7, Multiply the value obtained in number 6 by the number 1.5.  Remember, we learned that every 1 gram of NaOH neutralizes 1.5 grams of acetic acid.   For #8, Divide the grams of acetic acid by the grams of vinegar sample and multiply this value by…

How many grams of hy

Now that you know the moles of NaOH used for each trial as well as the volume of NaOH used for each trial, calculate the concentration of the NaOH that you made in lab for each trial.  Round to the ten-thousandths place please.

-7 An aqueous solution at 25 °C has a H,O' concentration of 3. × 10 'M. Calculate the OH concentration. Be sure your answer has 1 significant digits. x10 Continue Submit Assignr 2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessi MacBook Air esc DII DD F1 F2 F3 F4 F5 F6 F7 F10 F11 F8 F9

Please answer 7,8,9

Concentration of the KSCN stock solution, M Volume of the KSCN stock solution, mL Initial molar concentration of SCN in a 50-ml flask, M PART A. Establishing the Beer's Law Coefficient: blank 0 0 solution 2 1.00×10-³ 2.00 solution 3 1.00×10-3 5.00 solution 4 1.00×10-³ 10.00 solution 5 1.00-10-3 15.00

This Quiz VWill Be izzes > Cell & Molecular Biology competency exam ell & Molecular Biology competency exam arted: Feb 13 at 7:38pm Quiz Instructions Question 4 How many grams of NaOH is in 1.7 L of 1.4 Molar solution? « Previous No new data to save. Last checked at 8:08pr

1.10 M Acetic acid 0.900 M Sodium acetate [H30*1 (M) Solution (mL) |(mL) 1 8.00 2.00 8.71e-5M 2 7.00 3.00 5.13e-5M 6.00 4.00 3.24e-5M 4 5.00 5.00 2.17e-5 5 4.00 6.00 1.45e-5M 6. 3.00 7.00 9.31e-6M 7 2.00 8.00 1.00 9.00 00

31 and 32 please

Online teaching and learning resource f Car note CAU EMAIL CANVAS Pirate Ship MYJSCC BLACKBOARD Vacancies | A...| Birmingham New [Review Topics] [References] Use the References to access important values if needed for this questi The mass of lead sulfate that is dissolved in 175 mL of a saturated solution is grams. Submit Answer Retry Entire Group 5 more group attempts remaining tv 30 888 DD F9 F10 F11 F4 F5 F6 F7 F8 $ & ( 5 6 7 * 00

Table 2. Titration data   Trial 1 Trial 2 Trial 3 Initial burette reading (mL) 1.19   2.26   2.39   Molarity of NaOH (M) 0.100   0.100   0.100   Volume of vinegar sample (mL) 5.00   5.00   5.00   Final burette reading (mL) 48.55   49.43   49.99   Expected color at end point             Volume of NaOH used (mL)           Average Volume of NaOH used in liters   Average moles of NaOH used (mol)   Average moles of acetic acid (mol)   Average molarity of acetic acid (M)     Average mass of acetic acid (g)   Average mass of vinegar (g) (assume the density of vinegar is 1.00 g/mL)   Average mass % of acetic acid in vinegar   Known mass % of acetic acid in vinegar is 5.45%   Percent Error

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ASSIGNMENT 1 Problem solving: Kindly show complete solution and round off final in nearest 2 decimal point 1. If a 0.380 g sample of sodium bicarbonate (94.5%) is titrated with 0.8900 N sulfuric acid, what volume of the acid is required to produce an end point? mEq wt. of sodium bicarbonate is 0.08 g. 2. A sample of Drug A weighing 0.2400 g was assayed by nonaqueous titrimetry using 27.8 mL of an acid with normality of 0.1125. Each mL of 0.1 N acid used is equivalent to 10.71 mg of Drug A>titer value. Determine the % purity of the sample.

Determination of unknown acid concentration     Trial 1 Trial 2 Trial 3 Unknown Acid number Volume of acid used (mL) 25 mL 25 mL 25 mL Initial buret reading (mL) 50 mL 50 mL 50 mL Final buret reading (mL) 14.8 mL 15 mL 14.5 mL Volume of NaOH used (mL) 50 mL 50 mL 50 mL Molarity of NaOH       Calculated molarity of HCl (M)               Show a sample calculation of HCl molarity   AVERAGE MOLARITY OF Unknown HCl Show a sample calculation of NaOH molarity

Please answer the last questions. Question 1 and 2

Number 2: find the absolute and percent error

AaBbCcDdEe AaBbCcDc AaBbCcDdE AaBbCcDdF AaBb A v 三v Emphasis Heading 1 Normal Strong Sub PRE-LAB QUESTIONS 1. Calculate the molarity of a 6.15% (w/v%) sodium hypochlorite (NaOCI) solution. 2. Calculate the molarity of a solution of Erythrocin B (MW 879.9 g/mol) if a 0.5028-g sample is diluted to 100 mL in a volumetric flask and then two serial dilutions are carried out in which 5-mL aliquots are diluted to 100 mL using volumetric equipment. 3. Based on the table, what is the order of reaction for Red Dye #3 and bleach if the following graph gives a straight line: Order of m Straight Line Plot [Red Dye #3] vs time In[Red Dye #3] vs time 1/[Red Dye #3] vs time 1 ates) E Focus 目 MacBook Air

7:21 1 4 7 +/- Question 8 of 13 A 20.0 mL solution of NaOH is neutralized with 22.8 mL of 0.200 M HBr. What is the concentration of the original NaOH solution? 2 5 8 M 3 60 9 O Submit Tap here or pull up for additional resources XU x 100

Sodium Chloride - 10.00 g  Trisodium phosphate - 11.00 g    both dissolve in final Vol of 4.00 grams    Find total concentration of NA+  make sure answer in M

What is the molarity of an aqueous solution that contains 0.0720 g CaH.O2 per gram of solution . The density of the solution is 1.04 g/mL STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 62.08 0.001 1.21 x 10-3 6.022 x 1023 1.04 1.12 1 1.21 4650 0.0720 1000 g solution/mL g C2HO2 g solution mol C2H6O2 g C:H6O2/g solution g C2H6O2/mol L solution M C2H&O2 mL solution

0.02 M NaOH reagent was standardized using 0.1000 g Potassium hydrogen phthalate (204.22 g/mol) and it required 25.8 mL to reach end point. Answer must be in 4 decimal places.

Pls help ASAP. Pls show all work and calculations.