CHM 101L M4 Fundamentals of Calorimetry Lab Report

docx

School

Southern New Hampshire University *

*We aren’t endorsed by this school

Course

101L

Subject

Chemistry

Date

Feb 20, 2024

Type

docx

Pages

6

Uploaded by CountWorld12585

Report
The Fundamentals of Calorimetry Sara Rigby 02/04/2024
1 Data Activity 1 Data Table 1 © 2016 Carolina Biological Supply Company *Note that the Average Heat Capacity (C) calculated above is used in Activities 2 and 3. Time (min) Trial 1 Temp. °C Trial 2 Temp. °C 1 45 45 2 40 44 3 40 43 4 40 42 5 40 42 6 38 41 7 38 40 8 37 40 9 37 40 10 36 39 Trial 1 Trial 2 Initial temperature of cold water, T c 15 15 Initial temperature of warm water, T h 82 80 Average temperature, T a 48.5 47.5 Temperature at time 0 from graph, T 0 43.267 45.067 Heat lost by water in J to calorimeter (Δq) -8103J -7308J Heat capacity (C) of calorimeter in J/°C 77 J/ O C 34J/ O C Average Heat capacity (C) of calorimeter in J/°C 55.5 J/ O C
2 1. Create a spreadsheet and graph of the data from Data Table 1, plotting temperature vs. time, and use the Y intercept to find the temperature at time 0 when the two volumes of water are mixed. a. Insert graph below. 0 2 4 6 8 10 12 0 10 20 30 40 50 f(x) = − 0.63 x + 45.07 f(x) = − 0.76 x + 43.27 Activity 1 Chart Water Temperature vs Time Trial 1 Temp(°C) Linear (Trial 1 Temp(°C)) Trial 2 Temp. (°C) Linear (Trial 2 Temp. (°C)) Time (min) Temperature (Celsius) Activities 2 and 3 Data Table 2 5g CaCl 2 10g CaCl 2 15g CaCl 2 5g NH 4 Cl 10g NH 4 Cl 15g NH 4 Cl Mass of water (g) 100g 100g 100g 100g 100g 100g Mass of salt (g) 5g 10g 15g 5g 10g 15g Moles of salt (g x mol/g) 0.045m 0.090m 0.135m 0.093m 0.187m 0.280m Initial Temperature (°C) T i 17 °C 17 °C 17 °C 17 °C 17 °C 17 °C Final Temperature (°C) T f 23 °C 30 °C 36 °C 13 °C 9 °C 6 °C Change in Temperature (°C) ∆T = T f - T i 6 °C 13 °C 19 °C -4 °C -8 °C -11 °C Heat absorbed by the solution (J) q w = -[c w x m w x -2636J -5983J -9142J 1757J 3681J 5293J © 2016 Carolina Biological Supply Company
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
3 ∆T] Heat Capacity of the Calorimeter (J/°C) 55.5 J/ O C 55.5 J/ O C 55.5 J/ O C 55.5 J/ O C 55.5 J/ O C 55.5 J/ O C Heat absorbed by the calorimeter (J) q c = -[C x ∆T] 333J 721.5J 1054.5J -222J -444J -610.5J Enthalpy of solution (J) ∆H = q w + q c -2303J -5261.5J -8087.5J 1535J 3237J 4682.5J Enthalpy of solution (kJ) *Note: 1 kJ = 1000 J - 2.303kJ - 5.2615kJ - 8.0875kJ 1.535kJ 3.237kJ 4.6825kJ Enthalpy/mole of solution (kJ/mol) ∆H/moles of salt -51 kJ/mol -58 kJ/mol -60 kJ/mol 17 kJ/mol 17 kJ/mol 17 kJ/mol 2. Create a spreadsheet and graph for CaCl 2 and NH 4 Cl, using the data from Data Table 2. Plot mass on the X axis and change in temperature on the Y axis for both graphs. The slope will be the change in temperature per gram of salt dissolved. a. Insert graphs below. 4 6 8 10 12 14 16 0 2 4 6 8 10 12 14 16 18 20 f(x) = 1.27 x CaCl2 Data Table Mass(g) Change in Temperature (Celcius) © 2016 Carolina Biological Supply Company
4 4 6 8 10 12 14 16 -12 -10 -8 -6 -4 -2 0 f(x) = − 0.76 x NH4Cl Data Table Mass (g) Change in Temperature (Celcius) 3. What sort of relationship exists between the temperature change and the mass of the solid? Explain why that relationship exists. With CaCl 2 as the mass of the solid increases the temperature increases as well. This occurs because as you add more of the solid into to water there is more of a reaction creating more heat. With the NH 4 Cl compound the opposite occurs, as the mass of the solid increases the temperature decreases. This occurs because the compound does not create heat but absorbs it and as you at more NH 4 Cl the more heat that gets absorbed. 4. How do the calculated molar heats of solution for calcium chloride compare to one another? How do the calculated molar heats of solution for ammonium chloride compare to one another? The molar heats of the calcium chloride solution vary, but are located within 10 degrees of each other. The molar heat is not as steady as the calculated molar heats of ammonium chloride, which are all the same. 5. The actual molar enthalpy of solution for calcium chloride is -81.3 kJ/mol, whereas the molar enthalpy of solution of ammonium chloride is 14.8 kJ/mol. Calculate the average molar enthalpy of solution for each chemical based on your data, and then calculate the percentage error for each. Percent error is (|Actual – Experimental|/Actual) * 100% CaCl 2 – (-51 + -58 + -60)/3 = -56.3 (|-81.3 - - 56.3| / 3) * 100% = 8.3% Percentage Error of NH 4 Cl = (17 + 17 + 17)/3 = 17 (|14.8-17| /3)*100% = 7.3% Activity 4 © 2016 Carolina Biological Supply Company
5 6. Based on the data and graphs for calcium chloride and ammonium chloride, determine which compound to use and what quantity of each compound will be needed to make a chemical hot pack and cold pack. Both packs should be calculated based on using 100 g (100 mL) of water. The hot pack should reach 60 °C, and the cold pack should go down to 3.0 °C from a room temperature of 25 °C. Hot Pack: Compound needed to achieve 60 °C above room temperature: You would need 24.83g of CaCl 2 Cold Pack: Compound needed to achieve 3.0 °C: You would need 35.132g of NH 4 Cl 7. What were some potential sources of error in this investigation? Some potential sources of error could be the air temp outside of the cup. Also, I am not sure that I was able to fully dump the material into the water because I noticed that there was a small amount left behind on the tray. 8. Suggest some ways in which the calorimeter or lab protocol could be improved to have lower percentage of errors. If possible I would seal the calorimeter to prevent heat from escaping. You could also weight the tray before and after dumping it into the water to see how much residue is leftover, if any. I might also take a reading of the outside air temp if unable to seal the calorimeter. © 2016 Carolina Biological Supply Company
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help