Grignard worksheet-1 (1)

This is my data. Could you help me to find the theoretical yield of acetylsalicylic acid in moles and grams. Also Theoretical yield of dry product as well?

Scientifically, nitrogen and hydrogen at high temperature are converted to ammonia. When 350 grams of Hydrogen gas are added to an excess amount of Nitrogen gas, 80 grams of Ammonia are formed. Calculate the percent yield. * (10 Points) 3H2+ N2> 2NH3

Black Forest Biologicals, a biotech startup, has a promising Alzheimer's drug candidate Compound SLT-88 entering Phase I trials this year. SLT-88 is the only product formed by the reaction of two precursor compounds A and B, both of which are quite expensive. The chief medicinal chemist of Black Forest is trying out different reaction conditions to minimize the cost of manufacturing SLT-88. actual amount of SLT-88 recovered in each case. Complete the table by calculating the theoretical yield of SLT-88 and the percent yield of SLT-88. Round your amounts to the nearest milligram and your percentages to the nearest whole percent. In the table below are listed the initial and final amounts of A and B used under two different trial conditions, and also the amount of B yield of SLT-88 amount of A Trial % final theoretical actual initial final initial 0 mg 400. mg 220. mg 876. mg 1 850. mg 1000. mg 0 mg 660. mg 537. mg 2 250. mg

3. Using this data, calculate a value for Kc for the reaction, A. 2.06 x 104 B. 4.84 x 10-3 C. 0.223 D. 4.49 E. 20.2 2 NO(g) + Cl₂(g) 2. NOCI(g) Kc = 3.20 x 10-³ 2 NO2(g) 2 NO(g) + O₂(g) Kc = 15.5 4. Using the data, NOCI(g) + 1/2O2(g) NO2(g) + ½ Cl₂(g) 3 A (g) + 4 B (g) A3B4 (g) calculate a value for Kc for the reaction, 3 A (g) + 4 B -A3B4 (g) 2 AB (g) + AB2 (g) (g) Kc = 25 Kc = 3.75 2 AB (g) + AB2 (g)

3,25

If Kc = 1.52 for O 2 (g) + 2 CO (g) 2 CO 2 (g), what is the value of Ke for the reaction 4 CO2 (g) = 2 02 (g) + 4 CO (g) (with 3 significant figures)? a. 0.433 b.0.329 с. 1.32 d. 1.52 е. 3.04

Which of the following statements is correct concerning the formula of a hydrate experiment? All hydrated salts can be converted into anhydrous salts by heating O Heating the hydrated salt too strongly at the beginning, will lead to a decrease in the calculated value of "x". 20 If the dehydration of the hydrate is incomplete, the calculated value of x" will be lower than the actual value. If the mass of hydrated salt and H20 are 0.59 g and 0.24 g, respectively, then the mass % of water of crystallization is 29 %. O If1.1g of alum is recorded instead of 1.0 g, the calculated value of "x" will be lower than the actual value.

Use the following atomic weights and quantities to calculate the overall % yield of benzopinacol. Remember that your yield must be based on the stoichiometry (balance the equation!), the limiting reagent, and that grams must be converted to moles. Filling out most of the chart will help. Give only two significant digits in your answer. If after rounding the answer is a whole number, do not include a decimal point. C = 12, H = 1, O = 16 benzophenone isopropanol acetic acid →>> benzopinacol formula formula weight milliliters 2.093 0.889 density 0.786 1.05 grams moles 38.103 4.214 Answer: % yield ?

Use the following atomic weights and quantities to calculate the overall % yield of benzopinacol. Remember that your yield must be based on the stoichiometry (balance the equation!), the limiting reagent, and that grams must be converted to moles. Filling out most of the chart will help. Give only two significant digits in your answer. If after rounding the answer is a whole number, do not include a decimal point. C = 12, H = 1, O = 16 benzophenone isopropanol acetic acid → benzopinacol formula formula weight milliliters density 2.093 0.786 0.889 1.05 grams moles 38.103 4.214 Answer: % yield ? The conversion of benzopinacol to benzopinacolone is called a rearrangement because it does not fit the simple patterns of organic chemistry: substitution, addition and elimination. With that said, select all that apply to this reaction: Ph- OH OH Ph Ph Ph= phenyl -Ph 12 CH3CO₂H Ph Ph Ph Ph Careful to not select incorrect answers or you may receive a negative score! ☐ ☐ a. net increase in pi…

BACKGROUND KNOWLEDGE: The reaction performed is the precipitation of calcium hydroxide from solutions of calcium chloride and potassium hydroxide. The percentage yield of calcium hydroxide is 98.97% QUESTION: Comment on your calculated percentage yield and the main sources of error in this experiment.

A certain mixture of gasoline obtained from a petroleum refinery plant was found to contain only isooctane (C8H18; FM=114.22), methyl tert-butyl ether (C5H12O); FM=88.15), and tetraethyl lead (C8H20Pb; FM=323.4), a gasoline preservative. Upon complete combustion of 0.4582 g sample, it was found out that the mass of the CO2 (FM = 44.01) absorbent increases by 1.0702 g, while the mass of residue PbO (FM = 223.2) was determined to be 0.0964 g. From this data, calculate the following: a. % (w/w) C8H18b. % (w/w) C5H12Oc. % (w/w) C8H20Pb

Please calculate theoretical yield in grams and percent yield.

This is for my review please help!!!!

5. The reaction of gaseous potassium superoxide, KO, is used in life-support systems to replace CO:(g) in expired air with O:(g). The unbalanoced chemical equation for the reaction is given below. KO:(s) + CO:(g) – K:CO:(s) + O:(g) How many moles of K:CO:(s) are produced per milligram of KO2(s) consumed?

= 14 15 16 17 18 19 20 21 22 23 24 25 26 Nitric oxide (NO) can be formed from nitrogen, hydrogen and oxygen in two steps. In the first step, nitrogen and hydrogen react to form ammonia: N2(9) + 3 H2(9) 2 NH3(g) AH=-92. kJ dlo In the second step, ammonia and oxygen react to form nitric oxide and water: 4 NH3(g) + 50,(9) → 4NO(g) + 6H,0(g) AH=-905. kJ Calculate the net change in enthalpy for the formation of one mole of nitric oxide from nitrogen, hydrogen and oxygen from these reactions. Round your answer to the nearest kJ. ?

Can you make sure the numbers are correctly labeled

These are the percent conpositions of the limiting reactant for three trials. Calculate the coefficient variable for this data set.  Trial 1: 22.78%Trial 2: 24.14% Trial 3: 24.43%

12-13

Q3.When the Organic Chemistry students carried out the experiment, they weighed out 5.037 g of p-aminophenol and mixed it with excess acetic anhydride. (Show ALL steps and mathematical equations involved in your calculations) Calculate the moles of p-aminophenol (Provide all answers to 4 decimal places)   Calculate the theoretical yield of Acetaminophen (Paracetamol) in moles (Provide all answers to 4 decimal places)    Calculate the theoretical yield of Acetaminophen (Paracetamol) in grams  (Provide all answers to 3 decimal places)

[References] Use the References to access important values if needed for this question. According to the following reaction, how many moles of mercury will be formed upon the complete reaction of 25.4 grams of mercury(II) oxide? 2HgO (s) 2Hg (1) + O2 (g) moles mercury An error has been detected in your answer. Check for typos, miscalculations etc. before submitting your answer. Submit Answer Retry Entire Group 9 more group attempts remaining Previous Next Save a

The experimenter uses 3.25 mL of cyclohexanol (d=0.962 g/mL) and isolates 2.05 g of a clear liquid. Determine the yield for the reaction. (Integer only). the answer is NOT 65 or 66 or 67

please answer in the format seen above! ty:)

Request They Both Die at t... ula Enchanted Wa... Question 6 of 20 Balance the following chemical equation (if necessary): Sio,(s) + C(s) → Si(s) + CO(g) 04- 2. 3+ O4+ 1 6. 7 8. 9. Os 6. O9 (s) (1) (g) (aq) C Si Reset • x HO Delete MacBook Air 000 F3 F4 F5 @ %23 2$ % 2 3 5 6. 8 9. W E 5 4- 3. 2. 14

4. In the background reading, it was pointed out that heroin can be produced from morphine in a manner similar to synthesis performed in this experiment. The balanced equation for the synthesis of heroin is given below. How many grams of heroin can be produced by the reaction of 20.00 grams of morphine and 10.00 ml of acetic anhydride? 2 C4H6O3 Acetic Anhydride C17H19NO3 C21H23NO5 2 HC2H3O2 Morphine Heroin Acetic Acid

Given the balanced reaction, initial GRAMS of each reactant and product, and the molar masses of each species complete the remainder of the change and final rows, in GRAMS. NOTE: Report all masses with ONE DECIMAL PLACE and be sure to include + and - signs with numerical values with NO SPACES. 2 C2H6 (g) + 7 O2 (g) ----> 4 CO2 (g) + 6 H2O (g)   C2H6 (MM = 30.07 g/mol) O2 (MM = 32.00 g/mol) CO2 (MM = 44.01 g/mol) H2O (MM = 18.02 g/mol) Initial Grams 10.0 10.0 0.0 0.0 Change Grams         Final Grams

In terms of % yield = (actual / theorietical ) X 100, explain what is meant by “theorietical”.