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UNIT
3
CONTENTS
CHAPTER
5
Energy
and
Change
CHAPTER
6
Rates
of
Chemical
Reactions
UNIT
3
PROJECT
Developing
a
Bulletin
About
Catalysts
and
Enzymes
e
——rra—
UNIT
3
OVERALL
EXPECTATIONS
m
What
energy
transformations
and
mechanisms
are
involved
in
chemical
change?
m
What
skills
are
involved
in
determining
energy
changes
for
physical
and
chemical
processes
and
rates
of
reaction?
m
How
do
chemical
technologies
and
processes
depend
on
the
energetics
of
chemical
reactions?
Look
ahead
to
the
project
at
the
end
of
Unit
3.
Start
preparing
for
the
project
now
by
listing
what
you
already
know
about
catalysts
and
enzymes.
Think
about
how
catalysts
and
enzymes
affect
chemical
reactions.
As
you
work
through
the
unit,
plan
how
you
will
investigate
and
present
a
bulletin
about
the
uses
of
catalysts
and
enzymes
in
Canadian
industries.
In
the
nineteenth
century,
railway
tunnels
were
blasted
through
the
Rocky
Mountains
to
connect
British
Columbia
with
the
rest
of
Canada.
Workers
used
nitroglycerin
to
blast
through
the
rock.
This
compound
is
so
unstable,
however,
that
accidents
were
frequent
and
many
workers
died.
Alfred
B.
Nobel found
a
way
to
stabilize
nitroglycerin,
and
make
it
safer
to
use,
when
he
invented
dynamite.
What
makes
nitroglycerin
such
a
dangerous
substance?
First,
nitro-
glycerin,
C3H5(NQO3)3(,
gives
off
a
large
amount
of
energy
when
it
decomposes.
In
fact,
about
1500
k]
of
energy
is
released
for
every
mole
of
nitroglycerin
that
reacts.
Second,
the
decomposition
of
nitroglycerin
occurs
very
quickly—in
a
fraction
of
a
second.
This
fast,
exothermic
reaction
is
accompanied
by
a
tremendous
shock
wave,
which
is
caused
by
the
expansion
of
the
gaseous
products.
Finally,
nitroglycerin
is
highly
shock-
sensitive.
Simply
shaking
or
jarring
it
can
cause
it
to
react.
Thus,
nitroglycerin’s
explosive
properties
are
caused
by
three
fac-
tors:
the
energy
that
is
given
off
by
its
decomposition,
the
rate
at
which
the
reaction
occurs,
and
the
small
amount
of
energy
that
is
needed
to
initiate
the
reaction.
In
this
unit,
you
will
learn
about
the
energy
and
rates
of
various
chemical
reactions.
Energy
Changes
and
Rates
of
Reaction
.
-
SRSy
Y
g.‘
-
Chapter
Preview
5.1
The
Energy
of
Physical,
Chemical,
and
Nuclear
Changes
5.2
Determining
Enthalpy
of
Reaction
by
Experiment
5.3
Hess's
Law
of
Heat
Summation
5.4
Energy
Sources
Prerequisite
Concepts
and
Skills
Before
you
begin
this
chapter,
review
the
following
concepts
and
skills:
m
writing
balanced
chemical
equations
(Concepts
and
Skills
Review)
m
performing
stoichiometric
calculations
(Concepts
and
Skills
Review)
Energy
and
Change
Think
about
a
prehistoric
family
group
building
a
fire.
It
may
seem
as
though
this
fire
does
not
have
much
in
common
with
a
nuclear
power
plant.
Both
the
fire
and
the
nuclear
power
plant,
however,
are
technolo-
gies
that
harness
energy-producing
processes.
As
you
learned
in
Unit
2,
humans
continually
devise
new
techno-
logies
that
use
chemical
reactions
to
produce
materials
with
useful
properties.
Since
the
invention
of
fire,
humans
have
also
worked
to
devise
technologies
that
harness
energy.
These
technologies
depend
on
the
fact
that
every
chemical,
physical,
and
nuclear
process
is
accompanied
by
a
characteristic
energy
change.
Consider
the
melting
of
an
ice
cube
to
cool
a
drink,
the
combustion
of
natural
gas
to
cook
a
meal,
and
the
large-scale
production
of
electricity
via
a
nuclear
power
plant.
All
societies
depend
on
the
energy
changes
that
are
associated
with
these
physical,
chemical,
and
nuclear
processes.
In
this
chapter,
you
will
study
the
causes and
magnitude
of
the
energy
changes
that
accompany
physical
changes,
chemical
reactions,
and
nuclear
reactions.
You
will
see
that
different
processes
involve
vastly
different
amounts
of
energy.
You
will
learn
how
to
calculate
the
amount
of
energy
that
is
absorbed
or
released
by
many
simple
physical
changes
and
chemical
reactions.
This
will
allow
you
to
predict
energy
changes
without
having
to
carry
out
the
reaction—an
important
skill
to
have
when
dealing
with
dangerous
reactions.
Finally,
you
will
examine
the
efficiency
and
environmental
impact
of
traditional
and
alternative
energy
sources.
Enough
radiant
energy
reaches
Earth
every
day
to
meet
the
world’s
energy
needs
many
times
over.
Since
this
is
~the
case,
why
do
fossil
fuels
provide
most
of
Canada’s
energy,
while
solar
power
supplies
only
a
tiny
fraction?
"
220
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
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The
Energy
of
Physical,
Chemical,
and
Nuclear
Processes
Most
physical
changes,
chemical
reactions,
and
nuclear
reactions
are
accompanied
by
changes
in
energy.
These
energy
changes
are
crucial
to
life
on
Earth.
For
example, chemical
reactions
in
your
body
generate
the
heat
that
helps
to
regulate
your
body
temperature.
Physical
changes,
such
as
evaporation,
help
to
keep
your
body
cool.
On
a
much
larger
scale,
there
would
be
no
life
on
Earth
without
the
energy
from
the
nuclear
reactions
that
take
place
in
the
Sun.
The
study
of
energy
and
energy
transfer
is
known
as
thermodynamics.
Chemists
are
interested
in
the
branch
of
thermodynamics
known
as
thermochemistry:
the
study
of
energy
involved
in
chemical
reactions.
In
order
to
discuss
energy
and
its
interconversions,
thermochemists
have
agreed
on
a
number
of
terms and
definitions.
You
will
learn
about
these
terms and
definitions
over
the
next
few
pages.
Then
you
will
examine
the
energy
changes
that
accompany
chemical
reactions,
physical
changes,
and
nuclear
reactions.
Studying
Energy
Changes
The
law
of
conservation
of
energy
states
that
the
total
energy
of
the
universe
is
constant.
In
other
words,
energy
can
be
neither
destroyed
nor
created.
This
idea
can
be
expressed
by
the
following
equation:
AEuniverse
=0
Energy
can,
however,
be
transferred
from
one
substance
to
another.
It
can
also be
converted
into
various
forms.
In
order
to
interpret
energy
changes,
scientists
must
clearly
define
what
part
of
the
universe
they
are
dealing
with.
The
system
is
defined
as
the
part
of
the
universe
that
is
being
studied
and
observed.
In
a
chemical
reaction,
the
system
is
usually
made
up
of
the
reactants
and
products.
By
contrast,
the
surroundings
are
everything
else
in
the
universe.
The
two
equations
below
show
the
relationship
between
the
universe,
a
system,
and
the
system’s
surroundings.
Universe
=
System
+
Surroundings
AEyniverse
=
AEsystem
+
AEsurroundings
=0
From
the
relationship,
we
know
that
any
change
in
the
system
is
accompanied
by
an
equal
and
opposite
change
in
the
surroundings.
AEsystem
=
_AEsurroundings
Look
at
the
chemical
reaction
that
is
taking
place
in
the flask
in
Figure
5.1.
A
chemist
would
probably
define
the
system
as
the
contents
of
the
flask—the
reactants
and
products.
Technically,
the
rest
of
the
universe
is
the
surroundings.
In
reality,
however,
the
entire
universe
changes
very
little
when
the
system
changes.
Therefore,
the
surroundings
are
considered
to
be
only
the
part
of
the
universe
that
is
likely
to
be
affected
by
the
energy
changes
of
the
system.
In
Figure
5.1,
the
flask,
the
lab
bench,
the
air
in
the
room,
and
the
student
who
is
carrying
out
the
reaction
all
make
up
the
surroundings.
The
system
is
more
likely
to
significantly
influence
its
immediate
surroundings
than,
say,
a
mountaintop
in
Japan
(also,
technically,
part
of
the
surroundings).
Section
Preview/
Specific
Expectations
In
this
section,
you
will
m
write
thermochemical
equa-
tions,
expressing
the
energy
change
as
a
heat
term
in
the
equation
or
as
AH
m
represent
energy
changes
using
diagrams
m
compare
energy
changes
that
result
from
physical
changes,
chemical
reac-
tions,
and
nuclear
reactions
m
communicate
your
under-
standing
of
the
following
terms:
thermodynamics,
thermochemistry,
law
of
conservation
of
energy,
system,
surroundings,
heat
(Q),
temperature
(T),
enthalpy
(H),
enthalpy
change
(AH),
endothermic
reaction,
exothermic
reac-
tion,
enthalpy
of
reaction
(AH.
),
standard
enthalpy
of
reaction
(AH’
),
thermo-
chemical
equation,
mass
defect,
nuclear
binding
energy,
nuclear
fission,
nuclear
fusion
i
EETZXEN
The
solution
in
the
flask
is
the
system.
The
flask,
the
laboratory,
and
the
student
are
the
surroundings.
Chapter
5
Energy
and
Change
-
MHR
221
Heat
and
Temperature
Heat,
Q,
refers
to
the
transfer
of
kinetic
energy.
Heat
is
expressed
in
the
same
units
as
energy—joules
(J).
Heat
is
transferred
spontaneously
from
a
warmer
object
to
a
cooler
object.
When
you
close
the
door
of
your
home
on
a
cold
day
to
“prevent
the
cold
from
getting
in,”
you
are
actually
preventing
the
heat
from
escaping.
You
are
preventing
the
kinetic
energy
in
your
warm
home
from
transferring
to
colder
objects,
including
the
cold
air,
outside.
Temperature,
7,
is
a
measure
of
the
average
kinetic
energy
of
the
particles
that
make
up
a
substance
or
system.
You
can
think
of
temperature
as
a
way
of
quantifying
how
hot
or
cold
a
substance
is,
relative
to
another
substance.
K
B
uc
110
:(\
GETEEE]
Celsius
degrees
and
Kelvin
degrees
are the
same
size.
The
Kelvin
scale
begins
at
absolute
zero.
This
is
the
temperature
at
which
the
particles
in
a
substance
have
no
kinetic
energy.
Therefore,
Kelvin
temperatures
are
never
negative.
By
contrast,
0°C
is
set
at
the
melting
point
of
water.
Celsius
temperatures
can
be
positive
or
negative.
Temperature
is
measured
in
either
Celsius
degrees
(°C)
or
kelvins
(K).
The
Celsius
scale
is
a
relative
scale.
It
was
designed
so
that
water’s
boiling
point
is
at
100°C
and
water’s
melting
point
is
at
0°C.
The
Kelvin
scale,
on
the
other
hand,
is
an
absolute
scale.
It
was
designed
so
that
0
K
is
the
temperature
at
which
a
substance
possesses
no
kinetic
energy.
The
relationship
between
the
Kelvin
and
Celsius
scales
is
shown
in
Figure
5.2,
and
by
the
following
equation.
Temperature
in
Kelvin
degrees
=
Temperature
in
Celsius
degrees
+
273.15
Enthalpy
and
Enthalpy
Change
Chemists
define
the
total
internal
energy
of
a
substance
at
a
constant
pressure
as
its
enthalpy,
H.
Chemists
do
not
work
with
the
absolute
enthalpy
of
the
reactants
and
products
in
a
physical
or
chemical
process.
Instead,
they
study
the
enthalpy
change,
AH,
that
accompanies
a
process.
That
is,
they
study
the
relative
enthalpy
of
the
reactants
and
products
in
a
system.
This
is
like
saying
that
the
distance
between
your
home
and
your
school
is
2
km.
You
do
not
usually
talk
about
the
absolute
position
of
your
home
and
school
in
terms
of
their
latitude,
longitude,
and
elevation.
You
talk
about
their
relative
position,
in
relation
to
each
other.
The
enthalpy
change
of
a
process
is
equivalent
to
its
heat
change
at
constant
pressure.
222
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
Enthalpy
Changes
in
Chemical
Reactions
In
chemical
reactions,
enthalpy
changes
result
from
chemical
bonds
being
broken
and
formed.
Chemical
bonds
are
sources
of
stored
energy.
Breaking
a
bond
is
a
process
that
requires
energy.
Creating
a
bond
is
a
process
that
releases
energy.
For
example,
consider
the
combustion
reaction
that
takes
place
when
nitrogen
reacts
with
oxygen.
Nz
+
Oz
=
2NQg
In
this
reaction,
one
mole
of
nitrogen-nitrogen
triple
bonds
and
one
mole
of
oxygen-oxygen
double
bonds
are
broken.
Two
moles
of
nitrogen-oxygen
bonds
are
formed.
This
reaction
absorbs
energy.
In
other
words,
more
energy
is
released
to
form
two
nitrogen-oxygen
bonds
than
is
used
to
break
one
nitrogen-nitrogen
bond
and
one
oxygen-oxygen
bond.
When
a
reaction
results
in
a
net
absorption
of
energy,
it
is
called
an
endothermic
reaction.
On
the
other
hand,
when
a
reaction
results
in
a
net
release
of
energy,
it
is
called
an
exothermic
reaction.
In
an
exothermic
reaction,
more
energy
is
released
to
form
bonds
than
is
used
to
break
bonds.
Therefore,
energy
is
released.
Figure
5.3
shows
the
relationship
between
bond
breaking,
bond
formation,
and
endothermic
and
exothermic
reactions.
Reactants
-»
Products
(
D
[EETZXE]
The
energy
changes
bonds
broken
bonds
made
.
.
that
result
from
bonds
breaking
and
endothermic
reaction:
forming
determine
whether
a
reac
system
absorbs
E
)
energy
absorbed
>
energy
released
Y
tion
is
exothermic
or
endothermic.
I
™
bonds
broken
bonds
made
exothermic
reaction:
energy
absorbed
<
energy
released
|
system
releases
E
\_
J
Representing
Enthalpy
Changes
The
enthalpy
change
of
a
chemical
reaction
is
known
as
the
enthalpy
\l
CHEM
of
reaction,
AH,,,.
The
enthalpy
of
reaction
is
dependent
on
conditions
such
as
temperature
and
pressure.
Therefore,
chemists
often
talk
about
the
Chemists
use different
sub-
standard
enthalpy
of
reaction,
AH",,:
the
enthalpy
change
of
a
chemical
scripts
to
represent
enthalpy
reaction
that
occurs
at
SATP
(25°C
and
100
kPa).
Often,
AH",
is
written
changes
for
specific
kinds
simply
as
AH°.
The
°
symbol
is
called
“nought.”
It
refers
to
a
property
of
of
reactions.
For
example,
a
substance
at
a
standard
state
or
under
standard
conditions.
You
may
AHcomb
represents
the
enthalpy
see
the
enthalpy
of
reaction
referred
to
as
the
heat
of
reaction
in
other
change
of
a
combustion
chemistry
books.
L
reaction.
)
Representing
Exothermic
Reactions
There
are
three
different
ways
to
represent
the
enthalpy
change
of
an
exothermic
reaction.
The
simplest
way
is
to
use
a
thermochemical
equation:
a
balanced chemical
equation
that
indicates
the
amount
of
heat
that
is
absorbed
or
released
by
the
reaction
it
represents.
For
example,
consider
the
exothermic
reaction
of
one
mole
of
hydrogen
gas
with
half
a
mole
of
oxygen
gas
to
produce
liquid
water.
For
each
mole
of
hydrogen
gas
that
reacts,
285.8
kJ
of
heat
is
produced.
Notice
that
the
heat
term
is
included
with
the
products
because
heat
is
produced.
Hz(g)
+
%Oz(g)
—
Hy0
+
285.8
kJ
Chapter
5
Energy
and
Change
*
MHR
223
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1
A
Hj(g)
+
202(g)
(reactants)
—
|
AH®
=-285.8
kJ
enthalpy,
H
—
H,0¢)
-
(products)
IS
In
an
exothermic
reaction,
the
enthalpy
of
the
system
decreases
as
energy
is
released
to
the
surroundings.
A
MgO(s)
+
COZ(g)
(products)
"
\I\l’
AH"=117.3
k]
enthalpy,
H
e
MgCO3(S)
(reactants)
XX
In
an
endothermic
reaction,
the
enthalpy
of
the
system
increases
as
heat
energy
is
absorbed
from
the
surroundings.
You
can
also
indicate
the
enthalpy
of
reaction
as
a
separate
expression
beside
the
chemical
equation.
For
exothermic
reactions,
AH"
is
always
negative.
Hag)
+
%Oz(g)
—
Hy0)
AH'xy
=-285.8K]
A
third
way
to
represent
the
enthalpy
of
reaction
is
to
use
an
enthalpy
diagram.
Examine
Figure
5.4
to
see
how
this
is
done.
Representing
Endothermic
Reactions
The
endothermic
decomposition
of
solid
magnesium
carbonate
produces
solid
magnesium
oxide and
carbon
dioxide
gas.
For
each
mole
of
magne-
sium
carbonate
that
decomposes,
117.3
kJ
of
energy
is
absorbed.
As
for
an
exothermic
reaction,
there
are
three
different
ways
to
represent
the
enthalpy
change
of
an
endothermic
reaction.
You
can
include
the
enthalpy
of
reaction
as
a
heat
term
in
the
chemical
equation.
Because
heat
is
absorbed
in
an
endothermic
reaction,
the
heat
term
is
included
on
the
reactant
side
of
the
equation.
117.3
kJ
+
MgCO3()
—
MgOy)
+
COxg)
You
can
also
indicate
the
enthalpy
of
reaction
as
a
separate
expression
beside
the
chemical
reaction.
For
endothermic
reactions,
the
enthalpy
of
reaction
is
always
positive.
MgCOj35)
=
MgOg)
+
COz(g)
AH
=
117.3
K]
Finally,
you
can
use
a
diagram
to
show
the
enthalpy
of
reaction.
Figure
5.5
shows
how
the
decomposition
of
solid
magnesium
carbonate
can
be
represented
graphically.
Stoichiometry
and
Thermochemical
Equations
The
thermochemical
equation
for
the
decomposition
of
magnesium
carbonate,
shown
above,
indicates
that
117.3
k]
of
energy
is
absorbed
when
one
mole,
or
84.32
g,
of
magnesium
carbonate
decomposes.
The
decomposition
of
two
moles
of
magnesium
carbonate
absorbs
twice
as
much
energy,
or
234.6
kJ.
MgCO35)
—
MgOgs)
+
COyg
AH
i,
=
117.3
K]
2MgCO3(5)
—
2MgO(g)
+
ZCOZ(g)
AH’,
=
234.6
k]
Enthalpy
of
reaction
is
linearly
dependent
on
the
quantity
of
products.
That
is,
if
the
amount
of
products
formed
doubles,
the
enthalpy
change
also
doubles.
Figure
5.6
shows
the
relationship
between
the
stoichiometry
of
a
reaction
and
its
enthalpy
change.
Because
of
this
relationship,
an
exothermic
reaction
that
is
relatively
safe
on
a
small
scale
may
be
extremely
dangerous
on
a
large
scale.
One
of
the
jobs
of
a
chemical
engineer
is
to
design
systems
that
allow
exothermic
reactions
to
be
carried
out
safely
on
a
large
scale.
For
example,
the
blast
furnaces
used
in
steel
making
must
withstand
temperatures
of
up
to
2000°C,
produced
by
the
exothermic
combustion
reaction
of
coal
with
oxygen.
amount
of
varies
directly
with
amount
of
varies
directly
with
|
heat
absorbed
compound
A
compound
B
or
released
(mol)
(factor:
molar
ratio)
(mol)
(factor:
AHxn)
(kdJ)
A
A
A
A
XX
This
diagram
summarizes
the
relationship
between
the
stoichiometry
of
a
reaction
and
AH.
224
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
I
Sample
Problem
Stoichiometry
and
Thermochemical
Reactions
Problem
Aluminum
reacts
readily
with
chlorine
gas
to
produce
aluminum
chloride.
The
reaction
is
highly
exothermic.
2Al)
+
3Clyg
—
2AlCl3)
AH'rxn
=
—1408
k]
What
is
the
enthalpy
change
when
1.0
kg
of
Al
reacts
completely
with
excess
Cl,?
What
Is
Required?
You
need
to
calculate
the
enthalpy
change,
AH,
when
the
given
amount
of
Al
reacts.
What
Is
Given?
You
know
the
enthalpy
change
for
the
reaction
of
two
moles
of
Al
with
one
mole
of
Cl;.
From
the
periodic
table,
you
know
the
molar
mass
of
Al.
ZAl(S)
+
3C12(g)
-
2A1C13(S]
AH’
.,
=
—1408
k]
M1
=
26.98
g/mol
Plan
Your
Strategy
Convert
the
given
mass
of
Al
to
moles.
The
enthalpy
change
is
linearly
dependent
on
the
quantity
of
reactants.
Therefore,
you
can
use
a
ratio
to
determine
the
enthalpy
change
for
1.0
kg
of
Al
reacting
with
Cl,.
Act
on
Your
Strategy
Determine
the
number
of
moles
of
Al
in
1
kg.
Remember
to
convert
to
grams.
m
nmol
Al
=
AL
Mai
_
1.0x10%g
~
26.98
g/mol
=
37
mol
Use
ratios
to
compare
the
reference
reaction
with
the
known
enthalpy
change
(AH,)
to
the
reaction
with
the
unknown
enthalpy
change
(AH;).
AH,
ny;
mol
Al
AH;
n;mol
Al
AH,
37
mol
Al
—1408k]
2
mol
Al
AH,
=
-2.6
x
10*
kJ
Check
Your
Solution
The
sign
of
the
answer
is
negative,
which
corresponds
to
an
exothermic
reaction.
The
1
kg
sample
contained
about
20
times
more
moles
of
Al.
Therefore,
the
enthalpy
change
for
the
reaction
should
be
about
20
times
greater,
and
it
is.
N
\
Chapter
5
Energy
and
Change
*
MHR
225
I
Practice
Problems
—
1.
Consider
the
following
reaction.
Ny
+
Oz
=
2NOy)
AH’ix,
=
+180.6
k]
(a)
Rewrite
the
thermochemical
equation,
including
the
standard
enthalpy
of
reaction
as
either
a
reactant
or
a
product.
(b)
Draw
an
enthalpy
diagram
for
the
reaction.
(c)
What
is
the
enthalpy
change
for
the
formation
of
one
mole
of
nitrogen
monoxide?
(d)
What
is
the
enthalpy
change
for
the
reaction
of
1.000
x
10%
g
of
nitrogen
with
sufficient
oxygen?
2.
The
reaction
of
iron
with
oxygen
is
very
familiar.
You
can
see the
resulting
rust
on
buildings,
vehicles,
and
bridges.
You
may
be sur-
prised,
however,
at
the
large
amount
of
heat
that
is
produced
by
this
reaction.
4Fe(s)
+
3051
—
2Fe;05()
+
1.65
x
103
k]
(@)
What
is
the
enthalpy
change
for
this
reaction?
(b)
Draw
an
enthalpy
diagram
that
corresponds
to
the
thermochemical
equation.
(c)
What
is
the
enthalpy
change
for
the
formation
of
23.6
g
of
iron(III)
oxide?
L
Consider
the
following
thermochemical
equation.
25.9
k]
+
%Hz(g)
+
%Iz(g)
—
Hlg
(a)
What
is
the
enthalpy
change
for
this
reaction?
(b)
How
much
energy
is
needed
for
the
reaction
of
4.57
x
10%*
molecules
of
iodine,
I,
with
excess
hydrogen,
H,?
(c)
Draw
and
label
an
enthalpy
diagram
that
corresponds
to
the
given
thermochemical
equation.
4.
Tetraphosphorus
decoxide,
P4O1g,
is
an
acidic
oxide.
It
reacts
with
water
to
produce
phosphoric
acid,
H3POy,
in
an
exothermic
reaction.
P4010(S)
+
GHZO(Z)
—>
4H3PO4(aq)
AHorxn
-
_257.2
kI
(a)
Rewrite
the
thermochemical
equation,
including
the
enthalpy
change
as
a
heat
term
in
the
equation.
(b)
How
much
energy
is
released
when
5.00
mol
of
PO,
reacts
with
excess
water?
(c)
How
much
energy
is
released
when
235
g
of
H3POy,yq)
is
formed?
—
/
Heat
Changes
and
Physical
Changes
Enthalpy
changes
are
associated
with
physical
changes
as
well
as
with
chemical
reactions.
You
have
observed
examples
of
these
enthalpy
changes
in
your
daily
life.
Suppose
that
you
want
to
prepare
some
pasta.
You
put
an
uncovered
pot
of
water
on
a
stove
element.
The
heat
from
the
element
causes
the
water
to
become
steadily
hotter,
until
it
reaches
100°C
(the
boiling
point
of
water
at
100
kPa).
At
this
temperature,
heat
is
still
being
added
to
the
water.
The
average
kinetic
energy
of
the
liquid
water
molecules
does
not
increase,
however.
Instead,
the
energy
is
used
to
break
the
intermolecular
bonds
between
the
water
molecules
as
they
change
from
liquid
to
vapour.
The
temperature
of
the
liquid
water
remains
at
226
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
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100°C
until
all
the
water
has
been
vaporized.
If
you
add
heat
to
the
vapour,
the
temperature
of
the
vapour
will
increase
steadily.
When
you
heat
ice
that
is
colder
than
0°C,
a
similar
process
occurs.
The
temperature
of
the
ice
increases
until
it
is
0°C
(the
melting
point
of
water).
If
you
continue
to
add
heat,
the
ice
remains
at
0°C
but
begins
to
melt,
as
the
bonds
between
the
water
molecules
in
the
solid
state
begin
to
break.
Figure
5.7
shows
the
relationship
between
temperature
and
heat
for
a
solid
substance
that
melts
and
then
vaporizes
as
heat
is
added
to
it.
A
gas
boiling
|
)
point
:
!
g
liquid
i
i
As
heat
is
added
to
a
Q
!
!
substance,
the
temperature
of
the
£
melting
|
AHyap
|
substance
steadily
increases
until
it
F
point
|
.
i
.
|
reaches
its
melting
point
or
boiling
solid
i
i
i
i
i
point.
The
temperature
then
remains
!
AH
met
!
!
!
steady
as
the
substance
undergoes
'
'
'
:
>
a
phase change.
Heat
added
»
You
can
represent
the
enthalpy
change
that
accompanies
a
phase
change—from
liquid
to
solid,
for
example—just
like
you
represented
the
enthalpy
change
of
a
chemical
reaction.
You
can
include
a
heat
term
in
the
equation,
or
you
can
use
a
separate
expression
of
enthalpy
change.
For
example,
when
one
mole
of
water
melts,
it
absorbs
6.02
kJ
of
energy.
\-J
CHEM
The
process
of
melting
is
also
H,Or)
—
HoO)
AH
=6.02K]
known
as
fusion.
Therefore,
Normally,
however,
chemists
represent
enthalpy
changes
associated
with
you
will
sometimes
see
the
phase
changes
using
modified
AH
symbols.
These
symbols
are
described
enthalpy
of
melting
referred
to
below.
as
the
enthalpy
of
fusion.
N
Y
e
enthalpy
of
vaporization,
AH,,y
:
the
enthalpy
change
for
the
phase
change
from
liquid
to
gas
¢
enthalpy
of
condensation,
AH,opnq:
the
enthalpy
change
for
the
phase
change
of
a
substance
from
gas
to
liquid
e
enthalpy
of
melting,
AHpe1:
the
enthalpy
change
for
the
phase
change
of
a
substance
from
solid
to
liquid
e
enthalpy
of
freezing,
AHy,:
the
enthalpy
change
for
the
phase
change
of
a
substance
from
liquid
to
solid
Vaporization
and
condensation
are
opposite
processes.
Thus,
the
enthalpy
changes
for
these
processes
have
the
same
value
but
opposite
signs.
For
example,
6.02
k]
is
needed
to
vaporize
one
mole
of
water.
Therefore,
6.02
kJ
of
energy
is
released
when
one
mole
of
water
freezes.
AI_Ivap
=
—AH_ong
Similarly,
melting
and
freezing
are
opposite
processes.
AHmelt
=
~AHge
Several
enthalpies
of
melting
and
vaporization
are
shown
in
Table
5.1.
Notice
that
the
same
units
(kJ/mol)
are
used
for
the
enthalpies
of
melting,
vaporization,
condensation,
and
freezing.
Also
notice
that
energy
changes
associated
with
phase
changes
can
vary
widely.
Chapter
5
Energy
and
Change
«
MHR
227
Table
5.1
Enthalpies
of
Melting
and
Vaporization
for
Several
Substances
halpy
of
melti
Ipy
of
vaporizati
AH
i
(kJ/mol)
AH
5,
(kJ/mol)
argon
1.3
6.3
diethyl
ether
7.3
29
ethanol
5.0
40.5
mercury
23.4
29
methane
8.9
0.94
sodium
chloride
27.2
207
water
6.02
40.7
Hot
Packs
and
Cold
Packs:
Using
the
Energy
of
Physical
Changes
You
just
learned
about
the
enthalpy
changes
that
are
associated
with
phase
changes.
Another
type
of
physical
change
that
involves
a
heat
transfer
is
dissolution.
When
a
solute
dissolves
in
a
solvent,
the
enthalpy
change
that
occurs
is
called
the
enthalpy
of
solution,
AHg,.
Dissolution
can
be
either
endothermic
or
exothermic.
Manufacturers
take
advantage
of
endothermic
dissolution
to
produce
cold
packs
that
athletes
can
use
to
treat
injuries.
One
type
of
cold
pack
contains
water
and
a
salt,
such
as
ammonium
nitrate,
in
separate
compartments.
When
you
crush
the
pack,
the
membrane
that
divides
the
compartments
breaks,
and
the
salt
dissolves. This
dissolution
process
is
endothermic.
It
absorbs
heat
for
a
short
period
of
time,
so
the
cold
pack
feels
cold.
Figure
5.8
shows
how
a
cold
pack
works.
~
soluble
salt
membrane
of
water
pack
A
typical cold
pack
has
two
separate
chambers.
One
chamber
contains
a
salt.
The
other
chamber
contains
water.
Crushing
the
pack
allows
the
salt
to
dissolve
in
the
water—an
endothermic
process.
228
This
person’s
shoulder
was
injured.
Using
a
cold
pack
helps
to
reduce
the
inflammation
of
the
joint.
Some
types
of
hot
packs
are
constructed
in
much
the
same
way
as
the
cold
packs
described
above.
They
have
two
compartments.
One
compartment
contains
a
salt,
such
as
calcium
chloride.
The
other
compartment
contains
water.
In
hot
packs,
however,
the
dissolution
process
is
exothermic.
It
releases
heat
to
the
surroundings.
MHR
«
Unit
3
Energy
Changes
and
Rates
of
Reaction
Energy
and
Nuclear
Reactions
The
energy
that
is
released
by
a
physical
change,
such
as
the
dissolution
of
calcium
chloride,
can
warm
your
hands.
The
energy
that
is
released
by
a
chemical
reaction,
such
as
the
formation
of
water,
can
power
a
rocket.
The
energy
that
is
released
by
a
nuclear
reaction,
such
as
the
nuclear
reactions
in
the
Sun,
however,
can
provide
enough
heat
to
fry
an
egg
on
a
sidewalk
that
is
150
000
000
km
away
from
the
surface
of
the
Sun.
From
previous
science
courses,
you
will
recall
that
nuclear
reactions
involve
changes
in
the
nuclei
of
atoms.
Often
nuclear
reactions
result
in
the
transformation
of
one
or
more
elements
into
one
or
more
different
elements.
Like
physical
changes
and
chemical
reactions,
nuclear
reactions
are
accompanied
by
energy
changes.
Nuclear
reactions,
however,
produce
sig-
nificantly
more
energy
than
physical
and
chemical
processes.
In
nuclear
reactions,
a
significant
amount
of
the
mass
of
the
reactants
is
actually
converted
into
energy.
Ever
since
Albert
Einstein
devised
his
famous
equation,
E
=
mc?,
we
have
known
that
mass
and
energy
are
interconvertible.
In
Einstein’s
equation,
E
is
energy
in
kg
«
m?/s?
(J),
m
is
the
mass
in
kg,
and
¢?
is
the
square
of
the
speed
of
light.
c?
=
(3.0
x
10%
m/s)?
=
9.0
x
10'®
m?/s?
As
you
can
see,
¢?
is
an
enormous
number.
Therefore,
even
a
very
tiny
amount
of
matter
is
equivalent
to
a
significant
amount
of
energy.
For
example,
compare
the
mass
of
1
mol
of
carbon-12
atoms
with
the
mass
of
the
individual
nucleons
in
1
mol
of
carbon-12
atoms.
The
mass
of
6
mol
of
hydrogen-1
atoms
(one
proton
and
one
electron
each)
and
6
mol
of
neutrons
is
12.098
940
g.
The
mass
of
1
mol
of
carbon-12
atoms
is
exactly
12
g.
Note
that
the
mass
of
the
electrons
does
not
change
in
a
nuclear
reaction.
12.098
940
g/mol
—
12.000
000
g/mol
0.098
940
g/mol
The
difference
in
mass
is
significant.
It
would
show
up
on
any
reasonably
precise
balance.
Thus,
the
mass
of
the
nucleus
of
carbon-12
is
significant-
ly
less
than
the
mass
of
its
component
nucleons.
The
difference
in
mass
between
a
nucleus
and
its
nucleons
is
known
as
the
mass
defect.
What
causes
this
mass
defect?
It
is
caused
by
the
nuclear binding
energy:
the
energy
associated
with
the
strong
force
that
holds
a
nucleus
together.
Nucleus
+
Nuclear
binding
energy
—
Nucleons
You
can
use
Einstein’s
equation
to
calculate
the
nuclear
binding
energy
for
carbon-12.
AE
=
Amc*
=
(9.89
x
10™°
kg/mol)(9.0
x
10'®
m?/s?)
=
8.9
x
10"
J/mol
=
8.9
x
10°
kJ/mol
Clearly,
the
energy
associated
with
the
bonds
that
hold
a
nucleus
together
is
much
greater
than
the
energy
associated
with
chemical
bonds,
which
are
usually
only
a
few
hundred
kJ/mol.
The
higher
the
binding
energy
of
a
nucleus,
the
more
stable
the
nucleus
is.
Nuclei
with
mass
numbers
(A)
that
are
close
to
60
are
the
most
stable.
Nuclear
reactions,
in
which
nuclei
break
apart
or
fuse,
tend
to
form
nuclei
that
are
more
stable
than
the
reactant
nuclei.
Figure
5.9
illustrates
the
relative
stability
of
various
nuclei.
www.mcgrawhill.ca/links/
chemistry12
Not
all
hot
packs
use
dissolu-
tion
processes.
For
example,
one
kind
of
hot
pack
exploits
the
crystallization
of
sodium
thiosulfate
or
sodium
acetate.
Another
kind
uses
the
oxida-
tion
of
iron
(rusting).
On
the
Internet,
investigate
different
kinds
of
hot
packs.
Are
they
all
used
for
the
same
purpose?
What
are
the
pros
and
cons
of
their
designs?
To
start
your
search,
go
to
the
web
site
above
and
click
on
Web
Links.
Chapter
5
Energy
and
Change
*
MHR
229
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GETEXX]
This
graph
shows
the
relative
stability
of
nuclei.
It
indicates
whether
nuclei
are
more
likely
to
split
or
fuse
in
a
nuclear
reaction.
Notice
that
the
helium-4
nucleus
is
unusually
stable.
Electronic
Learning
Partner
To
learn
more
about
nuclear
fission,
go
to
the
Chemistry
12
Electronic
Learning
Partner.
9
34g
OFg
84Kr
119g,,
S
812¢
UL
§
region
of
very
<
74,
stable
nuclei
238
c
4He
5
5
67
3
E
5|
6L
2
fusion
fission
>
4
—
-
2
(]
S
3l
3y
2
5|
°He
2
.
|,
m
11
°H
0
I
I
I
I
I
I
I
I
I
I
I
I
I
20
40
60
80
100
120
140
160
Mass
number,
A
180
200
220
240
260
The
difference
between
the
nuclear
binding
energy
of
the
reactant
nuclei
and
the
product
nuclei
represents
the
energy
change
of
the
nuclear
reaction.
Nuclear
Fission
A
heavy
nucleus
can
split
into
lighter
nuclei
by
undergoing
nuclear
fission.
Nuclear
power
plants
use
controlled
nuclear
fission
to
provide
energy.
Uncontrolled
nuclear
fission
is
responsible
for
the
massive
destructiveness
of
an
atomic
bomb.
The
most
familiar
fission
reactions
involve
the
splitting
of
uranium
atoms.
In
these
reactions,
a
uranium-235
atom
is
bombarded
with
neutrons.
The
uranium
nucleus
then
splits
apart
into
various
product
nuclei.
Two
examples
of
fission
reactions
that
involve
uranium-235
are
shown
in
Figure
5.10.
)
>
+
energy
;n
zggu
>
\\
i
>
+
energy
L\
;n
¥
zggu
>
ETEEETY
Uranium
can
undergo
fission
in
numerous
different
ways,
producing
various
product
nuclei.
Two
examples
are
shown
here.
230
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
Fission
reactions
produce
vast
quantities
of
energy.
For
example,
when
one
mole
of
uranium-235
splits,
it
releases
2.1
x
10'3
J.
By
contrast,
when
one
mole
of
coal
burns,
it
releases
about
3.9
x
10°
J.
Thus,
the
combustion
of
coal
releases
about
five
million
times
fewer
joules
of
energy
per
mole
than
the
fission
of
uranium-235.
Nuclear
Fusion
Two
smaller
nuclei
can
fuse
to
form
a
larger
nucleus,
in
what
is
called
a
nuclear
fusion
reaction.
You
and
all
other
life
on
Earth
would
not
exist
without
nuclear
fusion
reactions.
These
reactions
are
the
source
of
the
energy
produced
in
the
Sun.
One
example
of
a
fusion
reaction
is
the
fusion
of
deuterium
and
tritium.
2H+3H
-
jHe
+
in
The
seemingly
simple
reaction
between
deuterium
and
tritium
produces
1.7
x
10'?
J
of
energy
for
each
mole
of
deuterium.
This
is
about
10
times
fewer
joules
of
energy
than
are
produced
by
the
fission
of
one
mole
of
uranium.
It
is
still,
however,
500 000
times
more
energy
than
is
produced
by
burning
one
mole
of
coal.
Scientists
are
searching
for
a
way
to
harness
the
energy
from
fusion
reactions.
Fusion
is
a
more
desirable
way
to
produce
energy
than
fission.
The
main
product
of
fusion,
helium,
is
relatively
harmless
compared
with
the
radioactive
products
of
fission.
Unfortunately,
fusion
is
proving
more
difficult
than
fission
to
harness.
The
fission
of
one
mole
of
uranium-235
produces
more
energy
than
the
fusion
of
one
mole
of
deuterium
with
one
mole
of
tritium,
What
if
you
compare
the
energy
that
is
produced
in
terms
of
mass
of
reactants?
Calculate
a
ratio
to
compare
the
energy
that
is
produced
from
fusion
and
fission,
per
gram
of
fuel.
What
practical
consequences
arise
from
your
result?
)
,
_
1024
)
—
Fusion
will
not
proceed
at
a
reasonable
rate
without
an
initial
i
t
of
This
i
t
bl
—
daily
solar
energy
enormous
initial
input
of
energy.
This
is
not
a
problem
102"
)
-
falling on
Earth
in
the
core
of
the
Sun,
where
the
temperature
ranges
|
energy
of
strong
earthquake
W\/\[W\M
from
7
500
000°C
to
15
000
000°C.
It
is
a
problem
in
108y
—
industry.
Scientists
are
working
on
safe
and
economical
daily
electrical
output
of
.
]
..
Canadian
dams
at
Niagara
Falls
ways
to
provide
the
high-temperature
conditions
that
108y
—
.
—
1000
t
of
coal
burned
are
needed
to
make
fusion
a
workable
energy
source.
1012J
—
Comparing
the
Energy
of
Physical,
Chemical,
o5,
-
1tof
TNT
exploded
4
and
Nuclear
Processes
|
-
7KW
h
of
electrical
energy
7
In
thi
i
1
d
that
physical
ch
64
—
n
this
section,
you
learned
that
physical
changes,
1080
9\
,
,
.
]
]
heat
released
from
combustion
chemical
reactions,
and
nuclear
reactions
all
involve
of
1
mol
glucose
energy
changes.
You
also
learned
that
the
energy
10°J
—
changes
have
some
striking
differences
in
magnitude.
heat
required
to
boil
1
mol
of
water
.
.
0
—
Figure
5.11
shows
energy
changes
for
some
physical,
10°J
chemical,
and
nuclear
processes.
Some
other
interesting
,
energy
statistics
are
included
for
reference.
107J
106J
102
J
——
heat
absorbed
during
division
of
one
bacterial
cell
10-12
)
—f—
energy
from
fission
of
one
235y
atom
£84
s
107150
—
e
GETEEREN
The
energy
changes
of
physical,
nuclear,
and
chemical
‘(&f?":
processes
vary
widely.
In
general,
however,
chemical
reactions
are
108y
—
o
'
associated
with
greater
energy
changes
than
physical
changes.
§5s
Nuclear
reactions
are
associated
with
far
greater
energy
changes
than
10-21
——
average
kinetic
energy
of
a
molecule
chemical
reactions.
in
air
at
300
K
Chapter
5
Energy
and
Change
-
MHR
231
The
following
Concept
Organizer
summarizes
what
you
learned
about
the
energy
changes
associated
with
physical
changes,
chemical
reactions,
and
nuclear
reactions.
(oo
]
T:To
MO
-1
[V{-1
dll
Energy
Changes
Physical
Changes
|
The
phase
of
a
Heatis
released
—
exothermic
change.
"|
substance
changes.
Chemical
Reactions
Heat
is
absorbed
—
Fission
and
Fusion
Reactions
endothermic
change.
In
general, physical
changes
&
involve
smaller
energy
changes
%
Heat
is
released
—
than
chemical
reactions.
Nuclear
=
exothermic
reaction.
reactions
produce
far
more
energy
|
@
,|
Bonds
between
than
chemical
reactions.
e
atoms
break
and
form.
c
Heat
is
absorbed
—
endothermic
reaction.
Mass
is
converted
An
enormous
quantity
into
energy.
of
energy
is
released.
Section
Summary
In
section
5.1,
you
learned
about
the
energy
changes
that
accompany
physical
changes,
chemical
reactions,
and
nuclear
reactions.
You
learned
how
to
represent
energy
changes
using
thermochemical
equations
and
diagrams.
In
the
next
section,
you
will
determine
the
enthalpy
of
a
reaction
by
experiment.
Section
Review
O
In
your
own
words,
explain
why
exothermic
reactions
have
AH
<
0.
(2]
Label
each
thermochemical
equation
with
the
most
specific
form(s)
of
AH.
Remember
to
pay attention
to
the
sign
of
AH.
(a)
Ag(s)
+
5
Clag
>
AgCliy
+
127.0
kJ
(at
25°C
and
100
kPa)
(b)
44.0
k]
+
H20()
—
H20
(at
25°C
and
100
kPa)
(c)
CoHyg)
+
303
—
2C04g
+
2H20(g)
+
energy
©
O
Suppose
that
one
of
your
friends
was
absent
on
the
day
that
you
learned
about
labelling
AH.
To
help
your
friend,
create
a
table
that
summarizes
the
different
ways
to
label
AH,
and
their
meanings.
O
©
Calcium
oxide,
CaO,
reacts
with
carbon
in
the
form
of
graphite.
Calcium
carbide,
CaC,,
and
carbon
monoxide,
CO,
are
produced
in
an
endothermic
reaction.
CaOg)
+
3C(g)
+
462.3
k]
—
CaGy(g)
+
COg
(a)
246.7
kJ
of
energy
is
available
to
react.
What
mass
of
calcium
carbide
is
produced,
assuming
sufficient
reactants?
232
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
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(b)
What
is
the
enthalpy
change
for
the
reaction
of
46.7
g
of
graphite
with
excess
calcium
oxide?
(e}
1.38
x
10?*
formula
units
of
calcium
oxide
react
with
excess
graphite.
How
much
energy
is
needed?
©
©
Acetylene,
C,H,,
undergoes
complete
combustion
in
oxygen.
Carbon
dioxide
and
water
are
formed.
When
one
mole
of
acetylene
undergoes
complete
combustion,
1.3
x
102
k]
of
energy
is
released.
(a)
Write
a
thermochemical
equation
for
this
reaction.
(b)
Draw
a
diagram
to
represent
the
thermochemical
equation.
(¢)
How
much
energy
is
released
when
the
complete
combustion
of
acetylene
produces
1.50
g
of
water?
@
©
Write
an
equation
to
represent
each
phase
change
in
Table
5.1
on
page
228.
Include
the
enthalpy
change
as
a
heat
term
in
the
equation.
@
@D When
one
mole
of
gaseous
water forms
from
its
elements,
241.8
kJ
of
energy
is
released.
In
other
words,
when
hydrogen
burns
in
oxygen
or
air,
it
produces
a
great
deal
of
energy.
Since
the
nineteenth
century,
scientists
have
been
researching
the
potential
of
hydrogen
as
a
fuel.
One
way
in
which
the
energy
of
the
combustion
of
hydrogen
has
been
successfully
harnessed
is
as
rocket
fuel
for
aircraft.
(a)
Write
a
thermodynamic
equation
for
the
combustion
of
hydrogen.
(b)
Describe
three
reasons
why
hydrogen
gas
is
a
desirable
rocket
fuel.
(c)
Suggest
challenges
that
engineers
might
have
had
to
overcome
in
order
to
make
hydrogen
a
workable
rocket
fuel
for
aircraft.
(d)
Use
print
and
electronic
resources
to
find
out
about
research
into
hydrogen
as
a
fuel.
Create
a
time
line
that
shows
significant
events
and
discoveries
in
this
research.
©
@D
A
healthy
human
body
maintains
a
temperature
of
about
37.0°C.
Explain
how
physical,
chemical,
and
nuclear
processes
all
contribute,
directly
or
indirectly,
to
keeping
the
human
body
at
a
constant
temperature.
Chapter
5
Energy
and
Change
*
MHR
233
Section
Preview/
Specific
Expectations
In
this
section,
you
will
m
determine
the
heat
that
is
produced
by
a
reaction
using
a
calorimeter,
and
use
the
data
obtained
to
calcu-
late
the
enthalpy
change
for
the
reaction
m
communicate
your
under-
standing
of
the
following
terms:
specific
heat
capacity
(c),
heat
capacity
(C),
calorimeter,
coffee-cup
calorimeter,
constant-
pressure
calorimeter
GETEXEE]
On
a
sunny
day,
you
would
probably
prefer
to
siton
a
bench
made
of
wood
rather
than
a
bench
made
of
aluminum.
Wood
has
a
higher
heat
capacity
than
aluminum.
Therefore,
more
heat
is
needed
to
increase
its
temperature.
CONCEPT
CHECK
Explain
why
water
is
some-
times
used
as
a
coolant
for
automobile
engines.
Determining
Enthalpy
of
Reaction
by
Experiment
Chemical
and
physical
processes,
such
as
the
ones
you
studied
in
section
5.1,
are
associated
with
characteristic
enthalpy
changes.
How
do
chemists
measure
these
enthalpy
changes?
To
measure
the
enthalpy
of
a
chemical
or
physical
process,
chemists
insulate
the
system
from
the
surroundings.
They
can
then
determine
the
heat
change
by
measuring
the
temperature
change
of
the
system.
What
is
the
relationship
between
the
heat
change
and
the
temperature
change?
As
you
learned
in
previous
science
courses,
each
substance
has
a
charac-
teristic
property
that
dictates
how
its
temperature
will
change
when
heat
is
lost
or
gained.
Specific
Heat
Capacity
The
amount
of
energy
that
is
needed
to
raise
the
temperature
of
one
gram
of
a
substance
1°C
(or
1
K)
is
the
specific
heat
capacity,
c,
of
the
substance.
Specific
heat
capacity
is
usually
expressed
in
units
of
J/g«
“C.
The
specific
heat
capacities
of
several
substances
are
given
in
Table
5.2.
Figure
5.12
shows
that
you
can
often
predict
the
relative specific
heat
capacities
of
familiar
substances.
Table
5.2
Specific
Heat
Capacities
of
Selected
Substances
(TR
(T
CE
T
T
LT
AW
T
IO
25"(:)‘
Element
aluminum
0.900
carbon
(graphite)
0.711
hydrogen
14.267
iron
0.444
Compound
ammonia
(liquid)
4.70
ethanol
2.46
ethylene
glycol
2.42
water
(liquid)
4.184
Other
material
air
1.02
concrete
0.88
glass
0.84
wood
1.76
You
can
use
the
specific
heat
capacity
of
a
substance
to
calculate
the
amount
of
energy
that
is
needed
to
heat
a
given
mass
a
certain
number
of
degrees.
You
can
also
use
the
specific
heat
capacity
to
determine
the
amount
of
heat
that
is
released
when
the
temperature
of
a
given
mass
decreases.
The
specific
heat
capacity
of
liquid
water,
as
shown
in
Table
5.2,
is
4.184
J/g«
°C.
This
relatively
large
value
indicates
that
a
considerable
amount
of
energy
is
needed
to
raise
or
lower
the
temperature
of
water.
234
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
All
samples
of
the
same
substance
have
the
same
specific
heat
capacity.
In
contrast,
heat
capacity,
C,
relates
the
heat
of
a
sample,
object,
or
system
to
its
change
in
temperature.
Heat
capacity
is
usually
expressed
in
units
of
kJ/°C.
Consider
a
bathtub
full
of
water
and
a
teacup
full
of
water
at
room
temperature.
All the
water
has
the
same
specific
heat
capacity,
but
the
two
samples
have
different
heat
capacities.
It
would
take
a
great
deal
more
heat
to
raise
the
temperature
of
the
water
in
the
bathtub
by
10°C
than
it
would
take
to
raise
the
temperature
of
the
water
in
the
teacup
by
10°C.
Therefore,
the
water
in
the
bathtub
has
a
higher
heat
capacity.
Specific
Heat
Capacity
and
Heat
Transfer
You
can
use
the
following
equation
to
calculate
the
heat
change
of
a
sub-
stance,
based
on
the
mass
of
the
substance.
You
can
also
use
this
equation
to
calculate
the
specific
heat
capacity
of
the
substance
and
the
change
in
its
temperature.
Q=mecAT
where
Q
=
heat
(J)
m
=
mass
(g)
¢
=
specific
heat
capacity
(J/g«
"C)
AT
=
T¢(final
temperature)
—
Tj(initial
temperature)(°C
or
K)
Water
is
often
used
in
controlled
surroundings
to
measure
the
heat
of
a
reaction.
For
example,
you
can
use
the
equation
above
to
determine
the
amount
of
energy
that
is
needed
to
heat
1.00
x
10?
g
of
water
from
20.0°C
to
45.0°C.
Q=mec+AT
The
mass
of
the
water
is
1.00
x
10%
g.
The
specific
heat
capacity
of
water
is
4.184
J/g
-
°C.
The
temperature
of
the
water
increases
by
25.0°C.
-
Q=
(1.00
x
10%.g)(4.184
J/g~
°€)(25.0°C)
=
1.05
x
10*]
To
raise
the
temperature
of
1.00
x
10%
g
of
water
by
25°C,
1.05
x
10*
J
of
heat
is
needed.
Try
the
following
problems
to
practise
working
with
specific
heat
capacity
and
temperature
change.
I
Practice
Problems
5.
A
sample
of
ethylene
glycol,
used
in
car
radiators,
has
a
mass
of
34.8
g.
The
sample
liberates
783
J
of
heat.
The
initial
temperature
of
the
sample
is
22.1°C.
What
is
the
final
temperature?
6.
A
sample
of
ethanol,
C;H50H,
absorbs
23.4
kJ
of
energy.
The
temperature
of
the
sample
increases
from
5.6°C
to
19.8°C.
What
is
the
mass
of
the
ethanol
sample?
The
specific
heat
capacity
of
ethanol
is
2.46
J/g«°C.
7.
A child’s
swimming
pool
contains
1000
L
of
water.
When
the
water
is
warmed
by
solar
energy,
its
temperature
increases
from
15.3°C
to
21.8°C.
How
much
heat
does
the
water
absorb?
8.
What
temperature
change
results
from
the
loss
of
255
kJ
from
a
10.0
kg
sample
of
water?
|
\
J/
Chapter
5
Energy
and
Change
-
MHR
235
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www.mcgrawhill.ca/links/
chemistry12
The
famous
French
scientist
Antoine
Laviosier
(1743-1794)
is
considered
by
many
to
be
the
first
modern
chemist.
Lavoisier
created
a
calori-
meter
to
study
the
energy
that
is
released
by
the
metabolism
of
a
guinea
pig.
To
learn
about
Lavoisier’s
experiment,
go
to
the
web
site
above
and
click
on
Web
Links.
What
do
you
think
about
using
animals
in
experiments?
Write
an
essay
to
explain
why
you
agree
or
disagree
with
this
practice.
Measuring
Heat
Transfer
in
a
Laboratory
From
previous
science
courses,
you
will
probably
remember
that
a
calorimeter
is
used
to
measure
enthalpy
changes
for
chemical
and
physical
reactions.
A
calorimeter
works
by
insulating
a
system
from
its
surroundings.
By
measuring
the
temperature
change
of
the
system,
you
can
determine
the
amount
of
heat
that
is
released
or
absorbed
by
the
reaction.
For
example,
the
heat
that
is
released
by
an
exothermic
reaction
raises
the
temperature
of
the
system.
Qreaction
=
_Qinsulated
system
In
your
previous
chemistry
course,
you
learned
about
various
types
of
calorimeters.
For
instance,
you
learned
about
a
bomb
calorimeter,
which
allows
chemists
to
determine
energy
changes
under
conditions
of
constant
volume.
In
section
5.1,
however,
you
learned
that
an
enthalpy
change
repre-
sents
the
heat
change
between
products
and
reactants
at
a
constant
pressure.
Therefore,
the
calorimeter
you
use
to
determine
an
enthalpy
change
should
allow
the
reaction
to
be
carried
out
at
a
constant
pressure.
In
other
words,
it
should
be
open
to
the
atmosphere.
To
determine
enthalpy
changes
in
high
school
laboratories,
a
coffee-cup
calorimeter
provides
fairly
accurate
results.
A
coffee-cup
calorimeter
is
composed
of
two
nested
polystyrene
cups
(“coffee
cups™).
They
can
be
placed
in
a
250
mL
beaker
for
added
stability.
Since
a
coffee-cup
calorimeter
is
open
to
the
atmosphere,
it
is
also
called
a
constant-pressure
calorimeter.
As
with
any
calorimeter,
each
part
of
the
coffee-cup
calori-meter
has
an
associated
heat
capacity.
Because
these
heat
capacities
are
very
small,
however,
and
because
a
coffee-cup
calorimeter
is
not
as
accurate
as
other
calorimeters,
the
heat
capacity
of
a
coffee-cup
calorimeter
is
usually
assumed
to
be
negligible.
It
is
assumed
to
have
a
value
of
0
J/°C.
Using
a
Calorimeter
to
Determine
the
Enthalpy
of
a
Reaction
A
coffee-cup
calorimeter
is
well-suited
to
determining
the
enthalpy
changes
of
reactions
in
dilute
aqueous
solutions.
The
water
in
the
calorimeter
absorbs
(or
provides)
the
energy
that
is
released
(or
absorbed)
by
a
chemical
reaction.
When
carrying
out
an
experiment
in
a
dilute
solution,
the
solution
itself
absorbs
or
releases
the
energy.
You
can
calculate
the
amount
of
energy
that
is
absorbed
or
released
by
the
solution
using
the
equation
mentioned
earlier.
Q=mec+AT
The
mass,
m,
is
the
mass
of
the
solution,
because
the
solution
absorbs
the
heat.
When
a
dilute
aqueous
solution
is
used
in
a
calorimeter,
you
can
assume
that
the
solution
has
the
same
density
and
specific
heat
capacity
as
pure
water.
As
you
saw
above,
you
can
also
assume
that
the
heat
capacity
of
the
calorimeter
is
negligible.
In
other
words,
you
can
assume
that
all
the
heat
that
is
released
or
absorbed
by
the
reaction
is
absorbed
or
released
by
the
solution.
The
following
Sample
Problem
illustrates
how
calorimetry
can
be
used
to
determine
AH
of
a
chemical
reaction.
236
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
Sample
Problem
Determining
the
Enthalpy
of
a
Chemical
Reaction
Step
1
Step
2
Step
3
Step
4
Step
5
Step
1
Problem
Copper(Il)
sulfate,
CuSOy,
reacts
with
sodium
hydroxide,
NaOH,
in
a
double
displacement
reaction.
A
precipitate
of
copper(II)
hydroxide,
Cu(OH);,
and
aqueous
sodium
sulfate,
Na,SQ,,
is
produced.
50.0
mL
of
0.300
mol/L.
CuSO,
solution
is
mixed
with
an
equal
volume
of
0.600
mol/L.
NaOH.
The
initial
temperature
of
both
solutions
is
21.4°C.
After
mixing
the
solutions
in
the
coffee-cup
calorimeter,
the
highest
temperature
that
is
reached
is
24.6°C.
Determine
the
enthalpy
change
of
the
reaction.
Then
write
the
thermochemical
equation.
What
Is
Required?
You
need
to
calculate
AH
of
the
given
reaction.
What
Is
Given?
You
know
the
volume
of
each
solution.
You
also
know
the
initial
temperature
of
each
solution
and
the
final
temperature
of
the
reaction
mixture.
Volume
of
CuSQO,
solution,
Vg,so,
=
50.0
mL
Volume
of
NaOH
solution,
VNaon
=
50.0
mL
Initial
temperature,
T;
=
21.4°C
Final
temperature,
T;
=
24.6°C
Plan
Your
Strategy
Act
on
Your
Strategy
Determine
the
total
volume
by
adding
the
volumes
of
the
two
solutions.
Determine
the
total
mass
of
the
reaction
mixture,
assuming
a
density
of
1.00
g/mL
(the
density
of
water).
Use
the
equation
Q
=
m«c+AT
to
calculate
the
amount
of
heat
that
is
absorbed
by
the
solution
(in
J).
Assume
that
the
reaction
mixture
has
the
same
specific
heat
capacity
as
water
(c=4.184J/g+"C).
Use
the
equation
Qreaction
=
—Wsolution
t0
determine
the
amount
of
heat
that
is
released
by
the
reaction.
Determine
the
number
of
moles
of
CuSO,
and
NaOH
that
reacted.
If
necessary,
determine
the
limiting
reactant.
Use
the
amount
of
limiting
reactant
to
get
AH
of
the
reaction
(in
kJ/mol).
Use
your
AH
to
write
the
thermochemical
equation
for
the
reaction.
The
total
volume
of
the
reaction
mixture
is
50.0
mL
+
50.0
mL
=
100.0
mL
The
mass
of
the
reaction
mixture,
assuming
a
density
of
1.00
g/ml,
is
m=DV
=
{1.00
g/m¥)(100.0
mk)
=1.00
x
10%*
g
Chapter
5
Energy
and
Change
-
MHR
237
Coninued
.
S
Step2
The
amount
of
heat,
QQ,
that
is
absorbed
by
the
solution
is
(solution
=
Msolution
*
Csolution
*
AT
solution
=
(100
g)(4.184
J/g
-
°C)(24.6°C
—
21.4°C)
=1.3
x
10*]
Step
3
Based
on
the
value
of
Q
in
step
2,
the
heat
change
for
the
reaction
is
—1.3
x
103
J.
Step
4
Calculate
the
number
of
moles
of
CuSQ,
as
follows.
n=ceV
=
(0.300
mol/K)(50.0
x
107°K)
=
0.0150
mol
Calculate
the
number
of
moles
of
NaOH.
n
mol
NaOH
=
(0.600
mol/K)(50.0
x
1073
k)
=
0.300
mol
The
reactants
are
present
in
stoichiometric
amounts.
(There
is
no
limiting
reactant.)
AH
of
the
reaction,
in
kJ/mol
CuSQ,,
is
-1.3
x
10%
]
0.0150
mol
CuSO,
=
-8.9
x
10°
J/mol
CuSO,
=
-89
kJ/mol
CuSO,
The
enthalpy
change
of
the
reaction
is
—89
kJ/mol
CuSQO,.
AH
=
Step5
The
thermochemical
equation
is
CuSO4(aq)
+
ZNaOH(aq)
—
Cu(OH]z(s)
+
NaZSO4(aq)
AH
=
-89
K]
Check
Your
Solution
The
solution
has
the
correct
number
of
significant
digits.
The
units
are
correct.
You
know
that
the
reaction
was
exothermic,
because
the
temper-
ature
of
the
solution
increased.
The
calculated
AH
is
negative,
which
is
correct
for
an
exothermic
reaction.
I
Practice
Problems
9.
A
chemist
wants
to
determine
the
enthalpy
of
neutralization
for
the
following
reaction.
HCl(aq)
+
NaOH(aq)
—
NaCl(aq)
+
Hz0()
The
chemist
uses
a
coffee-cup
calorimeter
to
neutralize
completely
61.1
mL
of
0.543
mol/L
HClyq) with
42.6
mL
of
NaOH(yq).
The
initial
temperature
of
both
solutions
is
17.8°C.
After
neutralization,
the
highest
recorded
temperature
is
21.6°C.
Calculate
the
enthalpy
of
neutralization,
in
units
of
kJ/mol
of
HCl.
Assume
that
the
density
of
both
solutions
is
1.00
g/mL.
Also
assume
that
the
specific
heat
capacity
of
both
solutions
is
the
same
as
the
specific
heat
capacity
of
water.
238
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
—
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—
10.
1".
12,
)
A
chemist wants
to
determine
empirically
the
enthalpy
change
for
the
following
reaction.
Mgs)
+
2HClaq)
—
MgCly(aq)
+
Hag
The
chemist
uses
a
coffee-cup
calorimeter
to
react
0.50
g
of
Mg
ribbon
with
100
mL
of
1.00
mol/L
HClg).
The
initial
temperature
of
the
HClyq)
is
20.4°C.
After
neutralization,
the
highest
recorded
temperature
is
40.7°C.
(a)
Calculate
the
enthalpy
change,
in
kJ/mol
of
Mg,
for
the
reaction.
(b)
State
any
assumptions
that
you
made
in
order
to
determine
the
enthalpy
change.
Nitric
acid
is
neutralized
with
potassium
hydroxide
in
the
following
reaction.
HNO3(aq)
+
KOH(gq)
&>
KNOg(aq)
+
HoOy
AH
=-53.4
kJ/mol
55.0
mL
of
1.30
mol/L
solutions
of
both
reactants,
at
21.4°C,
are
mixed
in
a
calorimeter.
What
is
the
final
temperature
of
the
mixture?
Assume
that
the
density
of
both
solutions
is
1.00
g/mL.
Also
assume
that
the
specific
heat
capacity
of
both
solutions
is
the
same
as
the
specific
heat
capacity
of
water.
No
heat
is
lost
to
the
calorimeter
itself.
A
student
uses
a
coffee-cup
calorimeter
to
determine
the
enthalpy
of
reaction
for
hydrobromic
acid
and
potassium
hydroxide.
The
student
mixes
100.0
mL
of
0.50
mol/L
HBr(q)
at
21.0°C
with
100.0
mL
of
0.50
mol/L
KOHg),
also
at
21.0°C.
The
highest
temperature
that
is
reached
is
24.4°C.
Write
a
thermochemical
equation
for
the
reaction.
N\
J/
In
Practice
Problems
9,
11,
and
12,
you
used
experimental
data
to
deter-
mine
the
enthalpy
of
reaction
for
neutralization
reactions.
Neutralization
reactions
are
particularly
well
suited
to
analysis
involving
the
use
of
a
coffee-cup
calorimeter
for
a
number
of
reasons:
e
When
using
dilute
solutions
of
acids
and
bases,
you
can
assume
their
density
is
close
to
the
density
of
water.
Therefore,
you
can
easily
measure
the
volume
of
the
solutions and
calculate
their
mass.
e
Neutralization
reactions
between
dilute
strong
acids
and
dilute
strong
bases
tend
to
cause
temperature
changes
in
the
reaction
mixture
that
are
large
enough
to
be
measurable
using
a
standard
thermometer,
but
small
enough
for
safety.
o
Neutralization
reactions
take
place very
quickly.
Therefore,
the
peak
temperature
change
also
occurs
very
quickly.
There
is
little
time
for
heat
transfer
between
the
insulated
system
and
the
surroundings
to
take
place.
In
the
following
investigation,
you
will
construct
a
coffee-cup
calorimeter
and
use
it
to
determine
the
enthalpy
of
a
neutralization
reaction.
Chapter
5
Energy
and
Change
-
MHR
239
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Determining
the
Enthalpy
of
a
Neutralization
Reaction
The
neutralization
of
hydrochloric
acid
with
sodium
hydroxide
solution
is
represented
by
the
following
equation.
HCl(aq)
+
NaOH(aq)
—
NaCl(aq)
+
HZO(Z)
Using
a
coffee-cup
calorimeter,
you
will
deter-
mine
the
enthalpy
change
for
this
reaction.
Question
What
is
the
heat
of
neutralization
for
hydro-
chloric
acid
and
sodium
hydroxide
solution?
Prediction
Will
the
neutralization
reaction
be
endothermic
or
exothermic?
Record
your
prediction, and
give
reasons.
Safety
Precautions
If
you
get
any
hydrochloric
acid
or
sodium
hydroxide
solution
on
your
skin,
flush
your
skin
with
plenty
of
cold
water.
Materials
100
mL
graduated
cylinder
400
mL
beaker
2
polystyrene
cups
that
are
the
same
size
polystyrene
lid
thermometer
stirring
rod
1.00
mol/L
HCl(aq)
1.00
mol/L
NaOHgq)
240
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
JL
thermometer
stirrer
I
§/
g
lid
polystyrene
cups
,{
r
—
=
i
Al
&
|
‘
.
—
=
reaction
]
mixture
beaker
:
(optional,
|
v
for
support)
rl
=
Procedure
1.
Your
teacher
will
allow
the
hydrochloric
acid
and
sodium
hydroxide
solution
to
come
to
room
temperature
overnight.
.
Read
the
rest
of
this
Procedure
carefully
before
you
continue.
Set
up
a
graph
to
record
your
temperature
observations.
.
Build
a
coffee-cup
calorimeter,
using
the
diagram
above
as
a
guide.
You
will
need
to
make
two
holes
in
the
polystyrene
lid—one
for
the
thermometer
and
one
for
the
stirring
rod.
The
holes
should
be
as
small
as
possible
to
minimize
heat
loss
to
the
surroundings.
.
Rinse
the
graduated
cylinder
with
a
small
quantity
of
1.00
mol/L.
NaOH,g).
Use
the
cylinder
to
add
50.0
mL
of
1.00
mol/L
NaOHg,g)
to
the
calorimeter.
Record
the
initial
temperature
of
the
NaOH(,q).
(This
will
also
represent
the
initial
temperature
of
the
HCl(aq).)
The
NaOH,q)
can
burn
your skin.
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5.
Rinse
the
graduated
cylinder
with
tap
water.
Then
rinse
it
with
a
small
quantity
of
1.00
mol/L
HClag).
Quickly
and
carefully,
add
50.0
mL
of
1.00
mol/L
HCl(g)
to
the
NaOH4q)
in
the
calorimeter.
The
HCl(,q)
can
burn
your
skin.
6.
Cover
the
calorimeter.
Record
the
temperature
every
30
s,
stirring
gently
and
continuously.
7.
When
the
temperature
levels
off,
record
the
final
temperature,
T%.
8.
If
time
permits,
repeat
steps
4
to
7.
Analysis
1.
Determine
the
amount
of
heat
that
is
absorbed
by
the
solution
in
the
calorimeter.
2.
Use
the
following
equation
to
determine
the
amount
of
heat
that
is
released
by
the
reaction:
_Qreaction
=
Qsolution
3.
Determine
the
number
of
moles
of
HClq)
and
NaOH(yq)
that
were
involved
in
the
reaction.
4.
Use
your
knowledge
of
solutions
to
explain
what
happens
during
a
neutralization
reac-
tion.
Use
equations
in
your
answer.
Was
heat
released
or
absorbed
during
the
neutralization
reaction?
Explain
your
answer.
Conclusion
5.
Use
your
results
to
determine
the
enthalpy
change
of
the
neutralization
reaction,
in
kJ/mol
of
NaOH.
Write
the
thermochemical
equation
for
the
neutralization
reaction.
Applications
6.
When
an
acid
gets
on
your
skin,
why
must
you
flush
the
area
with
plenty
of
water
rather
than
neutralizing
the
acid
with
a
base?
7.
Suppose
that
you had
added
solid
sodium
hydroxide
pellets
to
hydrochloric
acid,
instead
of
adding
hydrochloric
acid
to
sodium
hydroxide
solution?
(a)
Do
you
think
you
would
have
obtained
a
different
enthalpy
change?
(b)
Would
the
enthalpy
change
have
been
higher
or
lower?
{¢c)
How
can
you
test
your
answer?
Design
an
investigation,
and
carry
it
out
with
the
permission
of
your
teacher.
(d)
What
change
do
you
need
to
make
to
the
thermochemical
equation
if
you
perform
the
investigation
using
solid
sodium
hydroxide?
8.
In
Investigation
5-A,
you
assumed
that
the
heat
capacity
of
your
calorimeter
was
0
J/°C.
(a)
Design
an
investigation
to
determine
the
actual
heat
capacity
of
your
coffee-cup
calorimeter,
Ceaiorimeter-
Include
equations
for
any
calculations
you
will
need
to
do.
If
time
permits,
have
your
teacher
approve
your
procedure
and
carry
out
the
investiga-
tion.
Hint:
If
you
mix
hot
and
cold
water
together
and
no
heat
is
absorbed
by
the
calorimeter
itself,
then
the
amount
of
heat
absorbed
by
the
cold
water
should
equal
the
amount
of
heat
released
by
the
hot
water.
If
more
heat
is
released
by
the
hot
water
than
is
absorbed
by
the
cold
water,
the
difference
must
be
absorbed
by
the
calorimeter.
(b)
Include
the
heat
capacity
of
your
calorimeter
in
your
calculations
for
AH
o
tralization
-
Use
the
following
equation:
—Qreaction
=
(Msolution
*
Csolution
®*
AT)
+
(Cealorimeter
*
AT)
PROBEWARE
If
you
have
access
to
probeware,
do
Probeware
Investigation
5-A,
or
a
similar
investigation
from
a
probeware
company.
Chapter
5
Energy
and
Change
-
MHR
241
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Section
Summary
In
this
section,
you
measured
the
enthalpy
change
of
a
reaction
by
calorimetry.
You
may
have
noticed
that
the
reactions
you studied
in
this
section
involved
relatively
small
energy
changes.
How
do
chemists
work
quantitatively
with
some
of
the
large
energy
changes
you
examined
in
section
5.17
In
the
next
section,
you
will
learn
how
to
calculate
the
heat
of
reaction
for
virtually
any
chemical
reaction
or
physical
change.
This
powerful
skill
will
allow
you
to
find
heats
of
reaction
without
carrying
out
experiments.
Section
Review
O
Distinguish
between
heat
capacity
and
specific
heat
capacity.
(2]
What
properties
of
polystyrene
make
it
a
suitable
material
for
a
constant-pressure
calorimeter?
Why
are
polystyrene
coffee
cups
not
suitable
for
a
constant-volume
calorimeter?
(3]
Suppose
that
you
use
concentrated
reactant
solutions
in
an
experiment
with
a
coffee-cup
calorimeter.
Will
you
make
the
same
assumptions
that
you
did
when
you
used
dilute
solutions?
Explain.
O
©
Concentrated
sulfuric
acid
can
be
diluted
by
adding
it
to
water.
The
reaction
is
extremely
exothermic.
In
this
question,
you
will
design
an
experiment
to
measure
the
enthalpy
change
(in
kJ/mol)
for
the
dilution
of
concentrated
sulfuric
acid.
Assume
that
you
have
access
to
any
equipment
in
your
school’s
chemistry
laboratory.
Do
not
carry
out
this
experiment.
(a)
State
the
equipment
and
chemicals
that
you
need.
(b)
Write
a
step-by-step
procedure.
(c)
Set
up
an
appropriate
data
table.
(d)
State
any
information
that
you
need.
(e)
State
any
simplifying
assumptions
that
you
will
make.
©
©
A
chemist
mixes
100.0
mL
of
0.050
mol/L
potassium
hydroxide
with
100.0
mL
of
0.050
mol/L
nitric
acid
in
a
constant-pressure
calorimeter.
The
temperature
of
the
reactants
is
21.01°C.
The
temperature
of
the
products
is
21.34°C.
(a)
Write
a
thermochemical
equation
for
the
reaction.
(b)
If
you
performed
this
investigation,
would
you
change
the
procedure?
If
so,
how?
O
O
Explain
why
a
bomb
calorimeter
may
not
provide
accurate
results
for
determining
the
enthalpy
of
a
reaction.
©
D
From
experience,
you
know
that
you
produce
significantly
more
heat
when
you
are
exercising
than
when
you
are
resting.
Scientists
can
study
the
heat
that
is
produced
by
human
metabolism
reactions
using
a
“human
calorimeter.”
Based
on
what
you
know
about
calorimetry,
how
would
you
design
a
human
calorimeter?
What
variables
would
you
control
and study
in
an
investigation
using
your
calorimeter?
Write
a
brief
proposal
outlining
the
design
of
your
human
calorimeter
and
the
experimental
approach
you
would
take.
242
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
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Hess’s
Law
of
Heat
Summation
In
section
5.2,
you
used
a
coffee-cup
calorimeter
to
determine
the
quantity
of
heat
that
was
released
or
absorbed
in
a
chemical
reaction.
Coffee-cup
calorimeters
are
generally
used
only
for
dilute
aqueous
solutions.
There
are
many
non-aqueous
chemical
reactions,
however.
There
are
also
many
reactions
that
release
so
much
energy
they
are
not
safe
to
perform
using
a
coffee-cup
calorimeter.
Imagine
trying
to
determine
the
enthalpy
of
reaction
for
the
detonation
of
nitroglycerin,
an
unstable
and
powerfully
explosive
compound.
Furthermore,
there
are
reactions
that
occur
too
slowly
for
the
calorimetric
method
to
be
practical.
(You
will
learn
more
about
rates
of
reactions
in
the
next
chapter.)
Chemists
can
determine
the
enthalpy
change
of
any
reaction
using
an
important
law,
known
as
Hess’s
law
of
heat
summation.
This
law
states
that
the
enthalpy
change
of
a
physical
or
chemical
process
depends
only
on
the
beginning
conditions
(reactants)
and
the
end
conditions
(products).
The
enthalpy
change
is
independent
of
the
pathway
of
the
process
and
the
number
of
intermediate
steps
in
the
process.
It
is
the
sum
of
the
enthalpy
changes
of
all
the
individual
steps
that
make
up
the
process.
For
example,
carbon
and
oxygen
can
form
carbon
dioxide
via
two
pathways.
1.
Carbon
can
react
with
oxygen
to
form
carbon
monoxide.
The
carbon
monoxide
then
reacts
with
oxygen
to
produce
carbon
dioxide.
The
two
equations
below
represent
this
pathway.
Cis)
+
502t
>
COgg)
AH’®
=
-110.5
kJ
COg)
+
502
—
COxy
AH"
=-283.0k]
2.
Carbon
can
also
react
with
oxygen
to
produce
carbon
dioxide
directly.
Cs)
+
Oz(g)
=
CO2q)
AH®
=-393.5
k]
In
both
cases,
the
net
result
is
that
one
mole
of
carbon
reacts
with
one
mole
of
oxygen
to
produce
one
mole
of
carbon
dioxide.
(In
the
first
pathway,
all
the
carbon
monoxide
that
is
produced
reacts
with
oxygen
to
form
carbon
dioxide.)
Notice
that
the
sum
of
the
enthalpy
changes
for
the
first
pathway
is
the
same
as
the
enthalpy
change
for
the
second
pathway.
Examine
Figure
5.13
to
see
how
to
represent
the
two
pathways
using
one
enthalpy
diagram.
A
G
+
Oy
:
o
-
AH®
=-110.5
kJ
2l
coy+lo
|
2
@
+
202
|
)
_ccu
§
;
=
=
L
AH®
=-393.5
k]
c
(4]
@
AH°
=-283.0
k]
i
COyg)
@
Section
Preview/
Specific
Expectations
In
this
section,
you
will
m
explain
Hess's
law
of
heat
summation,
using
examples
m
apply
Hess’s
law
to
solve
problems,
including
problems
that
involve
data
obtained
through
experimentation
m
calculate
heat
of
reaction
using
given
enthalpies
of
formation
m
communicate
your
under-
standing
of
the
following
terms:
Hess’s
law
of
heat
summation,
formation
reactions,
standard
molar
enthalpy
of
formation
(AH's)
EMZERE]
Carbon
dioxide
can
he
formed
by
the
reaction
of
oxygen
with
carbon
to
form
carbon
monoxide,
followed
by
the
reaction
of
carbon
monoxide
with
oxygen.
Carbon
dioxide
can
also
be
formed
directly
from
carbon
and
oxygen.
No
matter
which
pathway
is
used,
the
enthalpy
change
of
the
reaction
is
the
same.
Chapter
5
Energy
and
Change
«
MHR
243
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The
routes
that
cyclists
take
to
get
from
the
starting
point
to
the
finishing
point
has
no
effect
on
the
nef
change
in
the
cyclists’
gravitational
potential
energy.
One
way
to
think
about
Hess’s
law
is
to
compare
the
energy
changes
that
occur
in
a
chemical
reaction
with
the
changes
in
the
potential
energy
of
a
cyclist
on
hilly
terrain.
This
comparison
is
shown
in
Figure
5.14.
starting
point
cyclist
A
Aheight
oy
cyclist
B
SN
©*
finishing
point
Hess’s
law
allows
you
to
determine
the
energy
of
a
chemical
reaction
without
directly
measuring
it.
In
this
section,
you
will
examine
two
ways
in
which
you
can
use
Hess’s
law
to
calculate
the
enthalpy
change
of
a
chemical
reaction:
1.
by
combining
chemical
equations
algebraically
2.
by
using
the
enthalpy
of
a
special
class
of
reactions
called
formation
reactions
Combining
Chemical
Equations
Algebraically
According
to
Hess’s
law,
the
pathway
that
is
taken
in
a
chemical
reaction
has
no
effect
on
the
enthalpy
change
of
the
reaction.
How
can
you
use
Hess’s
law
to
calculate
the
enthalpy
change
of
a
reaction?
One
way
is
to
add
equations
for
reactions
with
known
enthalpy
changes,
so
that
their
net
result
is
the
reaction
you
are
interested
in.
For
example,
you
can
combine
thermochemical
equations
(1)
and
(2)
below
to
find
the
enthalpy
change
for
the
decomposition
of
hydrogen
peroxide,
equation
(3).
(1)
H,054
—
Hz(g)
+
Oz(g)
AH®
=
+188
k]
(2)
Hyg
+
5Oz
—
Hz0p)
AH®
=
-286
K]
(3)
HZOZ(@
—>
HZO(g)
+
%Oz(g)
AH’
=7
Carefully
examine
equation
(3),
the
target
equation.
Notice
that
H,0,
is
on
the
left
(reactant)
side,
while
H,O
and
%Oz
are
on
the
right
(product)
side.
Now
examine
equations
(1)
and
(2).
Notice
which
sides
of
the
equations
H,O,
and
H,O
are
on.
They
are
on
the
correct
sides,
based
on
equation
(3).
Also
notice
that
hydrogen
does
not
appear
in
equation
(3).
Therefore,
it
must
cancel
out
when
equations
(1)
and
(2)
are
added.
Since
there
is
one
mole
of
Hy(g)
on
the
product
side
of
equation
(1)
and
one
mole
of
Ha(g)
on
the
reactant
side
of
equation
(2),
these
two
terms
cancel.
Set
up
equations
(1)
and
(2)
as
shown
on
the
next
page.
Add
the
products
and
the
reactants.
Then
cancel
any
substances
that
appear
on
opposite
sides.
244
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
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(1)
HzOz(g)
—
Hz(g]
+
Oz(g)
AH®
=+188
k]
(2)
Ha(g
+
3
Oz
=
Hz0(
AH®
=
—286
kJ
H3O0z¢)
+Hjg)
+
%Oz(g)
—
H30()
+
Oz
+Hz
AH
=7
or
(3)
HZOZ(E)
—
HZO(g)
+
%Oz(g)
AH®
=7
Equations
(1)
and
(2)
add
to
give
equation
(3).
Therefore,
you
know
that
the
enthalpy
change
for
the
decomposition
of
hydrogen
peroxide
is
the
sum
of
the
enthalpy
changes
of
equations
(1)
and
(2).
HOz
—>
HzO()
+
302
AH"
=188
kJ
—
286
k]
=
-98
k]
Figure
5.15
illustrates
this
combination
of
chemical
equations
in
an
enthalpy
diagram.
A
Hy(g)
+
Ogz(g)
A
|
equation
(1)
‘\
AH®
=188
kJ
H04()
equation
(2)
|
I
|
AHO
—
_286
k]'
l/
g
equation
(3)
GETIEERL]
The
algebraic
|
enthalpy,
H
AH"=-98
K]
combination
of
chemical
reactions
can
be
represented
in
an
enthalpy
diagram.
‘III
v
H,O()
+
302
In
the
previous
example,
you
did not
need
to
manipulate
the
two
equa-
tions
with
known
enthalpy
changes.
They
added
to
the
target
equation
as
they
were
written.
In
many
cases,
however,
you
will
need
to
manipulate
the
equations
before
adding
them.
There
are
two
key
ways
in
which
you
can
manipulate
an
equation:
1.
Reverse
an
equation
so
that
the
products
become
reactants
and
the
reactants
become
products.
When
you
reverse
an
equation,
you
need
to
change
the
sign
of
AH"(multiply
by
—1).
2.
Multiply
each
coefficient
in
an
equation
by
the
same
integer
or
fraction.
When
you
multiply
an
equation,
you
need
to
multiply
AH"
by
the
same
number.
Examine
the
following
Sample
Problem
to
see
how
to
manipulate
equations
so
that
they
add
to
the
target
equation.
Try
the
problems
that
follow
to
practise
finding
the
enthalpy
change
by
adding
equations.
I
Sample
Problem
Using
Hess's
Law
to
Determine
Enthalpy
Change
Problem
One
of
the
methods
that
the
steel
industry
uses
to
obtain
metallic
iron
is
to
react
iron(III)
oxide,
Fe,O5,
with
carbon
monoxide,
CO.
FeyO3(6)
+
SCO(g)
—
3C02(g)
+
2Fe,)
\_
Chapter
5
Energy
and
Change
«
MHR
245
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PROBLEM
TIP
Before adding
chemical
equations,
be
sure
to
line
up
the
equation
arrows.
Electronic
Learning
Partner
Go
to
the
Chemistry
12
Electronic
Learning
Partner
for
more
information
about
aspects
of
material
covered
in
this
section
of
the
chapter.
\—
Coninued
.
S
Determine
the
enthalpy
change
of
this
reaction,
given
the
following
equations
and
their
enthalpy
changes.
(1)
CO(g)
+
%Oz(g)
—
COz[g)
AH®
=-283.0
k]
(2)
2Fe)
+
30y
>
Fe;03
AH'
=
-822.3k]
What
Is
Required?
You
need
to
find
AH"
of
the
target
reaction.
Fey03()
+
3C0(g)
—
3C02(g]
+
2Fe()
What
Is
Given?
You
know
the
chemical
equations
for
reactions
(1)
and
(2),
and
their
corresponding
enthalpy
changes.
Plan
Your
Strategy
Step
1
Examine
equations
(1)
and
(2)
to
see
how
they
compare
with
the
target
equation.
Decide
how
you
need
to
manipulate
equations
(1)
and
(2)
so
that
they
add
to
the
target
equation.
(Reverse
the
equation,
multiply
the
equation,
do
both,
or
do
neither).
Remember
to
adjust
AH®
accordingly
for
each
equation.
Step2
Write
the
manipulated
equations
so
that
their
equation
arrows
line
up.
Add
the
reactants
and
products
on
each
side,
and
cancel
substances
that
appear
on
both
sides.
Step3
Ensure
that
you
have
obtained
the
target
equation.
Add
AH"
for
the
combined
equations.
Act
on
Your
Strategy
Step
1
Equation
(1)
has
CO
as
a
reactant
and
CO;
as
a
product,
as
does
the
target
reaction.
The
stoichiometric
coefficients
do
not
match
the
coefficients
in
the
target
equation,
however.
To
achieve
the
same
coefficients,
you
must
multiply equation
(1)
by
3.
Equation
(2)
has
the
required
stoichiometric
coefficients,
but
Fe
and
Fe,;03
are
on
the
wrong
sides
of
the
equation.
You
need
to
reverse
equation
(2)
and
change
the
sign
of
AH".
Step
2
Multiply
each
equation
as
required,
and add them.
3x(1)
3COfg
+
3Oy
—>
3COsg
AH"®
=
3(~283.0
kJ)
-1x(2)
Fe;03(5)
—
2Fe()
+
%Oz(g)
AH®
=
—-1(—824.2
k])
FeyO3(5)
+
%Oz(g)
+
3C0(g]
—
3C02(g)
+
2Fe()
+
%fiz(g]
or
Fey03(5)
+
3C0(g)
—
SCOz(g)
+
2Feyy)
Step3
The
desired
equation
is
achieved.
Therefore,
you
can
calculate
the
enthalpy
change
of
the
target
reaction
by
adding
the
heats
of
reaction
for
the
manipulated
equations.
AH®
=
3(-283.0
kJ)
+
824.2
k]
=
—24.8
kJ
~.Fey03(5)
+
3COg)
—
3COz
+
2Fe)
AH®
=-24.8
k]
Check
Your
Solution
Because
the
equations
added
correctly
to
the
target
equation,
you
know
you
manipulated
the
equations
with
known
enthalpy
changes
correctly.
Check
to
ensure
that
you
adjusted
AH® accordingly
for
each
equation.
246
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
—
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I
Practice
Problems
N\
13.
Ethene,
C;H,4,
reacts
with
water
to
form
ethanol,
CH;CH;OHy).
C2H4(g)
+
H;0¢)
—
CH3CH,OHy
Determine
the
enthalpy
change
of
this
reaction,
given
the
following
thermochemical
equations.
(1)
CH3CH20H(5)
+
302(8)
—
3H20(5)
+
ZCOZ(g)
AH®
=
-1367
k]
(2)
CaHy(g)
+
303
—
2H30()
+
2C05(
AH®
=
-1411
K]
14.
A
typical
automobile
engine
uses
a
lead-acid
battery.
During
discharge,
the
following
chemical
reaction
takes
place.
Pbs)
+
PbOys)
+
2H2S04(¢)
=
2PbSO4(aq)
+
2H20¢)
Determine
the
enthalpy
change
of
this
reaction,
given
the
following
equations.
(1)
Pbgs)
+
PbOgs)
+
2503
—
2PbSOy4)
AH®°
=-775K]
(2)
SO3(g]
+
HzO(g)
—>
HzSO4(g]
AH®
=-133
kI
15.
Mixing
household
cleansers
can
result
in
the
production
of
hydrogen
chloride
gas,
HCl).
Not
only
is
this
gas
dangerous
in
its
own
right,
but
it
also
reacts
with
oxygen
to
form
chlorine
gas
and
water
vapour.
4HCl(g)
+
Oz
—
2Clyg
+
2H,0(g
Determine
the
enthalpy
change
of
this
reaction,
given
the
following
equations.
(1)
Hz(g)
+
Clz[g)
—
ZHCI[g)
AH®
=-185
k]
(2)
Hagg)
+
3Os()
>
HoOy
AH®
=-285.8
kJ
(3)
H,Og
—
H,0py
AH®
=—40.7
K]
16.
Calculate
the
enthalpy
change
of
the
following
reaction
between
nitrogen
gas
and
oxygen
gas,
given
thermochemical
equations
(1),
(2),
and
(3).
ZN2(g)
+
502
=
2N205
(1)
2Hz(g)
+
Oz(g
—
2H20(y)
AH®
=
-572
k]
(2)
N;Os5(g)
+
HoOgy
—
2HNO;()
AH®
=-77
K]
(3)
2Nag)
+
20p)
+
THy
-
HNOyy
AH"
=-174
k]
_
)
\
J/
Sometimes
it
is
impractical
to
use
a
coffee-cup
calorimeter
to
find
the
enthalpy
change
of
a
reaction.
You
can,
however,
use
the
calorimeter
to
find
the
enthalpy
changes
of
other
reactions,
which
you
can
combine
to
arrive
at
the
desired
reaction.
In
the
following
investigation,
you
will
determine
the
enthalpy
changes
of
two
reactions.
Then
you
will
apply
Hess’s
law
to
determine
the
enthalpy
change
of
a
third
reaction.
Chapter
5
Energy
and
Change
«
MHR
247
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]
Performing
and
recording
WEWZALT
LRI
Gl
T
T
‘Communicating
resul
Hess's
Law
and
the
Enthalpy
of
Combustion
of
Magnesium
Magnesium
ribbon
burns
in
air
in
a
highly
exothermic
combustion
reaction.
(See
equation
(1).)
A
very
bright
flame
accompanies
the
production
of
magnesium
oxide,
as
shown
in
the
photograph
below.
It
is
impractical
and
dangerous
to
use
a
coffee-cup
calorimeter
to
determine
the
enthalpy
change
for
this
reaction.
(1)
Mggs)
+
5
O2()
>
MgOg)
Instead,
you
will
determine
the
enthalpy
changes
for
two
other
reactions
(equations
(2}
and
(3)
below).
You
will
use
these
enthalpy
changes,
along
with
the
known
enthalpy
change
for
another
reaction
(equation
(4)
below),
to
deter-
mine
the
enthalpy
change
for
the
combustion
of
magnesium.
(2)
MgOg,)
+
ZHCI(aq)
—
MgClz(aq)
+
Hy0O(y
(3)
Mg
+
ZHCI(aq)
—
MgClz(aq]
+
Hz(g)
(4)
Hag)
+
302
—
H,O()
AH®
=
-285.8
kJ/mol
Notice
that
equations
(2)
and
(3)
occur
in
aqueous
solution.
You
can
use
a
coffee-cup
calorimeter
to
determine
the
enthalpy
changes
for
these
reactions.
Equation
(4)
represents
the
formation
of
water
directly
from
its
elements
in
their
standard
state.
248
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
Question
How
can
you
use
equations
(2),
(3),
and
(4)
to
determine
the
enthalpy
change
of
equation
(1)?
Prediction
Predict
whether
reactions
(2)
and
(3)
will
be
exothermic
or
endothermic.
Materials
coffee
cup
calorimeter
(2
nested
coffee
cups
sitting
in
a
250
mL
beaker)
thermometer
100
mL
graduated
cylinder
scoopula
electronic
balance
MgO
powder
Mg
ribbon
(or
Mg
turnings)
sandpaper
or
emery
paper
1.00
mol/L
HCl(aq)
Safety
Precautions
e
Hydrochloric
acid
is
corrosive.
Use
care
when
handling
it.
e
Be
careful
not
to
inhale
the
magnesium
oxide
powder.
Procedure
Part
1
Determining
AH
of
Equation
(2)
1.
Read
the
Procedure
for
Part
1.
Prepare
a
fully-
labelled
set of
axes
to
graph
your
temperature
observations.
2.
Set
up
the
coffee-cup
calorimeter.
(Refer
to
Investigation
5-A)
Using
a
graduated
cylinder,
add
100
mL
of
1.00
mol/L
HCl
g
to
the
calorimeter.
HCl(4q)
can
burn
your
skin.
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3.
Record
the
initial
temperature,
T;,
of
the
HCl(ag),
to
the
nearest
tenth
of
a
degree.
4.
Find
the
mass
of
no
more
than
0.80
g
of
MgO.
Record
the
exact
mass.
5.
Add
the
MgO
powder
to
the
calorimeter
con-
taining
the
HCl(,q).
Swirl
the
solution
gently,
recording
the
temperature
every
30
s
until
the
highest
temperature,
T%,
is
reached.
6.
Dispose
of
the
reaction solution
as
directed
by
your
teacher.
Part
2
Determining
AH
of
Equation
(3)
1.
Read
the
Procedure
for
Part
2.
Prepare
a
fully-
labelled
set
of
axes
to
graph
your
temperature
observations.
2.
Using
a
graduated
cylinder,
add
100
mL
of
1.00
mol/L
HClg)
to
the
calorimeter.
3.
Record
the
initial
temperature,
Ti,
of
the
HCl(ag),
to
the
nearest
tenth
of
a
degree.
4.
If
you
are
using
magnesium
ribbon
(as
opposed
to
turnings),
sand
the
ribbon.
Accurately
determine
the
mass
of
no
more
than
0.50
g
of
magnesium.
Record
the
exact
mass.
5.
Add
the
Mg
to
the
calorimeter
containing
the
HCl(ag).
Swirl
the
solution
gently,
recording
the
temperature
every
30
s
until
the
highest
temperature,
T,
is
reached.
6.
Dispose
of
the
solution
as
directed
by
your
teacher.
Analysis
1.
Use
the
equation
Q
=
m«c+AT
to
determine
the
amount
of
heat
that
is
released
or
absorbed
by
reactions
(2)
and
(3).
List
any
assumptions
you
make.
2.
Convert
the
mass
of
MgO
and
Mg
to
moles.
Calculate
AH
of
each
reaction
in
units
of
kJ/mol
of
MgO
or
Mg.
Remember
to
put
the
proper
sign
(+
or
—)
in
front
of
each
AH
value.
3.
Algebraically
combine
equations
(2),
(3),
and
(4),
and
their
corresponding
AH
values,
to
get
equation
(1)
and
AH
of
the
combustion
of
magnesium.
4.(a)
Your
teacher
will
tell
you
the
accepted
value
of
AH
of
the
combustion
of
magnesium.
Based
on
the
accepted
value,
calculate
your
percent
error.
(b)
Suggest
some
sources
of
error
in
the
investigation.
In
what
ways
could you
improve
the
procedure?
5.
What
assumption
did
you
make
about
the
amount
of
heat
that
was
lost
to
the
calorimeter?
Do
you
think
that
this
is
a
fair
assumption?
Explain.
6.
Why
was
it
fair
to
assume
that
the
hydrochlo-
ric
acid
solution
has
the
same
density and
specific
heat
capacity
as
water?
Conclusion
7.
Explain
how
you
used
Hess’s
law
of
heat
sum-
mation
to
determine
AH
of
the
combustion
of
magnesium.
State
the
result
you
obtained
for
the
thermochemical
equation
that
corresponds
to
chemical
equation
(1).
Extension
8.
Design
an
investigation
to
verify
Hess’s
law,
using
the
following
equations.
(1)
NaOH)
—
Na+(aq)
+
OH_(aq)
(2)
NaOH)
+
H+(aq)
I
Cl_(aq)
—
Na+(aq)
+
Cl_(aq)
+
HZO(@
(3)
Na+(aq)
+
OH
(g
+
H+(aq]
+
Cl_(aq)
—
Na'*(aq)
+
Cl
(aq)
+
H2Oy
Assume
that
you
have
a
coffee-cup
calorimeter,
solid
NaOH,
1.00
mol/L
HClg),
1.00
mol/L
NaOHq),
and
standard
laboratory
equipment.
Write
a
step-by-step
procedure
for
the
investigation.
Then
outline
a
plan
for
analyzing
your
data.
Be
sure
to
include
appropriate
safety
precautions.
If
time
permits,
obtain
your
teacher’s
approval
and
carry
out
the
investigation.
Chapter
5
Energy
and
Change
«
MHR
249
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Using
Standard
Molar
Enthalpies
of
Formation
You
have
learned
how
to
add
equations
with
known
enthalpy
changes
to
obtain
the
enthalpy
change
for
another
equation.
This
method
can
be
time-consuming
and
difficult,
however,
because
you
need
to
find
reactions
with
known
enthalpy
changes
that
will
add
to
give
your
target
equation.
There
is
another
way
to
use
Hess’s
law
to
find
the
enthalpy
of
an
equation.
Formation
Reactions
In
Investigation
5-B,
you
used
the
reaction
of
oxygen
with
hydrogen
to
form
water.
Reactions
like
this
one
are
known
as
formation
reactions.
In
a
formation
reaction,
a
substance
is
formed
from
elements
in
their
standard
states.
The
enthalpy
change
of
a
formation
reaction
is
called
the
standard
molar
enthalpy
of
formation,
AH’;.
The
standard
molar
enthalpy
of
forma-
tion
is
the
quantity
of
energy
that
is
absorbed
or
released
when
one
mole
of
a
compound
is
formed
directly
from
its
elements
in
their
standard
states.
Some
standard
molar
enthalpies
of
formation
are
listed
in
Table
5.3.
Notice
that
the
standard
enthalpies
of
formation
of
most
compounds
are
negative.
Thus,
most
compounds
are
more
stable
than
the
elements
they
are
made
from.
Table
5.3
Selected
Standard
Molar
Enthalpies
of
Formation
(W)
TG
T
|
Iy,
i
|
Formation
equations
CO
-110.5
Cig)
+
3029
=
COg)
COy)
-393.5
Cs)+
Oz)
=
COx)
CHa)
~74.6
Cs)
+
2Hyg
—
CHygy
CH;30Hy,
~238.6
Cg+
2Hyg
+
302g
—
CH30Hy,
C.H5;0H
—-277.6
2C()
+
3Hyg)
+
30,
—
CH;0H(
CeHg(e)
+49.0
BCs)
+
3Hy
g
—>
CgHgle
CsH1206(s)
—1274.5
6C(s)
+
6Hy(g)
+
303(
—>
CeHi206(s)
H,0
—285.8
Ha+
202
—>
HaOgy
H,0()
—241.8
Hy(g)+
302
=
H20(g
CaCly
—-795.4
Cagg)
+
Clyg)
—
CaClyg
CaCOj)
-1206.9
Cagg)+
Cg+
304
—
CaCOsy
NaClg
-411.1
Na)+
3Clyg
—
NaClg
HCl,
-92.3
3Hog+
3Clyg
—
HClg
HClgq)
—-167.5
3Has+
3Cla
—
HClggy
By
definition,
the
enthalpy
of
formation
of
an
element
in
its
standard
state
is
zero.
The
standard
state
of
an
element
is
usually
its
most
stable
form
under
standard
conditions.
Recall,
from
section
5.1,
that
standard
conditions
are
25°C
and
100
kPa
(close
to
room
temperature
and
pressure).
Therefore,
the
standard
state
of
nitrogen
is
Ny).
The
standard
state
of
magnesium
is
Mg.
Some
elements
exist
in
more
than
one
form
under
standard
condi-
tions.
For
example,
carbon
can
exist
as
either
graphite
or
diamond,
as
shown
in
Figure
5.16.
Graphite
is
defined
as
the
standard
state
of
carbon.
Therefore,
the
standard
enthalpy
of
formation
of
graphite
carbon
is
0
kJ/mol.
The
standard
enthalpy
of
formation
of
diamond
is
1.9
kJ/mol.
Another
example
is
oxygen,
O;).
Oxygen
also
exists
in
the
form
of
ozone,
250
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
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Og3(g),
under
standard
conditions.
The
diatomic
molecule
is
defined
as
the
standard
state
of
oxygen,
however,
because
it
is
far
more
stable
than
ozone.
Therefore,
the
standard
enthalpy
of
formation
of
oxygen
gas,
Oy,
is
0
kJ/mol.
The
standard
enthalpy
of
formation
of
ozone
is
143
kJ/mol.
Carbon
can
exist
as
graphite
or
diamond
under
standard
conditions.
It
can,
however,
have
only
one
standard
state.
Carbon’s
standard
state
is
graphite.
Cigraphite)
—
Cidiamond)
AH¢
=
1.9
kdJ/mol
When
writing
a
formation
equation,
always
write
the
elements
in
their
standard
states.
For
example,
examine
the
equation
for
the
formation
of
water
directly
from
its
elements
under
standard
conditions.
Hag)
+
%Oz(g)
—
H;0
AH't=-285.8K]
A
formation
equation
should
show
the
formation
of
exactly
one
mole
of
the
compound
of
interest.
The
following
equation
shows
the
formation
of
benzene,
CgHg
under
standard
conditions.
6C(graphite)
+
3H2(g)
—>
CGHG(Z)
AH’s
=
49.1
k]
I
Practice
Problems
17.
Write
a
thermochemical
equation
for
the
formation
of
each
substance.
Be
sure
to
include
the
physical
state
of
all
the
elements
and
compounds
in
the
equation.
You
can
find
the
standard
enthalpy
of
formation
of
each
substance
in
Appendix
E.
(a)
CH,4
(b)
NaCl
{(c)
MgO
(d)
CaCOs
18.
Liquid
sulfuric
acid
has
a
very
large
negative
standard
enthalpy
of
formation
(—814.0
kJ/mol).
Write
an
equation
to
show
the
formation
of
liquid
sulfuric
acid.
The
standard
state
of
sulfur
is
rhombic
sulfur
(S).
19.
Write
a
thermochemical
equation
for
the
formation
of
gaseous
cesium.
The
standard
enthalpy
of
formation
of
Cs()
is
76.7
k]J/mol.
20.
Solid
phosphorus
is
found
in
two
forms:
white
phosphorus
(P,)
and
red
phosphorus
(P).
White
phosphorus
is
the
standard
state.
(a)
The
enthalpy
of
formation
of
red
phosphorus
is
—17.6
kJ/mol.
Write
a
thermochemical
equation
for
the
formation
of
red
phosphorus.
(b)
32.6
g
of
white
phosphorus
reacts
to
form
red
phosphorus.
What
is
the
enthalpy
change?
—
_J
Chapter
5
Energy
and
Change
«
MHR
251
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CONCEPT
CHECK
-
“Using
enthalpies
of
formation
is
like
a
shortcut
for
adding
equations
to
obtain
AH"."
Do
you
agree
with
this
statement?
Explain
your
answer.
Calculating
Enthalpy
Changes
You
can
calculate
the
enthalpy
change
of
a
chemical
reaction
by
adding
the
heats
of
formation
of
the
products
and
subtracting
the
heats
of
forma-
tion
of
the
reactants.
The
following
equation
can
be
used
to
determine
the
enthalpy
change
of
a
chemical
reaction.
AH"
=
X(nAH’;
products)
—
X(nAH";
reactants)
In
this
equation,
n
represents
the
molar
coefficient
of
each
compound
in
the
balanced chemical
equation
and
£
means
“the
sum
of.”
As
usual,
you
need
to
begin
with
a
balanced chemical
equation.
If
a
given
reactant
or
product
has
a
molar
coefficient
that
is
not
1,
you
need
to
multiply
its
AH";
by
the
same
molar
coefficient.
This
makes
sense
because
the
units
of
AH";
are
k]/mol.
Consider,
for
example,
the
complete
combustion
of
methane,
CHy.
CHy(g)
+
202
—
COqg
+
2H,0g
Using
the
equation
for
the
enthalpy
change,
and
the
standard
enthalpies
of
formation
in
Appendix
E,
you
can
calculate
the
enthalpy
change
of
this
reaction.
AH®
=
[(AH’;
of
COZ(g))
+
2(AH’¢
of
HZO(g))]
—
[1{AH¢
of
CH4(g])
+
2(AH’¢
of
Oz(g))]
Substitute
the
standard
enthalpies
of
formation
from
Appendix
E
to
get
the
following
calculation.
AH®
=
[(-393.5
k]J/mol)
+
2(-241.8
k]J/mol)]
—
[(-74.8
kJ/mol)
+
2(0
k]/mol)]
=
-802.3
kJ/mol
of
CH,
How
does
this
method
of
adding
heats
of
formation
relate
to
Hess’s
law?
Consider
the
equations
for
the
formation
of
each
compound
that
is
involved
in
the
reaction
of
methane
with
oxygen.
(1)
Hpg
+
50z
—>
HoOg
AH';=-241.8K]
(2)
Cis)
+
Oz(g)
&>
CO2q
AH’t=-393.5K]J
(3}
Cg)
+
2Hpg
—
CHyg
AH't=-74.6K]
There
is
no
equation
for
the
formation
of
oxygen,
because
oxygen
is
an
element
in
its
standard
state.
By
adding
the
formation
equations,
you
can
obtain
the
target
equation.
Notice
that
you
need
to
reverse
equation
(3)
and
multiply
equation
(1)
by
2.
2
x
(1)
2Hy(g)
+
Oz(g)
=
2H,0(
AH’;
=
2(-241.8)
kJ
2)
Cis)
+
Ozg
—
COyg)
AH’¢
=
-393.5
kJ
—1
x
(3)
CHyg
—
G
+
2Hyg
AHt=—1(-74.6)
kJ
CHy(g)
+
202(g)
+
L)
+
2Hzg)
=
2H2Ogg)
+
COyg)
+L(s)
+
2Hz(g)
or
CH4(g)
+
Zoz(g)
—
ZHZO(g)
+
COz(g)
Add
the
manipulated
AH";
values:
AH"
=
2(—241.8)
kJ
—
393.5
k]
+
74.6
k]J.
=-802.3
kJ
This
value
of
AH"
is
the
same
as
the
value
you
obtained
using
AH";
data.
When
you
used
the
addition
method,
you
performed
the
same
operations
on
the
enthalpies
of
formation
before
adding
them.
Therefore,
using
enthalpies
of
formation
to
determine
the
enthalpy
of
a
reaction
is
consistent
with
Hess’s
law.
Figure
5.17
shows
the
general
process
for
determining
the
enthalpy
of
a
reaction
from
enthalpies
of
formation.
252
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
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A
elements
(decomposition)
—AH;
R
——
,@
AH;
(formation)
reactants
B
o
-
o
__
enthalpy,
H
|
)
v
products
@
AH},,
=
Y(nAH¢products)
—
>.(nAH¢reactants)
=
GETZEREA
The
overall
enthalpy
change
of
any
reaction
is
the
sum
of
the
enthalpy
change
of
the
decomposition
of
the
reactants
to
their
elements
and
the
enthalpy
change
of
the
forma-
tion
of
the
products
from
their
elements.
It
is
important
to
realize
that,
in
most
reactions,
the
reactants
do
not
actually
break
down
into
their
elements
and
then
react
to
form
products.
Since
there
is
extensive
data
about
enthalpies
of
formation,
however,
it
is
useful
to
calculate
the
overall
enthalpy
change
this
way.
Moreover,
according
to
Hess’s
law,
the
enthalpy
change
is
the
same,
regardless
of
the
pathway.
(In
Chapter
6,
you
will
learn
more
about
the
mechanisms
by
which
compounds
and
elements
react
to
form
different
elements
and
compounds.)
Examine
the
following
Sample
Problem
to
see
how
to
use
enthalpies
of
formation
to
determine
the
enthalpy
change
of
a
reaction.
Then
try
the
Practice
Problems
that
follow.
I
Sample
Problem
VSR
G
EIT
I
il
Dl
EYal
]y
Problem
Iron(IlI)
oxide
reacts
with
carbon
monoxide
to
produce
elemental
iron
and
carbon
dioxide.
Determine
the
enthalpy
change
of
this
reaction,
using
known
enthalpies
of
formation.
Fe,O3(6)
+
3C0(g)
—
3C02(g)
+
2Fe(y)
What
Is
Required?
You
need
to
find
AH"
of
the
given
chemical
equation,
using
AH";
data.
What
Is
Given?
From
Appendix
E,
you
can
obtain
the
enthalpies
of
formation.
AH’¢
of
Fe;O3(5)
=
—824.2
kJ/mol
AH’s
of
CO)
=-110.5
kJ/mol
AH’;
of
COz(g)
=-393.5
kJ/mol
AH’¢
of Fe(s)
=
0
kJ/mol
(by
definition)
Plan
Your
Strategy
Multiply
each
AH";
value
by
its
molar
coefficient
from
the
balanced
chemical
equation.
Substitute
into
the
following
equation,
and
then
solve.
AH’®
=
X(nAH’¢
products)
—
X(nAH’;
reactants)
\
CONCEPT
CHECK
You
saw
the
reaction
between
iron(lll)
oxide
and
carbon
monoxide
in
the
Sample
Problem
on
page
245.
Which
method
for
determining
the
enthalpy
of
reaction
do
you
prefer?
Explain
your
answer.
Chapter
5
Energy
and
Change
*
MHR
253
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e
N
Act
on
Your
Strategy
AH®
=
X(nAH’¢
products)
—
Z(nAH’¢
reactants)
=
[3(AH’;
COyg))
+
2(AH’t
Fe)]
—
[(AH’t
Fe303(5))
+
3(AH’t
CO(g))]
=
[(-393.5
kJ/mol)
+
2(0
kJ/mol)]
—
[(-824.2
k]J/mol)
+
3(—-110.5
kJ/mol)]
=
—24.8
kJ/mol
~Fey03(5)
+
3COg
—
3CO;g)
+
2Fe)
AH®
=
-24.8
kJ/mol
Check
Your
Solution
A
balanced
chemical
equation
was
used
in
the
calculation.
The
number
of
significant
digits
is
correct.
The
units
are
also
correct.
N—
7
I
Practice
Problems
—
21.
Hydrogen
can
be
added
to
ethene,
C;H,4,
to
obtain
ethane,
C;Hs.
CoHagg)
+
Hagg)
—
CaHegg
Show
that
the
equations
for
the
formation
of
ethene
and
ethane
from
their
elements
can
be
algebraically
combined
to
obtain
the
equation
for
the
addition
of
hydrogen
to
ethene.
22.
Zinc
sulfide
reacts
with
oxygen
gas
to
produce
zinc
oxide
and
sulfur
dioxide.
27nS()
+
302
—
2Zn0g)
+
2504
Write
the
chemical
equation
for
the
formation
of
the
indicated
number
of
moles
of
each
compound
from
its
elements.
Algebraically
combine
these
equations
to
obtain
the
given
equation.
23.
Small
amounts
of
oxygen
gas
can
be
produced
in
a
laboratory
by
heating
potassium
chlorate,
KClO3.
2KClO3¢)
—
2KClg)
+
303
Calculate
the
enthalpy
change
of
this
reaction,
using
enthalpies
of
formation
from
Appendix
E.
24.
Use
the
following
equation
to
answer
the
questions
below.
CH3;0Hy,)
+
1-502[g)
—
COz(g)
+
ZHZO(g)
(a)
Calculate
the
enthalpy
change
of
the
complete
combustion
of
one
mole
of
methanol,
using
enthalpies
of
formation.
(b)
How
much
energy
is
released
when
125
g
of
methanol
undergoes
complete
combustion?
\
J/
Section
Summary
In
this
section,
you
learned
how
to
calculate
the
enthalpy
change
of
a
chemical
reaction
using
Hess’s
law
of
heat
summation.
Enthalpies
of
reaction
can
be
calculated
by
combining
chemical
equations
algebraically
or
by
using
enthalpies
of
formation.
Hess’s
law
allows
chemists
to
determine
enthalpies
of
reaction
without
having
to
take
calorimetric
measurements.
In
the
next
section,
you
will
see
how
the
use
of
energy
affects
your
lifestyle
and
your
environment.
254
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
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Section
Review
(1]
Explain
why
you
need
to
reverse
the
sign
of
AH*
when
you
reverse
an
equation.
Use
an
example
in
your
answer.
O
O
In
section
5.3,
you learned
two
methods
for
calculating
enthalpy
changes
using
Hess’s
law.
If
you had
only
this
textbook
as
a
reference,
which
method
would
allow
you
to
calculate
enthalpy
changes
for
the
largest
number
of
reactions?
Explain
your
answer.
©
©
In
the
early
1960s,
Neil
Bartlett,
at
the
University
of
British
Columbia,
was
the
first
person
to
synthesize
compounds
of
the
noble
gas
xenon.
A
number
of
noble
gas
compounds
(such
as
XeF,,
XeF,,
XeFg,
and
XeOj3)
have
since
been
synthesized.
Consider
the
reaction
of
xenon
difluoride
with
fluorine
gas
to
produce
xenon
tetrafluoride.
Xng(g)
+
Fz(g)
—>
XeF4(S)
Use
the
following
standard
molar
enthalpies
of
formation
to
calculate
the
enthalpy
change
for
this
reaction.
Compound
|
AH’;
(kJ/mol)
Xer(g)
-108
XeF
(g
-251
O
©
Calculate
the
enthalpy
change
of
the
following
reaction,
given
equations
(1),
(2),
and
(3).
2H3BO3(aq)
—
BZOS(S)
+
3H20(£)
(1)
H3BO3(aq]
—
HBOz(aq)
+
HyOp
AH'
=-0.02
K]
(2)
H2B407(5)
+
HzO(g)
—
4HBOz(aq)
AH®
=-11.3
k]
(3)
H3B407()
=
2B3203(5)
+
HaOyp
AH®
=
17.5
K]
©
©
The
standard
molar
enthalpy
of
formation
of
calcium
carbonate
is
—1207.6
kJ/mol.
Galculate
the
enthalpy
of
formation
of
calcium
oxide,
given
the
following
equation.
CaOg)
+
COy
—
CaCO3
AH®
=-178.1
k]
O
O
A
classmate
is
having
difficulty
understanding
Hess’s
law.
Write
a
few
paragraphs
to
explain
the
law.
Include
examples,
diagrams,
and
an
original
analogy.
©
©
In
your
own
words,
explain
why
using
enthalpies
of
formation
to
determine
enthalpy
of
reaction
depends
on
Hess’s
law.
Include
an
example.
Chapter
5
Energy
and
Change
-
MHR
255
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Section
Preview/
Specific
Expectations
In
this
section,
you
will
m
compare
the
efficiency
and
environmental
impact
of
conventional
and
alternative
sources
of
energy
m
communicate
your
under-
standing
of
the
following
terms:
non-renewable,
renewable
The
energy
that
Canadians
use
comes
from
a
variety
of
sources.
What
factors
account
for
the
changes
you
can
see
in
this
graph?
How
do
you
think
energy
use
has
changed
since
19967
Energy
Sources
Canadians
depend
on
energy
sources,
such
as
those
listed
in
Figure
5.18,
to
power
vehicles,
light
and
heat
buildings, and
manufacture
products
that
support
our
lives
and
lifestyles.
As society’s
needs
for
energy
and
energy-using
products
grow,
scientists
and
technologists
search
for
more
economical
and
environmentally
responsible
ways
to
meet
these
needs.
In
this
section,
you
will
compare
energy
sources
based
on
their
efficiency
and
environmental
impact.
Primary
Energy
by
Source,
Canada,
1871
to
1996
(Percent
of
Energy
Consumption)
Percent
0
-
T
T
1871
1895
1915
1935
1955
1975
T
T
T
1
1996
=
Wood
—
Coal
=
Petroleum
-
Hydro
—
Gas
Nuclear
Energy
and
Efficiency
When
you
think
about
energy
efficiency,
what
comes
to
mind?
You
may
think
about
taking
the
stairs
instead
of
the
elevator,
choosing
to
drive
a
small
car
instead
of
a
sport
utility
vehicle,
or
turning
off
lights
when
you
are
not
using
them.
What,
however,
does
efficiency
really
mean?
How
do
you
quantify
it?
There
are
several
ways
to
define
efficiency.
One
general
definition
says
that
energy
efficiency
is
the
ability
to
produce
a
desired
effect
with
minimum
energy
expenditure.
For
example,
suppose
that
you
want
to
bake
a
potato.
You
can
use
a
microwave
oven
or
a
conventional
oven.
Both
options
achieve
the
same
effect
(baking
the
potato), but
the
first
option
uses
less
energy.
According
to
the
general
definition
above,
using
the
microwave
oven
is
more
energy-efficient
than
using
the
conventional
oven.
The
general
definition
is
useful, but
it
is
not
quantitative.
Another
definition
of
efficiency
suggests
that
it
is
the
ratio
of
useful
energy
produced
to
energy
used
in
its
production,
expressed
as
a
percent.
This
definition
quantitatively
compares
input and
output
of
energy.
When
you
use
it,
however,
you
need
to
be
clear
about
what
you
mean
by
“energy
used.”
Figure
5.19
shows
factors
to
consider
when
calculating
efficiency
or
analyzing
efficiency
data.
256
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
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"Useful
energy”
is
m
energy
delivered
to
consumer
in
usable
form
=
actual
work
done
1
Useful
energy
produced
Efficiency
=
X
100%
Energy
used
"Energy
used”
could
include
=
ideal
energy
content
of
fuel
T
=
energy
used
to
extract
and
transport
fuel
m
solar
energy
used
to
create
fuel
(e.g.
biomass)
=
energy
used
to
build
and
maintain
power
plant
GIMIXAL)
Efficiency
is
expressed
as
a
percent.
Always
It
is
often
difficult
to
determine
how
much
energy
is
used
to
produce
specify
what
is
included
in
the
useful
energy.
Often
an
efficiency
percent
only
takes
into
account
the
“energy
used”
part
of
the
ratio.
“ideal”
energy
output
of
a
system,
based
on
the
energy
content
of
the
fuel.
Efficiency
and
Natural Gas
When
discussing
the
efficiency
of
a
fuel
such
as
natural
gas,
you
need
to
specify
how
that
fuel
is
being
used.
Consider,
for
example,
natural
gas.
Natural
gas
is
primarily
methane.
Therefore,
you
can
estimate
an
ideal
value
for
energy
production
using
the
enthalpy
of
combustion
of
methane.
CHy(g)
+
203()
>
COgg
+
2H;0ry)
AH"
=-802
k]
In
other
words,
16
g
of
methane
produces
802
k]
of
heat
(under
constant
pressure
conditions).
When
natural
gas
is
used
directly
in
cooking
devices,
its
efficiency
can
be
as
high
as
90%.
Thus,
for
every
16
g
of
gas
burned,
you
get
about
720
k]
(0.90
x
802
kJ)
of
usable
energy
as
heat
for
cooking.
This
is
a
much
higher
fuel
efficiency
than
you
can
get
with
appliances
that
use
electrical
energy
produced
in
a
power
plant
that
runs
on
a
fuel
such
as
coal.
If
natural
gas
is
used
to
produce
electricity
in
a
power
plant,
however,
the
efficiency
is
much
lower—around
37%.
Why?
The
heat
from
the
burning
natural
gas
is
used
to
boil
water.
The
kinetic
energy
of
the
result-
ing
steam
is
transformed
to
mechanical
energy
for
turning
a
turbine.
The
turbine
generates
the
electrical
energy.
Each
of
these
steps
has
an
associated
efficiency
that
is
less
than
100%.
Thus,
at
each
step,
the
overall
efficiency
of
the
fuel
decreases.
Thinking
About
the
Environment
Efficiency
is
not
the
only
criterion
for
selecting
an
energy
source.
Since
the
1970s,
society
has
become
increasingly
conscious
of
the
impact
of
energy
technologies
on
the
environment.
Suppose
that
you
want
to
analyze
the
environmental
impact
of
an
energy
source.
You
can
ask
the
following
questions:
e
Are
any
waste
products
or
by-products
of
the
energy
production
process
harmful
to
the
environment?
For
example,
any
process
in
which
a
hydrocarbon
is
burned
produces
carbon
dioxide.
Carbon
dioxide
is
a
known
greenhouse
gas,
which
contributes
to
global
warming.
Any
com-
bustion
process
provides
the
heat
required
to
form
oxides
of
nitrogen
from
nitrogen
gas.
Nitrogen
oxides
contribute
to
acid
precipitation.
e
Is
obtaining
or
harnessing
the
fuel
harmful
to
the
environment?
For
example,
oil
wells
and
strip
coal
mines
destroy
habitat.
Natural
gas
GEMTXET]
This
gas
pipeline
pipelines,
shown
in
Figure
5.20,
are
visually
unappealing.
They
also
harms
the
ecosystem
by
splitting
split
up
habitat,
which
harms
the
ecosystem.
up
habitat.
Chapter
5
Energy
and
Change
«
MHR
257
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e
Will
using
the
energy
source
permanently
remove
the
fuel
from
the
environment?
A
non-renewable
energy
source
(such
as
coal,
oil,
or
natural
gas)
is
effectively
gone
once
we
have
used
it
up.
Non-renewable
energy
sources
take
millions
of
years
to
form.
We
use
them
up
at
a
much
faster
rate
than
they
can
be
replenished.
An
energy
source
that
is
clearly
renewable
is
solar
energy.
The
Sun
will
continue
to
radiate
energy
toward
Earth
over
its
lifetime—many
millions
of
years.
A
some-
what
renewable
energy
source
is
wood.
Trees
can
be
grown
to
replace
those
cut
down.
It
takes
trees
a
long
time
to
grow,
however,
and
habitat
is
often
destroyed
in
the
meantime.
Comparing
Energy
Sources
Both
efficiency
and
environmental
impact
are
important
factors
to
con-
sider
when
comparing
energy
sources.
In
the
following
ThoughtLab,
you
will
research
and
compare
alternative
and
conventional
energy
sources.
LU
11T
Re
"«
Comparing
Energy
Sources
In
this
ThoughtLab,
you
will
work
as
a
class
to
fuels
back
to
solar
energy
that
powered
the
~
compare
two
different
energy
sources.
photosynthesis
in
the
plants
that
eventually
|
became
the
fossil
fuel.
Write
a
brief
outline
of
]
Procedure
your
findings.
1.
On
your
own,
or
with
a
group,
choose
an
energy
6.
Your
teacher
will
pair
you
(or
your
group)
with
source
from
the
following
list.
Other
energy
another
student
(or
group)
that
has
researched
a
sources
may
be
discussed
and
added
in
class.
different
energy
source.
Work
together
to
analyze
solar
(radiant)
energy
wood
the
comparative
merits
and
drawbacks
of
the
two
petroleum
biomass
energy
sources,
based
on
your
research.
hydrogen
fuel
cell
LI
EEY
R0
1.
Write
a
conclusion
that
summarizes
the
benefits
nz?tural
gas
fuel
cell
natural
gas
and
risks
of
both
energy
sources,
in
terms
of
Lol
EEETY
Bkl
their
efficiency
and
environmental
impact.
hydroelectric
power
tar
sands
geothermal
energy
8.
Present
your
findings
to
the
class.
2.
Before
beginning
your
research,
record
your
cur-
Analysis
rent
ideas
about
the
efficiency
and
environmental
)
1.
Discuss
the
presentations
as
a
class.
impact
of
your
chosen
energy
source.
(a)
Decide
which
energy
sources
are
most
3.
Research
the
efficiency
and
environmental
efficient.
Also
decide
which
energy
sources
impact
of
your
energy
source.
If
possible,
are
least
damaging
to
the
environment.
determine
what
the
efficiency
data
means.
For
example,
suppose
that
a
source
tells
you
that
natural gas
is
90%
efficient.
Is
the
source
referring
to
natural
gas
burned
directly
for
heat
or
for
cooking?
Is
the
energy
being
converted
from
heat
to
electricity
in
a
power
plant?
Be
as
specific
as
possible.
(b)
Decide
which
energy
source
is
best
overall
in
terms
of
both
efficiency
and
environmental
impact.
2.
Could
the
“best
overall”
energy
source
be
used
to
provide
a
significant
portion
of
Canada’s
energy
needs?
What
obstacles
would
need
to
be
overcome
for
this
to
happen?
4,
Ensure
that
you
use
a
variety
of
sources
to
find
your
data.
Be
aware
of
any
bias
that
might
be
present
in
your
sources.
3.
Besides
efficiency
and
environmental
impact,
what
other
factors
are
involved
in
developing
and
delivering
an
energy
source
to
consumers?
5.
Trace
the
energy
source
as
far
back
as
you
can.
For
example,
you
can
trace
the
energy
in
fossil
|
|
|=—
—
—
—
m—
258
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
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Nuclear
Safety
Supervisor
’v
’
1;'
e
=
p=p
_
Jennifer
Noronha
In
some
ways,
nuclear
power
is
an
appealing
power
source.
Nuclear
reactions
create
large
amounts
of
energy
from
minimal
material,
and
they
generate
none
of
the
carbon
dioxide
and
other
emissions
that
cause
acid
rain
and
global
warming.
The
products
and
reactants
of
nuclear
reactions,
however,
are
dangerously
radioactive.
Therefore,
special
meas-
ures
are
needed
to
protect
nuclear
power
station
employees
from
daily
exposure
to
radiation.
That
is
where
Jennifer
Noronha
comes
in.
Noronha
is
the
supervisor
of
Radiological
Services
at
Darlington.
Employee
safety—especially
from
high
radiation
doses—is
her
first
priority.
The
Darlington
Nuclear
Generating
Station
is
located
70
km
east
of
Toronto.
It
uses
a
fuel
of
natural
uranium
to
produce
enough
electricity
to
provide
power
for
a
city
the
size
of
Toronto.
Noronha
and
her
radiation
protection
team
plan
and
implement
safety
programs
that
minimize
dose
rates,
or
the
amount
of
radiation
that
station
employees
are
exposed
to.
Station
employees
must
undergo
four
weeks
of
radiation
protection
training.
This
training
was
designed
by
Noronha’s
department,
based
on
an
extensive
investigation
of
radiation
fields
within
the
station,
as
well
as
a
thorough
evaluation
of
past
safety
programs
and
approaches.
Through
this
training,
employees
learn
how
to
measure
existing
dose
rates
with
survey
equipment,
assess
what
kinds
of
tools
and
protective
clothing
are
needed,
and
take
appropriate
action
to
lower
radiation
doses.
For
example:
e
Airborne
hazards,
such
as
tritium
(present
in
radiated
water
vapour),
can
be
reduced
by
running
the
station’s
dryer
system.
The
dryer
system
catches
the
radiated
vapour
and
dries
it
out
of
the
air.
e
Non-airborne
radiation
can
be
countered
by
shielding
the
affected
area
with
lead
blankets
or
sheeting
material.
Noronha’s
strong
mathematics
skills
were
evident
from
an
early
age.
When
she
moved
to
Canada
from
Kenya
at
age
11,
she
was
immediately
put
ahead
a
grade.
Her
mathematics
skills
and
her
father’s
engi-
neering
profession
were what
propelled
her
toward
engineering.
Noronha
earned
her
engineering
physics
degree
from
McMaster
University.
Her
courses
included
general
chemistry,
biomedical
theory,
and
nuclear
theory.
She
worked
as
a
commissioning
engineer
at
Darlington
during
its
start-up.
She
tested
the
station’s
safety
shut-down
systems
and
helped
to
bring
the
station’s
first
reactor
on-line.
“It
was
pretty
amazing,”
Noronha
says.
“At
the
time,
it
was
still
relatively
new
technology,
and
it
was
Canadian
technology.”
Noronha
got
her
MBA
from
the
University
of
Toronto
in
1998.
Soon
after,
she
moved
to
her
current
position,
which
allows
her
to
combine
her
people
skills
and
technical
expertise.
Making
Career
Connections
1.
Are
you
interested
in
the
different
safety
con-
cerns
related
to
Canadian
nuclear
reactors,
and
the
steps
that
are
being
taken
to
counter
these
concerns?
Contact
the
Canadian
Nuclear
Safety
Commission
(CNSC)
or
explore
their
web
site.
(The
CNSC
is
the
Ottawa-based
government
watchdog
for
the
use
of
nuclear
energy
in
Canada.)
2.
To
learn
more
about
the
wide
variety
of
careers
in
nuclear
power
generation,
Ontario
Power
Generation
is
a
good
place
to
start.
Their
web
site
has
a
helpful
career
page
that
lists
opportuni-
ties
for
students
and
recent
graduates,
as
well
as
experienced
professionals.
Chapter
5
Energy
and
Change
«
MHR
259
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Chemistry
Bulletin
EIETS)
NN
EEEET)
Hot
Ice
When
engineers
first
began
extending
natural
gas
pipelines
through
regions
of
bitter
cold,
they
noticed
that
their
lines
plugged
with
a
dangerous
slush
of
ice
and
gas.
The
intense
pressure
of
the
lines,
combined
with
the
cold,
led
to
the
formation
of
methane
hydrates,
a
kind
of
gas-permeated
ice.
More
than
a
mere
nuisance,
methane
hydrate
plugs
were
a
potential
threat
to
pipelines.
The
build-up
of
gas
pressure
behind
a
methane
hydrate
plug
could
lead
to
an
explosion.
Now,
however,
this
same
substance
may
hold
the
key
to
a
vast
fuel
supply.
Methane
hydrates
form
when
methane
molecules
become
trapped
within
an
ice
lattice
as
water
freezes.
They
can
form
in
very
cold
conditions
or
under
high-pressure
conditions.
Both
of
these
conditions
are
met
in
deep
oceans
and
in
permafrost.
In
Canada,
hydrates
have
already
been
found
in
large
quantities
in
the
Canadian
Arctic.
Methane
hydrate
has
a
number
of
remarkable
properties.
For
example,
when
brought
into
an
oxygen
atmosphere,
the
methane
fumes
can
be
ignited,
making
it
appear
that
the
ice
is
burning!
Methane
releases
25%
less
carbon
dioxide
per
gram
than
coal,
and
it
emits
none
of
the
oxides
of
nitrogen
and
sulfur
that
contribute
to
acid
precipitation.
Therefore,
using
methane
in
place
of
other
fossil
fuels
is
very
desirable.
Methane
hydrates
seem
to
be
an
ideal
and
plentiful
“pre-packaged”
source
of
natural
gas.
Estimates
of
the
exact
amount
of
methane
stored
in
hydrates
suggest
there
could
be
260
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
l':mrfrr.nmr:r:.’J
enough
to
serve
our
energy
needs
anywhere
from
350
years
to
3500
years,
based
on
current
levels
of
energy
consumption.
This
would
con-
stitute
a
significant
source
of
fossil
fuels,
if
we
can
find
a
way
to
extract
the
gas
safely
and
economically.
Unfortunately,
hydrates
become
unstable
when
the
pressure
or
temperature
changes.
Even
small
changes
in
these
conditions
can
cause
hydrates
to
degrade
rapidly.
Methane
hydrates
are
stable
at
ocean
depths
greater
than
300
m,
but
offshore
drilling
at
these
depths
has
been
known
to
disturb
the
hydrate
formations,
causing
large,
uncontrolled
releases
of
flamma-
ble
methane
gas.
Also,
methane
hydrates
often
hold
sediment
layers
together.
Therefore,
in
addition
to
the
danger
of
a
gas
explosion,
there
is
the
danger
of
the
sea
floor
collapsing
where
drilling
occurs.
Methane
is
a
significant
greenhouse
gas.
A
massive
release
of
methane
could
cause
catastrophic
global
climate
change.
Some
researchers
believe
that
the
drastic
climate
change
that
occurred
during
the
Pleistocene
era
was
due
to
methane
hydrate
destabilization
and
widespread
methane
release.
Nonetheless,
Canada,
Japan,
the
United
States,
and
Russia
all
have
active
research
and
exploration
programs
in
this
area.
As
global
oil
supplies
dwindle,
using
methane
hydrates
might
increasingly
be
seen
as
worth
the
risk
and
cost.
Making
Connections
1.
Compare
using
methane
from
natural
gas
with
using
methane
from
methane
hydrates
in
terms
of
environmental
impact
and
effi-
ciency.
You
will
need
to
do
some
research
to
find
out
extraction
methods
for
each
source
of
methane.
2.
On
the
Internet,
research
one
possible
struc-
ture
of
methane
hydrate.
Create
a
physical
model
or
a
three-dimensional
computer
model
to
represent
it.
Use
your
model
to
explain
why
methane
hydrates
are
unstable
at
temperatures
that
are
warmer
than
0°C.
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Emerging
Energy
Sources
In
the
Thoughtl.ab
on
page
258,
you
probably
noticed
that
all
energy
sources
have
drawbacks
as
well
as
benefits.
Scientists
and
engineers
are
striving
to
find
and
develop
new
and
better
energy
sources.
One
energy
source
that
engineers
are
trying
to
harness
is
nuclear
fusion.
As
you
learned
in
section
5.1,
nuclear
fusion
provides
a
great
deal
of
energy
from
readily
available
fuel
(isotopes
of
hydrogen).
In
addition,
nuclear
fusion
produces
a
more
benign
waste
product
than
nuclear
fission
(helium).
Unfortunately,
fusion
is
not
yet
practical
and
controllable
on
a
large
scale
because
of
the
enormous
temperatures
involved.
Chemists
are
also
striving
to
find
new
sources
for
existing
fuels
that
work
well.
The
Chemistry
Bulletin
on
the
facing
page
discusses
a
new
potential
source
of
methane.
Section
Summary
In
this
section,
you learned
about
efficiency.
You
learned
how
it
can
be
defined
in
different
ways
for
different
purposes.
You
used
your
understanding
of
processes
that
produce
energy
to
investigate
the
efficiency
and
environmental
impact
of
different
energy
sources.
In
Chapter
5,
you learned
about
the
energy
that
is
associated
with
chemical
reactions.
You
used
a
calorimeter
to
measure
heat
changes,
and
you
used
these
heat
changes
to
write
thermochemical
equations.
You
probably
already
realize
that
adding
heat
to
reactants
often
speeds
up
a
reaction.
In
other
words,
raising
the
temperature
of
a
system
consisting
of
a
chemical
reaction
often
increases
the
speed
of
the
reaction.
A
familiar
example
is
cooking.
You
increase
the
temperature
of
a
heating
element
to
speed
up
the
reactions
that
are
taking
place
in
the
food
as
it
cooks.
How
does
increasing
temperature
speed
up
a
reaction?
Is
the
enthalpy
of
a
reaction
related
to
its
speed?
Chapter
6
addresses
these
questions.
Section
Review
©
O
Your
friend
tells
you
about
an
energy
source
that
is
supposed
to
be
46%
efficient.
What
questions
do
you
need
to
ask
your
friend
in
order
to
clarify
this
claim?
©
O
Efficiency
and
environmental
concerns
are
not
always
separate.
In
fact,
they
are
often
closely
linked.
Give
three
examples
of
energy
sources
in
which
changes
in
efficiency
affect
environmental
impact,
or
vice
versa.
©
O
Design
an
experiment
to
determine
the
efficiency
of
a
laboratory
burner.
You
will
first
need
to
decide
how
to
define
the
efficiency,
and
you
will
also
need
to
find
out
what
fuel
your
burner
uses.
Include
a
complete
procedure
and
safety
precautions.
O
D
Some
high-efficiency
gas
furnaces
can
heat
with
an
efficiency
of
up
to
97%.
These
gas
furnaces
work
by
allowing
the
water
vapour
pro-
duced
during
combustion
to
condense.
Condensation
is
an
exothermic
reaction
that
releases
further
energy
for
heating.
Use
the
information
in
this
section
to
demonstrate
the
increased
heat
output,
using
Hess’s
law.
The
enthalpy
of
condensation
of
water
is
44
kJ/mol.
Chapter
5
Energy
and
Change
-
MHR
261
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©
D
“Nuclear
energy
is
an
energy
source
that
is
less
hazardous
to
the
environment
than
energy
derived
from
burning
coal.”
Write
a
brief
essay,
explaining
why
you
agree
or
disagree
with
this
statement.
@O
D
The
label
on
an
electric
kettle
claims
that
the
kettle
is
95%
efficient.
(a)
What
definition
of
efficiency
is
the
manufacturer
using?
(b)
Write
an
expression
that
shows
how
the
manufacturer
might
have
arrived
at
an
efficiency
of
95%
for
the
kettle.
(c)
Design
a
detailed
experiment
to
test
the
manufacturers’
claim.
Include
safety
precautions.
(7]
Read
the
Chemistry
Bulletin
on
page
260.
How
does
the
efficiency
of
using
methane
as
a
fuel
source
compare
to
using
methane
hydrates?
Justify
your
answer.
©
©
Hydrogen
is
a
very
appealing
fuel,
in
part
because burning
it
produces
only
non-polluting
water.
One
of
the
challenges
that
researchers
face
in
making
hydrogen
fuel
a
reality
is
how
to
produce
hydrogen
economically.
Researchers
are
investigating
methods
of
producing
hydrogen
indirectly.
The
following
series
of
equations
represent
one
such
method.
3FeClz(s)
+
4H20(g)
—
FegOy)
+
GHCI(g)
+
Hz(g)
AH®
=
318
kJ
Fe30y)
+
%Clz(g)
+
BHCI(g)
—
3F8C13(s)
+
3H20(g)
+
%Oz(g)
AH®
=
-249
kJ
3FeCly)
—
3FeClyg)
+
%Clz(g)
AH®
=173
k]
(a)
Show
that
the
net
result
of
the
three
reactions
is
the
decomposition
of
water
to
produce
hydrogen
and
oxygen.
(b)
Use
Hess’s
law
and
the
enthalpy
changes
for
the
reactions
to
determine
the
enthalpy
change
for
the
decomposition
of
one
mole
of
water.
Check
your
answer,
using
the
enthalpy
of
formation
of
water.
262
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
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Review
Reflecting
on
Chapter
5
Summarize
this
chapter
in
the
format
of
your
choice.
Here
are
a
few
ideas
to
use
as
guidelines:
e
Compare
the
magnitude
of
energy
changes
resulting
from
physical
changes,
chemical
reactions,
and
nuclear
reactions.
e
Compare
the
processes
that
are
responsible
for
the
energy
changes
resulting
from
physical
changes,
chemical
reactions,
and
nuclear
reactions.
e
Explain
the
different
ways
to
represent
the
ener-
gy
changes
of
physical
and
chemical
processes.
¢
Give
examples
of
important
exothermic
and
endothermic
processes.
e
Explain
how
a
calorimeter
is
used
to
determine
enthalpy
of
reaction.
e
Use
examples
and
analogies
to
explain
Hess’s
law.
¢
Show
how
to
use
Hess’s
law
and
experimentally
determined
enthalpies
of
reaction
to
calculate
unknown
enthalpies
of
reaction.
e
Show
how
to
calculate
enthalpy
of
reaction
using
known
enthalpies
of
formation,
and
explain
how
this
calculation
relates
to
Hess’s
law.
e
Explain
the
concept
of
efficiency,
and
discuss
the
efficiency
and
environmental
impact
of
conventional
and
alternative
energy
sources.
Reviewing
Key
Terms
For
each
of
the
following
terms,
write
a
sentence
that
shows
your
understanding
of
its
meaning.
thermodynamics
thermochemistry
law
of
conservation
system
of
energy
surroundings
heat
(Q)
enthalpy
(H)
endothermic
reaction
enthalpy
of
reaction
thermochemical
equation
nuclear
binding
energy
nuclear
fusion
heat
capacity
(C)
temperature
(T')
enthalpy
change
(AH)
exothermic
reaction
standard
enthalpy
of
reaction
(AH")
mass
defect
nuclear
fission
specific
heat
capacity
(c)
calorimeter
coffee-cup
calorimeter
constant-pressure
Hess’s
law
of
heat
calorimeter
summation
formation
reactions
standard
molar
enthalpy
of
formation
(AH®;)
non-renewable
renewable
Knowledge/Understanding
1.
In
your
own
words,
describe
the
relationship
between
a
system
and
its
surroundings.
Use
an
example
to
illustrate
your
description.
.
The
vaporization
of
liquid
carbon
disulfide,
CS;,
requires
an
energy
input
of
29
kJ/mol.
(a)
Is
this
reaction
exothermic
or
endothermic?
What
is
the
enthalpy
change
of
this
reaction?
(b)
Write
a
thermochemical
equation
of
this
reaction.
Include
29
kJ
as
either
a
reactant
or
a
product.
(c)
Draw
and
label
an
enthalpy
diagram
for
the
vaporization
of
liquid
carbon
disulfide.
.
A
given
chemical
equation
is
tripled
and
then
reversed.
What
effect,
if
any,
will
there
be
on
the
enthalpy
change
of
the
reaction?
.
Explain
why
two
nested
polystyrene
coffee
cups,
with
a
lid,
make
a
good
constant-pressure
calorimeter.
.
Write
the
balanced
equation
for
the
formation
of
each
substance.
(a)
LiCl(S)
(b)
C;HsOHyy
(¢)
NHsNO;3(g
.
If
the
enthalpy
of
formation
of
an
element
in
its
standard
state
is
equal
to
zero,
explain
why
the
heat
of
formation
of
iodine
gas,
Iy,
is
21
kJ/mol.
Inquiry
7.
In
an
oxygen-rich
atmosphere,
carbon
burns
to
produce
carbon
dioxide,
CO,.
Both
carbon
monoxide,
CO,
and
carbon
dioxide
are
produced
when
carbon
is
burned
in
an
oxygen-deficient
atmosphere.
This
makes
the
direct
measurement
of
the
enthalpy
of
forma-
tion
of
CO
difficult.
CO,
however,
also
burns
in
oxygen,
O,
to
produce
pure
carbon
dioxide.
Explain
how
you
would
experimentally
deter-
mine
the
enthalpy
of
formation
of
carbon
monoxide.
.
Two
30.0
g
pieces
of
aluminium,
Al, are
placed
in
an
insulated
container.
(a)
One
piece
of
Al
has
an
initial
temperature
of
100.0°C.
The
other
piece
has
an
initial
temperature
of
20.0°C.
What
is
the
tempera-
ture
inside
the
container
after
the
system
has
equilibrated?
Assume
that
no
heat
is
lost
to
the
container
or
the
surroundings.
Chapter
5
Energy
and
Change
*
MHR
263
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I
T
I
D
M
R
10.
1.
12.
13.
14.
264
MHR
-
Unit
3
Energy
Changes
and
Rates
of
Reaction
(b)
Repeat
the
calculation
in
part
(a)
with
the
following
change:
The
piece
of
Al
at
20.0°C
has
a
mass
of
50.0
g.
The
complete
combustion
of
1.00
mol
of
sucrose,
C12H22011,
releases
—5641
kJ
of
energy
(at
25°C
and
100
kPa).
C12H22011(5)
+
1202(8)
—
12C02(g)
+
11H,0(y
(a)
Use
the
enthalpy
change
of
this
reaction,
and
enthalpies
of
formation
from
Appendix
E,
to
determine
the
enthalpy
of
formation
of
sucrose.
(b)
Draw
and
label
an
enthalpy
diagram
for
this
reaction.
A
10.0
g
sample
of
pure
acetic
acid,
CH;CO,H,
is
completely
burned.
The
heat
released
warms
2.00
L
of
water
from
22.3°C
to
39.6°C.
Assuming
that
no
heat
was
lost
to
the
calorimeter,
what
is
the
enthalpy
change
of
the
complete
combus-
tion
of
acetic
acid?
Express
your
answer
in
units
of
kJ/g
and
kJ/mol.
Use
equations
(1),
(2),
and
(3)
to
find
the
enthalpy
change
of
the
formation
of
methane,
CH,,
from
chloroform,
CHCl;.
CHClj()
+
3HC1(g)
—
CHyg)
+
3C12(g)
(1)
%Hz(g)
+
%Clz(g]
—
HCl(g)
AH®
=
-92.3
k]
(2)
C)
+
ZHz(g]
—
CH4(g]
AH®
=
-74.8
K]
(3)
C)
+
%Hz(g)
+
%Clg(g)
—
CHClg(g)
AH®
=
-134.5
k]
The
following
equation
represents
the
combustion
of
ethylene
glycol,
(CH,OH),.
(CHZOH)Z(Z)
+
%Oz(g)
—
ZCOZ(g)
+
3H;0(
AH®
=
-1178
k]
Use
known
enthalpies
of
formation
and
the
given
enthalpy
change
to
determine
the
enthalpy
of
formation
of
ethylene
glycol.
Most
of
us
associate
the
foul
smell
of
hydrogen
sulfide
gas,
HyS(g),
with
the
smell
of
rotten
eggs.
3
H>Sg)
+
Eoz(g]
—
SOq)
+
HO)
AH
=-519
k]
How
much
energy
is
released
when
15.0
g
of
H,S()
burns?
Hydrogen
peroxide,
H,O,,
is
a
strong
oxidizing
agent.
It
is
used
as
an
antiseptic
in
a
3.0%
aqueous
solution.
Some
chlorine-free
bleaches
contain
6.0%
hydrogen
peroxide.
(a)
Write
the
balanced chemical
equation
for
the
formation
of
one
mole
of
HyOy(y).
15.
16.
172.
18.
(b)
Using
the
following
equations,
determine
the
enthalpy
of
formation
of
H,0,.
(1)
2H302¢)
—
2H30()
+
Oz
AH’
=-196
k]
(2)
Hyg)
+
302t
>
HyOry
AH"
=-286
]
Hydrogen
cyanide
is
a
highly
poisonous
gas.
It
is
produced
from
methane
and
ammonia.
CHy(g)
+
NHjg)
—
HCN(g)
+
3Hy(g)
Find
the
enthalpy
change
of
this
reaction,
using
the
following
thermochemical
equations.
(1)
Hag)
+
2C(graphite)
+
Nag)
—
2HCN(g
AH®
=
270k]
AH®
=-92
K]
AH*
=
-75
k]
The
following
equation
represents
the
complete
combustion
of
butane,
C;H;q.
C4Hig(g)
+
6.502(g)
—
4C0O3)
+
5H20(g
(a)
Using
known
enthalpies
of
formation,
calculate
the
enthalpy
change
of
the
complete
combustion
of
C4Hqg.
(The
enthalpy
of
formation
of
C4H,¢
is
—126
kJ/mol.)
(b)
Using
known
enthalpies
of
formation,
calcu-
late
the
enthalpy
change
of
the
complete
combustion
of
ethane,
C,Hg,
to
produce
carbon
dioxide
and
water
vapour.
Express
your
answer
in
units
of
kJ/mol
and
kJ/g.
(c)
A
10.0
g
sample
that
is
30%
C,Hg
and
70%
C;Hy0,
by
mass,
is
burned
in
excess
oxygen.
How
much
energy
is
released?
(2)
Nag)
+
3Hag)
—
2NHsg)
(3)
C(graphite)
+
2H2(g)
—
CH4(8)
The
caloric
content
(energy
content)
of
foods
is
measured
using
a
bomb
calorimeter.
A
sample
of
food
is
burned
in
oxygen,
O,,
inside
the
calorimeter.
You
can
make
a
simple
food
calorimeter
using
an
empty
food
can
or
pop
can.
Design
an
investigation
in
which
you
make
your
own
calorimeter
and
then
use
your
calorimeter
to
measure
the
energy
content
of
a
piece
of
cheese
or
a
cracker.
Include
a
diagram
of
your
proposed
calorimeter.
List
the data,
and
other
observations,
that
you
plan
to
record.
Get
your
teacher’s
approval
before
carrying
out
your
investigation.
Note:
Some
students
have
a
severe
nut
allergy.
Do
not use
peanuts,
or
any
other
nuts,
in
your
investigation.
Design
an
investigation
to
determine
the
enthalpy
change
of
the
combustion
of
ethanol
using
a
wick-type
burner,
similar
to
that
in
a
kerosene
lamp.
(a)
Draw
and
label
a
diagram
of
the
apparatus.
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(b)
Write
a
step-by-step
procedure.
(c)
Prepare
a
table
to
record
your
data
and
other
observations.
(d)
State
any
assumptions
that
you
will
make
when
carrying
out
the
calculations.
Communication
19.
Suppose
that
you
need
to
find
the
enthalpy
change
of
a
chemical
reaction.
Unfortunately,
you
are
unable
to
carry
out
the
reaction
in
your
school
laboratory.
Does
this
mean
that
you
cannot
find
the
enthalpy
change
of
the
reaction?
Explain.
20.
Acetylene,
C;H;,
and ethylene, C;H,,
are
both
used
as
fuels.
They
combine
with
oxygen
gas
to
produce
carbon
dioxide
and
water
in
an
exothermic
reaction.
Acetylene
also
reacts
with
hydrogen
to
produce
ethylene,
as
shown.
Csz(g)
+
Hz(g)
—
C2H4(g)
AH’
=-175.1
k]
(a)
Without
referring
to
any
tables
or
doing
any
calculations,
explain
why
C;H,
has
a
more
positive
enthalpy
of
formation
than
C,H,.
(b)
Do
you
think
G,H;
or
C,H,
is
a
more
energetic
fuel?
Explain.
Making
Connections
21.
When
a
vehicle
is
parked
in
the
sunlight
on
a
hot
summer
day,
the
temperature
inside
can
approach
55°C.
One
company
has
patented
a
non-CFC
propelled
aerosol
that
can
be
sprayed
inside
a
vehicle
to
reduce
the
temperature
to
25°C
within
seconds.
The
spray
contains
a
mixture
of
two
liquids:
10%
ethanol,
C,H5;0H,
and
90%
water
by
mass.
(a)
Use
thermochemical
equations,
and
the
corresponding
enthalpy
changes,
to
explain
how
the
spray
works.
(b)
1.0
g
of
the
aerosol
is
sprayed
into
a
hot
vehicle.
How
much
heat
(in
kJ)
can
be
absorbed
due
to
vaporization
of
the
aerosol?
Note:
AH,,,
of
water
=
44.0
kJ/mol
and
AHy,;,
of
ethanol
=
38.56
k]/mol
(¢)
Do
you
think
there
are
any
risks
associated
with
using
a
spray
like
the
one
described
above?
Explain
your
answer.
22.
Consider
methane,
CH,,
and
hydrogen,
H;,
as
possible
fuel
sources.
N
I
e
e
(a)
Write
the
chemical
equation
for
the
complete
combustion
of
each
fuel.
Then
find
the
enthalpy
of
combustion,
AH.omy,,
of
each
fuel.
Express
your
answers
in
kJ/mol
and
kJ/g.
Assume
that
water
vapour,
rather
than
liquid
water,
is
formed
in
both
reactions.
(b)
Which
is
the
more
energetic
fuel,
per
unit
mass?
(c)
Consider
a
fixed
mass
of
each
fuel.
Which
fuel
would
allow
you
to
drive
a
greater
distance?
Explain
briefly.
(d)
Describe
how
methane
and
hydrogen
could
be
obtained.
Which
of
these
methods
do
you
think
is
less
expensive?
Explain.
(e)
Which
fuel
do
you
think
is
more
environmentally
friendly?
Explain.
Answers
to
Practice
Problems
and
Short
Answers
to
Section
Review
Questions
Practice
Problems:
1.(a)
Nz
+
Oz()
+
180.6
k]
—
2NO(,
{b)
Reactants
have
lower
energy
than
products.
(¢)
+90.3
kJ
(d)
+644.5
k]
2.(a)
—1.65
x
10°
k]
(b)
Reactants
have
higher
energy
than
products.
(¢}
—1.22
x
104
k]
3.a)
+25.9
k]
{b)
+393
k]
(c)
Reactants
have
lower
energy
than
products.
4.(a)
P4O10(5)
+
6H20(¢)
—
4H3POy(aq)
+
257.2
kJ
{b)
—1.29
x
103
kJ
(¢)
—1.54
x
102
k]
5.12.8°C
6.6.70
x
10%
g
7.
2.7
x
10*
k]
8.6.09°C
9.-50
kJ/mol
10.(a)
—4.1
x
10%
kJ/mol
Mg
(b)
The
density
and
heat
capacity
of
the
solutions
are
the
same
as
the
density
and
heat
capacity
of
water.
No
heat
is
lost
to
the
calorimeter.
11.29.7°C
12
HBr(aq)
+
KOH(aq)
—
H20()
+
KBr(aq)
+
57
kJ
13.
—44
k]
14.-509kJ
15.—120k]
16.+30
k]
17.{a)
Cs)
+
ZHz(g)
—
CH4(g)
+74.6
kJ
(b)
Nagg)
+
+Clyg
—
NaClg)
+
411.2
k]
{c)
Mg(s)
+
%Oz(g)
—
MgO¢s)
+
601.2
kJ
(d)
Cag)
+
Cig)
+
%Oz(g)
—
CaCOj3()
+
1207.6
k]
18.
Hyg)
+
S(s)
+
2035
=
H2SO04()
+
814.0
k]
19.
Csg)
+
76.7
k]
—
Cs(g)
20.8)
3Pa)
>
P+
17.6
K]
{b)
—18.5
kJ
21.
Get
the
target
equation
from
the
two
formation
equations.
22.
Get
the
target
equation
from
the
formation
equations.
23.-77.6
kJ/mol
24.(a)
-637.9
kJ
{b)
2.49
x
10%
kJ
Section
Review:
5.1:
2.(a)
AH’,,,
=
—127.0
K]
(b)
AH"yzp
=
+44.0
K]
(6)
AH'rxn
=
AH'
gy
<
0
4.{a)
34.21
g
{b)
599
kJ
{c)
1.06
x
103
k]
5.(a)
Csz(g)
+
%Oz(g)
—
HyO
+
ZCOZ(g)
+1.3x
103k
(6)
108
kJ
7.a)
Hyg)
+
3Ozt
>
HzO0g)
+
241.8
k]
5.2;
5.(a)
KOH(aq)
+
HNOg(aq)
—
HzO0(g
+
KNO3(aq)
+
55
kJ
5.3:
3.-143
k]
4.14.3
kJ
5.-636.0
kJ
Chapter
5
Energy
and
Change
*
MHR
265
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