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CHM130LL
Lab 9 – Stoichiometric Analysis
42/100
Complete the following items by typing into the text box provided. The boxes will increase in size if additional space is necessary. Please be sure to save all your work as an MS Word document to submit properly.
A. Data Table:
Complete the Data Table using data taken from the photos provided. (6 pts)
Item Measured/
Quantity
Calculated
Mass (grams) Iron nails (before reaction)
7.75g
Iron nails (after reaction)
5.50g
Mass of iron consumed
2.25g
Initial mass of filter paper (before filtration)
0.86g
Mass of filter paper and solid product
3.52g
Mass of solid product
2.66g
B. Calculations:
1.
Determine the mass of iron
consumed in the reaction. Show your work. (4 pts)
Formula
:
massof ironconsumed
=
initial massof iron
−
finalmassof iron
7.75g – 5.50g = 2.25g
2.
Calculate the number of moles of iron
consumed using dimensional analysis and the molar mass of iron as a conversion factor. Show your work. (10 pts)
2.25g iron x 1mol iron/ 55.85g iron = 0.0402 = 4.02 x 10^-2 mol iron consumed Great job showing your work and paying attention to significant figures. 3.
Determine the mass of copper
formed. Show your work. (4 pts)
Formula
:
massof copper formed
=
mass of filter paper
∧
copper
−
massof filter paper
3.52g – 0.86g = 2.66g
4.
Calculate the number of moles of copper
formed using dimensional analysis and the molar mass of copper as a conversion factor. Show your work. (10 pts)
2.66g copper x 1 mol copper/ 63.55g copper = 0.0419 = 4.19 x 10^-2 mol copper formed Scientific notation is a great way to show this answer.
5.
What is the experimental
mole ratio between the iron and the copper? Determine the simplest whole number ratio of moles
of iron consumed (see Question 2), to moles of copper formed (see Question 4). [Note: To find the ratio, you must use your answers to Question 2 and Question 4 and divide both values by whatever value is smaller.] (8 pts)
0.0402 mol Iron/ 0.0402 mol Iron = 1
0.0419 bol Copper/ 0.0419 mol copper = 1.04 = 1 Ratio = 1:1
Thank you for following the directions and providing a whole number ratio. C. Analysis Questions:
6.
What color was the 1
M
CuCl
2
·2H
2
0 solution before the nails were placed in it? What ion was responsible for this color? Explain your reasoning with support from the lab. (8 pts) -8 points
7.
After the nails were allowed to react, did the solution change color? What was responsible for this color change? Explain your reasoning with support from the lab. (8 pts) -8 points
8.
What type of chemical reaction
was this? You need to determine the type of reaction and explain how you know it falls into that category. (8 pts) -8 points
9.
What was the solid product that formed on the nails? Explain your reasoning with support from the lab. (8 pts) -8 points
10. Based on the experimental mole ratio, which of the following equations is MOST LIKELY to be the one represented by this experiment? Justify your answer with support from the lab. (9 pts) -9 points
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alo
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What mass of ammonium phosphate is produced by the reaction of 1.7 g of ammonia?
Ar
Be sure your answer has the correct number of significant digits.
Explanation
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moles ammonia
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References
14. Stoichiometry of Reactions: Gram/Mole: This is group attempt 1 of 10
HOMEW X
Use the References to access Important values if needed for this question.
According to the following reaction, how many moles of nitrogen monoxide will be formed upon the complete reaction of 27.9 grams of nitrogen
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nitrogen(g) + oxygen(g) →→→→nitrogen monoxide(g)
moles nitrogen monoxide
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A chemist adds 0.30 L of a 1.7M nickel(II) chloride (NiCl,) solution to a reaction flask. Calculate the mass in grams of nickel(II) chloride the chemist has
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x10
Submit Assignr
Continue
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1. Moles of NaHCO3 and NaCl:2. Mole Ratio:3. How does your experimental ratio compare to the theoretical? If they are different,explain what might have caused the difference.4. Calculate the percent error.
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Calculate the theoretical mass and the percent yield. Please show all work!
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What is the balance coefficient
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7:27 O O
@ X all 25%
Submission
Name: De Ocampo, Cyzvell N.
Date: 11-30-21
Strand and Section: 12STEMA7
Teacher: Mr. Reynante S. Santos
Homework 7.1| Stoichiometry in Chemical Reactions
Directions: Use the balanced chemical equation to solve the following
problems.
4Fe + 302 → 2FE203
1. How many moles of Fe,0z are produced when 7.27 grams of Fe is
reacted?
1 mel Fe
2 mol Fe203
0.07 or 0.0650
mol Fe203
7.27 gFe
55.85 g Fe
4 mel Fe
2. How many moles of Fe,0, are produced when 19.0 grams of 0, is
reacted?
1 mel02
2 Fe203
19:0
g02----
= 0.40 or 0.395
mol Fe203
32 g02
3 mele2
3. How many moles of 0, are needed to react with 25.9 grams of Fe?
1 met-Fe
3 mol 02
= 0.35 mol 02
25.9 Fe
55.85 g Fe
4 met Fe
COMMENTS
FILES (1)
RUBRIC
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Table 7.1(data)
Mass of crucible and lid
33.059
Mass of crucible, lid, and hydrate sample before heating
33.533
Mass of crucible, lid and hydrate sample after heating
33.460
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6 IZICIt iniED 10 11 12
13 I 14 I-
15
16 .
Chemical Equation
Write a balanced equation that describes each of the following chemical reaction.
1. Acetylene gas, C2H2, burns in air forming gaseous carbon dioxide and, CO2, and water.
Answer: 2C2H2 + 502 → 4CO2 + 2H20 (double displacement/Combustion reaction)
2. MnO2 + KOH + O2 → H20 + K2MNO4
3. FeCl2 + Cl2 → FeCl3
English (United States)
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1.
Develop a detailed separation scheme for the separation and determination of the percent
composition of your sample which will be a mixture of NaCl, NH.CL, and sand. You are
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student should be able to pick up your scheme, understand it, and use it to complete the
separation and calculation of % composition. Place the scheme on a separate sheet of paper.
Component
Solubility (@25°C)
Melting Point
Hardness
sodium chloride, NaCl
35 g/100 mL water
801°C
soft
ammonium chloride, NH&Cl
37 g/100 mL water
sublimes 350°C
soft
sand, SIQ2
insoluble
1600°C
hard
Example of
compounds
in a
container.
Naci
NH.CI
sio2
Exploring the Chemical World, PGCC, 2003
4
RESULTS
Show all calculations with units in this space.
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In this exercise, we are going to calculate the percent composition of water in a hydrate and
percent (%)
composition =
of water
mass of water
х 100
mass of entire hydrate
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Nelice the three in front of the water will give us a total of six hydrogens and three oxygens.
Li: 1x 6.94 g/mol
N: 1x 14.01 g/mol
H: 6x 1.01 g/mol
О: 3х 16.00 g/mol
O: 3x 16.00 g/mol
54.06 g/mol
go l00 68.95 g/mol
percent (%)
composition =
of water
3 H20
х 100
LINO3 · 3H20
percent (%)
composition =
of water
54.06 g/mol
х 100
(68.95 g/mol + 54.06 g/mol)
percent (%) composition of water in LINO3 • 3 H20 = 43.9 %
1. Calculate the percent composition of water in the following hydrates: (show all work)
ZnSO, 7H20
M9SO 7H20
BaCl2 2H20
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General Direction:
1. On a separate sheet, answer the following item below.
2. Used the format GRESFA (Given, Required, Equation, Solution, and Final Answer).
3. In submission, using cam scanner or take a photo of your output.
4. Clear, neat, and portrait scanning of your answers will be part of the grading.
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What is the chemical formula for the limiting reactant in the reaction shown?
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Write the balanced chemical equation for the reaction, using lowest whole-number coefficients.
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LWR # 1 Apply Stoichiometry
A student performed an experiment to find the amount of sodium carbonate, (Na₂CO₂)
that is produced from the decomposition of baking soda, NaHCO, by heating.
Decomposition of baking soda: 2NaHCO,> Na₂CO, + CO₂ + H₂O
The following data were collected. Complete the data table.
Mass of empty evaporating dish
24.353 grams
Mass of evaporating dish and baking
27.868 grams
soda
26.885 grams
Mass of evaporating dish and sodium
carbonate
Mass of baking soda
84.007 g/mol
Mass of sodium carbonate (experimental) 105.9888 g/mol
Molar mass of baking soda
84.007 g/mol
Molar mass of sodium carbonate
105.9888 g/mol
1.678 grams >
Theoretical (calculated) mass of sodium
carbonate
09314 g/mol
Calculate percent error of the analysis
(1105.9888-09314) +100/.09314
= 9.8%
1 =
Atomic mass: Na = 23.0g; H=1.0 g; C=12.0g; O=16.0g
% error = (Experimental-Calculated) x 100/ Calculated
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5)
3)
2)
Percentage Composition Worksheet
Give the % composition of all elements in these compounds. Show all work!
1)
ammonium sulfite % N
% H
sodium bromide
aluminum acetate % Al
% C
4) copper (II) hydroxide
% S
% O
magnesium carbonate
% H
% O
% Na
% Br
M_
For chemistry help, visit http://www.chemfiesta.com
% Cu
% O
% H
% Mg
% C
% O
O
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Potassium nitrate was synthesized in an experiment using 10 mL of nitric acid and excess
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Given that the percentage yield of potassium nitrate was 88.3 %, calculate the concentration
(% m/v) of the nitric acid used in the experiment.
Table 1: Mass data for the synthesis of potassium nitrate from nitric acid and potassium
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Mass of clock glass and crystallized potassium nitrate/ g
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Mass of empty clock glass/ g
39.18
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Potassium nitrate was synthesized in an experiment using 10 mL of nitric acid and excess potassium hydroxide. The mass data obtained from the experiment is shown in Table 1 below. Given that the percentage yield of potassium nitrate was 88.3 %, calculate the concentration (% m/v) of the nitric acid used in the experiment.
Table 1: Mass data for the synthesis of potassium nitrate from nitric acid and potassium hydroxide
Mass of clock glass and crystallized potassium nitrate/ g
45.55
Mass of empty clock glass/ g
39.18
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- Image uploaded solution is not allowed please dear expertarrow_forward1. Moles of NaHCO3 and NaCl:2. Mole Ratio:3. How does your experimental ratio compare to the theoretical? If they are different,explain what might have caused the difference.4. Calculate the percent error.arrow_forwardBasic Analytical Chemistryarrow_forward
- What is the balance coefficientarrow_forward7:27 O O @ X all 25% Submission Name: De Ocampo, Cyzvell N. Date: 11-30-21 Strand and Section: 12STEMA7 Teacher: Mr. Reynante S. Santos Homework 7.1| Stoichiometry in Chemical Reactions Directions: Use the balanced chemical equation to solve the following problems. 4Fe + 302 → 2FE203 1. How many moles of Fe,0z are produced when 7.27 grams of Fe is reacted? 1 mel Fe 2 mol Fe203 0.07 or 0.0650 mol Fe203 7.27 gFe 55.85 g Fe 4 mel Fe 2. How many moles of Fe,0, are produced when 19.0 grams of 0, is reacted? 1 mel02 2 Fe203 19:0 g02---- = 0.40 or 0.395 mol Fe203 32 g02 3 mele2 3. How many moles of 0, are needed to react with 25.9 grams of Fe? 1 met-Fe 3 mol 02 = 0.35 mol 02 25.9 Fe 55.85 g Fe 4 met Fe COMMENTS FILES (1) RUBRICarrow_forwardTable 7.1(data) Mass of crucible and lid 33.059 Mass of crucible, lid, and hydrate sample before heating 33.533 Mass of crucible, lid and hydrate sample after heating 33.460arrow_forward
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