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Jun 26, 2024

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Solutions Lab Report Instructions: Complete all sections of this report and answer all questions in complete sentences for full credit. Solutions Pre-Lab Questions Complete the pre-lab questions to get the values you need for your drink solutions. 1. Calculate the molar mass of powered fruit drink mix, made from sucrose (C 12 H 22 O 11 ). - c = 12.01(12) = 144.012 g/mol - h = 1.008(22) = 22.176 g/mol - o = 16.000 (11) = 175.989 g/mol - 342.177 g/mol 2. Determine the mass of powdered drink mix needed to make a 1.0 M solution of 100 mL. Use molarity = moles of solute (mol) ÷ liters of solution (L) to calculate the amount of drink mix, in moles. Then convert moles to grams using a mole conversion: moles = grams/molar mass - M = mol/liters - mol = M(L) - mol = (1.0M)(.100L) - 0.1 mol - 34.218 g 3. What mass of powdered drink mix is needed to make a 0.5 M solution of 100 mL? 34.218/2 = 17.109G Data Taste Texture Color Control sweet Smooth Light Red 1.0 M without heat sweet & strong Grainy Dark Red 0.5 M without heat Strong and very sweet Smooth Dark Red 1.0 M with heat BiƩersweet Grainy Light Red 0.5 M with heat More sweet than biƩer Smooth Light red 1.0 M with sƟr Strong and sour Very grainy Dark red Unless Otherwise Noted All Content © 2022 Florida Virtual School. FlexPoint EducaƟon Cloud™ is a trademark of Florida Virtual School.

0.5 M with sƟr Strong and sour, a liƩle sweet Smooth Dark red 1.0 M without sƟr Sour Very grainy Light red 0.5 M without sƟr biƩersweet smooth Light red 1.0 M with sugar Sweet smooth very dark red 0.5 M with sugar Dull smooth very dark red 1.0 M w sugar cubes Sweet smooth very dark red 0.5 M w sugar cubes Dull smooth very dark red Conclusion Using complete sentences, write a conclusion that addresses the following:  The purpose of the lab, what you explored, what you learned  What the effects of temperature, agitation, and particle size had on solubility.  A statement identifying the solubility factors that changed the mixture the most.  A statement identifying the solubility factor that changed the mixture the least. Post-Lab Connection Questions Unless Otherwise Noted All Content © 2022 Florida Virtual School. FlexPoint EducaƟon Cloud™ is a trademark of Florida Virtual School. The lab was conducted to determine the differnt factors that inﬂuenced the solubility of sucrose in a powdered fruit drink mix: temperature, agitaƟon, and parƟcle size. I found that generally, solubility went up as the temperature increased, although this occasionally produced a biƩer aŌertaste. AgitaƟon, such as in sƟrring, increased the qualiƟes of solubility, making smoother textures. Smaller parƟcles dissolved faster and more fully than larger ones. Temperature had the greatest effect on solubility and changed the mixture the most. The lowest impact was parƟcle size, where changes were not as prominent as those in temperature and agitaƟon. Overall, it turned out that different factors can inﬂuence this process of dissoluƟon and characterisƟcs of a soluƟon.

Answer questions in complete sentences and show work. 1. If you were working for a beverage company, which molarity would you recommend, and what directions for mixing would you create for the drink package? Support your claims using the data you collected. Based on the data collected, I would recommend using a 0.5 M solution for the beverage company. This concentration provided a strong, sweet flavor with a smooth texture without being overpowering. To mix the drink, the directions would be:  Measure 17.109 grams of the powdered fruit drink mix.  Dissolve the powder in 100 mL of water.  For best results, sƟr the mixture thoroughly unƟl the powder is fully dissolved.  Also, you could heat the soluƟon to enhance solubility but avoid boiling to prevent biƩerness. 2. If you needed to make 100 mL of a 0.2 M fruit drink solution from the 1.0 M fruit drink solution, how would you do it? (Hint: Use M s V s = M d V d to find the amount of concentrated solution you need, then add water to reach 100 mL.) Show your work. Using M1V1=M2V2:  M1=1.0M  M2=0.2M  V2=100 mL V1=0.2×100/1.0=20mL Measure 20 mL of the 1.0 M soluƟon and add water to reach 100 mL. SƟr thoroughly. Unless Otherwise Noted All Content © 2022 Florida Virtual School. FlexPoint EducaƟon Cloud™ is a trademark of Florida Virtual School.

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