CHEM 120 Final Answers - Shshhsjssjjwjsjsvshs

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May 29, 2024

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CHEM 120 Final Answers - Shshhsjssjjwjsjsvshs Introduction To General, Organic & Biological Chemistry with Lab (Chamberlain University) Scan to open on Studocu Studocu is not sponsored or endorsed by any college or university CHEM 120 Final Answers - Shshhsjssjjwjsjsvshs Introduction To General, Organic & Biological Chemistry with Lab (Chamberlain University) Scan to open on Studocu Studocu is not sponsored or endorsed by any college or university Downloaded by Cyndi McKenzie (cyndimckenzie27@yahoo.com) lOMoARcPSD|8596025
Week 8 : Final Exam - Final Exam CHEM120Final-Exam-Page-3 1. Question: (TCO 7) (a, 5 pts) Given that the molar mass of H 3 PO 4 is 97.994 grams, determine the number of grams of H 3 PO 4 needed to prepare 0.25L of a 0.2M H 3 PO 4 solution. Show your work. (b, 5 pts) What volume, in Liters, of a 0.2 M H 3 PO 4 solution can be prepared by diluting 50 mL of a 5M H 3 PO 4 solution? Show your work. (Pts. : 10) A. Molarity = moles of solute/liters of solution moles of solute = 0.2 M*0.25 L = 0.05 mol H3PO4 Using the molar mass given, convert this amount to grams. mass = 0.05 mol * (97.994 g/mol) = 4.89 grams H3PO4 B. C1V1 = C2V2. C1 = 5 M, V1=0.05L, C2 = 0.2M; V2 = [(5M)(0.05L)]/(0.2M) = 1.25L 2. Question: (TCO 7) (a, 5 pts) What is the mass/volume percent of a solution prepared by dissolving 43 g of NaOH in enough water to make a final volume of 120 mL? Show your work. (b, 5 pts) How many mL of a 10% solution can be made from the solution in part a? Show your work. (Pts. : 10) 2. First convert the given mass of NaOH to volume (in mL) using the density of NaOH w hich is 2.13 g/mL. Volume = 43 g * (1 mL/2.13 g) = 20.19 mL Volume % = (volume of solute / volume of solution) * 100% Volume % = (20.19 mL/120 mL) * 100% = 16.8 % b. Volume % = volume of NaOH/ total volume 0.10 = 20.19 mL/total volume Solving for total volume yields: V_total = 201.88 mL So, about 202 mL of a 10% solution can be made from the solution in part a. This study source was downloaded by 100000841438751 from CourseHero.com on 02-23-2022 14:19:57 GMT -06:00 https://www.coursehero.com/file/51964991/CHEM-120-Final-Answersdocx/ Downloaded by Cyndi McKenzie (cyndimckenzie27@yahoo.com) lOMoARcPSD|8596025
3. Question: (TCO 12) Polyethylene is a polymer found in many applications, including packaging for fruit and vegetables. Discuss the structural differences between (1) polyethylene, (2) polypropylene, and (3) polystyrene and how the structure impacts their commercial uses. (Pts. : 15) 1. The prevalent plastic polyethylene is the simplest and least expensive synthetic polymer. It is familiar today in the plastic bags used for packaging fruit and vegetables, in garment bags for dry-cleaned clothing, in garbage-can liners, and in many other items. Polyethylene is made from ethylene (CH2 = CH2) an unsaturated hydrocarbon (Chapter 9) produced in large quantities from the cracking of petroleum, a process by w hich large hydrocarbon molecules are broken dow n into simpler hydrocarbons. 2.Polypropylene is a tough plastic material that resists moisture, oils, and solvents. It is molded into hard-shell luggage, battery cases, and various kinds of appliance parts. It is also used to make packaging material, fibers for textiles such as upholstery fabrics and carpets, and ropes that float. Because of its high melting point (121 °C), polypropylene objects can be sterilized w ith steam 3. Polystyrene is the plastic used to make transparent disposable drinking cups. With color and filler added, it is the material of thousands of inexpensive toys and household items. When a gas is blow n into polystyrene liquid, it foams and hardens into the familiar material of ice chests and disposable coffee cups. The polymer can easily be formed into shapes as packing material for shipping instruments and appliances, and it is w idely used for home insulation. 4. Question: (TCO 11) Tungsten (W), with a mass number of 180 and an atomic number of 74, decays by emission of an alpha particle. Identify the product of the nuclear reaction by providing its atomic symbol (5 pts), mass number (5 pts), and atomic number (5 pts). (Pts. : 15) mass of 180 becomes 176 atomic number of 74 becomes 72 name: Hafnium Symbol: Hf 6. Question: (TCO 13) What is the mRNA sequence for the following segment of DNA: --TAACGAATAGCCTGT-- (10 pts)? Based upon the mRNA sequence, what is the peptide sequence (10 pts)? (Pts. : 20) This study source was downloaded by 100000841438751 from CourseHero.com on 02-23-2022 14:19:57 GMT -06:00 https://www.coursehero.com/file/51964991/CHEM-120-Final-Answersdocx/ Downloaded by Cyndi McKenzie (cyndimckenzie27@yahoo.com) lOMoARcPSD|8596025
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DNA RNA A = U T = A C = G G = C TAACGAATAGCCTGT w ill become AUUGCUUAUCGGACA Peptide sequence is AUU GCU UAU CGG ACA w hich is Ile-Ala-Tyr-Arg-Thr 7. Question: (TCO 5) Given the following unbalanced chemical equation: Al + Cl 2 -> AlCl 3 (a, 5 pts) Balance the equation. (b, 5 pts) How many moles of AlCl 3 are produced from 1.75 mole of Cl 2 ? Show your work. (c, 5 pts) What is the molar mass of AlCl 3 ? Show your work. (d, 5 pts) Calculate the number of grams of AlCl 3 produced from 1.75 mol Cl 2 . Show your work. (Pts. : 20) A. Balance: 2Al + 3 Cl2 > 2 AlCl3 B. Moles: 1.75 mol Cl2 * (2 mol AlCl3 / 3 mol Cl2) = 1.17 mol AlCl3 C. Molar Mass: Al = 26.981 g/mol Cl = 35.453 g/mol (1 x Al) + (3 x Cl) = (1 x 26.981g/mol) + (3 x 35.453g.mol) 26.981g/mol + 106.359 g/mol = 133.340g/mol = 133.34g/mol D. Grams: 1.75 mol cl2*2/133.34=0.026g 8. Question: (TCO 13) What is the mRNA sequence for the following segment of DNA: --CTCGTGGTTTCATCC-- (10 pts)? Based upon the mRNA sequence, what is the peptide sequence (10 pts)? This study source was downloaded by 100000841438751 from CourseHero.com on 02-23-2022 14:19:57 GMT -06:00 https://www.coursehero.com/file/51964991/CHEM-120-Final-Answersdocx/ Downloaded by Cyndi McKenzie (cyndimckenzie27@yahoo.com) lOMoARcPSD|8596025
(Pts. : 20) DNA RNA A = U T = A C = G G = C CTCGTGGTTTCATCC w ill become GAGCACCAAAGUAGG Peptide sequence is GAG CAC CAA AGU AGG w hich is Glu-His-Gln-Ser-Arg This study source was downloaded by 100000841438751 from CourseHero.com on 02-23-2022 14:19:57 GMT -06:00 https://www.coursehero.com/file/51964991/CHEM-120-Final-Answersdocx/ Powered by TCPDF (www.tcpdf.org) Downloaded by Cyndi McKenzie (cyndimckenzie27@yahoo.com) lOMoARcPSD|8596025