OIDD615 practice questions - solutions
pdf
keyboard_arrow_up
School
University of Pennsylvania *
*We aren’t endorsed by this school
Course
615
Subject
Business
Date
Apr 3, 2024
Type
Pages
13
Uploaded by MegaKnowledgeCrocodile30
1 OIDD615
Practice Questions
Below is a sample of past exam questions. This is not meant to provide a comprehensive list of
possible questions, but it does provide a decent representation of the type of questions that could
be asked on the exam.
Newsvendor
(Q1-5) The National Football League (NFL) has granted Nike an exclusive license to sell NFL replica
jerseys. Nike outsources the jersey cutting and sewing operations to an offshore contract
manufacturer (CM). The jerseys are then delivered to Nike’s Distribution Center (DC). Because of
the long production and shipment leadtimes, Nike must decide in advance how much inventory to
hold at the DC in anticipation of retailers’ orders for the coming season. Nike developed the demand
forecasts provided in the table for the Baltimore Ravens for the upcoming season, assuming
independent normal demand distributions.
Nike sells the NFL jerseys to retailers at a wholesale price of $30 per jersey. For popular players
(like the first four listed above), the CM prints the player’s name and number on the jersey and
ships the completely finished good, known as a dressed jersey, to Nike’s DC. The cost to Nike of a
dressed jersey is $12. Nike does not have the opportunity to make a mid-season replenishment. At
the end of the season, Nike sells its unsold jerseys at a discount price of $8 per jersey.
Product Description
Mean
Standard
Deviation
Joe Flacco
45,000
30,000
Ray Rice
35,000
20,000
Haloti Ngata
25,000
15,000
Terrell Suggs
15,000
10,000
Other players
60,000
30,000
Q1. How many Joe Flacco jerseys should Nike order to maximize expected profit? Demand for his
jersey is Normally distributed with a mean of 45,000 and a standard deviation of 30,000.
Answer: 72,300.
Underage cost is the marginal cost of making one less jersey than the true demand, Cu= 30 - 12 =
18;
Overage cost is the marginal cost of making one more jersey than the true demand, Co= 12 - 8 = 4.
Then the Critical Ratio = Cu / (Co+Cu) = 0.8182
Looking up the probability from the Standard Normal Distribution Function Table we obtain z =
0.91. Then the optimal production quantity, Q = µ + z*σ = 72,300.
2 Q2. Demand for Ray Rice jerseys in normally distributed with a mean of 35,000 and a standard
deviation of 20,000. If Nike orders 45,000 Ray Rice jerseys, how many of these jerseys can Nike
expect to sell at the full price ($30)?
Q3. Demand for the Haloti Ngata jersey is Normally distributed with a mean of 25,000 and a
standard deviation of 15,000. If Nike orders 28,000 Haloti Ngata jerseys, what is the probability
that Nike will be able to satisfy all demand for this jersey? Express the probability as a number
between 0 and 1 (and not as a %).
Q4. Demand for the Terrell Suggs jersey is Normally distributed with a mean of 15,000 and a
standard deviation of 10,000. If Nike orders 10,000 Terrell Suggs jerseys, how many of these
jerseys will they have to sell (in expectation) at the discount price?
Answer: 31,044.
First find the z-score corresponding to the order quantity.
z=(Q-µ)/σ = (45000-35000)/20000= 0.50
To find sales, first find expected leftover inventory. I(z) = I(0.5) = 0.6978. Expected left over inventory =
s
x I(z) = 20,000 x 0.6978 = 13956
Expected Sales = Q – Expected left over inventory = 45,000 – 13956 = 31,044.
Answer: 0.5793.
If Demand is less than 28,000, we satisfy all demand. Hence we need to find the probability
F(28,000)= Pr(Demand<=28000). This is the in-stock probability. (If you satisfy all demand, you are
“in-stock” at the end of the season.)
Find the z-score corresponding to the order quantity.
z=(Q-µ)/σ = 0.2
From the Standard Normal Distribution Function Table Φ(z) = 0.5793.
Answer: 1,978.
First we find the z-score corresponding to the order quantity.
z=(Q-µ)/σ = -0.5.
From the Normal Distribution Inventory Function Table we obtain I(z) = I(-0.5) = 0.1978
Expected leftover inventory =
s
x I(z) = 10,000 x 0.1978 = 1,978
3 Q5. For the less popular players (“Other Players”) the CM ships a blank jersey to Nike’s DC at a cost
of $11. After receiving the orders from retailers, Nike prints the name of the player and number on
the blank jersey, which costs Nike $2 per jersey. Assume the selling price of jerseys with the names
is still the same. If Nike runs out of blank jerseys, they can order more blank jerseys from a local
supplier with essentially an immediate response time. But that supplier charges $14 per blank
jersey. If Nike has blank jerseys left over at the end of the season, they sell them blank for $7 each.
Demand for “Other Players” is Normally distributed with a mean of 60,000 and a standard deviation
of 30,000. How many blank jerseys should Nike purchase from the CM (for $11 each) to maximize
their expected profit from selling “Other Players”?
(Q6-7) (Simplified Hosting Problem) Vmail is a service provider of free email. It hosts all emails on
servers on “the cloud”. The typical usage on Mondays is normally distributed with mean 300 million
minutes and standard deviation 75 million minutes. For a particular Monday, Vmail can buy cloud
capacity well in advance for $0.01 per minute. If it purchases more capacity than it needs, the
capacity goes unused (and they cannot get a refund for the capacity they purchased). If demand on
Monday exceeds the capacity they purchased in advance, they must purchase additional capacity as
needed from a company called Mackspace. However, Mackspace charges $0.03 per minute.
Q6. How much capacity should Vmail purchase in advance (at $0.01 per minute) to minimize its
total expected capacity expense? Give your answer in units of million minutes.
Answer: 54,600.
Cu= 14-11=3. If they order one jersey fewer than demand, they order from the more expensive
supplier which costs $14 (instead of $11 from the regular supplier). The $2 printing cost doesn’t
matter because it is incurred whether $11 or $14 is paid for a blank jersey.
Co = Cost – salvage = $11-$7 = $4. If they over order by one unit, it must be salvaged (but there is no
printing on this blank jersey).
The Critical Ratio = Cu / (Co + Cu) = 0.4286
From the Normal Distribution Function Table we obtain z = -0.18.
Then Q = µ + z*σ = 54,600.
Answer: 333.
Cu= 0.03-0.01 = 0.02 because if you had known you would use the minute of capacity, you would
have purchased it for $0.01 rather than having to buy it from Mackspace for $0.03.
Co=0.01 because if you buy the minute of capacity but don’t use it, you would have just not
purchased the capacity and saved yourself 0.01.
Critical Ratio = 0.6667
From the Standard Normal distribution function table, z = 0.44.
Then Q = µ + z*σ = 333M.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
4 Q7. Suppose Vmail purchases 435 million minutes in advance. How much should Vmail expect to
pay (in $s) to Mackspace (at $0.03 per minute) for the additional capacity required? Recall, their
usage is Normally distributed with mean 300 million minutes and standard deviation 75 million
minutes.
Q8-10 The Penn Bookstore sells several magazines. A single stocking quantity is ordered for each
issue. When a new issue arrives, any remaining copies of the old issue are returned to the publisher.
If a magazine sells out, then it remains unavailable until the next issue arrives.
Q8. Consider the following data on Bits and Bytes magazine at the Penn Bookstore:
The forecast column lists their forecast of demand for that issue (when they ordered copies for that
issue). It is generated by an internal computer system that accounts for seasonality and other
Answer: 32,175.
The charge to Mackspace equals the price per minute times the number of minutes needed. The
number of minutes needed is the expected number of minutes used above 435M.
z= (Q-µ)/σ = (435-300)/75 = 1.80.
From the Standard Normal Inventory Function table we obtain, I(z) = I(1.80) = 1.81
Expected Leftover inventory = sigma x I(z) = 75 x 1.81 = 136.1
Expected Loss Sales = mu – Q + Exp Leftover = 300 – 435 + 136.1 = 1.1
Vmail expected to pay = Expected Loss Sales * 1,000,000 * (0.03) = 32,175.
5 events in the store (which is why the forecast varies from issue to issue). The quantity column is the
actual number of issues stocked that week and the sales column provides the number of units
actually sold. The estimated demand column provides an estimate of what sales could have been
had there been no stockouts. (If sales is less than or equal to the order quantity, the estimated
demand equals sales, otherwise it can be greater.)
Q8. Suppose the week 37 forecast is for 20 copies. What would be the coefficient of variation of
demand? Again, assume a normal distribution is chosen to model demand.
Q9. Consider Modern Active MBA, a periodical dedicated to selecting an MBA program and getting
the most out of the experience. The publisher charges the Penn Bookstore $1.25 for each copy of
MAMBA sold. It costs the publisher $0.40 to print and deliver each copy of the magazine. The
copies that are left over are discarded at a cost of $0.10 per copy to the publisher. The forecast of
demand is normally distributed with a mean of 90 and a standard deviation of 22. What order
quantity maximizes the publisher’s expected profit? (Leave your answer in decimal form, i.e., no
need to round to an integer value.)
Answer = 0.385
The average A/F ratio is 0.97 and the standard deviation of the A/F ratios is 0.37. So the coefficient
of variation is the 0.37 / 0.97 = 0.385
Answer: 97.48.
Cu =$1.25-$0.40 = $0.85 because if you under order by one unit, you could have purchased it for
$0.40 and sold it for $1.25, earning a profit of $0.85
Co = Overage Cost = cost –salvage = 0.40 – (- 0.10) = 0.40+0.10 = $0.50. If an unit is purchased that
is not needed, the publisher incurs the cost to print of $0.4 as well as the cost to dispose which is
$0.10, making the publisher worse off by $0.50
The Critical Ratio=0.6296.
Looking up Standard Normal distribution function table, this gives z=0.34.
Then, the optimal quantity to order = µ + z*σ = 97.48.
6 Q10. Suppose the forecast for the May issue of National Geographic is normally distributed with a
mean of 160 and a standard deviation of 45. The Penn Bookstore plans to stock 200 copies. What is
the probability that they stockout (i.e., do not satisfy all demand)?
Q11. BASF sells customized petrochemical catalysts that are produced in a plant in Germany. Many
of their customers are in North America and transportation is done via ocean carrier. They can
purchase container capacity in advance at the price of $2,250 per container. However, if they
advance purchase containers, they bear the risk of not knowing their exact needs for containers. In
particular, here is a forecast of their needs for June (i.e., a density and distribution function):
If they purchase a container in advance and don’t actually need it, then they will fill it with some
excess product and store that product in North America until it will be sold (i.e., the product is
neither perishable nor at risk of obsolescence). The expected extra storage cost is $350 per
container. For example, if their needs are for 2 containers but they advanced purchased 3
containers, then they ship all three containers and incur an extra $350 charge for the 1 container
filled with excess product. Containers purchased on the spot market (after they learn their needs)
are expected to cost $3000 per container. For example, they may advance purchase 1 container but
discover that they need 3 containers, in which case they would purchase an additional 2 containers
at $3000 each. How many containers should they advance purchase to minimize their costs?
Q
f(Q)
F(Q)
Q
f(Q)
F(Q)
0
0.0952
0.0952
11
0.0222
0.8997
1
0.1640
0.2592
12
0.0182
0.9179
2
0.1343
0.3935
13
0.0149
0.9328
3
0.1099
0.5034
14
0.0122
0.9450
4
0.0900
0.5934
15
0.0100
0.9550
5
0.0737
0.6671
16
0.0082
0.9631
6
0.0603
0.7275
17
0.0067
0.9698
7
0.0494
0.7769
18
0.0055
0.9753
8
0.0404
0.8173
19
0.0045
0.9798
9
0.0331
0.8504
20
0.0037
0.9834
10
0.0271
0.8775
Answer: 0.187.
Q=200. Normalize the order quantity: z= (Q-µ)/σ = 0.89. From the Standard Normal Distribution
Table the outcome of a standard normal is 0.89 or lower with probability 0.813. So the stockout
prob is 1-0.813 = 0.187
Answer: 6 containers
Co = $350. If they reserve one too many containers, they incur a cost of $350 that they would not
have occurred otherwise. The product would have been shipped eventually, so the shipping costs do
not factor into the overage cost.
Cu = $750. If they reserve one too few containers, then they need to purchase a container on the
spot for $3000. Had they known that they would need the container, they could have purchased it
for $2,250. Hence, they incur $750 in additional charges.
Critical ratio = 750 / (350 + 750) = 0.6818
From the table above, F(5) = 0.6671 and F(6) = 0.7275, so they should advance purchase 6
containers.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
7 Q12. PECO has an idea to reduce consumption of electricity by residential users. With a
new plan, the customer pays $0.08 per kWh for the first 1000 kWhs of the month and $0.15
per kWh for additional kWhs (i.e., all kWhs above 1000). If a household’s monthly usage is
normally distributed with a mean of 900 and a standard deviation of 400, what would be
the household’s average monthly bill under this new plan?
Answer:
$80.0
Evaluate some performance metrics for the threshold of 1000 kWhs:
Z = (1000 – 900)/400 = 0.25
I(z=0.25) = 0.5363 and I(Q) = sigma x I(z) = 400 x 0.5363 = 214.5
S(Q) = Q – I(Q) = 1000 – 214.5 = 785.5
L(Q) = mu – S(Q) = 900 – 785.5 = 114.5
S(Q) is the usage that is Q or lower. L(Q) is the usage above Q.
So total spend = 0.08 x S(Q) + 0.15 x L(Q) = 80.0
Alternatively, you spend $0.08 on all demand and an additional $0.07 for each kWh above 1000.
Hence, total spend = $0.08 x 900 + $0.07 x 114.5 = 80.0
8 Q13. A company collected data on the performance of their forecasts of 38 items in the previous
season. The average A/F ratio across this sample is 1.02 and the standard deviation of the A/F
ratios is 0.40. The average forecast is 2405 units. The data are plotted in the following graph.
What comment best describes the quality of their forecasting process?
a)
Their forecasts are too optimistic.
b)
Their forecasts are too pessimistic.
c)
Their forecast errors are small because the average A/F ratio is close to 1.00.
d)
Their high forecasts are too pessimistic and low forecasts are too optimistic.
e)
Their high forecasts are too optimistic and low forecasts are too pessimistic.
f)
It is not possible to assess the quality of their forecasts because of the inherent randomness
of the forecast errors.
0
1000
2000
3000
4000
5000
6000
7000
8000
0
1000
2000
3000
4000
5000
6000
Forecast (in units)
Actual (in units)
Answer d. Forecasts above 2000 tend to have actual demands that are greater than the forecast
(the dot is above the 45 degree line). Forecasts below 2000 tend to have actual demand that are
lower than the forecast (the dot is below the 45 degree line). So they are pessimistic for high
forecasts and optimistic for low forecasts.
9 Q14. Which of the following statements is most likely to correctly characterize the difference
between make-to-order and make-to-stock production?
a)
There is no work-in-process inventory with make-to-order whereas there can be a
considerable amount with make-to-stock.
b)
When firms move production from high labor cost countries to lower labor cost countries
they usually switch from make-to-stock to make-to-order production.
c)
Make-to-stock production copes with seasonal demand by building and drawing down
inventory whereas make-to-order production copes with seasonal demand by adding and
reducing labor.
d)
Firms that offer a narrow product line are more likely to implement make-to-order
production.
e)
None of the above is correct.
f)
All of the above are correct.
Order Upto
Q15. Maxter Healthcare manages inventory of medical supplies at the Hospital of the University of
Pennsylvania. In the emergency ward, their daily need of saline solution is normally distributed
with a mean of 100 units and standard deviation 50 units. Orders are placed daily and received the
next day (i.e. the lead time is one day). What order up-to level should Maxter use if they want to
ensure a 99.5% in-stock probability while minimizing inventory?
Answer c. (a) is incorrect because there is WIP with make-to-order. (b) is incorrect because it is not
the case that high labor cost countries operate with make-to-stock and low-labor cost countries
operate make-to-order (if anything, the pattern would probably be reversed). (d) make-to-order is
done to provide variety, not to reduce it. (c) is correct because make-to-stock makes product in
advance of demand, so if there is seasonality, then make-to-stock must build inventory in advance
of a peak. As make-to-order cannot make product in advance of demand, when demand is high, it
either makes customers wait a long time or it hires labor to cope with the surge.
Answer: 382
We want instock probability of 0.9950.
Looking up the Standard Normal distribution function table, we find z-score corresponding to the
probability 0.995 is 2.58.
Mu = The mean over L+1 periods is 100*2 = 200;
Sigma = The standard deviation over L+1 periods is sqrt(2)*50 = 70.7,
S= mu + z * sigma = 382
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
10 Q16. Continuing from Q15, the lead time to replenish a particular drug is 2 days and they are able to
order replenishment daily. Demand over a 3 day period is normally distributed with a mean of 50
units and a standard deviation of 20 units. Suppose Maxter operates with a basestock level of 75.
What would be the average number of units on-hand at the end of each day?
Q17. Indiana Steel orders coal on a weekly basis for its steel processing facility. The coal arrives in
rail cars. Their weekly demand is normally distributed with a mean of 2500 tons and a standard
deviation of 1000 tons. Orders are received with a four-week leadtime. If their base stock level is
13,000 tons, then what is their in-stock probability?
Q18. To manage its inventory of coal, suppose Indiana Steel uses an order up-to policy with a base
stock level of 11,000 tons, weekly demand remains 2500 tons with a standard deviation of 1000
tons, and there is a four-week leadtime. On average, how many tons of coal do they have on order
(i.e., in pipeline inventory)?
Answer: 26.0
We are given the demand distribution over l+1 periods.
Z = (75 - 50)/20 = 1.25
I(z) = 1.3006
Expected on-hand =
s
x I(z) = 20 x 1.3006 = 26
Answer = 0.588
Mu = demand over l+1 periods = 5 x 2500 = 12,500
Sigma = stdev over l+1 periods = sqrt(5) x 1000 = 2236
Z = (S-mu)/sigma = (13,000 - 12,500)/2236 = 0.223
F(z) = in-stock = 0.588
Answer: 10000
Pipeline inventory = demand over l periods = 4 x 2500 = 10,000
Pipeline inventory does not depend on the basestock level.
11 Q19. A company ships products from China to the United States with a weekly order up-to system.
The transit time between these two locations is 8 weeks. Weekly demand is 600 units with
standard deviation 300. Each unit costs $80 and the company’s annual inventory holding cost is
36%. Assume 52 weeks per year. Considering only the holding costs associated with the transit
from China to the United States, what is the holding cost incurred per unit?
Q20. SuperFresh uses a base-stock policy to order Fage yoghurt. They place orders at the start of
each day and receive their order two days later (i.e., the lead time is two days). For example, the
Monday morning order is received Wednesday morning. They place orders and receive orders all
seven days of the week. Daily demand for one flavor is Poisson with mean 1.5. It is Monday
morning; they have 4 units on-hand and 2 units in pipeline (on-order). They choose a basestock
level to achieve a 98.5% in-stock probability while minimizing inventory. What was demand
yesterday (i.e., on Sunday)?
Answer: 4.43
8 week lead time -> 8 x 600 = 4800 units in inventory
4800 x $80 = $348,000 total inventory cost.
Holding cost for the year is 36% x $348,000 = $138,240
Yearly demand = 52 x 600 = 31,200
Hold cost per unit = $138,240 / 31,200 = $4.43
Answer: 4
Demand over L+1 days is (2+1) x 1.5 = 4.5
From the Poisson Distribution Function Table, F(10)=0.993 and F(9)=0.983, so round up to S = 10.
The inventory position is 4 + 2 = 6.
Demand yesterday must be the difference between the basestock level and the inventory position,
which is 10 - 6 = 4.
12 Q21. Aldi sells its private label granola cereal. Daily demand is Poisson with mean 3.5. Aldi
replenishes stores daily, and the lead time to receive an order is 1 day. If they manage inventory of
this product using a base stock level of 10, then what would be their average end-of-the-day on-
hand inventory?
Q22. Weekly demand for a wrench kit at Ace Hardware is Poisson with mean 0.2. They have
a one week replenishment lead time and operate with a basestock level of 1. What is their
weeks-of-supply for this wrench kit?
Q23. Lowes sells the Sunburst Rose for $25 per unit and they buy it for $10 per unit. There is a
short season for this product and they get to place a single order with their supplier. Demand
during the selling season is expected to be Poisson with mean 8.25. Roses that are left over at the
end of the season are thrown away. If they purchase 12 of the Sunburst Roses, what is the
probability that Lowes makes a positive profit on this purchase?
Answer: 3.2
Demand over l+1 days is (1+1)x3.5 = 7.0
S = 10
From the Poisson Inventory Function Table, I(S) = 3.2
Answer: 3.35 weeks
Demand over l+1 weeks is (1+1) x 0.2 = 0.4
S = 1
From the Poisson Inventory Function table, I(S) = 0.67
Weeks of supply = 0.67 / 0.2 = 3.35
Answer: 0.914
If they purchase 12 at $10 each, their total cost is 12 x $10 = 120. At $25 per sale, they need
120/$25 = 4.8 sales to break even. As they cannot get 4.8 sales, they break even if they sell 5 or
more.
The probability to sell 5 or more is equal to 1 - Prob(Sell 4 or fewer).
From the Poisson Distribution Function Table with mean 8.25, F(4) = 0.086
So they get a positive profit with probability 1-0.086= 0.914
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
13 Q24. Product A’s demand is normally distributed with mean 150 and standard deviation 50.
Product B’s demand is also normally distributed with mean 150 and standard deviation 50. The
sum of demand for these two products is normally distributed with a mean of 300 and a standard
deviation of 50. Which of the following is most likely?
a)
Demands for these products are positively correlated
b)
Demands for these products are negatively correlated
c)
Demands for these products are independent
d)
It is not possible to determine with this information if these products are
positively correlated, negatively correlated or independent.
Q25. Based on the HP case, which of the following explain why the remote localization strategy was
more effective for the European market than for the North American market?
i.
From the production facility in Vancouver, the lead time to Europe is shorter than
the lead time to North America.
ii.
Demand in the North American market is dominated by only one printer version
whereas demand is more dispersed across several versions in the European market.
iii.
The in-stock requirement is lower in Europe than it is in North America
a)
I only
b)
II only
c)
III only
d)
I and II
e)
I and III
f)
II and III
g)
All of above (i.e., I, II and III)
h)
None of the above (i.e., neither I, II or III)
Answer: b.
The easiest way to solve this question, is assume that the demands are independent.
If the products are not-correlated (i.e., independent) the standard deviation of the total demand for
two products would be sqrt(2)*50 = 70.70.
However, the current observed standard deviation is smaller.
Hence the products are negatively
correlated.
Answer: b. The lead time to Europe is longer. The in-stock requirements are the same.
Related Documents
Recommended textbooks for you

Purchasing and Supply Chain Management
Operations Management
ISBN:9781285869681
Author:Robert M. Monczka, Robert B. Handfield, Larry C. Giunipero, James L. Patterson
Publisher:Cengage Learning
Recommended textbooks for you
- Purchasing and Supply Chain ManagementOperations ManagementISBN:9781285869681Author:Robert M. Monczka, Robert B. Handfield, Larry C. Giunipero, James L. PattersonPublisher:Cengage Learning

Purchasing and Supply Chain Management
Operations Management
ISBN:9781285869681
Author:Robert M. Monczka, Robert B. Handfield, Larry C. Giunipero, James L. Patterson
Publisher:Cengage Learning