OIDD615 practice questions - solutions

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1 OIDD615 Practice Questions Below is a sample of past exam questions. This is not meant to provide a comprehensive list of possible questions, but it does provide a decent representation of the type of questions that could be asked on the exam. Newsvendor (Q1-5) The National Football League (NFL) has granted Nike an exclusive license to sell NFL replica jerseys. Nike outsources the jersey cutting and sewing operations to an offshore contract manufacturer (CM). The jerseys are then delivered to Nike’s Distribution Center (DC). Because of the long production and shipment leadtimes, Nike must decide in advance how much inventory to hold at the DC in anticipation of retailers’ orders for the coming season. Nike developed the demand forecasts provided in the table for the Baltimore Ravens for the upcoming season, assuming independent normal demand distributions. Nike sells the NFL jerseys to retailers at a wholesale price of $30 per jersey. For popular players (like the first four listed above), the CM prints the player’s name and number on the jersey and ships the completely finished good, known as a dressed jersey, to Nike’s DC. The cost to Nike of a dressed jersey is $12. Nike does not have the opportunity to make a mid-season replenishment. At the end of the season, Nike sells its unsold jerseys at a discount price of $8 per jersey. Product Description Mean Standard Deviation Joe Flacco 45,000 30,000 Ray Rice 35,000 20,000 Haloti Ngata 25,000 15,000 Terrell Suggs 15,000 10,000 Other players 60,000 30,000 Q1. How many Joe Flacco jerseys should Nike order to maximize expected profit? Demand for his jersey is Normally distributed with a mean of 45,000 and a standard deviation of 30,000. Answer: 72,300. Underage cost is the marginal cost of making one less jersey than the true demand, Cu= 30 - 12 = 18; Overage cost is the marginal cost of making one more jersey than the true demand, Co= 12 - 8 = 4. Then the Critical Ratio = Cu / (Co+Cu) = 0.8182 Looking up the probability from the Standard Normal Distribution Function Table we obtain z = 0.91. Then the optimal production quantity, Q = µ + z*σ = 72,300.
2 Q2. Demand for Ray Rice jerseys in normally distributed with a mean of 35,000 and a standard deviation of 20,000. If Nike orders 45,000 Ray Rice jerseys, how many of these jerseys can Nike expect to sell at the full price ($30)? Q3. Demand for the Haloti Ngata jersey is Normally distributed with a mean of 25,000 and a standard deviation of 15,000. If Nike orders 28,000 Haloti Ngata jerseys, what is the probability that Nike will be able to satisfy all demand for this jersey? Express the probability as a number between 0 and 1 (and not as a %). Q4. Demand for the Terrell Suggs jersey is Normally distributed with a mean of 15,000 and a standard deviation of 10,000. If Nike orders 10,000 Terrell Suggs jerseys, how many of these jerseys will they have to sell (in expectation) at the discount price? Answer: 31,044. First find the z-score corresponding to the order quantity. z=(Q-µ)/σ = (45000-35000)/20000= 0.50 To find sales, first find expected leftover inventory. I(z) = I(0.5) = 0.6978. Expected left over inventory = s x I(z) = 20,000 x 0.6978 = 13956 Expected Sales = Q – Expected left over inventory = 45,000 – 13956 = 31,044. Answer: 0.5793. If Demand is less than 28,000, we satisfy all demand. Hence we need to find the probability F(28,000)= Pr(Demand<=28000). This is the in-stock probability. (If you satisfy all demand, you are “in-stock” at the end of the season.) Find the z-score corresponding to the order quantity. z=(Q-µ)/σ = 0.2 From the Standard Normal Distribution Function Table Φ(z) = 0.5793. Answer: 1,978. First we find the z-score corresponding to the order quantity. z=(Q-µ)/σ = -0.5. From the Normal Distribution Inventory Function Table we obtain I(z) = I(-0.5) = 0.1978 Expected leftover inventory = s x I(z) = 10,000 x 0.1978 = 1,978
3 Q5. For the less popular players (“Other Players”) the CM ships a blank jersey to Nike’s DC at a cost of $11. After receiving the orders from retailers, Nike prints the name of the player and number on the blank jersey, which costs Nike $2 per jersey. Assume the selling price of jerseys with the names is still the same. If Nike runs out of blank jerseys, they can order more blank jerseys from a local supplier with essentially an immediate response time. But that supplier charges $14 per blank jersey. If Nike has blank jerseys left over at the end of the season, they sell them blank for $7 each. Demand for “Other Players” is Normally distributed with a mean of 60,000 and a standard deviation of 30,000. How many blank jerseys should Nike purchase from the CM (for $11 each) to maximize their expected profit from selling “Other Players”? (Q6-7) (Simplified Hosting Problem) Vmail is a service provider of free email. It hosts all emails on servers on “the cloud”. The typical usage on Mondays is normally distributed with mean 300 million minutes and standard deviation 75 million minutes. For a particular Monday, Vmail can buy cloud capacity well in advance for $0.01 per minute. If it purchases more capacity than it needs, the capacity goes unused (and they cannot get a refund for the capacity they purchased). If demand on Monday exceeds the capacity they purchased in advance, they must purchase additional capacity as needed from a company called Mackspace. However, Mackspace charges $0.03 per minute. Q6. How much capacity should Vmail purchase in advance (at $0.01 per minute) to minimize its total expected capacity expense? Give your answer in units of million minutes. Answer: 54,600. Cu= 14-11=3. If they order one jersey fewer than demand, they order from the more expensive supplier which costs $14 (instead of $11 from the regular supplier). The $2 printing cost doesn’t matter because it is incurred whether $11 or $14 is paid for a blank jersey. Co = Cost – salvage = $11-$7 = $4. If they over order by one unit, it must be salvaged (but there is no printing on this blank jersey). The Critical Ratio = Cu / (Co + Cu) = 0.4286 From the Normal Distribution Function Table we obtain z = -0.18. Then Q = µ + z*σ = 54,600. Answer: 333. Cu= 0.03-0.01 = 0.02 because if you had known you would use the minute of capacity, you would have purchased it for $0.01 rather than having to buy it from Mackspace for $0.03. Co=0.01 because if you buy the minute of capacity but don’t use it, you would have just not purchased the capacity and saved yourself 0.01. Critical Ratio = 0.6667 From the Standard Normal distribution function table, z = 0.44. Then Q = µ + z*σ = 333M.
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4 Q7. Suppose Vmail purchases 435 million minutes in advance. How much should Vmail expect to pay (in $s) to Mackspace (at $0.03 per minute) for the additional capacity required? Recall, their usage is Normally distributed with mean 300 million minutes and standard deviation 75 million minutes. Q8-10 The Penn Bookstore sells several magazines. A single stocking quantity is ordered for each issue. When a new issue arrives, any remaining copies of the old issue are returned to the publisher. If a magazine sells out, then it remains unavailable until the next issue arrives. Q8. Consider the following data on Bits and Bytes magazine at the Penn Bookstore: The forecast column lists their forecast of demand for that issue (when they ordered copies for that issue). It is generated by an internal computer system that accounts for seasonality and other Answer: 32,175. The charge to Mackspace equals the price per minute times the number of minutes needed. The number of minutes needed is the expected number of minutes used above 435M. z= (Q-µ)/σ = (435-300)/75 = 1.80. From the Standard Normal Inventory Function table we obtain, I(z) = I(1.80) = 1.81 Expected Leftover inventory = sigma x I(z) = 75 x 1.81 = 136.1 Expected Loss Sales = mu – Q + Exp Leftover = 300 – 435 + 136.1 = 1.1 Vmail expected to pay = Expected Loss Sales * 1,000,000 * (0.03) = 32,175.
5 events in the store (which is why the forecast varies from issue to issue). The quantity column is the actual number of issues stocked that week and the sales column provides the number of units actually sold. The estimated demand column provides an estimate of what sales could have been had there been no stockouts. (If sales is less than or equal to the order quantity, the estimated demand equals sales, otherwise it can be greater.) Q8. Suppose the week 37 forecast is for 20 copies. What would be the coefficient of variation of demand? Again, assume a normal distribution is chosen to model demand. Q9. Consider Modern Active MBA, a periodical dedicated to selecting an MBA program and getting the most out of the experience. The publisher charges the Penn Bookstore $1.25 for each copy of MAMBA sold. It costs the publisher $0.40 to print and deliver each copy of the magazine. The copies that are left over are discarded at a cost of $0.10 per copy to the publisher. The forecast of demand is normally distributed with a mean of 90 and a standard deviation of 22. What order quantity maximizes the publisher’s expected profit? (Leave your answer in decimal form, i.e., no need to round to an integer value.) Answer = 0.385 The average A/F ratio is 0.97 and the standard deviation of the A/F ratios is 0.37. So the coefficient of variation is the 0.37 / 0.97 = 0.385 Answer: 97.48. Cu =$1.25-$0.40 = $0.85 because if you under order by one unit, you could have purchased it for $0.40 and sold it for $1.25, earning a profit of $0.85 Co = Overage Cost = cost –salvage = 0.40 – (- 0.10) = 0.40+0.10 = $0.50. If an unit is purchased that is not needed, the publisher incurs the cost to print of $0.4 as well as the cost to dispose which is $0.10, making the publisher worse off by $0.50 The Critical Ratio=0.6296. Looking up Standard Normal distribution function table, this gives z=0.34. Then, the optimal quantity to order = µ + z*σ = 97.48.
6 Q10. Suppose the forecast for the May issue of National Geographic is normally distributed with a mean of 160 and a standard deviation of 45. The Penn Bookstore plans to stock 200 copies. What is the probability that they stockout (i.e., do not satisfy all demand)? Q11. BASF sells customized petrochemical catalysts that are produced in a plant in Germany. Many of their customers are in North America and transportation is done via ocean carrier. They can purchase container capacity in advance at the price of $2,250 per container. However, if they advance purchase containers, they bear the risk of not knowing their exact needs for containers. In particular, here is a forecast of their needs for June (i.e., a density and distribution function): If they purchase a container in advance and don’t actually need it, then they will fill it with some excess product and store that product in North America until it will be sold (i.e., the product is neither perishable nor at risk of obsolescence). The expected extra storage cost is $350 per container. For example, if their needs are for 2 containers but they advanced purchased 3 containers, then they ship all three containers and incur an extra $350 charge for the 1 container filled with excess product. Containers purchased on the spot market (after they learn their needs) are expected to cost $3000 per container. For example, they may advance purchase 1 container but discover that they need 3 containers, in which case they would purchase an additional 2 containers at $3000 each. How many containers should they advance purchase to minimize their costs? Q f(Q) F(Q) Q f(Q) F(Q) 0 0.0952 0.0952 11 0.0222 0.8997 1 0.1640 0.2592 12 0.0182 0.9179 2 0.1343 0.3935 13 0.0149 0.9328 3 0.1099 0.5034 14 0.0122 0.9450 4 0.0900 0.5934 15 0.0100 0.9550 5 0.0737 0.6671 16 0.0082 0.9631 6 0.0603 0.7275 17 0.0067 0.9698 7 0.0494 0.7769 18 0.0055 0.9753 8 0.0404 0.8173 19 0.0045 0.9798 9 0.0331 0.8504 20 0.0037 0.9834 10 0.0271 0.8775 Answer: 0.187. Q=200. Normalize the order quantity: z= (Q-µ)/σ = 0.89. From the Standard Normal Distribution Table the outcome of a standard normal is 0.89 or lower with probability 0.813. So the stockout prob is 1-0.813 = 0.187 Answer: 6 containers Co = $350. If they reserve one too many containers, they incur a cost of $350 that they would not have occurred otherwise. The product would have been shipped eventually, so the shipping costs do not factor into the overage cost. Cu = $750. If they reserve one too few containers, then they need to purchase a container on the spot for $3000. Had they known that they would need the container, they could have purchased it for $2,250. Hence, they incur $750 in additional charges. Critical ratio = 750 / (350 + 750) = 0.6818 From the table above, F(5) = 0.6671 and F(6) = 0.7275, so they should advance purchase 6 containers.
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7 Q12. PECO has an idea to reduce consumption of electricity by residential users. With a new plan, the customer pays $0.08 per kWh for the first 1000 kWhs of the month and $0.15 per kWh for additional kWhs (i.e., all kWhs above 1000). If a household’s monthly usage is normally distributed with a mean of 900 and a standard deviation of 400, what would be the household’s average monthly bill under this new plan? Answer: $80.0 Evaluate some performance metrics for the threshold of 1000 kWhs: Z = (1000 – 900)/400 = 0.25 I(z=0.25) = 0.5363 and I(Q) = sigma x I(z) = 400 x 0.5363 = 214.5 S(Q) = Q – I(Q) = 1000 – 214.5 = 785.5 L(Q) = mu – S(Q) = 900 – 785.5 = 114.5 S(Q) is the usage that is Q or lower. L(Q) is the usage above Q. So total spend = 0.08 x S(Q) + 0.15 x L(Q) = 80.0 Alternatively, you spend $0.08 on all demand and an additional $0.07 for each kWh above 1000. Hence, total spend = $0.08 x 900 + $0.07 x 114.5 = 80.0
8 Q13. A company collected data on the performance of their forecasts of 38 items in the previous season. The average A/F ratio across this sample is 1.02 and the standard deviation of the A/F ratios is 0.40. The average forecast is 2405 units. The data are plotted in the following graph. What comment best describes the quality of their forecasting process? a) Their forecasts are too optimistic. b) Their forecasts are too pessimistic. c) Their forecast errors are small because the average A/F ratio is close to 1.00. d) Their high forecasts are too pessimistic and low forecasts are too optimistic. e) Their high forecasts are too optimistic and low forecasts are too pessimistic. f) It is not possible to assess the quality of their forecasts because of the inherent randomness of the forecast errors. 0 1000 2000 3000 4000 5000 6000 7000 8000 0 1000 2000 3000 4000 5000 6000 Forecast (in units) Actual (in units) Answer d. Forecasts above 2000 tend to have actual demands that are greater than the forecast (the dot is above the 45 degree line). Forecasts below 2000 tend to have actual demand that are lower than the forecast (the dot is below the 45 degree line). So they are pessimistic for high forecasts and optimistic for low forecasts.
9 Q14. Which of the following statements is most likely to correctly characterize the difference between make-to-order and make-to-stock production? a) There is no work-in-process inventory with make-to-order whereas there can be a considerable amount with make-to-stock. b) When firms move production from high labor cost countries to lower labor cost countries they usually switch from make-to-stock to make-to-order production. c) Make-to-stock production copes with seasonal demand by building and drawing down inventory whereas make-to-order production copes with seasonal demand by adding and reducing labor. d) Firms that offer a narrow product line are more likely to implement make-to-order production. e) None of the above is correct. f) All of the above are correct. Order Upto Q15. Maxter Healthcare manages inventory of medical supplies at the Hospital of the University of Pennsylvania. In the emergency ward, their daily need of saline solution is normally distributed with a mean of 100 units and standard deviation 50 units. Orders are placed daily and received the next day (i.e. the lead time is one day). What order up-to level should Maxter use if they want to ensure a 99.5% in-stock probability while minimizing inventory? Answer c. (a) is incorrect because there is WIP with make-to-order. (b) is incorrect because it is not the case that high labor cost countries operate with make-to-stock and low-labor cost countries operate make-to-order (if anything, the pattern would probably be reversed). (d) make-to-order is done to provide variety, not to reduce it. (c) is correct because make-to-stock makes product in advance of demand, so if there is seasonality, then make-to-stock must build inventory in advance of a peak. As make-to-order cannot make product in advance of demand, when demand is high, it either makes customers wait a long time or it hires labor to cope with the surge. Answer: 382 We want instock probability of 0.9950. Looking up the Standard Normal distribution function table, we find z-score corresponding to the probability 0.995 is 2.58. Mu = The mean over L+1 periods is 100*2 = 200; Sigma = The standard deviation over L+1 periods is sqrt(2)*50 = 70.7, S= mu + z * sigma = 382
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10 Q16. Continuing from Q15, the lead time to replenish a particular drug is 2 days and they are able to order replenishment daily. Demand over a 3 day period is normally distributed with a mean of 50 units and a standard deviation of 20 units. Suppose Maxter operates with a basestock level of 75. What would be the average number of units on-hand at the end of each day? Q17. Indiana Steel orders coal on a weekly basis for its steel processing facility. The coal arrives in rail cars. Their weekly demand is normally distributed with a mean of 2500 tons and a standard deviation of 1000 tons. Orders are received with a four-week leadtime. If their base stock level is 13,000 tons, then what is their in-stock probability? Q18. To manage its inventory of coal, suppose Indiana Steel uses an order up-to policy with a base stock level of 11,000 tons, weekly demand remains 2500 tons with a standard deviation of 1000 tons, and there is a four-week leadtime. On average, how many tons of coal do they have on order (i.e., in pipeline inventory)? Answer: 26.0 We are given the demand distribution over l+1 periods. Z = (75 - 50)/20 = 1.25 I(z) = 1.3006 Expected on-hand = s x I(z) = 20 x 1.3006 = 26 Answer = 0.588 Mu = demand over l+1 periods = 5 x 2500 = 12,500 Sigma = stdev over l+1 periods = sqrt(5) x 1000 = 2236 Z = (S-mu)/sigma = (13,000 - 12,500)/2236 = 0.223 F(z) = in-stock = 0.588 Answer: 10000 Pipeline inventory = demand over l periods = 4 x 2500 = 10,000 Pipeline inventory does not depend on the basestock level.
11 Q19. A company ships products from China to the United States with a weekly order up-to system. The transit time between these two locations is 8 weeks. Weekly demand is 600 units with standard deviation 300. Each unit costs $80 and the company’s annual inventory holding cost is 36%. Assume 52 weeks per year. Considering only the holding costs associated with the transit from China to the United States, what is the holding cost incurred per unit? Q20. SuperFresh uses a base-stock policy to order Fage yoghurt. They place orders at the start of each day and receive their order two days later (i.e., the lead time is two days). For example, the Monday morning order is received Wednesday morning. They place orders and receive orders all seven days of the week. Daily demand for one flavor is Poisson with mean 1.5. It is Monday morning; they have 4 units on-hand and 2 units in pipeline (on-order). They choose a basestock level to achieve a 98.5% in-stock probability while minimizing inventory. What was demand yesterday (i.e., on Sunday)? Answer: 4.43 8 week lead time -> 8 x 600 = 4800 units in inventory 4800 x $80 = $348,000 total inventory cost. Holding cost for the year is 36% x $348,000 = $138,240 Yearly demand = 52 x 600 = 31,200 Hold cost per unit = $138,240 / 31,200 = $4.43 Answer: 4 Demand over L+1 days is (2+1) x 1.5 = 4.5 From the Poisson Distribution Function Table, F(10)=0.993 and F(9)=0.983, so round up to S = 10. The inventory position is 4 + 2 = 6. Demand yesterday must be the difference between the basestock level and the inventory position, which is 10 - 6 = 4.
12 Q21. Aldi sells its private label granola cereal. Daily demand is Poisson with mean 3.5. Aldi replenishes stores daily, and the lead time to receive an order is 1 day. If they manage inventory of this product using a base stock level of 10, then what would be their average end-of-the-day on- hand inventory? Q22. Weekly demand for a wrench kit at Ace Hardware is Poisson with mean 0.2. They have a one week replenishment lead time and operate with a basestock level of 1. What is their weeks-of-supply for this wrench kit? Q23. Lowes sells the Sunburst Rose for $25 per unit and they buy it for $10 per unit. There is a short season for this product and they get to place a single order with their supplier. Demand during the selling season is expected to be Poisson with mean 8.25. Roses that are left over at the end of the season are thrown away. If they purchase 12 of the Sunburst Roses, what is the probability that Lowes makes a positive profit on this purchase? Answer: 3.2 Demand over l+1 days is (1+1)x3.5 = 7.0 S = 10 From the Poisson Inventory Function Table, I(S) = 3.2 Answer: 3.35 weeks Demand over l+1 weeks is (1+1) x 0.2 = 0.4 S = 1 From the Poisson Inventory Function table, I(S) = 0.67 Weeks of supply = 0.67 / 0.2 = 3.35 Answer: 0.914 If they purchase 12 at $10 each, their total cost is 12 x $10 = 120. At $25 per sale, they need 120/$25 = 4.8 sales to break even. As they cannot get 4.8 sales, they break even if they sell 5 or more. The probability to sell 5 or more is equal to 1 - Prob(Sell 4 or fewer). From the Poisson Distribution Function Table with mean 8.25, F(4) = 0.086 So they get a positive profit with probability 1-0.086= 0.914
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13 Q24. Product A’s demand is normally distributed with mean 150 and standard deviation 50. Product B’s demand is also normally distributed with mean 150 and standard deviation 50. The sum of demand for these two products is normally distributed with a mean of 300 and a standard deviation of 50. Which of the following is most likely? a) Demands for these products are positively correlated b) Demands for these products are negatively correlated c) Demands for these products are independent d) It is not possible to determine with this information if these products are positively correlated, negatively correlated or independent. Q25. Based on the HP case, which of the following explain why the remote localization strategy was more effective for the European market than for the North American market? i. From the production facility in Vancouver, the lead time to Europe is shorter than the lead time to North America. ii. Demand in the North American market is dominated by only one printer version whereas demand is more dispersed across several versions in the European market. iii. The in-stock requirement is lower in Europe than it is in North America a) I only b) II only c) III only d) I and II e) I and III f) II and III g) All of above (i.e., I, II and III) h) None of the above (i.e., neither I, II or III) Answer: b. The easiest way to solve this question, is assume that the demands are independent. If the products are not-correlated (i.e., independent) the standard deviation of the total demand for two products would be sqrt(2)*50 = 70.70. However, the current observed standard deviation is smaller. Hence the products are negatively correlated. Answer: b. The lead time to Europe is longer. The in-stock requirements are the same.