Gummy Bear Osmosis Experiment: Analysis and Results

Assignment 5 submission form Part A – online activities: Complete the playposit video and h5p game shared in the assignment instructions. Collect images of your final score and insert here. [copy snapshot of playposit video score here] [copy snapshot of h5p game score here] Part B – anatomy practice: Download and save (or download and print) anatomy images shared in assignment instructions. Label all structures referenced in the list. Save or take a clear picture/snapshot of each page and insert here. [copy labeled image here]

Part C – hands on activity: Type/insert your work related to the osmosis activity below. Note some questions need to be answered in more than one sentence to earn full credit. Don’t limit yourself to the space below if you need more room. Initial items - Record your initial data here:  Control gummy: 20 mm length, 15mm width, 12 mm depth. 20*15*12= 3600mm cubed.  water gummy: 20 mm length, 15mm width, 12 mm depth. 20*15*12= 3600mm cubed.  sugar gummy: 20 mm length, 15mm width, 12 mm depth. 20*15*12= 3600mm cubed. [copy initial size picture here]

[copy start time and date picture here] Start Date: 3/3/21 at 4 pm Share your three hypotheses here:

Your preview ends here

Eager to read complete document? Join bartleby learn and gain access to the full version

Access to all documents
Unlimited textbook solutions
24/7 expert homework help

 I hypothesize that when a gummy bear is placed in water, it will swell after 24 hours due to osmosis effect. Water is moving towards the lower water concentrated side making the gummy bear hypertonic.  I hypothesize that when a gummy bear is placed in sugar solution, it will grow bigger since the water is moving to higher sugar concentration in the gummy bear indicating that it is hypertonic.  I hypothesize that when a gummy bear is placed in no solution it will maintain its original size since there is no osmosis affect involved with the gummy bear. 24hour items – Record your 24hour data here:  Control gummy: 20 mm length, 15mm width, 12 mm depth. 20*15*12= 3600mm cubed.  Water gummy: 30 mm length, 20 mm width, and 15 mm depth. 30*20*15= 9000 cubed  Sugar gummy bear: 15 mm length, 13 mm width, 10 mm depth. 15*10*10= 1950 cubed. [copy 24hour size picture here] [copy 24 hour selfie picture here]

Questions – 1. Did the control change? If so, did its volume get bigger or smaller, and by how much? Would you expect the control to change?  No, I did not expect the control to change in size or its volume since it was not afflicted with any solutions such as water or sugar compared to the other two gummy bears. 2. Did the Gummi bear in sugar, syrup, or saltwater change? If so, did its volume get bigger or smaller, and by how much?  Yes, the gummy bear in the sugar solution changed in size and it seamed smaller than the gummy bear that was in the water. The volume of the gummi bear in the sugar changed from 3600 mm to 19500mm 3. Did the Gummi bear in water change? If so, did its volume get bigger or smaller, and by how much?  Yes, the gummy bear in water grew the biggest and the volume of it changed from 3600mm to 9,000 mm. 4. Based on your results, did you support or reject your hypothesis for the control? Explain.  My hypothesis for the control gummi bear was supported since the gummy bear did not go through osmosis process. 5. Based on your results, did you support or reject your hypothesis for the Gummi bear in sugar, syrup, or salt water? Explain.

 my hypothesis was supported. The gummy bear grew bigger due to water moving in the gummy bear but since there the gummy bear was in sugar solution the gummy bear did not get as big as the gummy bear in the water and the reason for that is that there is sugar in both the water and in the gummy bear gelatin so the water was balanced in both the sugar water and in the gummy bear. 6. Based on your results, did you support or reject your hypothesis for the Gummi bear in water? Explain.  My hypothesis was supported for the gummi bear in water since there was more sugar in the gummy bear and no sugar in water, water started to move inside the gummy bear trying to balance, making the gummy bear swell and hypertonic. 7. Did you prove any of your hypotheses? If so, which one(s)?  I was able to support my hypothesis for both the gummi bear in sugar and the gummy bear in water since the two processes was involved with osmosis. Osmosis occurs when water starts to move from hypotonic to hypertonic within the plasma membrane as the water eventually equalizes water concentration in both sides. [copy 24 hour switch size picture here] Questions – 8. Compare your 24 hour and 24-hour switch pictures for your Gummi candy that was originally in the water, but then switched to the sugar, syrup, or salt solution. What differences do you observe?  I observed that the when the gummy bear that was originally in water decreased in size after switching it to sugar solution after 24hour switch.

Your preview ends here

Eager to read complete document? Join bartleby learn and gain access to the full version

Access to all documents
Unlimited textbook solutions
24/7 expert homework help

9. Compare your 24 hour and 24 hour switch pictures for your Gummi candy that was originally in the sugar, syrup, or salt solution, but then switched to the water. What differences do you observe?  The gummy bear that was in the sugar originally increased in size after 24 hours of switching into water. 10. Based on your results of the switch, does it appear as though osmosis is reversible?  It seems that osmosis is reversible since one became bigger in size and another smaller in size after 24hour switch. However, I do not think it would be reversable if there was no gelatin in the gummy bears. 11. Based on your experimental results, was one of your solutions clearly hypertonic to your Gummi candy? If so, which solution was the hypertonic solution? (hint: this question is best answered by looking at both your 24 hour and 24 hour switch results; the gelatin in Gummi candies makes them very resistant to changes in shape, even when put into a hypertonic solution; however, the 24 hour switch helps to clarify your results)  Yes, one of the solutions was hypertonic to the gummy candy. The solution that was hypertonic to the gummy bear was the sugar solution since water was moving out of the gummy bear but not entirely (equilibrium), making the gummy bear shrink in size and volume. 12. Based on your experimental results, was one of your solutions clearly hypotonic to your Gummi candy? If so, which solution was the hypotonic solution?  The solution that was hypotonic to the gummy candy was the water solution since water was moving between the membrane trying to equalize water concentration of both sides which caused the gummy bear to grow in size and volume. 13. Suppose a human blood cell containing a 0.9 percent solute concentration were put into a container of 0 percent solute solution (i.e., distilled water). Would the blood cell get bigger or smaller? Why? In your explanation, you must tell me which area has the hypotonic solution (inside the blood cell or outside the blood cell), which area has the hypertonic solution (inside the blood cell or outside the blood cell), and which direction the water would be moving (into the cell or out of the cell).  0 percent solute solution would move into the blood cells and will would make the cell bigger when human blood cell containing 0.9% solute concentration is placed into a container of 0% solute solution. The blood cell is hypertonic compared to the distilled water which is hypotonic outside of the cell. 14. Suppose a human blood cell containing a 0.9 percent solute concentration were put into a container of 30 percent solute solution. Would the blood cell get bigger or smaller? Why? In your explanation, you must tell me which area has the hypotonic solution (inside the blood cell or outside the blood cell), which area has the hypertonic solution

(inside the blood cell or outside the blood cell), and which direction the water would be moving (into the cell or out of the cell).  30 percent solute solution outside the blood cell would be hypertonic whereas the solute solution inside the blood cell is hypotonic. This is because the water molecules inside the blood cell are moving out of the blood cell decreasing the size of the cell to smaller size. 15. What percent solute concentration would be isotonic to this blood cell?  When 0.9 percent solute concentration of blood cells is put into container of 30 percent solute solution, the result would be equal to each side since the water molecules are moving the inside and outside of the blood cells resulting the blood cell to maintain their original size (not bigger or smaller).

Bio 156 Assig 5

Related Documents