Amir Mehdi
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School
George Mason University *
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Course
353
Subject
Aerospace Engineering
Date
Apr 3, 2024
Type
docx
Pages
5
Uploaded by DeaconWhaleMaster97
Amir Mehdi
IT 353 DL01
Fall 2023
HOMEWORK 2
Q1) I have read and understood all the directions for this assignment, especially Q18.
Q2) I retrieved my data set from Blackboard at 2023-NOV-07 16:53:59 EDT.
1 XX227U YYNNNPPP 23282.88279351 -.00000014 00000-0 00000-0 0 999Z
2 XX227 0.0188 133.4147 0001767 58.3953 143.4051 1.00271602 5116Z
Q3) XX227
XX27
Q4) 23282.88279351
2023OCT09 21:11:13.359
Q5) Inclination: 0.0188
The satellite orbit: it is an equatorial orbit because it
is so close to 0 that make it close to equator. Q6)
Right Ascension of the Ascending Node: 133.4147
°
Q7) Eccentricity: 0001767
The orbital path of this satellite is: the path would be circle, but this Eccentricity is so close to 0 that makes it like circle shape, or we can call it a dormant shape like close to perfect circle. Q8) Argument of Perigee: 58.3953
°
Q9)
Mean Anomaly: 143.4051
°
True Anomaly: up to e
3
: 143.4171
°
Q10) Mean Motion: 1.00271602
Orbital Period: 1436.10814min
Q11) .99726 days is 1436.0544 min.
Q12) Satellite orbital period: 1436.1081 min
Earth rotational period: 1436.0544 min Because both numbers are so close to each other it is synchronous or nearly synchronous orbit or
it this satellite is geostationary satellite.
Q13) The orbit of this satellite is geostationary or Clarke obit.
The category I chose is https://www.n2yo.com/?s=54742&live=1
Q14) Modified satellite number= XX27 is equator it has approximately is has same rotation speed as earth (geostationary satellite), so it is close to 24 hours and it is not passing anywhere because it is stationery on equator. Q15) Epoch: 2023OCT09 21:11:13.359
GMST: 22h 24m 07.809s
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GMA: 336.0325364522°
Q16)
LONG
frame
=
RAAN
+
AofP
+
TA .
133.4147
°
+
58.3953
°
+143.4171
°
= 335.2271
°
LONG
Earth
=
LONG
frame
-GMA= 335.2271
°
-336.0325
°
= -.8054
°
LONG
SAT
=
LONG
EARTH
= WESTLY, W Q17)
Period: 1436.1 ± 0.1 minutes
Inclination: 0.02 ± 0.5°
Longitude: W
Satellite I found:
Satellite name: MSG 3
NORAD ID: 38552 Period: 1436.0 minutes Inclination: 2.5° Longitude: -.28° W
Satellite name: SKYNET 4E
NORAD ID: 25639 Period: 1436.1 minutes Inclination: 11.5° Longitude: -1.84° W
Q18)
I Except as explicitly acknowledged above (in the form of
citations and reference listing details), I did not receive any assistance from any other person in preparing
and completing this assignment.
Q19)
I understand that the quality of my work will be one of the factors assessed for this assignment.