Lab

Conclusion: From the data we have gathered throughout the lab we can conclude that as the weight got bigger some of the forces got bigger, and some stayed the same. Although not every force got bigger, they never got small. Friction Lab Part 3 Hypothesis: If you add more weight to the block to make the mass of an object bigger, then the force will become bigger making the coefficient of kinetic friction become smaller. Data: Mass of the Wood Block Coefficient of Kinetic Friction .509kg .5007 .609kg .5858 .709kg .5032 .809kg .4410 .909kg .4485 1.009kg .4041 1.109kg .4159 1.409kg .3979 Calculations: Mass-.509 F= μFN μ= F f /FN μ= (2.5)/ (4.99329) μ= .5007 Fg=FN Fg=mg FN=mg FN=(.509) (9.81) FN= 4.99329 N Mass-.609 F= μFN μ= Ff/FN μ= (3.5)/ (5.97429) μ= .5858 Fg=FN Fg=mg FN=mg FN=(.609) (9.81) FN= 5.97429 N Mass-.709 F= μFN μ= Ff/FN μ= (3.5)/ (6.95529) μ= .5032 Fg=FN Fg=mg FN=mg FN=(.709) (9.81) FN= 6.95529 N Mass-.809 F= μFN μ= Ff/FN μ= (3.5)/ (7.93629) μ= .4410 Fg=FN Fg=mg FN=mg FN=(.809) (9.81) FN= 7.93629 N Mass-.909 F= μFN μ= Ff/FN μ= (4)/ (8.91729) μ= .4485 Fg=FN Fg=mg FN=mg FN=(.909) (9.81) FN= 8.91729 N Mass-1.009 F= μFN μ= Ff/FN μ= (4)/(9.89829) μ= .4041 Fg=FN Fg=mg FN=mg FN=(1.009)(9.81) Mass-1.109 F= μFN μ= Ff/FN μ= (4.5)/(10.817929) μ= .4159 Fg=FN Fg=mg FN=mg FN=(1.109)(9.81) Mass-1.409 F= μFN μ= Ff/FN μ= (5.5)/(13.82229) μ= .3979 Fg=FN Fg=mg FN=mg FN=(1.409)(9.81)