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Assignment – 1
CIT 101/L Fall 2023
Save answers as MS Word file. Due to Canvas on Friday 9/22/2023 at 11:55pm.
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1. Convert the following binary numbers to decimal equivalents: A, 001100 = 0x2
5
+ 0x2
4
+ 1x2
3
+ 1x2
2
+ 0x2
1
+ 0x2
0 = 0x32 + 0x16 + 1x8 + 1x4 + 0x2 + 0x1 = 0 + 0 + 8 + 4 + 0 + 0 =12
B, 000011 = 0x2
5
+ 0x2
4
+ 0x2
3
+ 0x2
2
+ 1x2
1
+ 1x2
0 = 0x32 + 0x16 + 0x8 + 0x4 + 1x2 + 1x1 = 0 + 0 + 0 + 0 + 2 + 1
= 3
C, 011100 = 0x2
5
+ 1x2
4
+ 1x2
3
+ 1x2
2
+ 0x2
1
+ 0x2
0 = 0x32 + 1x16 + 1x8 + 1x4 + 0x2 + 0x1 = 0 + 16 + 8 + 4 + 0 + 0
= 28
D, 111100 = 1x2
5
+ 1x2
4
+ 1x2
3
+ 1x2
2
+ 0x2
1
+ 0x2
0 = 1x32 + 1x16 + 1x8 + 1x4 + 0x2 + 0x1
= 32 + 16 + 8 + 4 + 0 + 0
= 60
E, 111111= 1x2
5
+ 1x2
4
+ 1x2
3
+ 1x2
2
+ 1x2
1
+ 1x2
0 = 1x32 + 1x16 + 1x8 + 1x4 + 1x2 + 1x1 = 32 + 16 + 8 + 4 + 2 + 1
= 63
2. Convert the following binary numbers to their decimal equivalents: A, 11100.001
= 1 x 2
4
+ 1 x 2
3
+ 1 x 2
2
+ 0 x 2
1
+ 0 x 2
0
+ 0 x 2
0
+ 0 x 2
-1
+ 0 x 2
-2
+ 1 x 2
-3
= 1 x 16 + 1 x 8 + 1 x 4 + 0 + 0 + 0 + 0 + 0 + ⅛
= 16 + 8 + 4 + 0 + 0 + 0 + 0 + 0 + 0.125 = 28 + 0.125
= 28.125
B, 110011.10011
= 1 x 2
5
+ 1 x 2
4
+ 0 x 2
3
+ 0 x 2
2
+ 1 x 2
1
+ 1 x 2
0
+ 1 x 2
-1
+ 0 + 0 + 1 x 2
-4
+ 1 x 2
-5 = 1 x 32 + 1 x 16 + 0 + 0 + 1 x 2 + 1 + 1/2 + 0 + 0 + 1/16 + 1/32
= 32 + 16 + 2 + 1 + 0.5 + 0.0625 + 0.03125
=
51.59375
C, 101010101010.1
= 1 x 2
11
+ 0 x 2
10
+ 1 x 2
9
+ 0 x 2
8
+ 1 x 2
7
+ 0 x 2
6
+ 1 x 2
5
+ 0 x 2
4
+ 1 x 2
3
+ 0 x 2
2
+ 1 x 2
1
+ 0 x 2
0
+ 1 x 2
-1
= 2048 + 0 + 512 + 0 + 128 + 0 + 32 +0 + 8 + 2 + 0.5
= 2730 + 0.5
=
2730.5
3. Convert the following decimal numbers to their binary equivalents A, 64 = 01000000
64 ÷ 2 = 32 r 0 32 ÷ 2 = 16 r 0 16 ÷ 2 = 8 r 0
8 ÷ 2 = 4 r 0
4 ÷ 2 = 2 r 0
2 ÷ 2 = 1 r 0
1 ÷ 2 = 0 r 1
B, 128 = 10000000
128 ÷ 2 = 64 r 0
64 ÷ 2 = 32 r 0
32 ÷ 2 = 16 r 0
16 ÷ 2 = 8 r 0
8 ÷ 2 = 4 r 0
4 ÷ 2 = 2 r 0
2 ÷ 2 = 1 r 0
1 ÷ 2 = 0 r 1
C, 256 = 100000000
256 ÷ 2 = 128 r 0
128 ÷ 2 = 64 r 0
64 ÷ 2 = 32 r 0
32 ÷ 2 = 16 r 0
16 ÷ 2 = 8 r 0
8 ÷ 2 = 4 r 0
4 ÷ 2 = 2 r 0
2 ÷ 2 = 1 r 0
1 ÷ 2 = 0 r 1
D, 100 = 01100100 100 ÷ 2 = 50 r 0
50 ÷ 2 = 25 r 0
25 ÷ 2 = 12 r 1
12 ÷ 2 = 6 r 0
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6 ÷ 2 = 3 r 0
3 ÷ 2 = 1 r 1
1 ÷ 2 = 0 r 1
E, 111 = 0111111
111 ÷ 2 = 55 r 1
55 ÷ 2 = 27 r 1
27 ÷ 2 = 13 r 1
13 ÷ 2 = 6 r 1
6 ÷ 2 = 3 r 0
3 ÷ 2 = 1 r 1
1 ÷ 2 = 0 r 1
F, 145 = 10010001
145 ÷ 2 = 72 r 1
72 ÷ 2 = 36 r 0
36 ÷ 2 = 18 r 0
18 ÷ 2 = 9 r 0
9 ÷ 2 = 4 r 1
4 ÷ 2 = 2 r 0
2 ÷ 2 = 1 r 0
1 ÷ 2 = 0 r 1
G, 255 = 11111111
255 ÷ 2 = 127 r 1
127 ÷ 2 = 63 r 1
63 ÷ 2 = 31 r 1
31 ÷ 2 = 15 r 1
15 ÷ 2 = 7 r 1
7 ÷ 2 = 3 r 1
3 ÷ 2 = 1 r 1
1 ÷ 2 = 0 r 1
4. Convert the following decimal numbers to their binary equivalents A, 34.75 = 100010.11
34 ÷ 2 = 17 r 0
17 ÷ 2 = 8 r 1
8 ÷ 2 = 4 r 0
4 ÷ 2 = 2 r 0
2 ÷ 2 = 1 r 0
1 ÷ 2 = 0 r 1
0.75 × 2 = 1 + 0.5
0.5 × 2 = 1 + 0
B, 25.25 = 11001.01
25 ÷ 2 = 12 r 1
12 ÷ 2 = r 0
6 ÷ 2 = 3 r 0
3 ÷ 2 = 1 r 1
1 ÷ 2 = 0 r 1
0.25 × 2 = 0 + 0.5
0.5 × 2 = 1 + 0.
C, 27.1875
27 ÷ 2 = 13 r 1
13 ÷ 2 = 6 r 1
6 ÷ 2 = 3 r 0
3 ÷ 2 = 1 r 1
1 ÷ 2 = 0 r 1
5. Convert the following hexadecimal number to their decimal equivalents a, C = 12
b, 9F
Decimal equivalent of "F" = (F) 15 × 16^0 = 15
Decimal equivalent of "9" = 9 × 16^1 = 144
Decimal equivalent of "9F" = 15+144
9F = 159
c, B52 Decimal equivalent of "2" = 2 × 16^0 = 2
Decimal equivalent of "5" = 5 × 16^1 = 80
Decimal equivalent of "B" = (B) 11 × 16^2 = 2816
Decimal equivalent of "B52" = 2+80+2816
B52 = 2898
d, F117 Decimal equivalent of "7" = 7 × 16^0 = 7
Decimal equivalent of "1" = 1 × 16^1 = 16
Decimal equivalent of "1" = 1 × 16^2 = 256
Decimal equivalent of "F" = (F) 15 × 16^3 = 61440
Decimal equivalent of "F117" = 7+16+256+61440
F117 = 61719
e, ABCD
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Decimal equivalent of "D" = (D) 13 × 16^0 = 13
Decimal equivalent of "C" = (C) 12 × 16^1 = 192
Decimal equivalent of "B" = (B) 11 × 16^2 = 2816
Decimal equivalent of "A" = (A) 10 × 16^3 = 40960
Decimal equivalent of "ABCD" = 13+192+2816+40960
ABCD = 43981
f, 1111.1 Decimal equivalent of "1" = 1 × 16^0 = 1
Decimal equivalent of "1" = 1 × 16^1 = 16
Decimal equivalent of "1" = 1 × 16^2 = 256
Decimal equivalent of "1" = 1 × 16^3 = 4096
Decimal equivalent of "1111" = 1+16+256+4096
1111 = 4369
Decimal equivalent of "1" = 1 × 16^-1 = 0.0625
Decimal equivalent of "0.1" = 0.0625
0.1 = 0.0625
= 1111.1
= 4369+ 0.0625
1111.1 = 4369.0625
g, 888.8 Decimal equivalent of "8" = 8 × 16^0 = 8
Decimal equivalent of "8" = 8 × 16^1 = 128
Decimal equivalent of "8" = 8 × 16^2 = 2048
Decimal equivalent of "888" = 8+128+2048
888 = 2184
Decimal equivalent of "8" = 8 × 16^-1 = 0.5
Decimal equivalent of "0.8" = 0.5
0.8 = 0.5
= 888.8
= 2184 + 0.5
888.8 = 2184.5
h, EBA.C
Decimal equivalent of "A" = (A) 10 × 16^0 = 10
Decimal equivalent of "B" = (B) 11 × 16^1 = 176
Decimal equivalent of "E" = (E) 14 × 16^2 = 3584
Decimal equivalent of "EBA" = 10+176+3584
EBA = 3770
Decimal equivalent of "C" = (C) 12 × 16^-1 = 0.75
Decimal equivalent of "0.C" = 0.75
0.C = 0.75
EBA.C
= 3770 + 0.75
EBA.C = 3770.75
6. Convert the following decimal numbers to their hexadecimal equivalents a, 80 = 50
Division by 16
Quotient
Remainder (Digit)
80/16
5
0
5/16
0
5
-
-
-
b, 2560 = A00
Division by 16
Quotient
Remainder (Digit)
Remainder (Hex)
2560/16
160
0
0
160/16
10
0
0
10/16
0
10
A
c, 65536 = 10000
Division by 16
Quotient
Remainder (Digit)
65536/16
4096
0
4096/16
256
0
256/16
16
0
16/16
1
0
1/16
0
1
d, 204.125 = CC.2
Division by 16
Quotient
Remainder (Digit)
Remainder (Hex)
3266/16
204
2
2
204/16
12
12
C
12/16
0
12
C
e, 631.25 = 277.4
Division by 16
Quotient
Remainder (Digit)
10100/16
631
4
631/16
39
7
39/16
2
7
2/16
0
2
f, 100000.00390625 = 2710.01
Division by 16
Quotient
Remainder (Digit)
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2560001/16
160000
1
160000/16
10000
0
10000/16
625
0
625/16
39
1
39/16
2
7
2/16
0
2
7. Convert the following decimal numbers to their octal equivalents A, 68
Octal equivalent: 104
68/8 = 4 8/8 = 0
1/8 = 1 B, 236
Octal equivalent: 354
236/8 = 4
29/8 = 5
3/8 = 3
C, 348
Octal equivalent: 534
348/8 = 4
43/8 = 3
5/8 = 5
D, 584
Octal equivalent: 1110
584/8 = 0 73/8 = 1
9/8 = 1
1/8 = 1
8. Convert the following octal numbers to their decimal equivalents
A, 47
= 4x8
1
+ 7x8
0
=39
B, 75
= 7x8
1
+ 5x8
0
= 61
C, 360
= 3x8
2
+ 6x8
1 + 0x8
0
=192 + 48 + 0
=240
D, 545 = 5x8
2
+ 4x8
1 + 5x8
0
=5 + 32 + 320
=357
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09 Operational and Legal Considerations -
>
Calculating Capacity
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Thursday : January 21, 2021 --- 80 Minutes
1. In this section we examine three theories of investor preference: The dividend irrelevance
theory. The "bird in the hand" theory, the tax preference theory, which theory is the best?
What is the different of stock dividends, stock splits, and stock repurchase.
2. In the working capital management, we know about cash conversion cycle model. For
problem if average inventories are $3 million and sales are $11 million. If receivables are
S 657.535 and sales are S 11 million. Then, if its cost of goods sold are $9 million per year
and if its accounts payable average $ 657.535. What is the length of the cash conversion
sicle?
3. The ELGRAJO Corporation has capital structure as follow…
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Ayayai Mowers Ltd. agreed to sell the City of Halifax four riding mowers and 20 push lawn mowers. The contract price was $72,00O.
Ayayai normally sells its riding mowers for $14,400 and its push lawn mowers for $960. The contract required the City of Halifax to
pay Ayayai once all of the merchandise has been delivered to the city's public works yard. Ayayai's management does not expect any
returns or any issues with payment.
Ayayai delivered all four of the riding mowers and 14 of the push mowers on April 26. The remaining six push mowers were delivered
on May 5. Ayayai received payment from the city on May 18. Ayayai's cost for each riding mower is $9,960, while the push mowers
cost…
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Exercise 7-16 (Algo) Record amortization expense (LO7-5)
On January 1, 2024, Weaver Corporation purchased a patent for $255,000. The remaining legal life is 20 years, but the company
mates the patent will be useful for only six more years. In January 2026, the company incurred legal fees of $75,000 in
successfully defending a patent infringement suit. The successful defense did not change the company's estimate of useful life.
Weaver Corporation's year-end is December 31.
Required:
1. Record the purchase in 2024; amortization in 2024; amortization in 2025; legal fees in 2026; and amortization in 2026.
2. What is the balance in the Patent account at the end of 2026?
Complete this question by entering your answers in the tabs below.
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A newspaper editor starts a retirement savings plan in which $225 per month is deposited at the beginning of each month into an account that earns an annual interest rate of 6.4% compounded monthly.
Find the value of this investment (in dollars) after 20 years. (Round your answer to the nearest cent.)
$
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logo design company purchases four new computers for $12,500. The company finances the cost of the computers for 3 years at an annual interest rate of 5.175% compounded monthly. Find the month
ayment (in dollars) for this loan. (Round your answer to the nearest cent. See Example 8 in this section.)
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TB MC Qu. 5-161 On September 1, 2021, Middleton Corp. lends cash and accepts...
On September 1, 2021, Middleton Corp. lends cash and accepts a $1,000 note receivable that offers 18
interest revenue wiI Middleton Corp. report during 2022? (Do not round Intermediate calculations.
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$30.
$63.
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Double-Declining-Balance Depreciation
A building acquired at the beginning of the year at a cost of $1,193,000 has an estimated residual value of $220,000 and an estimated useful life of 40 years.
Determine the following.
a. The double-declining-balance rate
%
b. The double-declining-balance depreciation for the first year
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