Bonus MET EQN Problems - Exam 1 - Spring 2024
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KINE 4340 – Testing & Prescription BONUS QUESTIONS
You have the option to supplement your grade on the 1
st
exam by answering the following questions. Each
question is worth 5 points each for a maximum potential of 20 extra points. Each answer should
calculated to two
decimal places (rounded up and only rounded after the calculations are completed). Be
sure to include the proper units for each value as well (e.g., ml/kg/min, kg/m/min). Failure to provide the
units or a value at two decimal places will result in a zero for the question. SHOW YOUR WORK! Name: _______Noah Platzer_____________ Date: ________________
1. What is an individual's target exercise heart rate, using the heart rate reserve method, if they are 25 years old, resting heart rate of 62 bpm, and prescribed a workout intensity of 85% maximal heart rate? 220 – 25 = 195
85% x (195 – 62) + 62
.85 x (133) + 62 = 175.05 bpm
2. What speed would an individual need to walk
at to achieve a steady-state VO
2
of 24 ml/kg/min but with
a 12% incline?
24 = (0.1 x speed) + (1.8 x speed x 0.12) + 3.5 24 = (.316 x speed) + 3.5
20.5 = .316 x speed Speed = 20.5/.316 = 64.9
64.9/26.8 = 2.42mph
3. What is the (A) workrate for someone with a cadence of 75 rpm, resistance of 2 kg, and cycle flywheel of 6 m/revolution? 2kg x 9.81m/s^2
=19.62N
W= 19.62N x 6m/revolution x 75rpm
WR=
8829N x m/min
(B) How many watts are they generating? W= 8829N x m/min / 60 = 147.15W
4. If someone was walking for 30 minutes on a track at 3.2 mph, what is their estimated VO
2 in L/min if they weighed 150 lb? VO2 = (0.1 x 85.76) + (1.8 x 85.76 x 0) + 3.5
VO2 = 8.576 + 3.5 = 12.1 L/min
5. How long would it take an individual to expend 1000 kcals if they were running at a speed of 5 mph and weighed 150 lb?
VO2 = (0.2 x 134) + (0.9 x 134 x 0) + 3.5
VO2 = 26.8 + 3.5 = 30.3 L/min
Time =1000kcals / (30.3L/min x 5 x 0.239 x 68.04kg)
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Convert 30% to a decimal.
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Submit
A boutique buys some merchandise with a list price of $2,400. If the wholesaler extends a 30% trade discount rate, find the trade discount.
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