Chapter ST, Problem 30PQ

Interpretation Introduction

Interpretation:

Percentage yield of reaction of ${\text{Fe}}_{\text{2}}{\text{O}}_{\text{3}}$ and ${\text{H}}_{\text{2}}$ has to be determined.

Concept Introduction:

Ratio of actual yield by theoretical yield multiplied by 100 gives percent yield. Percent yield equal to $100\%$ implies same actual and theoretical yield. Usually, percent yield is obtained below $100\%$ because actual yield lower in magnitude than theoretical value due to incomplete reactions and loss of sample during recovery.

The equation for percent yield is as follows:

  $\text{percent yield }=\left(\frac{\text{actual yield}}{\text{theoretical yield}}\right)\times 100\%$

Here,

Actual yield is quantity of product obtained from a chemical reaction

Theoretical yield is quantity of product obtained from balanced equation.

Units for actual and theoretical yield are same either in moles of grams.