Chapter SR21, Problem 1P

Solution

Find the value of x.

  $x={40}^o$

Given:

The given triangle.

  

Concept Used:

• The sum of the interior angles of a triangle is $={180}^o$

Calculation:

The given triangle is -

  

As the sum of the interior angles of a triangle is $={180}^o$

  $\begin{array}{c}{68}^o+{72}^o+x^o={180}^o\\ 68+72+x=180\\ 140+x=180\\ x=180-140\\ x=40\end{array}$

  $x={40}^o$