Explanation Given: The expression x ( 2 x + 5 ) 2 ( x 2 − 4 ) − 1 2 + 2 ( x 2 − 4 ) 1 2 ( 2 x + 5 ) . Calculation: There is a common factor of ( 2 x + 5 ) 2 ( x 2 − 4 ) − 1 2 and ( x 2 − 4 ) 1 2 ( 2 x + 5 ) . Always factor out the quantity to the smallest exponent. Here, 1 < 2 and ( − 1 2 ) < ( 1 2 ) . Factor out the terms as, x ⋅ ( 2 x + 5 ) ⋅ ( 2 x + 5 ) ⋅ ( x 2 − 4 ) − 1 2 + 2 ⋅ ( x 2 − 4 ) − 1 2 ⋅ ( x 2 − 4 ) 1 ⋅ ( 2 x + 5 ) . So, the common factor is ( x 2 − 4 ) − 1 2 ( 2 x + 5 ) and the factored form is, x ( 2 x + 5 ) 2 ( x 2 − 4 ) − 1 2 + 2 ( x 2 − 4 ) 1 2 ( 2 x + 5 ) = ( 2 x + 5 ) ⋅ ( x 2 − 4 ) − 1 2 [ x ⋅ ( 2 x + 5 ) + 2 ⋅ ( x 2 − 4 ) 1 ] Apply Distributive property, x ( 2 x + 5 ) 2 ( x 2 − 4 ) − 1 2 +

10th Edition

ISBN: 8220102020252

Author: RITCHEY

Publisher: PEARSON

See similar textbooks

Concept explainers

Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.

Videos

Question

Chapter R.6, Problem 55E

To determine

To factor: The expression x(2x+5)2(x2−4)−12+2(x2−4)12(2x+5).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter R.6, Problem 54E

Chapter R.6, Problem 56E

Students have asked these similar questions

Find the volume of the region under the surface z = corners (0,0,0), (2,0,0) and (0,5, 0). Round your answer to one decimal place. 5x5 and above the triangle in the xy-plane with

Given y = 4x and y = x² +3, describe the region for Type I and Type II. Type I 8. y + 2 -24 -1 1 2 2.5 X Type II N 1.5- x 1- 0.5 -0.5 -1 1 m y -2> 3 10

Given D = {(x, y) | O≤x≤2, ½ ≤y≤1 } and f(x, y) = xy then evaluate f(x, y)d using the Type II technique. 1.2 1.0 0.8 y 0.6 0.4 0.2 0- -0.2 0 0.5 1 1.5 2 X X This plot is an example of the function over region D. The region identified in your problem will be slightly different. y upper integration limit Integral Value

Chapter R Solutions

EBK FINITE MATHEMATICS AND CALCULUS WIT

Ch. R.1 - Perform the operation 3(x24x5)4(3x25x7)Ch. R.1 - Perform the operation (3y+2)(4y22y5).Ch. R.1 - Find (2x+7)(3x1) using the FOIL method.Ch. R.1 - Find (3x+2y)3.Ch. R.1 - Perform the indicated operations....Ch. R.1 - Perform the indicated operations....Ch. R.1 - Perform the indicated operations....Ch. R.1 - Perform the indicated operations....Ch. R.1 - Perform the indicated operations....Ch. R.1 - Perform the indicated operations....

Knowledge Booster

$Calculus$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.

To factor: The expression x ( 2 x + 5 ) 2 ( x 2 − 4 ) − 1 2 + 2 ( x 2 − 4 ) 1 2 ( 2 x + 5 ) .

Solution Summary: The author explains how to factor out the expression x(2x+5)2 (x

Concept explainers

Videos

To factor: The expression x(2x+5)2(x2−4)−12+2(x2−4)12(2x+5).

Want to see the full answer?

Chapter R Solutions