Explanation Given: The expression x ( 2 x + 5 ) 2 ( x 2 − 4 ) − 1 2 + 2 ( x 2 − 4 ) 1 2 ( 2 x + 5 ) . Calculation: There is a common factor of ( 2 x + 5 ) 2 ( x 2 − 4 ) − 1 2 and ( x 2 − 4 ) 1 2 ( 2 x + 5 ) . Always factor out the quantity to the smallest exponent. Here, 1 < 2 and ( − 1 2 ) < ( 1 2 ) . Factor out the terms as, x ⋅ ( 2 x + 5 ) ⋅ ( 2 x + 5 ) ⋅ ( x 2 − 4 ) − 1 2 + 2 ⋅ ( x 2 − 4 ) − 1 2 ⋅ ( x 2 − 4 ) 1 ⋅ ( 2 x + 5 ) . So, the common factor is ( x 2 − 4 ) − 1 2 ( 2 x + 5 ) and the factored form is, x ( 2 x + 5 ) 2 ( x 2 − 4 ) − 1 2 + 2 ( x 2 − 4 ) 1 2 ( 2 x + 5 ) = ( 2 x + 5 ) ⋅ ( x 2 − 4 ) − 1 2 [ x ⋅ ( 2 x + 5 ) + 2 ⋅ ( x 2 − 4 ) 1 ] Apply Distributive property, x ( 2 x + 5 ) 2 ( x 2 − 4 ) − 1 2 +

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Chapter R.6, Problem 55E

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To factor: The expression x(2x+5)2(x2−4)−12+2(x2−4)12(2x+5).

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Chapter R.6, Problem 54E

Chapter R.6, Problem 56E

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To factor: The expression x ( 2 x + 5 ) 2 ( x 2 − 4 ) − 1 2 + 2 ( x 2 − 4 ) 1 2 ( 2 x + 5 ) .

Solution Summary: The author explains how to factor out the expression x(2x+5)2 (x

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To factor: The expression x(2x+5)2(x2−4)−12+2(x2−4)12(2x+5).

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Chapter R Solutions