Surface area and mass. The surface area of a person whose mass is 75 kg can be approximated by f ( h ) = 0.144 h 1 / 2 , where f ( h ) is measured in square meters and h is the person's height in centimeters ( Source· US Oncology. ) a. Find the approximate surface area of a person whose mass is 75 kg and whose height is 180 cm. b. Find the approximate surface area of a person whose mass is 75 kg and whose height is 170 cm. c. Graph the function f for 0 ≤ h ≤ 200 .
Surface area and mass. The surface area of a person whose mass is 75 kg can be approximated by f ( h ) = 0.144 h 1 / 2 , where f ( h ) is measured in square meters and h is the person's height in centimeters ( Source· US Oncology. ) a. Find the approximate surface area of a person whose mass is 75 kg and whose height is 180 cm. b. Find the approximate surface area of a person whose mass is 75 kg and whose height is 170 cm. c. Graph the function f for 0 ≤ h ≤ 200 .
Solution Summary: The author explains the approximate surface area function, f(h)=0.144h raisebox1ex1!
Consider the following system of equations, Ax=b :
x+2y+3z - w = 2
2x4z2w = 3
-x+6y+17z7w = 0
-9x-2y+13z7w = -14
a. Find the solution to the system. Write it as a parametric equation. You can use a
computer to do the row reduction.
b. What is a geometric description of the solution? Explain how you know.
c. Write the solution in vector form?
d. What is the solution to the homogeneous system, Ax=0?
2. Find a matrix A with the following qualities
a. A is 3 x 3.
b. The matrix A is not lower triangular and is not upper triangular.
c. At least one value in each row is not a 1, 2,-1, -2, or 0
d. A is invertible.
Intro Stats, Books a la Carte Edition (5th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.
Area of a Rectangle, Triangle, Circle & Sector, Trapezoid, Square, Parallelogram, Rhombus, Geometry; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=JnLDmw3bbuw;License: Standard YouTube License, CC-BY