Chapter R.1, Problem 38PE

Solve x² - 10x + 24 = 0 ○ A) 4,6 B) -12, -2 C) 12,2 D) -4, -6

c7. = -(9 - x) 25 A a) -1, 11 b) 31 c) 11 d) 1, 11

2 4x² - 12x-7=0 A) 7 ON 1,-1 4 OB)-, 7 1 C) 2,2 Oa½½-½ c) 17/17, - 1/1/1 D) 2, 2 ODI-,-

Solve using the quadratic equation formula 4x² + 12x=-6 ○ a) -12±√√3 2 b) -3±√15 -3+√15 2 ○ c) c) -3±√√√3 2 d) -3±√3 8

Listen Solve the quadratic equation by factoring. One solution is 0. Find the other. 2x² + 16x = 0 Your Answer: Answer

Solve x²+4x-45 = 0 ○ A) -9,5 ☐ B) -15, 3 C) -3,15 D) -5,9

Solve 3x² + 2x-5=0 О ○ A) 3,- 11/1 ○ B) 1,- 5/35 5 Oc)-1, 33 ○ D) 1, - 3/3

Factor the polynomial completely. x^2- 9 A) (x - 1)(x -9) B) (x - 3)(x + 3) c) (x -3)(x-3) D) (x + 3)(x + 3)

Directions: Use the equation A = Pet to answer each question and be sure to show all your work. 1. If $5,000 is deposited in an account that receives 6.1% interest compounded continuously, how much money is in the account after 6 years? 2. After how many years will an account have $12,000 if $6,000 is deposited, and the account receives 3.8% interest compounded continuously? 3. Abigail wants to save $15,000 to buy a car in 7 years. If she deposits $10,000 into an account that receives 5.7% interest compounded continuously, will she have enough money in 7 years? 4. Daniel deposits $8,000 into a continuously compounding interest account. After 18 years, there is $13,006.40 in the account. What was the interest rate? 5. An account has $26,000 after 15 years. The account received 2.3% interest compounded continuously. How much was deposited initially?