Chapter PVI, Problem 24RE

To determine

To explain what they show in the output.

Explanation of Solution

It is given in the question that the study described in previous exercise also looked in mathematics and language. The software outputs for the appropriate tests are as:

  $\begin{array}{l}\text{Mathematics}\\ \text{T-Test of }{\mu }_1-{\mu }_2=0\\ {\mu }_{Cert}-{\mu }_{NoCert}=4.53\\ t(86)=2.95\\ p=0.002\\ \text{Language}\\ \text{T-Test of }{\mu }_1-{\mu }_2=0\\ {\mu }_{Cert}-{\mu }_{NoCert}=2.13\\ t(84)=1.71\\ p=0.045\end{array}$

So, in the Mathematics, the t -value and the P-value is given with the $df=86$ . Thus, As we know that if the P-value is less than or equal to the significance level then the null hypothesis is rejected, so we have,

  $P<0.05\Rightarrow \text{Reject }{H}_0$

Thus, we conclude that the scores of the certified and uncertified teachers are different in Mathematics.

And in the Language, the t -value and the P-value is given with the $df=84$ . Thus, As we know that if the P-value is less than or equal to the significance level then the null hypothesis is rejected, so we have,

  $P<0.05\Rightarrow \text{Reject }{H}_0$

Thus, we conclude that the scores of the certified and uncertified teachers are different in Language.