Chapter PIV, Problem 34RE

(a)

To determine

To find: the number of points would expect a roll to add to the score.

Answer to Problem 34RE

2.5 points

Explanation of Solution

Each of the results has a 1/6 chance of being observed (1, 2, 3, 4, and 5).

Given that all the rolls were not 6's, we would predict a roll to a score of around 6 so that apply something to current score. $\left(1+2+3+4+5\right)\times \frac{1}{6}=2.5$ points.

(b)

To determine

To find: a roll will be required to deduct from the score the amount of points.

Answer to Problem 34RE

0

Explanation of Solution

If there were to roll a 6, it would have scored 0, regardless of previous rolls. Therefore, it would expect a roll to remove from the score the entire current score, leading to a score of 0.

(c)

To determine

To find: the score would another roll break ever on the basis of given in part (a) and (b).

Answer to Problem 34RE

0

Explanation of Solution

For the first time on roll 6, can hope to get a 6 (since the chance of observing 6 is 1/6). To get a positive score and the predicted score, roll 5 times; if roll 5 times, it would be 1 + 2 + 3 + 4 + 5= 15 = 15. So, another roll will even break at this score, as the next possible result would be a 6 that results in a score of 0.

(d)

To determine

To Explain: the strategy for this result suggests.

Explanation of Solution

The approach of this outcome implies that stop when the score hits 15 points.