Student Solutions Manual for Stewart's Single Variable Calculus: Early Transcendentals, 8th (James Stewart Calculus)
8th Edition
ISBN: 9781305272422
Author: James Stewart, Jeffrey A. Cole, Daniel Drucker, Daniel Anderson
Publisher: Cengage Learning
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Chapter H, Problem 42E
To determine
To write: The number
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the answer is Dcould you explain how using the curland also please disprove each option that is wrong
The correct answer is D
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For number 4 the answer is B
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Chapter H Solutions
Student Solutions Manual for Stewart's Single Variable Calculus: Early Transcendentals, 8th (James Stewart Calculus)
Ch. H - Prob. 1ECh. H - Prob. 2ECh. H - Prob. 3ECh. H - Prob. 4ECh. H - Prob. 5ECh. H - Prob. 6ECh. H - Prob. 7ECh. H - Evaluate the expression and write your answer in...Ch. H - Prob. 9ECh. H - Prob. 10E
Ch. H - Prob. 11ECh. H - Prob. 12ECh. H - Prob. 13ECh. H - Evaluate the expression and write your answer in...Ch. H - Prob. 15ECh. H - Prob. 16ECh. H - Prob. 17ECh. H - Prove the following properties of complex numbers....Ch. H - Prob. 19ECh. H - Prob. 20ECh. H - Prob. 21ECh. H - Find all solutions of the equation. 22. 2x2 2x +...Ch. H - Prob. 23ECh. H - Find all solutions of the equation. 24....Ch. H - Write the number in polar form with argument...Ch. H - Prob. 26ECh. H - Prob. 27ECh. H - Prob. 28ECh. H - Write the number in polar form with argument...Ch. H - Prob. 30ECh. H - Prob. 31ECh. H - Prob. 32ECh. H - Find the indicated power using De Moivres Theorem....Ch. H - Prob. 34ECh. H - Prob. 35ECh. H - Prob. 36ECh. H - Prob. 37ECh. H - Prob. 38ECh. H - Prob. 39ECh. H - Prob. 40ECh. H - Prob. 41ECh. H - Prob. 42ECh. H - Prob. 43ECh. H - Prob. 44ECh. H - Prob. 45ECh. H - Prob. 46ECh. H - Prob. 47ECh. H - Use Eulers formula to prove the following formulas...Ch. H - If u(x) = f(x) + ig(x) is a complex-valued...Ch. H - (a) If u is a complex-valued function of a real...
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- For number 9 The answer is A Could you show me howarrow_forwardThe answer is B, Could you please show the steps to obtain the answerarrow_forward2. Suppose that U(x, y, z) = x² + y²+ z² represents the temperature of a 3-dimensional solid object at any point (x, y, z). Then F(x, y, z) = -KVU (x, y, z) represents the heat flow at (x, y, z) where K > 0 is called the conductivity constant and the negative sign indicates that the heat moves from higher temperature region into lower temperature region. Answer the following questions. (A) [90%] Compute the inward heat flux (i.e., the inward flux of F) across the surface z = 1 - x² - y². (B) [10%] Use the differential operator(s) to determine if the heat flow is rotational or irrotational.arrow_forward
- Could you show why the answer is B Using polar coordinates and the area formulaarrow_forward1. The parametric equations x = u, y = u cos v, z = usin v, with Ou≤ 2, 0 ≤ v ≤ 2π represent the cone that is obtained by revolving (about x-axis) the line y = x (for 0 ≤ x ≤2) in the xy-plane. Answer the following questions. (A) [50%] Sketch the cone and compute its surface area, which is given by dS = [ | Ər Or ди მა × du dv with S being the cone surface and D being the projection of S on the uv-plane. (B) [50%] Suppose that the density of the thin cone is σ(x, y, z) = 0.25x gr/cm². Compute the total mass of the cone.arrow_forwardThe value of sin (2V · F) at x = 3, y = 3, z = −4, where F -0.592 -0.724 0.661 -0.113 -0.822 -0.313 0.171 0.427 = (-2x² + -4,2yz − x − 3, −5xz - 2yz), isarrow_forward
- The correct answer is C Could you show me whyarrow_forwardThe graph of f(x) is given below. Select each true statement about the continuity of f(x) at x = -4. Select all that apply: ☐ f(x) is not continuous at x = -4 because it is not defined at x = −4. ☐ f(x) is not continuous at x = -4 because lim f(x) does not exist. x-4 f(x) is not continuous at x = -4 because lim f(x) = f(−4). ☐ f(x) is continuous at x = -4. x-4 ين من طلب نہ 1 2 3 4 5 6 7arrow_forwardThe graph of f(x) is given below. Select each true statement about the continuity of f(x) at x = -1. -7-6-5 N HT Select all that apply: ☐ f(x) is not continuous at x = -1 because it is not defined at x = -1. ☐ f(x) is not continuous at -1 because lim f(x) does not exist. x-1 ☐ f(x) is not continuous at x = -1 because lim f(x) = f(−1). ☐ f(x) is continuous at x = -1. x-1 5 6 7arrow_forward
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