The equation of the line where the slope is m = − 3 and contains the point ( − 5 , 4 ) .

Question

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Answer 1

Question

Chapter G, Problem 1DE

To determine

To calculate: The equation of the line where the slope is m=−3 and contains the point (−5,4).

Expert Solution & Answer

Answer to Problem 1DE

Solution:

The equation of the line where the slope is m=−3 and contains the point (−5,4) is y=−3x−11.

Explanation of Solution

Given Information:

The slope is m=−3 and the point is (−5,4).

Formula used:

The point-slope equation of a line that has slope m and passing point (x1,y1) is denoted by the formula;

y−y1=m(x−x1)

Calculation:

Here, slope is m=−3 and the point is (−5,4).

That is, (x1,y1)=(−5,4).

As the point-slope equation of a line that has slope m and passing point (x1,y1) is denoted by the formula;

y−y1=m(x−x1)

Thus, it becomes;

y−4=−3(x−(−5))y−4=−3(x+5)y−4=−3x−15y=−3x−11

Hence, the equation of the line where the slope is m=−3 and contain the point (−5,4) is y=−3x−11.

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Answer 2

Question

Chapter G, Problem 1DE

To determine

To calculate: The equation of the line where the slope is m=−3 and contains the point (−5,4).

Expert Solution & Answer

Answer to Problem 1DE

Solution:

The equation of the line where the slope is m=−3 and contains the point (−5,4) is y=−3x−11.

Explanation of Solution

Given Information:

The slope is m=−3 and the point is (−5,4).

Formula used:

The point-slope equation of a line that has slope m and passing point (x1,y1) is denoted by the formula;

y−y1=m(x−x1)

Calculation:

Here, slope is m=−3 and the point is (−5,4).

That is, (x1,y1)=(−5,4).

As the point-slope equation of a line that has slope m and passing point (x1,y1) is denoted by the formula;

y−y1=m(x−x1)

Thus, it becomes;

y−4=−3(x−(−5))y−4=−3(x+5)y−4=−3x−15y=−3x−11

Hence, the equation of the line where the slope is m=−3 and contain the point (−5,4) is y=−3x−11.

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Answer 3

Question

Chapter G, Problem 1DE

To determine

To calculate: The equation of the line where the slope is m=−3 and contains the point (−5,4).

Expert Solution & Answer

Answer to Problem 1DE

Solution:

The equation of the line where the slope is m=−3 and contains the point (−5,4) is y=−3x−11.

Explanation of Solution

Given Information:

The slope is m=−3 and the point is (−5,4).

Formula used:

The point-slope equation of a line that has slope m and passing point (x1,y1) is denoted by the formula;

y−y1=m(x−x1)

Calculation:

Here, slope is m=−3 and the point is (−5,4).

That is, (x1,y1)=(−5,4).

As the point-slope equation of a line that has slope m and passing point (x1,y1) is denoted by the formula;

y−y1=m(x−x1)

Thus, it becomes;

y−4=−3(x−(−5))y−4=−3(x+5)y−4=−3x−15y=−3x−11

Hence, the equation of the line where the slope is m=−3 and contain the point (−5,4) is y=−3x−11.

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Answer 4

Question

Chapter G, Problem 1DE

To determine

To calculate: The equation of the line where the slope is m=−3 and contains the point (−5,4).

Expert Solution & Answer

Answer to Problem 1DE

Solution:

The equation of the line where the slope is m=−3 and contains the point (−5,4) is y=−3x−11.

Explanation of Solution

Given Information:

The slope is m=−3 and the point is (−5,4).

Formula used:

The point-slope equation of a line that has slope m and passing point (x1,y1) is denoted by the formula;

y−y1=m(x−x1)

Calculation:

Here, slope is m=−3 and the point is (−5,4).

That is, (x1,y1)=(−5,4).

As the point-slope equation of a line that has slope m and passing point (x1,y1) is denoted by the formula;

y−y1=m(x−x1)

Thus, it becomes;

y−4=−3(x−(−5))y−4=−3(x+5)y−4=−3x−15y=−3x−11

Hence, the equation of the line where the slope is m=−3 and contain the point (−5,4) is y=−3x−11.

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Answer 5

Chapter G, Problem 1DE

To determine

To calculate: The equation of the line where the slope is m=−3 and contains the point (−5,4).

Expert Solution & Answer

Answer to Problem 1DE

Solution:

The equation of the line where the slope is m=−3 and contains the point (−5,4) is y=−3x−11.

Explanation of Solution

Given Information:

The slope is m=−3 and the point is (−5,4).

Formula used:

The point-slope equation of a line that has slope m and passing point (x1,y1) is denoted by the formula;

y−y1=m(x−x1)

Calculation:

Here, slope is m=−3 and the point is (−5,4).

That is, (x1,y1)=(−5,4).

As the point-slope equation of a line that has slope m and passing point (x1,y1) is denoted by the formula;

y−y1=m(x−x1)

Thus, it becomes;

y−4=−3(x−(−5))y−4=−3(x+5)y−4=−3x−15y=−3x−11

Hence, the equation of the line where the slope is m=−3 and contain the point (−5,4) is y=−3x−11.

Answer 6

Chapter G, Problem 1DE

To determine

To calculate: The equation of the line where the slope is m=−3 and contains the point (−5,4).

Expert Solution & Answer

Answer to Problem 1DE

Solution:

The equation of the line where the slope is m=−3 and contains the point (−5,4) is y=−3x−11.

Explanation of Solution

Given Information:

The slope is m=−3 and the point is (−5,4).

Formula used:

The point-slope equation of a line that has slope m and passing point (x1,y1) is denoted by the formula;

y−y1=m(x−x1)

Calculation:

Here, slope is m=−3 and the point is (−5,4).

That is, (x1,y1)=(−5,4).

As the point-slope equation of a line that has slope m and passing point (x1,y1) is denoted by the formula;

y−y1=m(x−x1)

Thus, it becomes;

y−4=−3(x−(−5))y−4=−3(x+5)y−4=−3x−15y=−3x−11

Hence, the equation of the line where the slope is m=−3 and contain the point (−5,4) is y=−3x−11.

Answer 7

Chapter G, Problem 1DE

To determine

To calculate: The equation of the line where the slope is m=−3 and contains the point (−5,4).

Answer 8

Expert Solution & Answer

Answer to Problem 1DE

Solution:

The equation of the line where the slope is m=−3 and contains the point (−5,4) is y=−3x−11.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given Information:

The slope is m=−3 and the point is (−5,4).

Formula used:

The point-slope equation of a line that has slope m and passing point (x1,y1) is denoted by the formula;

y−y1=m(x−x1)

Calculation:

Here, slope is m=−3 and the point is (−5,4).

That is, (x1,y1)=(−5,4).

As the point-slope equation of a line that has slope m and passing point (x1,y1) is denoted by the formula;

y−y1=m(x−x1)

Thus, it becomes;

y−4=−3(x−(−5))y−4=−3(x+5)y−4=−3x−15y=−3x−11

Hence, the equation of the line where the slope is m=−3 and contain the point (−5,4) is y=−3x−11.

Answer 12

Ch. G - Prob. 1DE Ch. G - Prob. 2DE Ch. G - Prob. 3DE Ch. G - Prob. 4DE Ch. G - Prob. 5DE Ch. G - Prob. 6DE Ch. G - Prob. 1ES Ch. G - Prob. 2ES Ch. G - Prob. 3ES Ch. G - Prob. 4ES

The equation of the line where the slope is m = − 3 and contains the point ( − 5 , 4 ) .

Concept explainers

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To calculate: The equation of the line where the slope is m=−3 and contains the point (−5,4).

Answer to Problem 1DE

Explanation of Solution

Want to see more full solutions like this?

Chapter G Solutions