DEVELOP.MATH(3 VOLS) CUSTOM-W/MML <IC<
DEVELOP.MATH(3 VOLS) CUSTOM-W/MML <IC<
16th Edition
ISBN: 9781323235911
Author: BITTINGER
Publisher: Pearson Custom Publishing
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Chapter F, Problem 4DE
To determine

To calculate: The factor of 125+t3.

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survey of 5050 young professionals found that they spent an average of ​$20.5620.56 when dining​ out, with a standard deviation of ​$11.4111.41. Can you conclude statistically that the population mean is greater than ​$2323​? Use a​ 95% confidence interval.       Question content area bottom Part 1 The​ 95% confidence interval is left bracket nothing comma nothing right bracketenter your response here, enter your response here. As ​$2323 is ▼     of the confidence​ interval, we ▼   can cannot conclude that the population mean is greater than ​$2323. ​(Use ascending order. Round to four decimal places as​ needed.)
1. vector projection. Assume, ER1001 and you know the following: ||||=4, 7=-0.5.7. For each of the following, explicitly compute the value. འབ (a) (b) (c) (d) answer. Explicitly compute ||y7||. Explain your answer. Explicitly compute the cosine similarity of and y. Explain your Explicitly compute (x, y). Explain your answer. Find the projection of onto y and the projection of onto .
A survey of 250250 young professionals found that two dash thirdstwo-thirds of them use their cell phones primarily for​ e-mail. Can you conclude statistically that the population proportion who use cell phones primarily for​ e-mail is less than 0.720.72​? Use a​ 95% confidence interval.       Question content area bottom Part 1 The​ 95% confidence interval is left bracket nothing comma nothing right bracket0.60820.6082, 0.72510.7251. As 0.720.72 is within the limits   of the confidence​ interval, we cannot   conclude that the population proportion is less than 0.720.72. ​(Use ascending order. Round to four decimal places as​ needed.)
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