Find the all values in the given table.

Question

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Answer 1

Question

Chapter E, Problem 1PS

To determine

Find the all values in the given table.

Expert Solution & Answer

Answer to Problem 1PS

The complete table is

Degree	Radians	Sine	Cosine	Tangent
−45° 180° −240° 210° 90°	−π4 π−4π3 7π6 π2	−12 032 −12 1	12 −1−12 −32 0	−10−3 13 undefined

Explanation of Solution

Given:

The given table is

Calculus, Chapter E, Problem 1PS

Calculation:

180°=πc1°=πc180−45°=πc180×−45°=−πc4sin(− 45°)=−sin( 45°)=−12cos(− 45°)=cos( 45°)=12tan(− 45°)=−tan( 45°)=−1

πc=180°sin( 180°)=0cos( 180°)=−1tan( 180°)=0

πc=180°πc= 180°π−4π3= 180°π×(− 4π3)=−240°sin(− 240°)=−sin( 240°)=−sin( 180°+ 60°)=sin( 60°)=32cos(− 240°)=cos( 240°)=cos( 180°+ 60°)=−cos( 60°)=−12tan(− 240°)=−tan( 240°)=−tan( 180°+ 60°)=−tan( 60°)=−3

180°=πc1°=πc180210°=πc180×210°=( 7π 6)csin( 210°)=sin( 180°+ 30°)=−sin( 30°)=−12cos( 210°)=cos( 180°+ 30°)=−cos( 30°)=−32tan( 210°)=tan( 180°+ 30°)=tan( 30°)=13

180°=πc1°=πc18090°=πc180×90°=( π 2)csin( 90°)=1cos( 90°)=0tan( 90°)=undefined

Hence the complete table is

Degree	Radians	Sine	Cosine	Tangent
−45° 180° −240° 210° 90°	−π4 π−4π3 7π6 π2	−12 032 −12 1	12 −1−12 −32 0	−10−3 13 undefined

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Answer 2

Question

Chapter E, Problem 1PS

To determine

Find the all values in the given table.

Expert Solution & Answer

Answer to Problem 1PS

The complete table is

Degree	Radians	Sine	Cosine	Tangent
−45° 180° −240° 210° 90°	−π4 π−4π3 7π6 π2	−12 032 −12 1	12 −1−12 −32 0	−10−3 13 undefined

Explanation of Solution

Given:

The given table is

Calculus, Chapter E, Problem 1PS

Calculation:

180°=πc1°=πc180−45°=πc180×−45°=−πc4sin(− 45°)=−sin( 45°)=−12cos(− 45°)=cos( 45°)=12tan(− 45°)=−tan( 45°)=−1

πc=180°sin( 180°)=0cos( 180°)=−1tan( 180°)=0

πc=180°πc= 180°π−4π3= 180°π×(− 4π3)=−240°sin(− 240°)=−sin( 240°)=−sin( 180°+ 60°)=sin( 60°)=32cos(− 240°)=cos( 240°)=cos( 180°+ 60°)=−cos( 60°)=−12tan(− 240°)=−tan( 240°)=−tan( 180°+ 60°)=−tan( 60°)=−3

180°=πc1°=πc180210°=πc180×210°=( 7π 6)csin( 210°)=sin( 180°+ 30°)=−sin( 30°)=−12cos( 210°)=cos( 180°+ 30°)=−cos( 30°)=−32tan( 210°)=tan( 180°+ 30°)=tan( 30°)=13

180°=πc1°=πc18090°=πc180×90°=( π 2)csin( 90°)=1cos( 90°)=0tan( 90°)=undefined

Hence the complete table is

Degree	Radians	Sine	Cosine	Tangent
−45° 180° −240° 210° 90°	−π4 π−4π3 7π6 π2	−12 032 −12 1	12 −1−12 −32 0	−10−3 13 undefined

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Answer 3

Question

Chapter E, Problem 1PS

To determine

Find the all values in the given table.

Expert Solution & Answer

Answer to Problem 1PS

The complete table is

Degree	Radians	Sine	Cosine	Tangent
−45° 180° −240° 210° 90°	−π4 π−4π3 7π6 π2	−12 032 −12 1	12 −1−12 −32 0	−10−3 13 undefined

Explanation of Solution

Given:

The given table is

Calculus, Chapter E, Problem 1PS

Calculation:

180°=πc1°=πc180−45°=πc180×−45°=−πc4sin(− 45°)=−sin( 45°)=−12cos(− 45°)=cos( 45°)=12tan(− 45°)=−tan( 45°)=−1

πc=180°sin( 180°)=0cos( 180°)=−1tan( 180°)=0

πc=180°πc= 180°π−4π3= 180°π×(− 4π3)=−240°sin(− 240°)=−sin( 240°)=−sin( 180°+ 60°)=sin( 60°)=32cos(− 240°)=cos( 240°)=cos( 180°+ 60°)=−cos( 60°)=−12tan(− 240°)=−tan( 240°)=−tan( 180°+ 60°)=−tan( 60°)=−3

180°=πc1°=πc180210°=πc180×210°=( 7π 6)csin( 210°)=sin( 180°+ 30°)=−sin( 30°)=−12cos( 210°)=cos( 180°+ 30°)=−cos( 30°)=−32tan( 210°)=tan( 180°+ 30°)=tan( 30°)=13

180°=πc1°=πc18090°=πc180×90°=( π 2)csin( 90°)=1cos( 90°)=0tan( 90°)=undefined

Hence the complete table is

Degree	Radians	Sine	Cosine	Tangent
−45° 180° −240° 210° 90°	−π4 π−4π3 7π6 π2	−12 032 −12 1	12 −1−12 −32 0	−10−3 13 undefined

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Answer 4

Question

Chapter E, Problem 1PS

To determine

Find the all values in the given table.

Expert Solution & Answer

Answer to Problem 1PS

The complete table is

Degree	Radians	Sine	Cosine	Tangent
−45° 180° −240° 210° 90°	−π4 π−4π3 7π6 π2	−12 032 −12 1	12 −1−12 −32 0	−10−3 13 undefined

Explanation of Solution

Given:

The given table is

Calculus, Chapter E, Problem 1PS

Calculation:

180°=πc1°=πc180−45°=πc180×−45°=−πc4sin(− 45°)=−sin( 45°)=−12cos(− 45°)=cos( 45°)=12tan(− 45°)=−tan( 45°)=−1

πc=180°sin( 180°)=0cos( 180°)=−1tan( 180°)=0

πc=180°πc= 180°π−4π3= 180°π×(− 4π3)=−240°sin(− 240°)=−sin( 240°)=−sin( 180°+ 60°)=sin( 60°)=32cos(− 240°)=cos( 240°)=cos( 180°+ 60°)=−cos( 60°)=−12tan(− 240°)=−tan( 240°)=−tan( 180°+ 60°)=−tan( 60°)=−3

180°=πc1°=πc180210°=πc180×210°=( 7π 6)csin( 210°)=sin( 180°+ 30°)=−sin( 30°)=−12cos( 210°)=cos( 180°+ 30°)=−cos( 30°)=−32tan( 210°)=tan( 180°+ 30°)=tan( 30°)=13

180°=πc1°=πc18090°=πc180×90°=( π 2)csin( 90°)=1cos( 90°)=0tan( 90°)=undefined

Hence the complete table is

Degree	Radians	Sine	Cosine	Tangent
−45° 180° −240° 210° 90°	−π4 π−4π3 7π6 π2	−12 032 −12 1	12 −1−12 −32 0	−10−3 13 undefined

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Answer 5

Chapter E, Problem 1PS

To determine

Find the all values in the given table.

Expert Solution & Answer

Answer to Problem 1PS

The complete table is

Degree	Radians	Sine	Cosine	Tangent
−45° 180° −240° 210° 90°	−π4 π−4π3 7π6 π2	−12 032 −12 1	12 −1−12 −32 0	−10−3 13 undefined

Explanation of Solution

Given:

The given table is

Calculus, Chapter E, Problem 1PS

Calculation:

180°=πc1°=πc180−45°=πc180×−45°=−πc4sin(− 45°)=−sin( 45°)=−12cos(− 45°)=cos( 45°)=12tan(− 45°)=−tan( 45°)=−1

πc=180°sin( 180°)=0cos( 180°)=−1tan( 180°)=0

πc=180°πc= 180°π−4π3= 180°π×(− 4π3)=−240°sin(− 240°)=−sin( 240°)=−sin( 180°+ 60°)=sin( 60°)=32cos(− 240°)=cos( 240°)=cos( 180°+ 60°)=−cos( 60°)=−12tan(− 240°)=−tan( 240°)=−tan( 180°+ 60°)=−tan( 60°)=−3

180°=πc1°=πc180210°=πc180×210°=( 7π 6)csin( 210°)=sin( 180°+ 30°)=−sin( 30°)=−12cos( 210°)=cos( 180°+ 30°)=−cos( 30°)=−32tan( 210°)=tan( 180°+ 30°)=tan( 30°)=13

180°=πc1°=πc18090°=πc180×90°=( π 2)csin( 90°)=1cos( 90°)=0tan( 90°)=undefined

Hence the complete table is

Degree	Radians	Sine	Cosine	Tangent
−45° 180° −240° 210° 90°	−π4 π−4π3 7π6 π2	−12 032 −12 1	12 −1−12 −32 0	−10−3 13 undefined

Answer 6

Chapter E, Problem 1PS

To determine

Find the all values in the given table.

Expert Solution & Answer

Answer to Problem 1PS

The complete table is

Degree	Radians	Sine	Cosine	Tangent
−45° 180° −240° 210° 90°	−π4 π−4π3 7π6 π2	−12 032 −12 1	12 −1−12 −32 0	−10−3 13 undefined

Explanation of Solution

Given:

The given table is

Calculus, Chapter E, Problem 1PS

Calculation:

180°=πc1°=πc180−45°=πc180×−45°=−πc4sin(− 45°)=−sin( 45°)=−12cos(− 45°)=cos( 45°)=12tan(− 45°)=−tan( 45°)=−1

πc=180°sin( 180°)=0cos( 180°)=−1tan( 180°)=0

πc=180°πc= 180°π−4π3= 180°π×(− 4π3)=−240°sin(− 240°)=−sin( 240°)=−sin( 180°+ 60°)=sin( 60°)=32cos(− 240°)=cos( 240°)=cos( 180°+ 60°)=−cos( 60°)=−12tan(− 240°)=−tan( 240°)=−tan( 180°+ 60°)=−tan( 60°)=−3

180°=πc1°=πc180210°=πc180×210°=( 7π 6)csin( 210°)=sin( 180°+ 30°)=−sin( 30°)=−12cos( 210°)=cos( 180°+ 30°)=−cos( 30°)=−32tan( 210°)=tan( 180°+ 30°)=tan( 30°)=13

180°=πc1°=πc18090°=πc180×90°=( π 2)csin( 90°)=1cos( 90°)=0tan( 90°)=undefined

Hence the complete table is

Degree	Radians	Sine	Cosine	Tangent
−45° 180° −240° 210° 90°	−π4 π−4π3 7π6 π2	−12 032 −12 1	12 −1−12 −32 0	−10−3 13 undefined

Answer 7

Chapter E, Problem 1PS

To determine

Find the all values in the given table.

Answer 8

Expert Solution & Answer

Answer to Problem 1PS

The complete table is

Degree	Radians	Sine	Cosine	Tangent
−45° 180° −240° 210° 90°	−π4 π−4π3 7π6 π2	−12 032 −12 1	12 −1−12 −32 0	−10−3 13 undefined

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given:

The given table is

Calculus, Chapter E, Problem 1PS

Calculation:

180°=πc1°=πc180−45°=πc180×−45°=−πc4sin(− 45°)=−sin( 45°)=−12cos(− 45°)=cos( 45°)=12tan(− 45°)=−tan( 45°)=−1

πc=180°sin( 180°)=0cos( 180°)=−1tan( 180°)=0

πc=180°πc= 180°π−4π3= 180°π×(− 4π3)=−240°sin(− 240°)=−sin( 240°)=−sin( 180°+ 60°)=sin( 60°)=32cos(− 240°)=cos( 240°)=cos( 180°+ 60°)=−cos( 60°)=−12tan(− 240°)=−tan( 240°)=−tan( 180°+ 60°)=−tan( 60°)=−3

180°=πc1°=πc180210°=πc180×210°=( 7π 6)csin( 210°)=sin( 180°+ 30°)=−sin( 30°)=−12cos( 210°)=cos( 180°+ 30°)=−cos( 30°)=−32tan( 210°)=tan( 180°+ 30°)=tan( 30°)=13