CALCULUS+ITS APPLICATIONS (LL)
CALCULUS+ITS APPLICATIONS (LL)
12th Edition
ISBN: 9780135165928
Author: BITTINGER
Publisher: PEARSON
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Chapter CR, Problem 1CR
To determine

Find fx+h and fx+hfxh for the function fx=x25 .

Expert Solution & Answer
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Answer to Problem 1CR

The value of fx+h=x2+h2+2hx5 and fx+hfxh=h+2x .

Explanation of Solution

Given:

The given function is fx=x25 .

Calculation:

Evaluating fx+h for the function fx=x25 by plugging x=x+h in fx=x25 .

Therefore,

  fx+h=x+h25=x2+h2+2hx5 ....1

Similarly, evaluating fx+hfxh ,

  fx+hfxh=x2+h2+2hx5x25h ....From 1=x2+h2+2hx5x2+5h=h2+2hxh=h+2x

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