EBK MACHINE TOOL PRACTICES
11th Edition
ISBN: 9780134985824
Author: CURRAN
Publisher: VST
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Chapter C.8, Problem 2ST
What is the discrimination of the universal bevel protractor?
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The evaporator of a vapor compression refrigeration cycle utilizing R-123 as the refrigerant isbeing used to chill water. The evaporator is a shell and tube heat exchanger with the water flowingthrough the tubes. The water enters the heat exchanger at a temperature of 54°F. The approachtemperature difference of the evaporator is 3°R. The evaporating pressure of the refrigeration cycleis 4.8 psia and the condensing pressure is 75 psia. The refrigerant is flowing through the cycle witha flow rate of 18,000 lbm/hr. The R-123 leaves the evaporator as a saturated vapor and leaves thecondenser as a saturated liquid. Determine the following:a. The outlet temperature of the chilled waterb. The volumetric flow rate of the chilled water (gpm)c. The UA product of the evaporator (Btu/h-°F)d. The heat transfer rate between the refrigerant and the water (tons)
(Read image) (Answer given)
Problem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a
mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and
(y2), respectively.
Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s].
Givens:
y1 = 4.112 m
y2 =
0.387 m
b = 0.942 m
Answers:
( 1 ) 1880.186 lit/s
( 2 ) 4042.945 lit/s
( 3 ) 2553.11 lit/s
( 4 ) 3130.448 lit/s
Chapter C Solutions
EBK MACHINE TOOL PRACTICES
Ch. C.1 - Prob. 1STCh. C.1 - Prob. 2STCh. C.1 - Prob. 3STCh. C.1 - Prob. 4STCh. C.1 - Prob. 5STCh. C.1 - Prob. 6STCh. C.1 - Prob. 7STCh. C.1 - Prob. 8STCh. C.1 - Prob. 9STCh. C.1 - Prob. 10ST
Ch. C.2 - Prob. 1STCh. C.2 - Prob. 2STCh. C.2 - Prob. 3STCh. C.2 - Prob. 4STCh. C.2 - Prob. 5STCh. C.2 - Prob. 6STCh. C.2 - Prob. 7STCh. C.2 - Prob. 8STCh. C.2 - Prob. 9STCh. C.2 - Can an inch machine tool be converted to work in...Ch. C.3 - Prob. 1.1STCh. C.3 - Prob. 1.2STCh. C.3 - Prob. 1.3STCh. C.4 - Prob. 1.1STCh. C.4 - Prob. 1.2STCh. C.4 - Prob. 1.3STCh. C.5 - Prob. 1STCh. C.5 - Prob. 2STCh. C.5 - Prob. 3STCh. C.5 - Prob. 4STCh. C.5 - Prob. 5STCh. C.5 - Prob. 6STCh. C.5 - Prob. 7STCh. C.5 - Prob. 8STCh. C.5 - Prob. 9STCh. C.5 - Prob. 10STCh. C.5 - Prob. 11STCh. C.5 - Prob. 1.1STCh. C.5 - Prob. 1.2STCh. C.5 - Prob. 2.1STCh. C.5 - Prob. 3.1STCh. C.5 - Prob. 4.1STCh. C.6 - What is comparison measurement?Ch. C.6 - Define cosine error.Ch. C.6 - Prob. 3STCh. C.6 - Prob. 4STCh. C.6 - Prob. 5STCh. C.6 - Prob. 6STCh. C.6 - Prob. 7STCh. C.6 - Prob. 8STCh. C.7 - What is a wringing interval?Ch. C.7 - Why are wear blocks frequently used in combination...Ch. C.7 - As related to gage block use, what is meant by the...Ch. C.7 - Prob. 4STCh. C.7 - What is a conditioning stone and how is it used?Ch. C.7 - Prob. 6STCh. C.7 - Prob. 7STCh. C.7 - Prob. 8STCh. C.7 - Prob. 9STCh. C.7 - Prob. 10STCh. C.8 - Name two angular measuring instruments with one...Ch. C.8 - What is the discrimination of the universal bevel...Ch. C.8 - Describe the use of the sine bar.Ch. C.8 - Prob. 4STCh. C.8 - Calculate the required sine bar elevation for an...Ch. C.8 - A 10-inch sine bar is elevated 2.750 inch....Ch. C.8 - How do 10-inch and 5-inch sine bars affect the...Ch. C.8 - What gage block stack would establish an angle of...Ch. C.8 - What gage block stack would establish an angle of...Ch. C.8 - A 10-inch bar is elevated 2.5 inch. What angle is...Ch. C.9 - Prob. 1STCh. C.9 - Prob. 2STCh. C.9 - Prob. 3STCh. C.9 - Prob. 4STCh. C.9 - Prob. 5STCh. C.9 - Prob. 6STCh. C.9 - Prob. 7STCh. C.9 - Prob. 8STCh. C.9 - Prob. 9STCh. C.9 - Prob. 10STCh. C.9 - Prob. 11STCh. C.9 - Prob. 12STCh. C.9 - Prob. 13STCh. C.9 - Prob. 14STCh. C.9 - Prob. 15STCh. C.9 - Prob. 16STCh. C.9 - Prob. 17STCh. C.9 - Prob. 18STCh. C.9 - Prob. 19STCh. C.9 - Prob. 20STCh. C.9 - Prob. 21STCh. C.9 - Prob. 22STCh. C.9 - Prob. 23STCh. C.9 - Prob. 24STCh. C.9 - Prob. 25STCh. C.9 - Prob. 26STCh. C.9 - Prob. 27STCh. C.9 - Prob. 28STCh. C.9 - Prob. 29STCh. C.9 - Prob. 30STCh. C.9 - Prob. 31STCh. C.9 - Prob. 32STCh. C.9 - Prob. 33STCh. C.9 - Prob. 34STCh. C.10 - Prob. 1STCh. C.10 - Prob. 2STCh. C.10 - Prob. 3STCh. C.10 - Prob. 4STCh. C.10 - Prob. 5STCh. C.10 - Prob. 6STCh. C.10 - Prob. 7STCh. C.10 - Prob. 8STCh. C.10 - Prob. 9ST
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- Problem (14): A pump is being used to lift water from an underground tank through a pipe of diameter (d) at discharge (Q). The total head loss until the pump entrance can be calculated as (h₁ = K[V²/2g]), h where (V) is the flow velocity in the pipe. The elevation difference between the pump and tank surface is (h). Given the values of h [cm], d [cm], and K [-], calculate the maximum discharge Q [Lit/s] beyond which cavitation would take place at the pump entrance. Assume Turbulent flow conditions. Givens: h = 120.31 cm d = 14.455 cm K = 8.976 Q Answers: (1) 94.917 lit/s (2) 49.048 lit/s ( 3 ) 80.722 lit/s 68.588 lit/s 4arrow_forwardProblem (13): A pump is being used to lift water from the bottom tank to the top tank in a galvanized iron pipe at a discharge (Q). The length and diameter of the pipe section from the bottom tank to the pump are (L₁) and (d₁), respectively. The length and diameter of the pipe section from the pump to the top tank are (L2) and (d2), respectively. Given the values of Q [L/s], L₁ [m], d₁ [m], L₂ [m], d₂ [m], calculate total head loss due to friction (i.e., major loss) in the pipe (hmajor-loss) in [cm]. Givens: L₁,d₁ Pump L₂,d2 오 0.533 lit/s L1 = 6920.729 m d1 = 1.065 m L2 = 70.946 m d2 0.072 m Answers: (1) 3.069 cm (2) 3.914 cm ( 3 ) 2.519 cm ( 4 ) 1.855 cm TABLE 8.1 Equivalent Roughness for New Pipes Pipe Riveted steel Concrete Wood stave Cast iron Galvanized iron Equivalent Roughness, & Feet Millimeters 0.003-0.03 0.9-9.0 0.001-0.01 0.3-3.0 0.0006-0.003 0.18-0.9 0.00085 0.26 0.0005 0.15 0.045 0.000005 0.0015 0.0 (smooth) 0.0 (smooth) Commercial steel or wrought iron 0.00015 Drawn…arrow_forwardThe flow rate is 12.275 Liters/s and the diameter is 6.266 cm.arrow_forward
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