Calculus, Early Transcendentals
Calculus, Early Transcendentals
9th Edition
ISBN: 9781337613927
Author: Stewart
Publisher: CENGAGE L
Question
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Chapter C, Problem 1E
To determine

The equation of the circle with center 3,1 and radius 5 .

Expert Solution & Answer
Check Mark

Answer to Problem 1E

The equation of the circle is x32+y+12=25 .

Explanation of Solution

Given:

The center of the circle is 3,1 and radius 5 .

Concept used:

The equation of the circle with center h,k and radius r is xh2+yk2=r2 ....1

Calculation:

Since the center of the circle is 3,1 and radius 5 . Therefore, from 1 .

  xh2+yk2=r2 ....From 1x32+y12=52x32+y+12=25

Hence, the equation of the circle is x32+y+12=25 .

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