EBK CALCULUS EARLY TRANSCENDENTALS
9th Edition
ISBN: 9780357687901
Author: Stewart
Publisher: CENGAGE L
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Chapter C, Problem 16E
To determine
Identify the type of curve
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A tank contains 60 kg of salt and 2000 L of water. Pure water enters a tank at the rate 8 L/min. The
solution is mixed and drains from the tank at the rate 11 L/min.
Let y be the number of kg of salt in the tank after t minutes.
The differential equation for this situation would be:
dy
dt
y(0) =
Solve the initial value problem:
y= 0.05y + 5
y(0) = 100
y(t) =
y=f'(x)
1
8
The function f is defined on the closed interval [0,8]. The graph of its derivative f' is shown above.
How many relative minima are there for f(x)?
O
2
6
4
00
Chapter C Solutions
EBK CALCULUS EARLY TRANSCENDENTALS
Ch. C - Prob. 1ECh. C - Prob. 2ECh. C - Prob. 3ECh. C - Prob. 4ECh. C - Prob. 5ECh. C - Prob. 6ECh. C - Prob. 7ECh. C - Prob. 8ECh. C - Prob. 9ECh. C - Prob. 10E
Ch. C - Prob. 11ECh. C - Prob. 12ECh. C - Prob. 13ECh. C - Prob. 14ECh. C - Prob. 15ECh. C - Prob. 16ECh. C - Prob. 17ECh. C - Prob. 18ECh. C - Prob. 19ECh. C - Prob. 20ECh. C - Prob. 21ECh. C - Prob. 22ECh. C - Prob. 23ECh. C - Prob. 24ECh. C - Prob. 25ECh. C - Prob. 26ECh. C - Prob. 27ECh. C - Prob. 28ECh. C - Prob. 29ECh. C - Prob. 30ECh. C - Prob. 31ECh. C - Prob. 32ECh. C - Prob. 33ECh. C - Prob. 34ECh. C - Prob. 35ECh. C - Prob. 36ECh. C - Prob. 37ECh. C - Prob. 38ECh. C - Prob. 39ECh. C - Prob. 40E
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- There is exactly number a and one number b such that the vector field F = conservative. For those values of a and b, the value of cos(a) + sin(b) is (3ay + z, 3ayz + 3x, −by² + x) is -0.961 -0.772 -1.645 0.057 -0.961 1.764 -0.457 0.201arrow_forwardA: Tan Latitude / Tan P A = Tan 04° 30'/ Tan 77° 50.3' A= 0.016960 803 S CA named opposite to latitude, except when hour angle between 090° and 270°) B: Tan Declination | Sin P B Tan 052° 42.1'/ Sin 77° 50.3' B = 1.34 2905601 SCB is alway named same as declination) C = A + B = 1.35 9866404 S CC correction, A+/- B: if A and B have same name - add, If different name- subtract) = Tan Azimuth 1/Ccx cos Latitude) Tan Azimuth = 0.737640253 Azimuth = S 36.4° E CAzimuth takes combined name of C correction and Hour Angle - If LHA is between 0° and 180°, it is named "west", if LHA is between 180° and 360° it is named "east" True Azimuth= 143.6° Compass Azimuth = 145.0° Compass Error = 1.4° West Variation 4.0 East Deviation: 5.4 Westarrow_forwardds 5. Find a solution to this initial value problem: 3t2, s(0) = 5. dt 6. Find a solution to this initial value problem: A' = 0.03A, A(0) = 100.arrow_forward
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