EBK MACHINE TOOL PRACTICES
11th Edition
ISBN: 9780134985824
Author: CURRAN
Publisher: VST
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Chapter B.9, Problem 7ST
To determine
The reason behind the running of grinder after changing a wheel for short time.
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Problem 9.5
9.5 A 1080-kg car is parked on a sloped street. The figure shows its wheels and the position of
its center of mass. The street is icy, and as a result the coefficient of static friction between
the car's tires and the street surface is μs = 0.2. Determine the steepest slope (in degrees
relative to the horizontal) at which the car could remain in equilibrium if
a. the brakes are applied to both its front and rear wheels;
b. the brakes are applied to the front (lower) wheels only.
Problem 9.5
1380 mm
532 mm
2370 mm
Can someone explain please with conversions
Correct Answer is written below. Detailed and complete fbd only please. I will upvote, thank you.
1: The assembly shown is composed of a rigid plank ABC, supported by hinge at A, spring at B and cable at C.The cable is attached to a frictionless pulley at D and rigidly supported at E. The cable is made of steel with E = 200,000MPa and cross-sectional area of 500 mm2. The details of pulley at D is shown. The pulley is supported by a pin, passingthough the pulley and attached to both cheeks. Note that E is directly above B.Given: H = 3 m; L1 = 2 m; L2 = 4 m; w = 12 kN/m; x:y = 3:4Spring Parameters:Wire diameter = 30 mmMean Radius = 90 mmNumber of turns = 12Modulus of Rigidity = 80 GPaAllowable stresses:Allowable shear stress of Pin at D = 85 MPaAllowable normal stress of cheek at D = 90MPaAllowable bearing stress of cheek at D = 110MPa1. Calculate the reaction of spring Band tension in cable at C.2. Calculate the vertical displacementat C and the required diameter ofpin at D.3.…
Chapter B Solutions
EBK MACHINE TOOL PRACTICES
Ch. B.1 - List several uses of the arbor press.Ch. B.1 - A newly machined steel shaft with an interference...Ch. B.1 - The ram of an arbor press is loose in its guide...Ch. B.1 - When a bushing is pushed into a bore that is...Ch. B.1 - Prob. 5STCh. B.1 - What difference is there in the way a press fit is...Ch. B.1 - Prior to installing a bushing with the arbor...Ch. B.1 - Name five ways to avoid tool breakage and other...Ch. B.2 - Name two types of bench visesCh. B.2 - Prob. 2ST
Ch. B.2 - How can the finished surface of a part be...Ch. B.2 - Name three things that should never be done to a...Ch. B.2 - How should a vise be Lubricated?Ch. B.2 - Prob. 6STCh. B.2 - What advantage does the lever-jawed wrench offer...Ch. B.2 - Some objects should never be struck with a hard...Ch. B.2 - Why should pipe wrenches never be used on bolts,...Ch. B.2 - What are the two important things to remember...Ch. B.3 - What is the kerf?Ch. B.3 - What is the set on a saw blade?Ch. B.3 - What is the pitch of the hacksaw blade?Ch. B.3 - What determines the selection of a saw blade for a...Ch. B.3 - Hand hacksaw blades fall into two basic...Ch. B.3 - Give four causes that make saw blades dull.Ch. B.3 - Give two reasons why hacksaw blades break.Ch. B.3 - A new hacksaw blade should not be used in a cut...Ch. B.4 - What are the four different cuts found on files?Ch. B.4 - Name four coarseness designations for files.Ch. B.4 - Which of the two kinds of files-single cut or...Ch. B.4 - What are the coarseness designations for needle...Ch. B.4 - Prob. 5STCh. B.4 - What causes a file to get dull?Ch. B.4 - Why should a handle be used on a file?Ch. B.4 - How does the hardness of a workpiece affect the...Ch. B.4 - Should pressure be applied to a file on the return...Ch. B.4 - Why is a round file rotated while it is being...Ch. B.5 - Prob. 1STCh. B.5 - What is the purpose of a starting taper on a...Ch. B.5 - What is the advantage of a spiral flute reamer...Ch. B.5 - How does the shank diameter of a hand reamer...Ch. B.5 - Prob. 5STCh. B.5 - Prob. 6STCh. B.5 - What is the purpose of cutting fluid in reaming?Ch. B.5 - Prob. 8STCh. B.5 - How much reaming allowance is left for hand...Ch. B.5 - If you were repairing the lathe tailstock taper,...Ch. B.6 - What type of tap is used to produce threads that...Ch. B.6 - Prob. 2STCh. B.6 - Prob. 3STCh. B.6 - When is a spiral fluted tap used?Ch. B.6 - How are thread-forming taps different from...Ch. B.6 - How are taper pipe taps identified?Ch. B.6 - Why are finishing and roughing Acme taps used?Ch. B.6 - Why are rake angles varied on taps for different...Ch. B.7 - What kind of tools are used to drive taps when...Ch. B.7 - What is a hand tapper?Ch. B.7 - What is a tapping attachment?Ch. B.7 - Which three factors affect the strength of a...Ch. B.7 - How deep should the usable threads be in a tapped...Ch. B.7 - What causes taps to break while tapping?Ch. B.7 - What causes rough and tom threads?Ch. B.7 - Give three methods of removing broken taps from...Ch. B.8 - What is a die?Ch. B.8 - What tool is used to drive a die?Ch. B.8 - How much adjustment is possible with a round split...Ch. B.8 - What are important points to watch when assembling...Ch. B.8 - Why do dies have a chamfer on the cutting end?Ch. B.8 - Why are cutting fluids used?Ch. B.8 - What diameter should a rod be before being...Ch. B.8 - Why should a rod be chamfered before being...Ch. B.9 - Prob. 1STCh. B.9 - Why should a tool grinder never be used for rough...Ch. B.9 - Prob. 3STCh. B.9 - Prob. 4STCh. B.9 - Prob. 5STCh. B.9 - Prob. 6STCh. B.9 - Prob. 7STCh. B.9 - What is the purpose of the wheel blotter?Ch. B.9 - Prob. 9STCh. B.9 - What does the wheel ring test do?
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- Correct answer and complete fbd only. I will upvote. The compound shaft, composed of steel,aluminum, and bronze segments, carries the two torquesshown in the figure. If TC = 250 lb-ft, determine the maximumshear stress developed in each material (in ksi). The moduliof rigidity for steel, aluminum, and bronze are 12 x 106 psi, 4x 106 psi, and 6 x 106 psi, respectivelyarrow_forwardCan you explain the algebra steps that aren't shown but stated to be there, on how to get this equationarrow_forwardCorrect answer and complete fbd only. I will upvote. A flanged bolt coupling consists of two concentric rows of bolts. The inner row has 6 nos. of 16mm diameterbolts spaced evenly in a circle of 250mm in diameter. The outer row of has 10 nos. of 25 mm diameter bolts spaced evenly in a circle of 500mm in diameter. If the allowable shear stress on one bolt is 60 MPa, determine the torque capacity of the coupling. The Poisson’s ratio of the inner row of bolts is 0.2 while that of the outer row is 0.25 and the bolts are steel, E =200 GPa.arrow_forward
- Correct answer and complete fbd only. I will upvote. 10: The constant wall thickness of a steel tube with the cross sectionshown is 2 mm. If a 600-N-m torque is applied to the tube. Use G = 80 GPa forsteel.1. Find the shear stress (MPa) in the wall of the tube.2. Find the angle of twist, in degrees per meter of length.arrow_forwardCORRECT ANSWER WITH COMPLETE FBD ONLY. I WILL UPVOTE. A torque wrench is used to tighten the pipe shown.Dimensions: S1 = 400 mm; S2 = 250 mm; S3 = 100 mmModulus of Rigidity G = 78 GPa1. The diameter of the solid pipe is 20 mm. How much is themaximum force P (N) that can be applied based on theallowable shear stress of 60 MPa?2. For a hollow pipe with 50 mm outside diameter and is 6 mmthick, compute for the maximum force P (kN) that can beapplied such that the angle of twist at A does not exceed 5degrees.3. The torque applied to tighten the hollow pipe is 200 N-m.Given: Pipe outside diameter = 50 mm Pipe thickness = 6 mmSolve for the resulting maximum shear stress (MPa) in the pipe.arrow_forwardCorrect answer and complete fbd only. I will upvote. 6: The shaft carries a total torque T0 that is uniformly distributedover its length L. Determine the angle of twist (degrees) of the shaft in termsif T0 = 1.2 kN-m, L = 2 m, G = 80 GPa, and diameter = 120 mm.arrow_forward
- 2. Calculate the force in all members of the trusses shown using the method of joints. A 5525 lb C 3500 lb BY 14'-0" D 10'- 0" 6250 lb 10'- 0" Earrow_forwardCorrect answer and complete fbd only. I will upvote. 8: The steel rod fits loosely inside the aluminum sleeve. Both components are attached to a rigid wall at A andjoined together by a pin at B. Because of a slight misalignmentof the pre-drilled holes, the torque T0 = 750 N-m was appliedto the steel rod before the pin could be inserted into theholes. Determine the torque (N-m) in each component afterT0 was removed. Use G = 80 GPa for steel and G = 28 GPa foraluminumarrow_forwardCorrect answer and complete fbd only. I will upvote. 9: The two steel shafts, each with one end builtinto a rigid support, have flanges attached to their freeends. The flanges are to be bolted together. However,initially there is a 6⁰ mismatch in the location of the boltholes as shown in the figure. Determine the maximumshear stress(ksi) in each shaft after the flanges have beenbolted together. The shear modulus of elasticity for steelis 12 x 106 psi. Neglect deformations of the bolts and theflanges.arrow_forward
- Correct answer and complete fbd only. I will upvote. The tapered, wrought iron shaft carriesthe torque T = 2000 lb-in at its free end. Determine theangle of twist (degrees) of the shaft. Use G = 10 x 106psi for wrought ironarrow_forwardCorrect answer and complete fbd only. I will upvote. The compound shaft, consisting of steel and aluminumsegments, carries the two torques shown in the figure. Determine themaximum permissible value of T subject to the following designconditions: τst ≤ 83 MPa, τal ≤ 55 MPa, and θ ≤ 6⁰ (θ is the angle ofrotation of the free end). Use G =83 GPa for steel and G = 28 GPa foraluminum.arrow_forwardThe solid compound shaft, made of threedifferent materials, carries the two torques shown. Theshear moduli are 28 GPa for aluminum, 83 GPa for steel,and 35 GPa for bronze.1. Calculate the maximum shear stress (MPa) in eachmaterial.2. Find the angle of rotation (degrees) of the free endof the shaft.arrow_forward
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