Find the matrix C = A + 3 B .

Question

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Answer 1

Question

Chapter B, Problem 1P

To determine

Find the matrix C=A+3B.

Expert Solution & Answer

Answer to Problem 1P

The matrix C is [18−1118−11192818284]_.

Explanation of Solution

Given information:

A=[12−815−87101510−5] B=[2−11−146163]

Calculation:

Find the matrix 3B:

Substitute [2−11−146163] for B.

3B=3[2−11−146163]=[6−33−312183189]

Find the matrix C using the relation:

C=A+3B

Substitute [12−815−87101510−5] for A and [6−33−312183189] for 3B.

C=[12−815−87101510−5]+[6−33−312183189]=[18−1118−11192818284]

Thus, the matrix C is [18−1118−11192818284]_.

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1. What is the weight of each block shown below in pounds? A) 2’x2’x10’ Steel Bar w=490lb/ft^3 B) 5’x4’x3’ Concrete Block w=150lb/ft^3 A) 3’x10’x2’ Wood block w=50lb/ft^3 2.The 6” thick, 20’x25’ concrete slab weights 150lbs/ft^3 and has an area load of 50lbs/ft^2 (psf). What is the total load of the floor?

Lab Assignment #2 Loads: UDL and Concentrated Name: TA 1. Use the provided beam models to solve for the equivalent concentrated load of each beam configuration. Draw the loading conditions showing the equivalent concentrated load(s). a) w = 30lbs/ft 6ft 6ft c) w = 50lbs/ft 12ft w = 70lbs/ft b) 4ft w = 20lbs/ft w = 40lbs/ft d) 9ft 2. Find the equivalent concentrated load(s) for the bags of cement stacked on the dock as shown here. Each bag weighs 100 lbs and is 12 inches long. Draw the loading conditions for each showing the equivalent concentrated load(s). 1 bag = 100lbs L= 12 ft L= 6ft L= 8ft

Answer 2

Question

Chapter B, Problem 1P

To determine

Find the matrix C=A+3B.

Expert Solution & Answer

Answer to Problem 1P

The matrix C is [18−1118−11192818284]_.

Explanation of Solution

Given information:

A=[12−815−87101510−5] B=[2−11−146163]

Calculation:

Find the matrix 3B:

Substitute [2−11−146163] for B.

3B=3[2−11−146163]=[6−33−312183189]

Find the matrix C using the relation:

C=A+3B

Substitute [12−815−87101510−5] for A and [6−33−312183189] for 3B.

C=[12−815−87101510−5]+[6−33−312183189]=[18−1118−11192818284]

Thus, the matrix C is [18−1118−11192818284]_.

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Answer 3

Question

Chapter B, Problem 1P

To determine

Find the matrix C=A+3B.

Expert Solution & Answer

Answer to Problem 1P

The matrix C is [18−1118−11192818284]_.

Explanation of Solution

Given information:

A=[12−815−87101510−5] B=[2−11−146163]

Calculation:

Find the matrix 3B:

Substitute [2−11−146163] for B.

3B=3[2−11−146163]=[6−33−312183189]

Find the matrix C using the relation:

C=A+3B

Substitute [12−815−87101510−5] for A and [6−33−312183189] for 3B.

C=[12−815−87101510−5]+[6−33−312183189]=[18−1118−11192818284]

Thus, the matrix C is [18−1118−11192818284]_.

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Answer 4

Question

Chapter B, Problem 1P

To determine

Find the matrix C=A+3B.

Expert Solution & Answer

Answer to Problem 1P

The matrix C is [18−1118−11192818284]_.

Explanation of Solution

Given information:

A=[12−815−87101510−5] B=[2−11−146163]

Calculation:

Find the matrix 3B:

Substitute [2−11−146163] for B.

3B=3[2−11−146163]=[6−33−312183189]

Find the matrix C using the relation:

C=A+3B

Substitute [12−815−87101510−5] for A and [6−33−312183189] for 3B.

C=[12−815−87101510−5]+[6−33−312183189]=[18−1118−11192818284]

Thus, the matrix C is [18−1118−11192818284]_.

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Answer 5

Chapter B, Problem 1P

To determine

Find the matrix C=A+3B.

Expert Solution & Answer

Answer to Problem 1P

The matrix C is [18−1118−11192818284]_.

Explanation of Solution

Given information:

A=[12−815−87101510−5] B=[2−11−146163]

Calculation:

Find the matrix 3B:

Substitute [2−11−146163] for B.

3B=3[2−11−146163]=[6−33−312183189]

Find the matrix C using the relation:

C=A+3B

Substitute [12−815−87101510−5] for A and [6−33−312183189] for 3B.

C=[12−815−87101510−5]+[6−33−312183189]=[18−1118−11192818284]

Thus, the matrix C is [18−1118−11192818284]_.

Answer 6

Chapter B, Problem 1P

To determine

Find the matrix C=A+3B.

Expert Solution & Answer

Answer to Problem 1P

The matrix C is [18−1118−11192818284]_.

Explanation of Solution

Given information:

A=[12−815−87101510−5] B=[2−11−146163]

Calculation:

Find the matrix 3B:

Substitute [2−11−146163] for B.

3B=3[2−11−146163]=[6−33−312183189]

Find the matrix C using the relation:

C=A+3B

Substitute [12−815−87101510−5] for A and [6−33−312183189] for 3B.

C=[12−815−87101510−5]+[6−33−312183189]=[18−1118−11192818284]

Thus, the matrix C is [18−1118−11192818284]_.

Answer 7

Chapter B, Problem 1P

To determine

Find the matrix C=A+3B.

Answer 8

Expert Solution & Answer

Answer to Problem 1P

The matrix C is [18−1118−11192818284]_.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given information:

A=[12−815−87101510−5] B=[2−11−146163]

Calculation:

Find the matrix 3B:

Substitute [2−11−146163] for B.

3B=3[2−11−146163]=[6−33−312183189]

Find the matrix C using the relation:

C=A+3B

Substitute [12−815−87101510−5] for A and [6−33−312183189] for 3B.

C=[12−815−87101510−5]+[6−33−312183189]=[18−1118−11192818284]

Thus, the matrix C is [18−1118−11192818284]_.

Answer 12

Ch. B - Prob. 1P Ch. B - Prob. 2P Ch. B - Prob. 3P Ch. B - Prob. 4P Ch. B - Prob. 5P Ch. B - Prob. 6P Ch. B - Prob. 7P Ch. B - Prob. 8P Ch. B - Prob. 9P Ch. B - Prob. 10P

Find the matrix C = A + 3 B .

Find the matrix C=A+3B.

Answer to Problem 1P

Explanation of Solution

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Chapter B Solutions