The equation of the line that passes through the point ( 6 , 4 ) and has a slope m = − 2 3 .

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Answer 1

Question

Chapter B, Problem 1E

To determine

To find: The equation of the line that passes through the point $(6, 4)$ and has a slope $m = - \frac{2}{3}$ .

Expert Solution & Answer

Answer to Problem 1E

Solution: The equation of the line which passes through the point $(6, 4)$ and slope $m = - \frac{2}{3}$ is $y = - \frac{2}{3} x + 8$ .

Explanation of Solution

Given: The points through which the line passes is $(6, 4)$ and the slope is $m = - \frac{2}{3}$ .

Formula used:

The formula of straight line passing through the given point and having the given slope is,

$(y - y_{1}) = m (x - x_{1})$

Where,

• $y_{1}$ is the point on y-axis.

• $x_{1}$ is the point on x-axis.

Calculations:

Substitute 4 for $y_{1}$ , 6 for $x_{1}$ and $- \frac{2}{3}$ for m to find the equation of the line.

$\begin{matrix} (y - 4) = - \frac{2}{3} (x - 6) \\ (y - 4) = - \frac{2}{3} x + 4 \\ y = - \frac{2}{3} x + 8 \end{matrix}$

The equation of line that passes through the given point and has the given slope is $y = - \frac{2}{3} x + 8$ .

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Answer 2

Question

Chapter B, Problem 1E

To determine

To find: The equation of the line that passes through the point $(6, 4)$ and has a slope $m = - \frac{2}{3}$ .

Expert Solution & Answer

Answer to Problem 1E

Solution: The equation of the line which passes through the point $(6, 4)$ and slope $m = - \frac{2}{3}$ is $y = - \frac{2}{3} x + 8$ .

Explanation of Solution

Given: The points through which the line passes is $(6, 4)$ and the slope is $m = - \frac{2}{3}$ .

Formula used:

The formula of straight line passing through the given point and having the given slope is,

$(y - y_{1}) = m (x - x_{1})$

Where,

• $y_{1}$ is the point on y-axis.

• $x_{1}$ is the point on x-axis.

Calculations:

Substitute 4 for $y_{1}$ , 6 for $x_{1}$ and $- \frac{2}{3}$ for m to find the equation of the line.

$\begin{matrix} (y - 4) = - \frac{2}{3} (x - 6) \\ (y - 4) = - \frac{2}{3} x + 4 \\ y = - \frac{2}{3} x + 8 \end{matrix}$

The equation of line that passes through the given point and has the given slope is $y = - \frac{2}{3} x + 8$ .

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter B, Problem 1E

To determine

To find: The equation of the line that passes through the point $(6, 4)$ and has a slope $m = - \frac{2}{3}$ .

Expert Solution & Answer

Answer to Problem 1E

Solution: The equation of the line which passes through the point $(6, 4)$ and slope $m = - \frac{2}{3}$ is $y = - \frac{2}{3} x + 8$ .

Explanation of Solution

Given: The points through which the line passes is $(6, 4)$ and the slope is $m = - \frac{2}{3}$ .

Formula used:

The formula of straight line passing through the given point and having the given slope is,

$(y - y_{1}) = m (x - x_{1})$

Where,

• $y_{1}$ is the point on y-axis.

• $x_{1}$ is the point on x-axis.

Calculations:

Substitute 4 for $y_{1}$ , 6 for $x_{1}$ and $- \frac{2}{3}$ for m to find the equation of the line.

$\begin{matrix} (y - 4) = - \frac{2}{3} (x - 6) \\ (y - 4) = - \frac{2}{3} x + 4 \\ y = - \frac{2}{3} x + 8 \end{matrix}$

The equation of line that passes through the given point and has the given slope is $y = - \frac{2}{3} x + 8$ .

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter B, Problem 1E

To determine

To find: The equation of the line that passes through the point $(6, 4)$ and has a slope $m = - \frac{2}{3}$ .

Expert Solution & Answer

Answer to Problem 1E

Solution: The equation of the line which passes through the point $(6, 4)$ and slope $m = - \frac{2}{3}$ is $y = - \frac{2}{3} x + 8$ .

Explanation of Solution

Given: The points through which the line passes is $(6, 4)$ and the slope is $m = - \frac{2}{3}$ .

Formula used:

The formula of straight line passing through the given point and having the given slope is,

$(y - y_{1}) = m (x - x_{1})$

Where,

• $y_{1}$ is the point on y-axis.

• $x_{1}$ is the point on x-axis.

Calculations:

Substitute 4 for $y_{1}$ , 6 for $x_{1}$ and $- \frac{2}{3}$ for m to find the equation of the line.

$\begin{matrix} (y - 4) = - \frac{2}{3} (x - 6) \\ (y - 4) = - \frac{2}{3} x + 4 \\ y = - \frac{2}{3} x + 8 \end{matrix}$

The equation of line that passes through the given point and has the given slope is $y = - \frac{2}{3} x + 8$ .

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter B, Problem 1E

To determine

To find: The equation of the line that passes through the point $(6, 4)$ and has a slope $m = - \frac{2}{3}$ .

Expert Solution & Answer

Answer to Problem 1E

Solution: The equation of the line which passes through the point $(6, 4)$ and slope $m = - \frac{2}{3}$ is $y = - \frac{2}{3} x + 8$ .

Explanation of Solution

Given: The points through which the line passes is $(6, 4)$ and the slope is $m = - \frac{2}{3}$ .

Formula used:

The formula of straight line passing through the given point and having the given slope is,

$(y - y_{1}) = m (x - x_{1})$

Where,

• $y_{1}$ is the point on y-axis.

• $x_{1}$ is the point on x-axis.

Calculations:

Substitute 4 for $y_{1}$ , 6 for $x_{1}$ and $- \frac{2}{3}$ for m to find the equation of the line.

$\begin{matrix} (y - 4) = - \frac{2}{3} (x - 6) \\ (y - 4) = - \frac{2}{3} x + 4 \\ y = - \frac{2}{3} x + 8 \end{matrix}$

The equation of line that passes through the given point and has the given slope is $y = - \frac{2}{3} x + 8$ .

Answer 6

Chapter B, Problem 1E

To determine

To find: The equation of the line that passes through the point $(6, 4)$ and has a slope $m = - \frac{2}{3}$ .

Expert Solution & Answer

Answer to Problem 1E

Solution: The equation of the line which passes through the point $(6, 4)$ and slope $m = - \frac{2}{3}$ is $y = - \frac{2}{3} x + 8$ .

Explanation of Solution

Given: The points through which the line passes is $(6, 4)$ and the slope is $m = - \frac{2}{3}$ .

Formula used:

The formula of straight line passing through the given point and having the given slope is,

$(y - y_{1}) = m (x - x_{1})$

Where,

• $y_{1}$ is the point on y-axis.

• $x_{1}$ is the point on x-axis.

Calculations:

Substitute 4 for $y_{1}$ , 6 for $x_{1}$ and $- \frac{2}{3}$ for m to find the equation of the line.

$\begin{matrix} (y - 4) = - \frac{2}{3} (x - 6) \\ (y - 4) = - \frac{2}{3} x + 4 \\ y = - \frac{2}{3} x + 8 \end{matrix}$

The equation of line that passes through the given point and has the given slope is $y = - \frac{2}{3} x + 8$ .

Answer 7

Chapter B, Problem 1E

To determine

To find: The equation of the line that passes through the point $(6, 4)$ and has a slope $m = - \frac{2}{3}$ .

Answer 8

Expert Solution & Answer

Answer to Problem 1E

Solution: The equation of the line which passes through the point $(6, 4)$ and slope $m = - \frac{2}{3}$ is $y = - \frac{2}{3} x + 8$ .

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given: The points through which the line passes is $(6, 4)$ and the slope is $m = - \frac{2}{3}$ .

Formula used:

The formula of straight line passing through the given point and having the given slope is,

$(y - y_{1}) = m (x - x_{1})$

Where,

• $y_{1}$ is the point on y-axis.

• $x_{1}$ is the point on x-axis.

Calculations:

Substitute 4 for $y_{1}$ , 6 for $x_{1}$ and $- \frac{2}{3}$ for m to find the equation of the line.

$\begin{matrix} (y - 4) = - \frac{2}{3} (x - 6) \\ (y - 4) = - \frac{2}{3} x + 4 \\ y = - \frac{2}{3} x + 8 \end{matrix}$

The equation of line that passes through the given point and has the given slope is $y = - \frac{2}{3} x + 8$ .

Answer 12

Ch. B - Prob. 1E Ch. B - Prob. 2E Ch. B - Prob. 3E Ch. B - Prob. 4E Ch. B - Prob. 5E Ch. B - Prob. 6E Ch. B - Prob. 7E Ch. B - Prob. 8E Ch. B - Prob. 9E Ch. B - Prob. 10E

The equation of the line that passes through the point ( 6 , 4 ) and has a slope m = − 2 3 .

Videos

To find: The equation of the line that passes through the point $(6, 4)$ and has a slope $m = - \frac{2}{3}$ .

Answer to Problem 1E

Explanation of Solution

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Chapter B Solutions

The equation of the line that passes through the point ( 6 , 4 ) and has a slope m = − 2 3 .

Videos

To find: The equation of the line that passes through the point (6,4) and has a slope m=−23.

Answer to Problem 1E

Explanation of Solution

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Chapter B Solutions

To find: The equation of the line that passes through the point $(6, 4)$ and has a slope $m = - \frac{2}{3}$ .