Solve A = P 1 + r 2 for r in terms of A and P : that is, isolate r on the left side of the equation (with coefficient 1) and end up with an algebraic expression on the right side involving A and P but not r . Write the answer using positive square roots only.
Solve A = P 1 + r 2 for r in terms of A and P : that is, isolate r on the left side of the equation (with coefficient 1) and end up with an algebraic expression on the right side involving A and P but not r . Write the answer using positive square roots only.
Solution Summary: The author calculates the value of r for the equation A=P(1+r)2 by using positive square roots.
Solve
A
=
P
1
+
r
2
for
r
in terms of
A
and
P
: that is, isolate
r
on the left side of the equation (with coefficient 1) and end up with an algebraic expression on the right side involving
A
and
P
but not
r
. Write the answer using positive square roots only.
The diagonals of rhombus ABCD intersect at E. Given that BAC=53 degrees, DE=8, and EC=6 find AE
Not use ai please
2. [-/4 Points]
DETAILS
MY NOTES
SESSCALCET2 7.3.002.
Let S be the solid obtained by rotating the region shown in the figure about the y-axis. (Assume a = 6 and b = 2.)
ASK YOUR TEACHER
0
y = a sin(bx²)
Sketch a typical approximating shell.
y
6
4
2
x
π/b
y
2
1
x
0.5
1.0
1.5
0.2
0.4
0.6
0.8
1.0
-2
-1
-4
Chapter A Solutions
Finite Mathematics for Business, Economics, Life Sciences and Social Sciences
Elementary Statistics: Picturing the World (7th Edition)
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