Elementary Geometry For College Students, 7e
7th Edition
ISBN: 9781337614085
Author: Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher: Cengage,
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Chapter A.5, Problem 19E
To determine
To find:
To solve each equation by using the
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Chapter A Solutions
Elementary Geometry For College Students, 7e
Ch. A.1 - Which axiom of equality is illustrated in each of...Ch. A.1 - Prob. 2ECh. A.1 - Prob. 3ECh. A.1 - Prob. 4ECh. A.1 - Prob. 5ECh. A.1 - Prob. 6ECh. A.1 - Prob. 7ECh. A.1 - Prob. 8ECh. A.1 - Prob. 9ECh. A.1 - Prob. 10E
Ch. A.1 - Prob. 11ECh. A.1 - Prob. 12ECh. A.1 - The four owners of a shop realize a loss of 240 in...Ch. A.1 - Bill works at a weekend convention by selling...Ch. A.1 - Use the Distributive Axiom to simplify each...Ch. A.1 - Use the Distributive Axiom to simplify each...Ch. A.1 - Simplify each expression: a 6+4 c 16x2y9x2y b...Ch. A.1 - Prob. 18ECh. A.1 - Prob. 19ECh. A.1 - Prob. 20ECh. A.1 - Prob. 21ECh. A.1 - Prob. 22ECh. A.1 - Prob. 23ECh. A.1 - Prob. 24ECh. A.1 - Prob. 25ECh. A.1 - Prob. 26ECh. A.1 - Prob. 27ECh. A.1 - Prob. 28ECh. A.1 - Prob. 29ECh. A.1 - Prob. 30ECh. A.2 - In Exercises 1 to 6, simplify by combining similar...Ch. A.2 - Prob. 2ECh. A.2 - Prob. 3ECh. A.2 - Prob. 4ECh. A.2 - Prob. 5ECh. A.2 - Prob. 6ECh. A.2 - Prob. 7ECh. A.2 - Prob. 8ECh. A.2 - Prob. 9ECh. A.2 - Prob. 10ECh. A.2 - Prob. 11ECh. A.2 - Prob. 12ECh. A.2 - Prob. 13ECh. A.2 - Prob. 14ECh. A.2 - Prob. 15ECh. A.2 - Prob. 16ECh. A.2 - Prob. 17ECh. A.2 - Prob. 18ECh. A.2 - Prob. 19ECh. A.2 - Prob. 20ECh. A.2 - Prob. 21ECh. A.2 - Prob. 22ECh. A.2 - Prob. 23ECh. A.2 - Prob. 24ECh. A.2 - Prob. 25ECh. A.2 - Prob. 26ECh. A.2 - Prob. 27ECh. A.2 - Prob. 28ECh. A.2 - Prob. 29ECh. A.2 - Prob. 30ECh. A.2 - Prob. 31ECh. A.2 - Prob. 32ECh. A.2 - Prob. 33ECh. A.2 - Prob. 34ECh. A.2 - Prob. 35ECh. A.2 - Prob. 36ECh. A.3 - If line segment AB and line segment CD in the...Ch. A.3 - Prob. 2ECh. A.3 - Prob. 3ECh. A.3 - Prob. 4ECh. A.3 - Prob. 5ECh. A.3 - Prob. 6ECh. A.3 - Prob. 7ECh. A.3 - Prob. 8ECh. A.3 - Prob. 9ECh. A.3 - Of several angles, the degree measures are related...Ch. A.3 - Prob. 11ECh. A.3 - Prob. 12ECh. A.3 - Prob. 13ECh. A.3 - Prob. 14ECh. A.3 - Prob. 15ECh. A.3 - Prob. 16ECh. A.3 - Prob. 17ECh. A.3 - Prob. 18ECh. A.3 - Prob. 19ECh. A.3 - Prob. 20ECh. A.3 - Prob. 21ECh. A.3 - Prob. 22ECh. A.3 - Prob. 23ECh. A.3 - Prob. 24ECh. A.3 - Prob. 25ECh. A.3 - Prob. 26ECh. A.3 - Prob. 27ECh. A.3 - Prob. 28ECh. A.3 - Prob. 29ECh. A.3 - Prob. 30ECh. A.3 - Prob. 31ECh. A.3 - Prob. 32ECh. A.4 - Prob. 1ECh. A.4 - Note: Exercises preceded by an asterisk are of a...Ch. A.4 - Prob. 3ECh. A.4 - Prob. 4ECh. A.4 - Prob. 5ECh. A.4 - Prob. 6ECh. A.4 - In Exercises 5 to 8, factor each difference of two...Ch. A.4 - In Exercises 5 to 8, factor each difference of two...Ch. A.4 - Prob. 9ECh. A.4 - Prob. 10ECh. A.4 - In Exercises 9 to 16, factor each trinomial...Ch. A.4 - Prob. 12ECh. A.4 - Prob. 13ECh. A.4 - Prob. 14ECh. A.4 - Prob. 15ECh. A.4 - Prob. 16ECh. A.4 - Prob. 17ECh. A.4 - Prob. 18ECh. A.4 - Prob. 19ECh. A.4 - Prob. 20ECh. A.4 - Prob. 21ECh. A.4 - Prob. 22ECh. A.4 - Prob. 23ECh. A.4 - Prob. 24ECh. A.4 - Prob. 25ECh. A.4 - Prob. 26ECh. A.4 - Prob. 27ECh. A.4 - Prob. 28ECh. A.4 - In Exercises 25 to 32, solve each quadratic...Ch. A.4 - In Exercises 25 to 32, solve each quadratic...Ch. A.4 - Prob. 31ECh. A.4 - Prob. 32ECh. A.4 - Prob. 33ECh. A.4 - Prob. 34ECh. A.4 - Prob. 35ECh. A.4 - Prob. 36ECh. A.4 - Given that the area of the rectangle shown is 66,...Ch. A.4 - Determine the length x by solving either the...Ch. A.4 - Find the length a by solving the equation...Ch. A.4 - Prob. 40ECh. A.4 - Prob. 41ECh. A.5 - Use your calculator to find the approximate value...Ch. A.5 - Prob. 2ECh. A.5 - Prob. 3ECh. A.5 - Prob. 4ECh. A.5 - Prob. 5ECh. A.5 - Prob. 6ECh. A.5 - Prob. 7ECh. A.5 - Prob. 8ECh. A.5 - Use your calculator to verify that the following...Ch. A.5 - Prob. 10ECh. A.5 - Prob. 11ECh. A.5 - Prob. 12ECh. A.5 - Prob. 13ECh. A.5 - Prob. 14ECh. A.5 - Prob. 15ECh. A.5 - Prob. 16ECh. A.5 - Prob. 17ECh. A.5 - Prob. 18ECh. A.5 - Prob. 19ECh. A.5 - Prob. 20ECh. A.5 - Prob. 21ECh. A.5 - Prob. 22ECh. A.5 - Prob. 23ECh. A.5 - Prob. 24ECh. A.5 - Prob. 25ECh. A.5 - Prob. 26ECh. A.5 - Prob. 27ECh. A.5 - Prob. 28ECh. A.5 - Prob. 29ECh. A.5 - Prob. 30ECh. A.5 - Prob. 31ECh. A.5 - Prob. 32ECh. A.5 - Prob. 33ECh. A.5 - Prob. 34ECh. A.5 - Prob. 35ECh. A.5 - Prob. 36ECh. A.5 - Prob. 37ECh. A.5 - Prob. 38ECh. A.5 - Prob. 39E
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- Proof: LN⎯⎯⎯⎯⎯LN¯ divides quadrilateral KLMN into two triangles. The sum of the angle measures in each triangle is ˚, so the sum of the angle measures for both triangles is ˚. So, m∠K+m∠L+m∠M+m∠N=m∠K+m∠L+m∠M+m∠N=˚. Because ∠K≅∠M∠K≅∠M and ∠N≅∠L, m∠K=m∠M∠N≅∠L, m∠K=m∠M and m∠N=m∠Lm∠N=m∠L by the definition of congruence. By the Substitution Property of Equality, m∠K+m∠L+m∠K+m∠L=m∠K+m∠L+m∠K+m∠L=°,°, so (m∠K)+ m∠K+ (m∠L)= m∠L= ˚. Dividing each side by gives m∠K+m∠L=m∠K+m∠L= °.°. The consecutive angles are supplementary, so KN⎯⎯⎯⎯⎯⎯∥LM⎯⎯⎯⎯⎯⎯KN¯∥LM¯ by the Converse of the Consecutive Interior Angles Theorem. Likewise, (m∠K)+m∠K+ (m∠N)=m∠N= ˚, or m∠K+m∠N=m∠K+m∠N= ˚. So these consecutive angles are supplementary and KL⎯⎯⎯⎯⎯∥NM⎯⎯⎯⎯⎯⎯KL¯∥NM¯ by the Converse of the Consecutive Interior Angles Theorem. Opposite sides are parallel, so quadrilateral KLMN is a parallelogram.arrow_forwardQuadrilateral BCDE is similar to quadrilateral FGHI. Find the measure of side FG. Round your answer to the nearest tenth if necessary. BCDEFGHI2737.55arrow_forwardAn angle measures 70.6° more than the measure of its supplementary angle. What is the measure of each angle?arrow_forward
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