Explanation Approach: The distributive law for disjunction is given as, p ∨ ( q ∧ r ) ⇔ ( p ∨ q ) ∧ ( p ∨ r ) The distributive law for conjunction is given as, p ∧ ( q ∨ r ) ⇔ ( p ∧ q ) ∨ ( p ∧ r ) The law of logic is given as, p ∨ ∼ p ⇔ t p ∧ t ⇔ p Here, t is tautology. Calculation: Consider the left side of the given proposition, p ∨ ( ∼ p ∧ ∼ q ) From the distributive law for disjunction, the above proposition can be written as, ( p ∨ ∼ p ) ∧ ( p ∨ ∼ q ) Substitute t for ( p ∨ ∼ p ) in the above proposition

Finite Mathematics For The Managerial, Life, And Social Sciences

12th Edition

ISBN: 9781337606592

Author: Tan

Publisher: CENGAGE L

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Statements and Logic

Logic is the analysis of general patterns of thoughts without regard to any specific sense of context.

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Chapter A.4, Problem 22E

To determine

To prove:

The proposition of p∨(∼p∧∼q)⇔p∨∼q by using laws of logic.

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Chapter A Solutions

Finite Mathematics For The Managerial, Life, And Social Sciences

Ch. A.1 - In Exercises 114, determine whether the statement...Ch. A.1 - In Exercises 114, determine whether the statement...Ch. A.1 - Prob. 3E Ch. A.1 - Prob. 4E Ch. A.1 - Prob. 5E Ch. A.1 - Prob. 6E Ch. A.1 - Prob. 7E Ch. A.1 - Prob. 8E Ch. A.1 - Prob. 9E Ch. A.1 - Prob. 10E

Ch. A.1 - Prob. 11E Ch. A.1 - Prob. 12E Ch. A.1 - Prob. 13E Ch. A.1 - Prob. 14E Ch. A.1 - Prob. 15E Ch. A.1 - Prob. 16E Ch. A.1 - Prob. 17E Ch. A.1 - Prob. 18E Ch. A.1 - Prob. 19E Ch. A.1 - Prob. 20E Ch. A.1 - Prob. 21E Ch. A.1 - Prob. 22E Ch. A.1 - Prob. 23E Ch. A.1 - Prob. 24E Ch. A.1 - Prob. 25E Ch. A.1 - Prob. 26E Ch. A.1 - Prob. 27E Ch. A.1 - Prob. 28E Ch. A.1 - Prob. 29E Ch. A.1 - Let p and q denote the propositions p: The...Ch. A.1 - Prob. 31E Ch. A.1 - Prob. 32E Ch. A.1 - Prob. 33E Ch. A.2 - Prob. 1E Ch. A.2 - Prob. 2E Ch. A.2 - Prob. 3E Ch. A.2 - Prob. 4E Ch. A.2 - In Exercises 1-18, construct a truth table for...Ch. A.2 - Prob. 6E Ch. A.2 - Prob. 7E Ch. A.2 - In Exercises 1-18, construct a truth table for...Ch. A.2 - Prob. 9E Ch. A.2 - Prob. 10E Ch. A.2 - Prob. 11E Ch. A.2 - Prob. 12E Ch. A.2 - Prob. 13E Ch. A.2 - Prob. 14E Ch. A.2 - Prob. 15E Ch. A.2 - Prob. 16E Ch. A.2 - Prob. 17E Ch. A.2 - Prob. 18E Ch. A.2 - If a compound proposition consists of the prime...Ch. A.3 - In Exercises 14, write the converse, the...Ch. A.3 - In Exercises 14, write the converse, the...Ch. A.3 - Prob. 3E Ch. A.3 - Prob. 4E Ch. A.3 - Prob. 5E Ch. A.3 - In Exercises 5 and 6, refer to the following...Ch. A.3 - Prob. 7E Ch. A.3 - Prob. 8E Ch. A.3 - Prob. 9E Ch. A.3 - Prob. 10E Ch. A.3 - Prob. 11E Ch. A.3 - Prob. 12E Ch. A.3 - Prob. 13E Ch. A.3 - Prob. 14E Ch. A.3 - Prob. 15E Ch. A.3 - Prob. 16E Ch. A.3 - Prob. 17E Ch. A.3 - Prob. 18E Ch. A.3 - Prob. 19E Ch. A.3 - Prob. 20E Ch. A.3 - Prob. 21E Ch. A.3 - Prob. 22E Ch. A.3 - Prob. 23E Ch. A.3 - Prob. 24E Ch. A.3 - Prob. 25E Ch. A.3 - Prob. 26E Ch. A.3 - Prob. 27E Ch. A.3 - Prob. 28E Ch. A.3 - Prob. 29E Ch. A.3 - Prob. 30E Ch. A.3 - Prob. 31E Ch. A.3 - Prob. 32E Ch. A.3 - Prob. 33E Ch. A.3 - Prob. 34E Ch. A.3 - Prob. 35E Ch. A.3 - Prob. 36E Ch. A.3 - Prob. 37E Ch. A.3 - Prob. 38E Ch. A.4 - Prove the idempotent law for conjunction, ppp.Ch. A.4 - Prob. 2E Ch. A.4 - Prove the associative law for conjunction,...Ch. A.4 - Prob. 4E Ch. A.4 - Prove the commutative law for conjunction, pqqp.Ch. A.4 - Prob. 6E Ch. A.4 - Prob. 7E Ch. A.4 - Prob. 8E Ch. A.4 - Prob. 9E Ch. A.4 - Prob. 10E Ch. A.4 - Prob. 11E Ch. A.4 - Prob. 12E Ch. A.4 - Prob. 13E Ch. A.4 - Prob. 14E Ch. A.4 - Prob. 15E Ch. A.4 - Prob. 16E Ch. A.4 - Prob. 17E Ch. A.4 - In exercises 9-18, determine whether the statement...Ch. A.4 - Prob. 19E Ch. A.4 - Prob. 20E Ch. A.4 - In Exercises 21-26, use the laws of logic to prove...Ch. A.4 - Prob. 22E Ch. A.4 - In Exercises 21-26, use the laws of logic to prove...Ch. A.4 - In Exercises 21-26, use the laws of logic to prove...Ch. A.4 - In Exercises 21-26, use the laws of logic to prove...Ch. A.4 - Prob. 26E Ch. A.5 - Prob. 1E Ch. A.5 - Prob. 2E Ch. A.5 - Prob. 3E Ch. A.5 - Prob. 4E Ch. A.5 - Prob. 5E Ch. A.5 - Prob. 6E Ch. A.5 - Prob. 7E Ch. A.5 - Prob. 8E Ch. A.5 - Prob. 9E Ch. A.5 - In Exercises 116, determine whether the argument...Ch. A.5 - Prob. 11E Ch. A.5 - Prob. 12E Ch. A.5 - Prob. 13E Ch. A.5 - Prob. 14E Ch. A.5 - Prob. 15E Ch. A.5 - Prob. 16E Ch. A.5 - In Exercises 17-22, represent the argument...Ch. A.5 - Prob. 18E Ch. A.5 - In Exercises 17-22, represent the argument...Ch. A.5 - In Exercises 17-22, represent the argument...Ch. A.5 - In Exercises 17-22, represent the argument...Ch. A.5 - Prob. 22E Ch. A.5 - Prob. 23E Ch. A.5 - Prob. 24E Ch. A.5 - Prob. 25E Ch. A.6 - In Exercises 1-5, find a logic statement...Ch. A.6 - Prob. 2E Ch. A.6 - Prob. 3E Ch. A.6 - Prob. 4E Ch. A.6 - Prob. 5E Ch. A.6 - Prob. 6E Ch. A.6 - Prob. 7E Ch. A.6 - Prob. 8E Ch. A.6 - Prob. 9E Ch. A.6 - Prob. 10E Ch. A.6 - Prob. 11E Ch. A.6 - Prob. 12E Ch. A.6 - Prob. 13E Ch. A.6 - In Exercise 12-15, find a logic statement...Ch. A.6 - Prob. 15E Ch. A.6 - Prob. 16E

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To prove: The proposition of p ∨ ( ∼ p ∧ ∼ q ) ⇔ p ∨ ∼ q by using laws of logic.

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To prove:

The proposition of p∨(∼p∧∼q)⇔p∨∼q by using laws of logic.

Chapter A Solutions

To prove: The proposition of p ∨ ( ∼ p ∧ ∼ q ) ⇔ p ∨ ∼ q by using laws of logic.

Solution Summary: The author explains how the proposition of pvee (qwedge r) is proved using laws of logic.

Concept explainers

Videos

To prove: The proposition of p∨(∼p∧∼q)⇔p∨∼q by using laws of logic.

Chapter A Solutions

To prove:

The proposition of p∨(∼p∧∼q)⇔p∨∼q by using laws of logic.