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Chapter A3, Problem 41E
To determine

To calculate: The simplified form of (x2)13(x+1)326(x2)43(x+1)12 by factoring the expression.

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f(x) = = x - 3 x²-9 f(x) = {x + 1 x > 3 4 x < 3 -10 5 10 5 5. 10 5- 07. 10 -10 -5 0 10 5 -101 :: The function has a “step" or "jump" discontinuity at x = 3 where f(3) = 7. :: The function has a value of f (3), a limit as x approaches 3, but is not continuous at x = 3. :: The function has a limit as x approaches 3, but the function is not defined and is not continuous at x = 3. :: The function has a removable discontinuity at x=3 and an infinite discontinuity at x= -3.
Calculus lll  May I please have the solutions for the following examples? Thank you
Calculus lll  May I please have the solutions for the following exercises that are blank? Thank you
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