Calculus for Business, Economics, Life Sciences, and Social Sciences (13th Edition)
13th Edition
ISBN: 9780321869838
Author: Raymond A. Barnett, Michael R. Ziegler, Karl E. Byleen
Publisher: PEARSON
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Chapter A.2, Problem 60E
To determine
To write: An algebraic expression which represents the gross receipts from ticket sales and then simply the expression.
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For each real-valued nonprincipal character x mod k, let
A(n) = x(d) and F(x) = Σ
:
dn
* Prove that
F(x) = L(1,x) log x + O(1).
n
By considering appropriate series expansions,
e². e²²/2. e²³/3.
....
=
= 1 + x + x² + ·
...
when |x| < 1.
By expanding each individual exponential term on the left-hand side
the coefficient of x- 19 has the form
and multiplying out,
1/19!1/19+r/s,
where 19 does not divide s. Deduce that
18! 1 (mod 19).
Proof: LN⎯⎯⎯⎯⎯LN¯ divides quadrilateral KLMN into two triangles. The sum of the angle measures in each triangle is ˚, so the sum of the angle measures for both triangles is ˚. So, m∠K+m∠L+m∠M+m∠N=m∠K+m∠L+m∠M+m∠N=˚. Because ∠K≅∠M∠K≅∠M and ∠N≅∠L, m∠K=m∠M∠N≅∠L, m∠K=m∠M and m∠N=m∠Lm∠N=m∠L by the definition of congruence. By the Substitution Property of Equality, m∠K+m∠L+m∠K+m∠L=m∠K+m∠L+m∠K+m∠L=°,°, so (m∠K)+ m∠K+ (m∠L)= m∠L= ˚. Dividing each side by gives m∠K+m∠L=m∠K+m∠L= °.°. The consecutive angles are supplementary, so KN⎯⎯⎯⎯⎯⎯∥LM⎯⎯⎯⎯⎯⎯KN¯∥LM¯ by the Converse of the Consecutive Interior Angles Theorem. Likewise, (m∠K)+m∠K+ (m∠N)=m∠N= ˚, or m∠K+m∠N=m∠K+m∠N= ˚. So these consecutive angles are supplementary and KL⎯⎯⎯⎯⎯∥NM⎯⎯⎯⎯⎯⎯KL¯∥NM¯ by the Converse of the Consecutive Interior Angles Theorem. Opposite sides are parallel, so quadrilateral KLMN is a parallelogram.
Chapter A.2 Solutions
Calculus for Business, Economics, Life Sciences, and Social Sciences (13th Edition)
Ch. A.2 - (A)Given the polynomial 6x5 + 7x3 2, what is the...Ch. A.2 - Remove parentheses and simplify: (A)3(u2 2v2) +...Ch. A.2 - Prob. 3MPCh. A.2 - Subtract 2x2 5x + 4 from 5x2 6, both...Ch. A.2 - Multiply: (2x3)(2x2+3x2)Ch. A.2 - Prob. 6MPCh. A.2 - Perform the indicated operations and simplify:...Ch. A.2 - Prob. 1ECh. A.2 - Problems 18 refer to the following polynomials:...Ch. A.2 - Problems 18 refer to the following polynomials:...
Ch. A.2 - Problems 18 refer to the following polynomials:...Ch. A.2 - Prob. 5ECh. A.2 - Problems 18 refer to the following polynomials:...Ch. A.2 - Problems 18 refer to the following polynomials:...Ch. A.2 - Problems 18 refer to the following polynomials:...Ch. A.2 - In Problems 930, perform the indicated operations...Ch. A.2 - In Problems 930, perform the indicated operations...Ch. A.2 - In Problems 930, perform the indicated operations...Ch. A.2 - In Problems 930, perform the indicated operations...Ch. A.2 - In Problems 930, perform the indicated operations...Ch. A.2 - Prob. 14ECh. A.2 - In Problems 930, perform the indicated operations...Ch. A.2 - In Problems 930, perform the indicated operations...Ch. A.2 - In Problems 930, perform the indicated operations...Ch. A.2 - In Problems 930, perform the indicated operations...Ch. A.2 - In Problems 930, perform the indicated operations...Ch. A.2 - Prob. 20ECh. A.2 - In Problems 930, perform the indicated operations...Ch. A.2 - Prob. 22ECh. A.2 - In Problems 930, perform the indicated operations...Ch. A.2 - Prob. 24ECh. A.2 - Prob. 25ECh. A.2 - In Problems 930, perform the indicated operations...Ch. A.2 - Prob. 27ECh. A.2 - Prob. 28ECh. A.2 - Prob. 29ECh. A.2 - In Problems 930, perform the indicated operations...Ch. A.2 - In Problems 3144, perform the indicated operations...Ch. A.2 - Prob. 32ECh. A.2 - In Problems 3144, perform the indicated operations...Ch. A.2 - In Problems 3144, perform the indicated operations...Ch. A.2 - In Problems 3144, perform the indicated operations...Ch. A.2 - In Problems 3144, perform the indicated operations...Ch. A.2 - In Problems 3144, perform the indicated operations...Ch. A.2 - Prob. 38ECh. A.2 - Prob. 39ECh. A.2 - In Problems 3144, perform the indicated operations...Ch. A.2 - In Problems 3144, perform the indicated operations...Ch. A.2 - In Problems 3144, perform the indicated operations...Ch. A.2 - In Problems 3144, perform the indicated operations...Ch. A.2 - Prob. 44ECh. A.2 - Subtract the sum of the last two polynomials from...Ch. A.2 - Subtract the sum of the first two polynomials from...Ch. A.2 - In Problems 4750, perform the indicated operations...Ch. A.2 - Prob. 48ECh. A.2 - In Problems 4750, perform the indicated operations...Ch. A.2 - Prob. 50ECh. A.2 - If you are given two polynomials, one of degree m...Ch. A.2 - What is the degree of the sum of the two...Ch. A.2 - How does the answer to Problem 51 change if the...Ch. A.2 - How does the answer to Problem 52 change if the...Ch. A.2 - Prob. 55ECh. A.2 - Show by example that, in general, (ab)2a2b2....Ch. A.2 - Investment. You have 10,000 to invest, part at 9%...Ch. A.2 - Prob. 58ECh. A.2 - Prob. 59ECh. A.2 - Prob. 60ECh. A.2 - Prob. 61ECh. A.2 - Nutrition. Each ounce of food M contains 8 units...
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- By considering appropriate series expansions, ex · ex²/2 . ¸²³/³ . . .. = = 1 + x + x² +…… when |x| < 1. By expanding each individual exponential term on the left-hand side and multiplying out, show that the coefficient of x 19 has the form 1/19!+1/19+r/s, where 19 does not divide s.arrow_forwardLet 1 1 r 1+ + + 2 3 + = 823 823s Without calculating the left-hand side, prove that r = s (mod 823³).arrow_forwardFor each real-valued nonprincipal character X mod 16, verify that L(1,x) 0.arrow_forward
- *Construct a table of values for all the nonprincipal Dirichlet characters mod 16. Verify from your table that Σ x(3)=0 and Χ mod 16 Σ χ(11) = 0. x mod 16arrow_forwardFor each real-valued nonprincipal character x mod 16, verify that A(225) > 1. (Recall that A(n) = Σx(d).) d\narrow_forward24. Prove the following multiplicative property of the gcd: a k b h (ah, bk) = (a, b)(h, k)| \(a, b)' (h, k) \(a, b)' (h, k) In particular this shows that (ah, bk) = (a, k)(b, h) whenever (a, b) = (h, k) = 1.arrow_forward
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- Prove that Σ prime p≤x p=3 (mod 10) 1 Р = for some constant A. log log x + A+O 1 log x ,arrow_forwardLet Σ 1 and g(x) = Σ logp. f(x) = prime p≤x p=3 (mod 10) prime p≤x p=3 (mod 10) g(x) = f(x) logx - Ր _☑ t¯¹ƒ(t) dt. Assuming that f(x) ~ 1½π(x), prove that g(x) ~ 1x. 米 (You may assume the Prime Number Theorem: 7(x) ~ x/log x.) *arrow_forwardLet Σ logp. f(x) = Σ 1 and g(x) = Σ prime p≤x p=3 (mod 10) (i) Find ƒ(40) and g(40). prime p≤x p=3 (mod 10) (ii) Prove that g(x) = f(x) logx – [*t^¹ƒ(t) dt. 2arrow_forward
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